1. Menghitung Volume

a. Volume Bola

V = 4/3 π r3

= 4/3 (3,14) (12,7)3

= 4/3 (6431,9)

=8575,9 mm3

b. Volume Balok

V = p x l x t

= 31,1 x 22,9 x 15,65

= 7561,9 mm3

c. Volume Kubus

V = s x s x s = s3

= 23,53

= 12977,9 mm3

2. Menghitung Luas Permukaan

a. Luas Permukaan Bola

L = 4 π r2

L = 4 (3,14) (12,7)2

L =2025,8 mm2

b. Luas Permukaan Balok

L = 2(p x l) + 2(l x t) + 2(p x t)

L = 2(31,1 x 22,4) + 2(22,4 x 15,65) + 2(31,1 x 15,65)

L = 3181,9 mm2

c. Luas Permukaan Kubus

L = 6 x S2

L = 6 x 23,52

L = 3321,9 mm2

3. Menghitung Selisih Massa ∆M

Rumus : ∆M = Wo - W

a. Sampel Bola = 18,613 – 17,43 = 1,183 gram

b. Sampel Balok = 21,401 – 19,75 = 1,651 gram

c. Sampel Kubus = 25,042 – 23,54 = 1,502 gram

4. Menghitung persen reduksi CaCO3

Rumus : %R = Wo – W x 100%

Wo

a. Sampel bola

Wo = Massa CaCO3 = 18,613 gram

W = Massa CaO = 17,43 gram

R = 18,613 – 17,43 x 100% = 6,356%

18,613

b. Sampel Balok

Wo = Massa CaCO3 = 21,401 gram

W = Massa CaO = 19,75 gram

R = 21,401 – 19,75 x 100% = 7,715%

21,401

c. Sampel kubus

Wo = Massa CaCO3 = 25,042gram

W = Massa CaO = 23,54 gram

R = 25,042 – 23,54 x 100% = 5,998%

25,042

5. Menghitung PCO₂

T = 900⁰C = 1173 K

ΔG⁰T = 40.250 – 34,4 T

ΔG⁰T = 40.250 – 34,4 (1173 K)

= 40.250 – 40.351,2

= -101,2 K/mol

∆GoT = -RT ln K

K = [ CaO] [CO2]

[CaO]

K = [CO2]

K = PCO₂

∆GoT = -RT ln K

∆GoT = -RT ln PCO₂

-101,2 = - 8,314 (1173) ln K

ln K = -101,2

8,314 x 1173

ln K = 0,014

K = 1,044

PCO₂ = 1,044 atm