(Electron Configurations). Electromagnetic Radiationform of energy that exhibits wavelike...

Author
aleclambertson 
Category
Documents

view
224 
download
2
Embed Size (px)
Transcript of (Electron Configurations). Electromagnetic Radiationform of energy that exhibits wavelike...
(Electron Configurations)
Electromagnetic Radiationform of energy that exhibits wavelike behavior as it travels through space.
Electromagnetic Spectrumordered arrangement by wavelength or frequency for all forms of electromagnetic radiation.
Wavelengthlambda (λ)The distance between corresponding points on adjacent waves. Units: m, nm, cm, or Å
Frequencynu (ν)The number of waves passing a given point in a definite amount of time. Units: hertz (Hz) or cycles/sec = 1/sec = sec1
When an electric field changes, so does the magnetic field. The changing magnetic field causes the electric field to change. When one field vibrates—so does the other.
RESULTAn electromagnetic wave.
Waves or Particles Electromagnetic radiation has properties of
waves but also can be thought of as a stream of particles.
Example: Light Light as a wave: Light behaves as a transverse
wave which we can filter using polarized lenses.
Light as particles (photons)
When directed at a substance light can knock electrons off of a substance (Photoelectric effect)
c = λ∙ν λ = wavelength (m) ν = frequency (Hz) c = speed of light= 3.0 x 108 m/sec
(constant) λ and ν are _______________ related.
Truckmounted heliumneon laser produces red light whose wavelength (λ ) is 633 nanometers. Determine the frequency (v).
*Remember that c=3.0x108m/s. *Use the formula v= c
λ
c =3.0x108 m/s
c= λ . v
v=c / λλ = 633nm= 6.33x107m
v = 3.0x108 m/s = 0.47x 1015s1 = 4.7x1014
s1
6.33x107m
Frequency = 4.7x1014 Hz (cycles per second)
GIVEN:
= ?
= 434 nm = 4.34 107 m
c = 3.00 108 m/s
WORK: = c
= 3.00 108 m/s 4.34 107 m
= 6.91 1014 Hz
EX: Find the frequency of a photon with a wavelength of 434 nm.
2 problems that could not be explained if light only acted as a wave.
1.) Emission of Light by Hot bodies:Characteristic color given off as
bodies are heated: red yellow white
If light were a wave, energy would be given off continually in the infrared (IR) region of the spectrum.
2.) Absorption of Light by Matter = Photoelectric Effect
Light can only cause electrons to be ejected from a metallic surface if that light is at least a minimum threshold frequency . The intensity is not important.
If light were only a wave intensity would be the determining factor, not the frequency!
When an object loses energy, it doesn’t happen continuously but in small packages called “quanta”.
“Quantum”a definite amount of energy either lost or gained by an atom.
“Photon”a quantum of light or a particle of radiation.
Calculate the frequency for the yelloworange light of sodium.
Calculate the frequency for violet light.
Calculate the frequency for the yelloworange light of sodium.
Calculate the frequency for violet light.
E = h∙ν E = energy (joule) h = Planck’s constant = 6.63 x 1034
j∙sec ν = frequency (Hz) E and ν are ______________ related. Calculate the energy for the yellow
orange light for sodium.
Calculate the energy for the violet light.
Excited State: Higher energy state than the atom normally exists in.
Ground State: Lowest energy state “happy state”
Line Spectrum: Discrete wavelengths of light emitted.
2 Types:1.) Emission Spectrum: All wavelengths of light
emitted by an atom.2.) Absorption Spectrum: All wavelengths of light
that are not absorbed by an atom. This is a continuous spectrum with wavelengths removed that are absorbed by the atom. These are shown as black lines for absorbed light.
Continuous Spectrum: All wavelengths of a region of the spectrum are represented (i.e. visible light)
Hydrogen’s spectrum can be explained with the waveparticle theory of light.
Niel’s Bohr (1913) 1.) The electron travels in orbits (energy
levels) around the nucleus. 2.) The orbits closest to the nucleus are
lowest in energy, those further out are higher in energy.
3.) When energy is absorbed by the atom, the electron moves into a higher energy orbit. This energy is released when the electron falls back to a lower energy orbit. A photon of light is emitted.
Lyman Serieselectrons falling to the 1st orbit, these are highest energy, _____ region.
Balmer Series electrons falling to the 2nd orbit, intermediate energy, _______ region.
Paschen Serieselectrons falling to the 3rd orbit, smallest energy, ______ region.
En = (RH) 1/n2
En = energy of an electron in an allowed orbit (n=1, n=2, n=3, etc.)
n = principal quantum number (17) RH = Rydberg constant (2.18 x 1018 J) When an electron jumps between energy
levels: ΔE =Ef – Ei
By substitution: ΔE = hν = RH(1/ni2  1/nf
2) When nf > ni then ΔE = (+)
When nf < ni then ΔE = ()
DeBroglie (1924)Wave properties of the electron was observed from the diffraction pattern created by a stream of electrons.
Schrodinger (1926)Developed an equation that correctly accounts for the wave property of the electron and all spectra of atoms. (very complex)
Rather than orbits we refer to orbitals. These are 3dimensional regions of space where there is a high probability of locating the electron.
Heisenberg Uncertainty Principleit is not possible to know the exact location and momentum (speed) of an electron at the same time.
Quantum Numbers4 numbers that are used to identify the highest probability location for the electron.
1.) Principal Quantum Number (n)States the main energy level of the electron
and also identifies the number of sublevels that are possible.
n=1, n=2, n=3, etc. to n=72.) Orbital Quantum NumberIdentifies the shape of the orbital
s (2 electrons) sphere 1 orbital P (6 electrons) dumbbell 3 orbitals d (10 electrons) 44 leaf clovers & 1dumbbell w/doughnut5
orbitals f (14 electrons) very complex 7
orbitals
3.) Magnetic Quantum Number Identifies the orientation in space (x, y, z)
s 1 orientation p 3 orientations d 5 orientations f 7 orientations
4.) Spin Quantum Number States the spin of the electron. Each orbital can hold at most 2 electrons with
opposite spin.
1.) Principal Quantum Number (n)States the main energy level of the electron
and also identifies the number of sublevels that are possible.
n=1, n=2, n=3, etc. to n=72.) Azimuthal Quantum Number (l)Values from 0 to n1Identifies the shape of the orbital
l = 0 s sphere 1 orbital l = 1 p dumbbell 3 orbitals l = 2 d 44 leaf clovers & 1dumbbell w/doughnut5 orbitals l = 3 f very complex 7 orbitals
3.) Magnetic Quantum Number (ml)Values from –l lStates the orientation in space (x, y, z)
ml = 0 s only 1 orientation ml = 1, 0, +1 p 3 orientations ml = 2,1,0,+1,+2 d 5 orientations ml = 3,2,1,0,+1+2,+3 f 7 orientations
4.) Spin Quantum Number (ms) Values of +1/2 to 1/2 States the spin of the electron. Each orbital can hold at most 2 electrons
with opposite spin.