· Web view101.3 kPasc = 1 atm = 760 mm Hg S = S P P C + 273 = K Q = mcΔT ΔT = k m...
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Gen Chem 2 nd Sem Exam Equations P = F Titration Steps A 1. Balance Equation 2. M = mol given/ L PV = PV 3. Mol given to mol wanted 4. M = mol wanted/ L P = P T T % H 2 O in hydrate = mass of H 2 O V = V total mass T T PV = PV T T PV = nRT R = .0821 atm L mol K 101.3 kPasc = 1 atm = 760 mm Hg S = S P P C + 273 = K Q = mcΔT ΔT = k m ions M = mol L m = mol kg MV = MV % mass = mass solute mass solution
Transcript of · Web view101.3 kPasc = 1 atm = 760 mm Hg S = S P P C + 273 = K Q = mcΔT ΔT = k m...
Gen Chem 2nd Sem Exam Equations
P = F Titration Steps A 1. Balance Equation
2. M = mol given/ LPV = PV 3. Mol given to mol wanted
4. M = mol wanted/ LP = PT T
% H2O in hydrate = mass of H2OV = V total massT T
PV = PV T T
PV = nRT
R = .0821 atm L mol K
101.3 kPasc = 1 atm = 760 mm Hg
S = SP P
C + 273 = K
Q = mcΔT
ΔT = k m ions
M = mol L
m = mol kg
MV = MV
% mass = mass solute mass solution
% volume = volume solute volume solution
total time = n original mass = remaining masstime for 1 half life 2n
