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I?M?P?R?S on ASTROPHYSICS at LMU Munich
Astrophysics Introductory Course
Lecture given by
Ralf Bender
in collaboration with:
Chris Botzler, Andre Crusius-Watzel,Niv Drory, Georg Feulner, Armin Gabasch,
Ulrich Hopp, Claudia Maraston,Michael Matthias, Jan Snigula, Daniel Thomas
Fall 2002
Astrophysics Introductory Course Fall 2002
Chapter 1
Matter and Radiation
For a comprehensive treatment of this subject see:Rybicki and Lightman: Radiative Processes in Astrophysics, Wiley, New York 1979
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1.1 Kinetic theory of free particles
To understand astrophysical plasmas, and especially stars, we need to know their equa-tions of state, i.e. the relations between density ρ, temperature T , pressure P and energydensity u:
Pressure P = P (ρ, T )Energy density u = u(ρ, T )
}Equations of State
For the classical ideal gas we have (k = Boltzmann’s constant):
Pgas = nkTugas = 3
2nkT = 32P
}Classical Ideal Gas
The classical ideal gas law applies for most hydrogen burning stars (main sequence stars,see below).
Generally, an equation of state for a gas can be derived with kinetic theory from the mo-mentum or energy distribution function of the particles.
Consider a cube of volume L3 with N homogeneously distributed particles, i.e. we havethe particle density no = N/L3. Provided the distribution function of the momenta n(p) is
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isotropic we can calculate:
no =
∫ ∞
0
n(p)d3p =
∫ ∞
0
n(p)4πp2dp
The pressure P on a wall is determined by the transferred momentum dp per time intervaldt and per area L2:
P =F
L2=
1
L2
dp
dtThe momentum transferred to the wall perpendicular to the x-direction is:
dp =
∫ ∞
0
2px︸︷︷︸Term 1
vxdtL2︸ ︷︷ ︸Term 2
n(p)d3p︸ ︷︷ ︸Term 3
which is readily understood if we consider that:Term 1 = transferred momentum per particleTerm 2 = all particles in this volume reach the wall during dtTerm 3 = density of particles with momentum p
For an isotropic distribution of momenta, we can write in spherical polar coordinates:
px = p sin θ cos ϕ, vx = v(p) sin θ cos ϕ, d3p = p2 sin θdθdϕdp
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and obtain for the pressure:
P =1
L2
dp
dt=
∫ ∞
0
∫ 2π
0
∫ π
0
2pv p2 n(p) sin3 θ cos2 ϕ dθdϕdp
i.e.
P =1
3
∫ ∞
0
p · v(p) n(p) 4π p2dp
The pressure is determined by the momentum distribution function of the particles.
The energy density of the particles is:
ukin =
∫ ∞
0
ε(p) n(p) 4πp2dp
where ε(p) = kinetic energy of particle with momentum p. In the non-relativisitc case wehave of course ε = p2
2m. For relativistic particles we need:
ε(p) = p · c
(√1 +
(m0cp
)2
− m0cp
)and p · v = p·c√
1+(m0cp )
2 .
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1.2 Equilibrium distribution functions of fermions and bosons
All particles known obey either Bose-Einstein or Fermi-Dirac statistics. At low temper-atures, the nature of the particles is important for determining their thermodynamic be-haviour. At high temperatures, all ideal gases of free particles behave in the same way, i.e.like the classical ideal gas.
Using the grand canonical partition function one can show that fermions and bosons havethe following energy distribution functions in thermodynamical equilibrium:
dN =dg
e−η+E/kT ± 1
E = energy of the particledN = number of particles p in energy range (E, E + dE)dg = number of quantum states in energy range (E, E + dE)
= α d3x d3p/h3 (multiplicity α due to particle spin)+1 in denominator = Fermions, Pauli-principle, only one particle per phase space cell h3
−1 in denominator = Bosons, no Pauli-principleη = “Degeneracy parameter” = (chemical potential µ)/(kT )
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For all massive particles which are neither created nor destroyed, η is determined from therequirement of particle number conservation:
N =
∫dg
e−η+E/kT ± 1= const.
This does not apply for photons in a black body environment which have η = 0.
Depending on η we can identify:
η � 1 highly degenerate systems−5 < η < 5 medium to weakly degenerate systems
η � −1 non-degenerate systems
(see below for explanation).
1.2.1 Momentum distributions of non-degenerate free particles
If η � −1, we have exp(−η + E/kT ) � 1 and consequently:
dN ∝ eηe−E/kT
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As the kinetic energy for free particles is:
E =1
2mv2 =
p2
2m=
p21 + p2
2 + p23
2m
and the number of quantum states within (E, E + dE) is:
dg = αd3xd3p
h3
we have:
dN =αd3xd3p
h3exp(− p2
2mkT)eη
Integrating yields:N =
α
h3eηV (2πmkT )3/2
which we can use to eliminate eη and to obtain the well-known Maxwell distribution :
dN =N
V· 1
(2πmkT )32
exp(− p2
2mkT) d3p dV
This is the energy distribution function of non-degenerate free particles in thermodynamicequilibrium.
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1.2.2 Criteria for the degeneracy of a free particle gas
We first define the following two parameters to simplify the discussion:Typical de Broglie wavelength λdeBroglie of a particle in a thermodynamical plasma:
λdeBroglie =h√
2πmkT
Mean particle separation ro:n = N/V = 1/r3
o
In the previous subsection we have shown that for large negative η:
η � −1 : eη =n
α
h3
(2πmkT )3/2
which can be rewritten as:
η = ln
(1
α
λ3deBroglie
r3o
)Therefore, η � −1 implies a large separation of the particles, in which case their quantumnature is not anymore relevant and we can treat them as classical particles.
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Degenerate systems in astrophysics are mostly fermionic . Then the Pauli principle ap-plies and the maximum phase space density is α/h3, i.e. one particle per phase spacecell.
For fermions we have for the energy (ε = p2/2m) distribution function:
f (ε) =[exp(−η +
ε
kT) + 1
]−1
=
[exp(
ε− µ
kT) + 1
]−1
where we have used η = µ/(kT ).
Complete degeneracy is approached if the system is cooled to temperatures which aremuch smaller than the chemical potential µ, i.e. η � 0 (see also figure below):
kT � µ (η � 0) : f (ε) →{
1 if ε < µ0 if ε > µ
In this case, µ is called the Fermi energy εF = µ, the corresponding momentum is calledthe Fermi momentum pF . εF is the energy of the most energetic electron in the system(remember: dU = TdS − PdV + µdN ).
We can determine η by requiring that the integral over the occupation numbers is N :
N =α
h3
∫ ∫1
exp(−η + p2
2mkT ) + 1d3pd3x
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If the distribution of momenta is isotropic and the particle distribution homogenous, thisyields:
n =N
V=
α
h3
∫ ∫1
exp(−η + p2
2mkT ) + 14πp2dp
Substituting x = p2/(2mkT ) we obtain:
n =α
h3
2
π1/2(2πmkT )3/2
∫x1/2dx
exp(−η + x) + 1
For strong degeneracy η � 1, 1/(exp(−η + x) + 1) canbe approximated by a step function (see figure) andthe integral simplifies to:∫
x1/2dx
exp(−η + x) + 1=
∫ η
0
x1/2dx =2
3η3/2
Solving for η and inserting λdeBroglie and ro we finally have:
η =1.21
α2/3
(λdeBroglie
ro
)2
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Therefore, η � 1, if ro � λdeBroglie. The quantum mechanical nature of particles cannot beneglected anymore if their separation is smaller than their typical de Broglie wavelength.
We can calculate the Fermi momentum pF from the fully degenerate case:
n =α
h3
∫ pF
o
n(p)4πp2dp =α
h3
4π
3p3
F
or:
pF = h
(3
α4π
)1/3
n1/3
The Fermi momentum is the highest particle momentum in case of infinite degeneracy.
Bottom line: (λdeBroglie/ro) determines the degree of degeneracy:
λdeBroglie
ro
{� 1 Fermigas� 1 Maxwell/Boltzmanngas
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1.2.3 Astrophysical examples of degenerate fermions
We consider a white dwarf, a neutron star and the sun, all at a mass of one solar mass.The mean densities and temperatures are
n =1
mp
M�4π3 R3
�, T ≈ 2 · 107 K
The ratio (λdeBroglie/ro) is:
R n(cm−3) λdeBroglie/ro
Electrons Protons/Neutrons
Sun 7 · 1010cm 8 · 1023 0.15 3.7 · 10−3
White Dwarf 1100R� 8 · 1029 15 0.37
Neutron Star 1.4 · 10−5R� 3 · 1038 – 27
Degree of degeneracy
Sun: ideal gas, Maxwell/BoltzmannWhite dwarfs: electrons degenerate, protons MaxwellNeutron star: neutrons degenerate
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1.3 The Planck distribution function for photons
Photons are bosons. Because their particle number is not conserved in thermodynamicequilibrium, we have η = 0 and, so, their distribution function is:
dN =dg
e−E/kT − 1
Considering that in full thermodynamical equilibrium the distribution of momenta is isotropicand that photons have two directions of polarization, we obtain for dg:
dg = 2 Vd3p
h3=
2V
h34πp2dp
Energies, momenta and frequencies of photons are related via:
E = hν, p =hν
c, dp =
h
cdν
Inserting yields the number density of photons in the frequency interval ( ν, ν + dν):
dn =dN
dV=
4π
c
2ν2
c2
1
ehν/kT − 1dν
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Multiplication with hν results in the energy density of photons in the frequency interval(ν, ν + dν):
Uνdν =4π
c
2hν3
c2
1
ehν/kT − 1dν
If we define the intensity Bν(T ) as the energy which flows through a unit surface persecond and per solid angle, we obtain for the relation between energy density and intensity(without derivation):
Uν =1
c
∫4π
Bνdω =4π
cBν
Bν(T ) is the Planck function of photons in thermodynamic equilibrium (black bodyradiation):
Bν(T ) =2hν3
c2· 1
ehν/kT − 1
Note: the frequency distribution of radiation of a system in thermodynamic equilibrium is
isotropic
homogeneous
independent of chemical composition of emitting material
only dependent on temperature
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For high and low frequencies we have:
Rayleigh-Jeans approximation
hν
kT� 1 ⇒ ehν/kT ≈ 1 +
hν
kT
⇒ Bν(T ) =2ν2
c2kT
Wien’s approximation
hν
kT� 1 ⇒ ehν/kT � 1
⇒ Bν(T ) =2hν3
c2e−hν/kT
Integration over frequency yields the Stefan-Boltzmann law for black body radiation :
B(T ) =
∫ ∞
0
Bν(T )dν = σBT 4
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1.4 Equations of state
For the Maxwell gas we have:
n(p) =1
(2πmkT )3/2e−
p22m
Using pv = p2/m, ε = p2/(2m) and the pressure equation from kinetic theory:
P =1
3
∫ ∞
0
p · v(p) n(p) 4π p2dp
we obtain:
P =1
3
∫ ∞
0
pvn(p)4πp2dp = nkT
and
Ukin =
∫ ∞
0
ε(p)n(p)4πp2dp =3
2nkT =
3
2P
For a non-relativistic degenerate Fermi gas we obtain analogously:
P =1
3
2
h3
4π
m
∫ pF
0
p4dp =1
3
2
h3
4π
m
1
5p5
F .
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(where pF is the Fermi momentum as defined above), or:
P =8π
15h2
(3
8π
)5/31
mn5/3 =
3
2Ukin
(calculation of Ukin not shown).
For very high densities, we get a relativistic degenerate Fermi gas , i.e. pF � m0c2.
We then have to use the relativistic ε(p): pv(p) = pc(1 − 1/2m0c2/p2) (taylor series of
square root) to get:
P =1
3
2
h34πc
∫ pF
0
p3
(1− m2
0c2
2p2
)dp,
yielding
P =2
3
π
h3c p4
F
(1− m2
0c2
p2
)=
1
3Ukin
(1 +
4m0c
3pF
).
Or, as a function of n:
P =2
3c h
(3
8π
)4/3
n4/3
(1− n−2/3 m2
0c2
h2(
38π
)2/3)
and
P =1
3Ukin
(1 + n−1/3 4m0c
3h(
38π
)1/3)
.
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Temperature density diagram, adapted from Phillips (see Bibliography)
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Summary: equations of state
Normal stars: P = nkT , ρ = µmpn, Ukin = 32P . (µ is the mean particle weight; it is
operationally defined via µ = ρ/(mpn)
White dwarfs: Degenerate electron gas supplies pressure, n = ne, ρ = µempne, µe = zµ,where z is the number of free electrons per atom.
non-relativistic degeneracy (ρ < 106gcm−3): P = A1ρ5/3, Ukin = 3
2P
relativistic degeneracy (ρ > 106gcm−3): P = A2(ρ4/3 −B2ρ
2/3), P = 13Ukin(1 + C2ρ
−1/3)
Neutron star: Degenerate neutrons supply pressure, n = nn, ρ = nmn, formulae likewhite dwarf, but with different coefficients A1, A2, B2 and critical density.
Photons: photons are bosons, therefore
n(p) = 2h3
1ehν/kT−1
Uphot = 4πc
∫Bν(T )dν ∝ T 4
Pphot = 13Uphot
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1.5 The Boltzmann formula
Consider free non-degenerate atoms with an excited electron. The energy of one atom Ais the sum of its kinetic energy plus the excitation energy Ei:
E =p2
A
2mA+ Ei
The number of quantum states within (E, E + dE) is:
dgA =d3xd3pA
h3gi
where gi is the degeneracy of the excited level (see below). Integrating over the distributionfunction gives:
Ni =
∫dNi =
gi
h3eηAe−Ei/kT
∫ ∫e−p2
A/(2makT )d3pad3x
= V(2πmAkT )3/2
h3eηAgie
−Ei/kT
or:
ni =Ni
V=
(2πmAkT )3/2
h3eηAgie
−Ei/kT
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where ni gives the number density of atoms with an electron in quantum state i. The
number density ratio of atoms in two different energy levels Ei and Ej is:
nj
ni=
gj
giexp
(−Ej − Ei
kT
)which is the famous Boltzmann-formula for the ratio of occupation numbers .
To obtain the number density nA,i of an atom or ion A in a quantum state i relative tothe number density nA of all atoms or ions A, we first have to calculate the sum over allquantum states, i.e. to derive the partition function :
ZA(T ) =
∞∑i=0
gA,i exp(−EA,i
kT)
With ZA we then have:nA,i
nA=
gA,i
ZA(T )exp(−EA,i
kT)
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1.6 The Saha equation
We now treat the simplest case of ionisation (bound-free transition) which is described by:
atom in ground state + photon ⇒ ionised atom in ground state + free electron
We have:
EA =p2
A
2mA= energy of atom
EI =p2
I
2mA+ Eion = kinetic energy plus ionization energy of ion
Ee =p2
e
2me= kinetic energy of electron
where we have approximated with very good accuracy: mI = mA. The number of states is:
dgA = gAd3pAd3x
h3dgI = gI
d3pId3x
h3dge = ge
d3ped3x
h3
As in the previous section, we integrate over the distribution function for each of these
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particles to obtain the particle number densites:
nA =NA
V= gA
(2πmAkT )3/2
h3eηA
nI =NI
V= gI
(2πmAkT )3/2
h3eηIe−Eion/kT
ne =Ne
V= 2
(2πmekT )3/2
h3eηe
where we have used ge = 2 for the two spin states of the electron. As energy is conserved,the chemical potentials have to fulfill the relation:
ηI + ηe − ηA = 0
(note that the chemical potential of photons vanishes). Therefore, the product nI · ne/nA
allows to eliminate all unknowns η and we obtain the Saha-Equation:
nI · ne
nA=
2gI
gA
(2πmekT )32
h3exp−Eion
kT
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1.7 Radiation: basic definitions
Definition of Intensity:Consider energy flowing through a small surface element. We then define the intensityas the energy per frequency dν per time dt per solid angle dω and per projected areacos θ dσ flowing through the surface into the direction θ, i.e. via:
d4Eν = Iν cos θdσdνdωdt
Iν = Intensity per frequencydσ = Surface of receiver at rdω = Solid angle within which
radiation is receivedθ, φ = Angles with respect to
the norm of dσν = frequencyt = Time
The intensity has the following properties:
dim [Iν] = erg cm−2 s−1 Hz−1 sterad−1
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Particle picture: Number of particles times hν per dνdω dt and per cos θ dσ
Wave picture: Absolute value of Poynting vectorIν does not depend on distance (in the absence of absorption and in Eucledianspace)
Proof: for the above geometry the amount of energy d4Eν passing through the leftsurface is exactly the amount of energy flowing through the right surface d4E ′
ν = d4Eν,we have:
d4Eν = Iν cos θdσdωdνdt
d4E ′ν = I ′ν cos θ′dσ′dω′dνdt
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The solid angles under which the area elements appear are:
dω = r−2 cos θ′dσ′
dω′ = r−2 cos θdσ
(r = distance between the surfaces) which we can insert above and obtain:
I ′ν = Iν
This is nothing else than the conservation of surface brightness!
Radiation flux density of a star:The energy flux through dσ in all directions is:
d3Eν =
∫4π
d4Eνdω
which with the definition of Iν yields:
d3Eν = dνdtdσ
∫4π
Iν cos θdω
One now defines the radiation flux density Fν as
Fν =
∫4π
Iν cos θdω
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This is an integral over the full sphere, i.e. it represents the net energy emitted throughthe area dσ (energy emitted minus energy received). For stars, the received energy canbe neglected.
Luminosity of a star:We obtain the luminosity per frequency of the star via multiplication with the wholesurface area (R = radius of the star):
Lν = 4π R2Fν
Further integration over dν gives the total luminosity:
L = 4π R2
∫ν
Fνdν
Effective temperature of a star:If a star emits approximately black body radiation, we can write for the total luminosityaccording to the Stefan-Boltzmann-law:
L = 4π R2 σBT 4eff
This is the defining equation for the effective temperature Teff . This equation implies:
σBT 4eff =
∫ν
Fνdν =
∫ν
∫4π
Iν cos θdωdν
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andFν = Bν =
∫4π
Iν cos θdω
where Bν is the Plank radiation law (see below) and σB = 5.67 · 10−5erg/s/cm2/K4 is theStefan-Boltzmann constant.
Flux of a star received on earth:The flux per frequency received on earth is the luminosity emitted per frequency devidedby the surface area of a sphere with a radius corresponding to the distance r betweenstar and earth:
fν =Lν
4π r2=
R2
r2Fν =
R2
r2Bν
where the latter equation only holds if the star emits black body radiation.
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1.8 Atomic and Molecular Transitions
Emission and absorption of photons occurs through processes in atoms, molecules, andsolid bodies. These processes are governed by Quantum Mechanics. We have a:
discrete spectrum of energy eigenvalues for bound electrons (E < 0)
continuous energy spectrum for free electrons (E > 0)
The following interactions between photons and electrons are possible (provided the quan-tum mechanical transition rules are fulfilled):
absorption
spontaneous emission
stimulated emission
wherby these transitions can occur between the following energy levels:
discrete-discrete (bound-bound) → spectral lines
discrete-continuous (bound-free) → ionization/recombination continua
continuous-continuous (free-free) → “Bremsstrahlung” (ion required!)
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1.8.1 Eigenvalues of hydrogen and H-like ions (only one e −)
The state of the electron is decribed by the following quantum numbers :n Main quantum number n = 1, 2, 3, ...l Orbital angular momentum l = 0, 1, 2, ..., n− 1ml z-component of orbital angular momentum ml = −l,−(l − 1), ..., l − 1, ls Electron spin s = ±1
2
Energy Eigenvalues (a0 = Bohr radius = 0.529 A)
En = − e2Z2
2a0n2
Balmer lines: n = 2 → n = 3, 4, 5, ... (Hα, Hβ, Hγ, ...)
Degree of degeneracy per energy eigenvalue
gn = 2
n−1∑l=0
(2l + 1) = 2n2
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1.8.2 Eigenvalues of atoms with more electrons
N(electrons) = 1
Alkali metalsElectrostatic shielding of nuclear potential
N(electrons) > 1
LS-coupling (spin-orbit � Coulomb)
~L =∑
~li, ~S =∑
~si, ~J = ~L + ~S
jj-coupling (spin-orbit � Coulomb)
~ji = ~li + ~si, ~J =∑
~ji
1.8.3 Eigenvalues of molecules
Molecular transitions important in interstellar medium and cool stars
transition through vibration (near IR) and rotation (submm, mm, radio)
Eel � Evib � Erot
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1.8.4 Probability of line transitions
The probability for a line transition l → u (u → l) through absorption (emission) of a photonwith frequency (ν, ν + dν) from (into) the solid angle (ω, ω + dω) is:
d2W spul = Aulϕ(ν)dν
dω
4π(spontaneous emission)
d2W stimul = BulIνϕ(ν)dν
dω
4π(stimulated emission)
d2W abslu = BluIνϕ(ν)dν
dω
4π(absorption)
where Aul, Bul, Blu are the Einstein Coefficients which are related via:
Aul =2hν3
c2
gl
guBlu
guBul = glBlu
with:h = Planck’s constantgl, gu = statistical weights of the levels l, u = degree of degeneracy
Aul needs to be derived with quantum mechanical methods.
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ϕ(ν)dν describes the probability for absorption or emission with frequencies (ν, ν+dν). ϕ(ν)is needed because emission and absorption lines are broadened. ϕ(ν) is normalized via:∫ ∞
−∞ϕ(ν) dν = 1
1.8.5 Line broadening
Lines are broadened because of:
Heisenberg’s uncertainty principle: the excited level has finite lifetime τnatural = 1/Aul
which implies an energy uncertainty (natural line width ) ∆E of:
∆E · τ ≥ h (Heisenberg′s Uncertainty Relation)
Using quantum mechanics we can derive the line profile which has the following shape:
ϕ(ν) = 2π−1 Aul/2
(ν − νc)2 + (Aul/2)2
This is called a damping or Lorentzian profile . In classical damping theory, an oscil-
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lating and radiating electron would have:
Aul =8π2e2
3mecλ20
where λ0 is the central wavelength of the line.
Thermal motion of atoms imply a Maxwell distribution of their velocities (in thermal equi-librium):
Π(vx, vy, vz) =( m
2πkT
)3/2
e−m
2kT (v2x+v2
y+v2z)
The Doppler-effect then causes a frequency distribution:
ϕ(ν) = π−1/2 1
∆νtherme−(
ν−νc∆νtherm
)2
with a thermal line width of:
∆νtherm =
√2kT
mAtom
Perturbations of the energy levels through electromagnetic interaction with neighbouringparticles (atoms, ions, electrons), Stark-effect. We have:
ϕ(ν) = 2π−1 γ/2
(ν − νc)2 + (γ/2)2
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where γ is now related to the life times τ via:
γ =1
τnatural+
1
τpressure
and the pressure induced line width is:
τpressure '1
particle density
The final broadening function ϕ(ν) is obtainted via convolution of this latter broadeningfunction with the thermal broadening function → Voigt profile :
ϕ(ν) =1√
π∆νD
α
π
∫ + ∞
− ∞
exp(−y)2dy
α2 + (x− y)2
α =1
4π
γ
∆νD
x =ν − νc
∆νD
Width of line core proportional toT 1/2 or particle velocity.
Width of wings proportional toparticle density.
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1.8.6 Interaction cross sections
Interaction cross sections for line transitions. The reaction probability dWlu for anatom to be excited by a parallel beam of radiation can be written as:
dWlu(ν) = σlu(ν) c nν(ν)dν
where σlu(ν) is the cross section for the reaction and c nν(ν)dν is the photon flux in(ν,ν + dν), i.e. the number density of photons in (ν,ν + dν) times the speed of light.c nνdν we can rewrite as
c nνdν = cdE/(hν)
c dt dA=
dE
hν dt dA
where c dt dA is the volume element we consider and of which dA is chosen to be thesurface element perpendicular to the direction of radiation. Using the definition of theintensity (for a parallel beam there is no dω) and taking into account dA = dσ cos θ weobtain:
c nν =Iν
hνComparing this with the initially given definition of dWlu, we finally arrive at:
σlu =hν
4πBlu ϕ(ν)
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Interaction cross sections for bound-free transitions. Be νl the frequency corre-sponding to the ionization energy. Then, in case of hydrogen, we can use the Kramersapproximation for the interaction cross section:
ν < νl : σbf(ν) = 0
ν ≥ νl : σbf(ν) = const. (ν/νl)3
For more complex ions higher order terms in (ν/νl) are needed as well. As for linetransitions, there exist again simple relations between the cross sections for absorption,stimulated emission and spontaneous emission.
Interaction cross sections for free-free transitions (Bremsstrahlung).This cross section depend also on the velocities of the free electrons. We have:
σff =const.
ν3
∫gff(ν, v)
vdne(v)
where ne is the electron density per velocity interval and gff is the Gaunt-factor, aquantum-mechanical correction to the Kramers-approximation.
Note: If thermodynamical equilibrium holds, we know from Wien’s law that the maximumor typical frequency of the photons is proportional to the temperature ν ∝ T . Therefore,we expect that the opacities κ ∝ nσ (see below) for bound-free or free-free transitionsdecrease with the same power of the temperature as the power of the frequency, i.e.
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∝ T−3. Modifications from this simple expectation are introduced because, e.g., theionization changes as a function of temperature. Therefore, the opacity for bound-freeand free-free transitions actually shows κ ∝ ρT−3.5.
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1.9 Other Emission and Scattering Processes
1.9.1 Rayleigh Scattering
Interaction of bound electrons with low-energy photons.
Absorption or emission of a photon can be described as a resonance effect, with theinteraction cross section σ being:
σ(ν) ∝ ν4
(ν2 + ν2o)
2or for ν � νo : σ(ν) ∝ ν4
ν4o
where hνo corresponds to the energy of the line tranisition.
Even if a photon has a frequency much lower than ν � νo, there is still a small chanceof interaction. The scattering part of the interaction is called → Rayleigh scattering .For hydrogen, the Rayleigh cross section per atom is (now in wavelength λ):
σR =8πe4
3m2ec
4
(1026A)4
λ4
The reference wavelength does not just correspond to Lyα (1215A) or the Lyman limit(912A) because all Lyman lines contribute to the scattering.
Rayleigh scattering is the origin of the blue sky.
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1.9.2 Thomson Scattering
Interaction of free electrons with low-energy photons
This corresponds to a ’resonance’ with νo = 0. Therefore we have:
σT =8πe4
3m2ec
4= 6.6652 · 10−25cm2
Note: The Thomson cross section roughly corresponds to the radius at which the elec-trostatic potential of the electron equals its mass.
A better approximation for low energies is obtained from an expansion of the Klein-Nishina formula:
σ(ν) = σT (1− 2α + (56/5)α2 + ...) with α =hν
mec2
Important for IR, optical, UV radiation in:
Stellar atmospheres, stellar coresInterstellar and intergalactic gasQuasarsBig Bang (coupling of photons and matter before recombination)
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1.9.3 Compton Scattering
Interaction of free electrons with high-energy photons
An expansion of the Klein-Nishina formula in this case is:
σ(ν) = σT3
8α(ln(2α) +
1
2) with α =
hν
mec2
i.e.
0 < σc < σT ∀ hν
mec2
Compton scattering is important for
Extremely hot gasX-ray and γ quanta
Interaction of high-energy free electrons with low-energy photons is called inverseCompton effect .
X-ray production in jets and active galaxiesSunyaev-Zeldovich effect(scattering of the 3K radiation at X-ray gas of galaxy clusters)
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1.9.4 Synchrotron Radiation
Relativistic electrons
E = mc2 = m0c2γ � m0c
2 = 0.51 MeV
γ =1√
1− v2/c2
gyrate in a homogeneous magnetic field ~B. As they are accelerated in this process,they emit radiation. Low-energy electrons emit cyclotron radiation, relativistic electronsemit synchrotron radiation .
The radiation is emitted tangentially in a tight cone with apex angle θ
θ =m0c
2
E=
1
γ=
√1− v2
c2
Because there is a preferred plane of gyration perpendicular to the magnetic field, syn-chrotron radiation is highly polarized. The polarization is perpendicular to the magneticfield direction.
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The observer sees a series of short flashes, implying a broad energy distribution. Thepeak of the spectrum is at:
νsync = 0.069eB⊥
meγ2
For a power-law distribution of electron energies (as e.g. observed in the cosmic rayenergy distribution):
N(E)dE = E−pdE
we obtain a volume emissivity (see below for exact definition) of radiation:
ε(ν) ∝ B(p+1)/2⊥ ν−(p−1)/2
Synchrotron radiation is observed, e.g., in
Neutron stars → rotating magnetosphereSupernova remnantsSpiral galaxies → galactic magnetic fieldsGalaxy clustersActive galactic nuclei, jets
Synchrotron radiation is a typical form of non-thermal radiation.
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1.10 Radiative Transfer
1.10.1 Absorption coefficient
The intensity Iν changes, when a light beam passes through matter. Photons can beabsorbed, emitted and scattered.
We expect that the reduction in intensity dIν will be proportional to the intensity Iν itself andproportional to the path length ds through the material (this may not be correct for very highintensities!). Therefore, we define the absorption or opacity coefficient via:
dIν = −κν Iν ds
The inverse of the absorption coefficient is proportional to the mean free path of aphoton. Furthermore, as discussed above the probability for absorption of a photon by asingle atom in state l is:
d3 Wabs = Bluϕ(ν)Iνdνdωdt
If we have nl atoms per volume in level l, we obtain for the number of photons d N absγ
absorbed in the volume dV = dσ · ds along the beam:
d N absγ = nl · d3Wabs · dV = nl ·Bluϕ(ν)Iνdνdωdtdσds
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Therefore, the intensity is reduced by:
−dIν =Absorbed Energy
dνdωdtdσ=
hν · dN absγ
dνdωdtdσ= nl
hν
4πBluϕ(ν)Iνds
i.e.
κν = nlhν
4πBluϕ(ν) = nlσlu
where we have used σlu = hν4π Blu ϕ(ν). This equation relates the absorption coefficient to
the microphysical cross section. Including also stimulated emission we have
κν =hν
4πϕ(ν) (nlBlu − nuBul)
or, because of guBul = glBlu we can also write:
κν =hν
4πϕ(ν) Blu(nl − nu
gl
gu) = σlu (nl − nu
gl
gu)
If we generalize to all other bound-bound, bound-free and free-free absorption of all ele-ments, and include Thomson scattering, we obtain a formula like:
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κν =∑
α
∑β
{∑γ
[nα,β
γ σα,βbf,γ
(1− bα,β
γ e−hνkT
)bound− free
+∑δ>γ
(nα,β
γ −gα,β
γ
gα,βδ
nα,βδ
)σα,β
γ,δ
]lines
+ nα,β+1i ne σα,β
ff
[1− e−
hνkT
]}free− free
α = Elementsβ = Degree of ionizationγ = Levels within degree of ionizationδ > γ = Levels above γnα,β
γ = Occupation numbersσα,β
γ = Absorption cross sectionsgα,β
γ = Statistical weights of levelsne = Number density (cm−3) of free electrons
bα,βγ =
nα,βγ (NLTE)
nα,βγ (LTE)
≈ 1 (see below)
negative terms = stimulated emission
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Modern astrophysics takes millions of lines and several 10, 000 bound-free and free-freetransitions into account considering almost all elements in all levels of ionization.
Important absorption processes in cool stars (Teff ≤ 8000 K) are:
H−: bound-free/free-freeHI, AlI, MgI: bound-freeHI and all neutral elements: linesH2, CH, NH, OH, CO, C2, CN (diatomic molecules): bound-free/free-free/lines
Important absorption processes in hot stars (Teff > 8000 K) are:
H,HeI,HeII, abundant metal ions: bound-free, free-freeFree electrons: Thomson scatteringAll ions: lines
Because the occupation numbers nα,βγ enter, κν is a function of temperature and density:
κν(T, ρ). For not too large ranges in temperature and density, one can usually separate(see above, relation etween κ and cross section):
κν = ρ1...2κν(T )
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κ/ρ (in m2/nucleon) against λ in nm for the sun (T = 5000K) and τ Sco (T = 28000K).
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1.10.2 Emission Coefficient
Spontaneous emission enhances the intensity of radiation or can be the sole source ofradiation. Spontaneous emission rquires atoms or ions to be in excited states, i.e. they arein a hot plasma or exposed to radiation. We define the emission coefficient via:
dIν = εν ds
Note: dIν is independent of Iν because spontaneous emission does not depend on theincident radiation as stimulated emission (which was therefore included above with theextinction coefficient)
Because of the general Einstein relations between cross sections σabs and σspont, we have
εν =2hν3
c2
∑α
∑β
∑
γ
nα,βγ bα,β
γ σα,βγ e−
hνkT︸ ︷︷ ︸
bound−free
+∑δ>γ
nα,βδ
gα,βγ
gα,βδ
σα,βγ,δ︸ ︷︷ ︸
lines
+ nα,β+1i neσ
α,βff e−
hνkT︸ ︷︷ ︸
free−free
Therefore we have here as well: εν = εν(ρ, T ).
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1.10.3 Radiative Transfer Equation
Taking into account absorption, stimulated and spontaneous emission as processes reduc-ing or adding intensity, we finally write the Equation of Radiatve Transfer :
dIν = −κνIνds︸ ︷︷ ︸absorption
+ ενds︸︷︷︸emission
ordIν
ds= −κν Iν + εν
This an inhomogeneous 1st order differential equation which can be solved straightfor-wardly as long as κ and ε are known as a function of density, temperature and chemicalcomposition and are not dependent on Iν (as in case of a Laser or the absence of thermo-dynamical equilibrium).
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To solve the equation, we introduce the opti-cal depth τν defined via:
dτν = κν ds or τν =
∫ s
0
κνds′
We rewrite the equation of raditative transfer as:
dIν
dτν+ Iν =
εν
κν= Sν
where Sν is called the source function . We then multiply by exp(τν) and obtain:(dIν
dτν+ Iν
)eτν =
εν
κνeτν
which is equivalent to:d
dτν(eτνIν) =
εν
κνeτν
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of which integration yields:
eτν · Iν − I0ν =
∫ τν
0
εν
κνeτ ′νdτ ′ν
or by multiplication with exp(τν):
Iν = I0ν e−τν︸ ︷︷ ︸
absorption
+
∫ τν
0
εν
κνe−(τν−τ ′ν)dτ ′ν︸ ︷︷ ︸
emission
This relation can be explained as follows:I0ν is the radiation falling onto a plane-parallel sheet of plasma with an optical depth of τν.
What remains from this incident radiation after the sheet has been crossed is I0ν e−τν . On the
other hand, the sheet emits radiation itself. At each position along the ray, ενκν
is contributed.This contribution is however again reduced by the optical depth of the remaining path tothe edge of the sheet, i.e. by τν − τ ′ν.
We conclude that:
Radiation cannot penetrate areas with τν � 1
If we observe a radiating object, we cannot receive emission from regions with τν � 1(τ measured inward from the surface of the object).
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For several layers of gas at different temperature (stellar atmosphere!), the observedintensity reflects the temperature at τ ≈ 1, because τ ≈ 1 corresponds to the mean freepath of the photons.
In summary we have:
dIν = −κνIνds + ενds Equation of radiative transfer
τν =∫ s
0 κνds′ Optical depth or optical path
Sν = εν/κν Source FunctiondIνdτν
= −Iν + Sν Equation of radiative transfer
Iν = I0ν e−τν +
∫ τν
0ενκν
e−(τν−τ ′ν)dτ ′ν Integral of eq. of radiat. transf.
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1.11 Thermodynamical equilibrium and radiative transfer
In prefect radiative equilibrium, we have Iν = Bν(T ) and the radiation field is isotropic andhomogenous, i.e. we also have dIν/ds = 0. Under these conditions, the radiative transferequation reduces to Kirchhoff’s law :
Sν(T ) =εν
κν= Bν(T ) =
2hν3
c2
1
ehν/kT − 1
In principle, only a closed system can be in thermodynamic equilibrium. Therefore, radia-tive systems, like stars, can never be in a complete global thermodynamic equilibrium .Nevertheless, stellar interiors and many other systems are in approximate local thermo-dynamical equilibrium (LTE) if the following two conditions hold:
Elastic collisions of particles are efficient in establishing a Maxwell velocity distributionwith a single local kinetic temperature.
Inelastic collisions are more frequent than radiative absorption and emission processesand determine the occupation numbers of ionized states and energy levels. This is thecase, if the particle density is high enough (see section on LTE below).
Because it does not matter whether the equilibrium occupation numbers are established
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via photons or particles, the occupation numbers can be calculated with the Boltzmannand Saha formulae using the local kinetic temperature. Consequently the radiation emittedin the small volume in LTE also follows a Planck law and we have Sν = Bν(T ) = εν/κν,i.e. again Kirchhoff’s law. The total local distribution function of photons is however notdetermined by the local temperature:
dIν
ds6= 0 ⇒ Iν 6= Bν(T )
but by the local radiative transfer equation:
dIν
ds= −κν (Iν −Bν(T (s)))
At any frequency, depending on the difference between incident radiation and locally emit-ted black body radiation, the intensity either decreases or increases when passing throughthe small volume in LTE.
In the theory of stellar atmospheres, LTE is usually assumed (but see exceptions discussedlater). As already indicated, this assumption does not mean that we assume completethermodynamic equilibrium, it only means that we assume that the emission is black-body-radiation of a temperature corresponding to the kinetic temperature of the particles. Evenif the incident radiation is concentrated in one line, LTE implies that the radiation emittedwithin a small volume follows Bν(T ).
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1.12 Emission and absorption line spectra
We now discuss under which conditions we will observe emission and absorption line spec-tra. We consider a box of length s filled with hot gas and located in front of a light sourcewith intensity distribution I0
ν . We integrate the equation of radiative transfer through the box:
Iν = I0ν e−τν +
∫ τν
0
Sν(T )e−(τν−τ ′ν)dτ ′ν
and obtain (as above):Iν = I0
ν e−τν + Sν(T )(1− e−τν)
or:Iν = I0
ν e−τν + Bν(T )(1− e−τν) in LTE
where τν is the optical depth through the hot gas at frequency ν and Sν is its source function.
Four limiting cases illustrate what this equation implies:
I0ν → 0, τν � 1, LTE, i.e. the gas is in LTE but optically thin, and the background
illumination is negligible. Expansion of the exponent in a Taylor series results in:
Iν = τνBν = κνsBν
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This means that the gas will show strong (weak) emission where κν is large (small).At frequencies corresponding to line transitions between discrete energy levels of theatoms or ions of the gas, κν is large and we will see a characteristic emission linespectrum . Astrophysical examples for this situation are: stellar winds, star formationregions, and active galactic nuclei.
I0ν → 0, τν � 1, i.e. the gas is in LTE and optically thick, and the background
illumination is negligible. This reduces the equation to:
Iν = Sν or Iν = Bν in LTE
The gas in the box emits a featureless black body spectrum . Here an astrophysicalexample is the cosmic microwave background.
I0ν 6= 0, τν � 1, i.e. the gas is optically thin, and it is illuminated by a background
source. We have:Iν = I0
ν (1− τν) + Sντν = I0ν − κνs(I0
ν − Sν)
⇒ Iν ↓ for Sν < I0ν
Iν ↑ for Sν > I0ν
If we have Bν = Sν < I0ν and κν is large because the frequency correponds to a line
transition in the gas, we evidently obtain an absorption line (astrophysical examples:stellar atmospheres, interstellar medium in front of a star, intergalactic gas in front of aquasar).
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On the other hand, if Bν = Sν > I0ν and, again, κν is large because the frequency
correponds to a line transition in the gas, we will see an emission line on top of thebackground spectrum. Stellar coronae are example of this phenomenon.
I0ν 6= 0, τν � 1, i.e. the gas is optically thick, and it is illuminated by a background
source. Here we have again, as in the second case:
Iν = Sν
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1.13 Validity of Local Thermodynamical Equilibrium
In almost all plasmas (except very thin ones with magnetic fields), the Maxwell distributionis valid. The validity of Saha and Boltzmann formulas on the other hand depend on theratio of photon number density uphoton to particle number density uparticles
uphoton =4π
c
∫ ∞
0
Bνdν =4
cσBT 4
uparticle =3
2nkT
uphotons
uparticles= 36.5 · T 3/K3
n/cm−3
� 1 LTE∼ 1 LTE questionable� 1 Non− LTE
ncrit = 36.5 · T 3 is the limiting relation for which uphotons = uparticles.
If a system is in Non-LTE the population of energy levels and ionization states needs tobe calculated explicitly on the basis of the radiation field and collisions. The Boltzmannand Saha equations cannot be used anymore. Radiative transfer in this case requires thesolution of non-linearly coupled differential equations implying a significant numerical effort.
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LTE LTE questionable Non-LTE
Stellar atmospheres(n = 1013...1016 cm−3)for Teff ∼ 25000 K
Stellar cores
Atmospheres ofsuper-giants(n = 1010...1013 cm−3)
Outer atmospheres(chromosphere,coronae)
Stellar winds
Interstellar medium
Intergalactic medium
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