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### Transcript of AP Physics Mr. Jean November 8 th, 2011. Problems: A segment of steel railroad track has a length of...

• Slide 1
• AP Physics Mr. Jean November 8 th, 2011
• Slide 2
• Problems: A segment of steel railroad track has a length of 30.000m when the temperature is at 0.0 o C. What is its length at 40.0 o C? Helpful Hint: = 11 x 10 -6 ( o C) -1
• Slide 3
• Solution: L f = L i + L e L f = 30.000m + 0.013m L f = 30.013m Full solution on p.540 Serway & Jewett
• Slide 4
• Kinetic Theory: Temperature and pressure are macroscopic properties of gases. These properties are related to molecular motion, which is a microscopic phenomenon. The kinetic theory of gases correlates between macroscopic properties and microscopic phenomena. Kinetics means the study of motion, and in this case motions of gas molecules. At the same temperature and volume, the same numbers of moles of all gases exert the same pressure on the walls of their containers. This is known as Avogadros principle. His theory implies that same numbers of moles of gas have the same number of molecules. Common sense tells us that the pressure is proportional to the average kinetic energy of all the gas molecules. Avogadros principle also implies that the kinetic energies of various gases are the same at the same temperature. The molecular masses are different from gas to gas, and if all gases have the same average kinetic energy, the average speed of a gas is unique.
• Slide 5
• Kinetic Theory: Ideal Gas Law PV = nRT P = pressure V = Volume n = Number of moles R = Atomic constant T = Temperature
• Slide 6
• Thought Question A common material for cushioning objects in packages is made by trapping Bumbles of air between sheets of plastic. This material is more effective at keeping the contents of the package from moving around inside when. A) On a hot day B) On a cold day C) Either hot or cold days
• Slide 7
• Question: A spray can containing a propellant gas at twice atmospheric pressure (202 kPa) and having a volume of 125cm 3 is at 22 o C. It is tossed into an open fire. When the temperature reaches 195 o C what is the pressure in the can? Assume NO volume change. Assume Ideal Gas.
• Slide 8
• Solution: Ideal Gas Law PV = nRT No air escapes during the compression, so that nR remain constant. Thus we can eliminate them from both sides of the equation. P i V i = P f V f T i T f
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• Solution: P f = (T f / T i ) P i P f = 320 kPa
• Slide 10
• Thought Question: In air, the molecular mass of oxygen molecules is 32 g/mol; the molecular mass of nitrogen molecules is 28 g/mol. Which molecules are traveling faster on average? a. a.Oxygen b. b.Nitrogen c. c.Same speed
• Slide 11
• Equipartition Theorem The total kinetic energy of a system is shared equally among all of its independent parts, on the average, once the system has reached thermal equilibrium. independent: e.g. x, y, z (for translational KE) parts: translational, rotational, vibrational Specifically, each degree of freedom, of each molecule, has thermal energy of k B T
• Slide 12
• Thermal energy (measured by k B T) must be comparable to the quantum energy levels, or some degrees of freedom get frozen out From section 21.4: diatomic hydrogen Y-axis: heat added, divided by temperature change (per mole) Units: J/mol K
• Slide 13
• Translational KE: Calculate the average kinetic energy of one nitrogen molecule at 300K? Hint: Ek = 3/2 (RT) Mr.Cooper should have given you this equation by now.
• Slide 14
• Solution Assume nitrogen behave as an ideal gas, then Ek = 3/2 R T = (3/2) 8.3145 J/(mol K) * 300 K = 3742 J / mol (or 3.74 kJ/mol)
• Slide 15
• Molecular View of Pressure, cont. Result for v instead of v x : a. a.P = N m v 2 / V What does PV equal? Compare to: PV = N k B T What does T equal?
• Slide 16
• Question: Which molecules have the most kinetic energy? a. a.The heavy ones b. b.The light ones c. c.Same Which ones have the fastest average velocity?