Bonding

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Bonding in H 2 + : MO Theory Jan. 28, 2014

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Transcript of Bonding

  • Bonding in H2+: MOTheory

    Jan. 28, 2014

  • H2+ is the simplest molecular species

    The Hamiltonian is

    H = p2

    2m e

    2

    rA e

    2

    rB+e2

    R

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  • Approx. wavefunction for H2+

    guessed from R =

    Two equally likely dissociation pathways for H2+

    1 H2+ HA + HB+

    2 H2+ HB + HA+

    When R =, has significant amplitude only near A andnear B

    1 Electron near A = = cA1sA2 Electron near B = = cB1sB

    Guess that = cA1sA + cB1sB everywhere in spaceMatter wave constructed by superposition of H AO

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  • Indistinguishability restricts cA and cB

    Physically measurable quantities unaffected on interchangingparticle labels

    ||2 is unaffected by particle interchange

    |(A,B)|2 = |(B,A)|2

    = |cA|2 = |cB|2 = |c|2

    For real values, cA = cB and cA = cB or

    = c(1sA 1sB)

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  • Normalization used to find c.

    ||2d = c2

    |1sA 1sB|2d

    1 = c2(|1sA|2d

    1sA1sBd

    1sA1s

    Bd +

    |1sB|2d

    )When R,

    1sA1sBd =

    1sA1s

    Bd = 0.

    1 = c2(1 + 0 + 0 + 1)

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  • At infinite internuclear distanceE(H+2 ) = EH(1s)

    E() =

    all spaceHd

    =

    near A

    1s(A)2HA

    1s(A)2d

    +

    near B

    1s(B)2HB

    1s(B)2d

    =1

    2EH(1s) +

    1

    2EH(1s) = EH(1s)

    Define this as the zero of energy

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  • At finite R, is approximately a sumof atomic orbitals

    + = c0 (1s(A) + 1s(B))

    = c1 (1s(A) 1s(B))

    Linear Combination of Atomic Orbitals (LCAO)1 Maximum simplicity with reasonable accuracy2 Natural and intuitive appeal3 Simplifies calculations - atomic orbitals already determined

    to high accuracy4 Wavefunctions around atoms in molecules like those

    around free atomsBond formation a small perturbation to atomic structure

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  • Normalization constant depends onthe overlap integral

    |+|2d = 1 = c20

    (|1s(A)|2 +

    |1s(B)|2d

    +

    1s(A)1s(B)d +

    1s(A)1s(B)d

    )Defining S =

    1s(A)1s(B)d , we find

    |+|2d = 2c20(1 + S)

    S is zero when A and Bare infinitely far apart

    S has a large contributionfrom regions where 1s(A)and 1s(B) are bothappreciable

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  • Electron density between the nuclei ismore in +

    The electron density in the + MO is

    |+|2 =|1s(A)|2 + |1s(B)|2 + 2(1s(A)1s(B))

    2(1 + S)

    S reduces the electron density everywhere.Between the nuclei 2(1s(A)1s(B)) is dominant and

    = |+|2 > |1s(A)|2 + |1s(B)|2

    Constructive interference of the two atomic orbitals between thenuclei in +.

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  • There are 0 and 1 nodes in the twolowest MOs

    Dotted - non-interacting,dashed - LCAO, solid - exact

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  • Two lowest MOs show interferenceBonding MO Antibonding MO

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  • Forces responsible for binding

    Potential energy - electrostatic

    + describes a bonding state

    Kinetic energy - delocalization

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  • The approximate energy of + isgiven by

    +H+d

    E+(R) =1

    2(1 + S)

    (1s(A)H1s(A)d +

    1s(A)H1s(B)d+

    1s(B)H1s(A)d +

    1s(B)H1s(B)d)

    Define an integral

    Hij =

    iHjd

    E+(R) =HAA +HAB +HBA +HBB

    2(1 + S)

    E+(R) =HAA +HAB

    (1 + S)

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  • The atomic integral HAA has aCoulomb term

    HAA =

    1s(A)

    (p2

    2m e

    2

    rA

    )1s(A)d +

    e2

    R

    1s(A)1s(A)d

    1s(A)1s(A)e2

    rBd

    = EH(1s) +e2

    R+ J

    where

    J =

    e2

    rB1s(A)1s(A)d

    is the Coulombic interaction between the orbital around oneatom and the other nucleus.

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  • The resonance integral HAB has anexchange term

    HAB =

    1s(A)

    (p2

    2m e

    2

    rB

    )1s(B)d +

    e2

    R

    1s(A)1s(B)d

    1s(A)1s(B)e2

    rAd

    = S

    (EH(1s) +

    e2

    R

    )+K

    where

    K =

    e2

    rA1s(A)1s(B)d

    has no classical interpretation.

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  • In the GS the electron has a netbonding effect

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  • Exchange integral is important forbinding

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  • The LCAO method can begeneralized

    If = c1f1 + c2f2 then E =Hd is

    E(c1, c2) =c21H11 + 2c1c2H12 + c

    22H22

    c21S11 + 2c1c2S12 + c22S22

    At the minimum of the energy

    E

    c1=E

    c2= 0

    c1(H11 ES11) + c2(H12 ES12) = 0

    c1(H21 ES21) + c2(H22 ES22) = 0

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  • The LCAO method can be extended

    If =

    i cifi then E =Hd is

    E(c1, c2) =

    i c

    2iHii +

    i

    j>i 2cicjHij

    i c2iSii +

    i

    j>i 2cicjSij

    At the minimum of the energy

    E

    ci= 0

    c1(H11 ES11) + c2(H12 ES12) + = 0

    c1(H21 ES21) + c2(H22 ES22) + = 0

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