Physical Measures
Stefano LuzzattoAbdus Salam International Centre for Theoretical Physics
Trieste, Italy.
International conference on Dynamical SystemsHammamet, TunisiaSeptember 5-7, 2017
Let f : M →M . For x ∈M let O+(x) := {fn(x)}n∈N be the orbit of x.Define a sequence of probability measures
µn(x) :=1
n
n−1∑
i=0
δf i(x)
Question: Does µn(x) converge?
Example (Convergence)
1 fn(x)→ p implies µn(x)→ δp2 µ ergodic invariant implies µn(x)→ µ for µ a.e. x (Birkhoff).
Example (Non-Convergence - Bowen’s eye)
∃ subsequences ni, nj such that µni(x)→ δp1 and µnj (x)→ δp2
Stefano Luzzatto (ICTP) 2 / 14
Let µ be a probability measure. The basin of µ is
Bµ := {x ∈ X : µn(x)→ µ}.
Definition
µ is a physical measure if Leb(Bµ) > 0.
Example (Physical measures)
1 δp where p is an attracting fixed point;
2 µ invariant, ergodic, and µ� Leb (µ(Bµ) = 1⇒ Leb(Bµ) > 0);
3 Sinai-Ruelle-Bowen (SRB) measures.
Example (No physical measures)
1 The identity map;
2 Bowen’s eye.
Conjecture (Palis conjecture)
Typical systems have (finitely many) physical measures.
Stefano Luzzatto (ICTP) 3 / 14
Conjecture (Palis conjecture)
Typical systems have (finitely many) physical measures.
Definition (Hyperbolicity)
A measurable invariant set Λ ⊂M is (nonuniformly) hyperbolic if:
1 there exists an invariant measurable splitting TxM = Esx ⊕Eux s.t.
limn→±∞
](Esfn(x), E
ufn(x)
)= 0
2 there exists χ > 0 such that for every vs ∈ Esx, vu ∈ Eux we have
limn→±∞
1
nln ‖Dfnx (vs)‖ < χ and lim
n→±∞
1
nln ‖Dfnx (vu)‖ > χ.
Λ is uniformly hyperbolic if the splitting is continuous, ](Esx, Eux) is
uniformly bounded, and 1/n ln ‖Dfnx (vs/u)‖ converge uniformly in x.
Conjecture (Viana conjecture)
Hyperbolic systems have (finitely many) physical measures.
Stefano Luzzatto (ICTP) 4 / 14
Existence of SRB physical measures in higher dimensions:
1 Eu uniform, Es uniform, splitting continous.Sinai-Ruelle-Bowen, 1960’s-1970’s
2 Eu uniform, Es non-uniform, splitting continous.Pesin-Sinai, Erg. Th. & Dyn. Syst. 1982Bonatti-Viana, Israel J. Math. 2000
3 Eu non-uniform, Es uniform, splitting continous.Alves-Bonatti-Viana, Inv. Math. 2000Alves-Dias-L-Pinheiro, J. Eur. Math. Soc. 2015
4 Eu non-uniform, Es trivial (non-uniformly expanding)Alves-L.-Pinheiro, Ann. IHP, 2005Alves-Dias-L. Ann. IHP, 2013
5 Es, Eu non-uniform, splitting measurable.Climenhaga-Dolgopyat-Pesin, Comm. Math. Phys. 2017Climenhaga-L.-Pesin, In progress, 2017
Remark: most results assume implicitly or explicitly additionaltechnical conditions including recurrence assumptions.
Stefano Luzzatto (ICTP) 5 / 14
Three methods for construction of SRB physical measures:
1 Symbolic coding and thermodynamical formalism;
2 Pushing forward Lebesgue measure;
3 Inducing (+ combination of previous two).
Inducing: Let Γ ⊂M , τ : Γ→ N a return time s.t. f τ(x)(x) ∈ Γ. Then
f := f τ : Γ→ Γ
is the corresponding induced map. The induced map f may havebetter properties than the original map f and may be easier to study.In particular we may be able to show that f admits an SRB measure.
Proposition
Suppose f : Γ→ Γ admits an SRB probability µ and τ :=∫τdµ <∞.
Then f admits an SRB probability measure.
Problem:find GOOD induced map with INTEGRABLE return times
Stefano Luzzatto (ICTP) 6 / 14
Example: Pomeau-Manneville maps: Let γ ≥ 0 and
f(x) = x+ x1+γ mod 1.
For γ = 0, f(x) = 2x mod 1 and Lebesgue is ergodic and invariant.For γ > 0, f ′(x) = 1 + (1 + γ)xγ and so f ′(0) = 1.Since 0 is a fixed point, f is not uniformly expanding and we cannotapply any existing methods to construct physical measures.
The inducing time is integrable if and only if γ ∈ [0, 1).Stefano Luzzatto (ICTP) 7 / 14
Example: Anosov DiffeomorphismΓ = element of the Markov partition; τ = first return time
fk fk
fk
fn
fk
fn
F = f τ : Γ→ Γ is a Young Tower and therefore ∃ µ SRB for F .Moreover, τ integrable and therefore ⇒ µ SRB for f .
Similar construction without a priori Markov partitions (Young ’98)
Stefano Luzzatto (ICTP) 8 / 14
Definition (Rectangle)
Let Λ be a hyperbolic set. A set Γ ⊂ Λ is a rectangle if for everyx, y ∈ Γ, the intersection V s
x ∩ V uy is a single point which belongs to Γ.
P
Q
Wu(P)
Ws(Q) Ws(P)
Wu(Q)
R
Γ = CS ∩ CU where CS =⋃
x∈Γ
V s(x), CU =⋃
x∈Γ
V u(x)
In general Γ is a Cantor set so the Young Tower is harder to get.
Stefano Luzzatto (ICTP) 9 / 14
P
Q
Wu(P)
Ws(Q) Ws(P)
Wu(Q)
R
We let Γ denote the region bounded by V sp , V
up , V
sq , V
uq .
Definition
A rectangle Γ is
1 nice if f i(V sp/q) ∩ intΓ = ∅ and f−i(V u
p/q) ∩ intΓ = ∅ ∀i > 0.
2 recurrent if every x ∈ Γ returns to Γ;
3 fat if Leb(∪x∈Γ0Vsx ) > 0.
Stefano Luzzatto (ICTP) 10 / 14
Definition
A rectangle Γ is
1 nice if f i(V sp/q) ∩ intΓ = ∅ and f−i(V u
p/q) ∩ intΓ = ∅ ∀i > 0.
2 recurrent if every x ∈ Γ returns to Γ;
3 fat if Leb(∪x∈Γ0Vsx ) > 0.
Theorem (Climenhaga-L-Pesin)
Let f : M →M be a C2 surface diffeomorphism with a
1 hyperbolic set Λ ⊆M , and a
2 nice recurrent rectangle Γ ⊆ Λ.
Then there exists a Topological First Return Young Tower.
If Γ is fat then this Topological Young Tower satisfies hyperbolicity anddistortion estimates and f admits an SRB probability measure.
Stefano Luzzatto (ICTP) 11 / 14
Definition (Hyperbolic branch)
A hyperbolic branch f i : Cs → Cu is a stable strip that gets mappedto an unstable strip with uniformly hyperbolic estimates.
p
bCS
bCU
q
b�0
Stefano Luzzatto (ICTP) 12 / 14
Definition (Hyperbolic recurrence)
A rectangle Γ is hyperbolically recurrent if every return to Γ givesrise to a hyperbolic branch.
Theorem
Let Γ0 ⊆ Λ be a nice recurrent rectangle.Then Γ0 is a nice hyperbolically recurrent rectangle.
Definition (Saturation)
A hyperbolically recurrent rectangle Γ = Cs ∩ Cu is saturated if forevery hyperbolic branch f i : Cs → Cu we have
f−i(Cu ∩ Cs) ⊂ Cs and f i(Cs ∩ Cu) ⊂ Cu.
Theorem
Let Γ0 be a nice hyperbolically recurrent rectangle.Then there is a nice hyperbolically recurrent saturated rectangle Γ.
Stefano Luzzatto (ICTP) 13 / 14
Theorem
Let Γ be a nice hyperbolically recurrent saturated rectangle.Then Γ admits a First Return Topological Young Tower.
Theorem
Let Γ be a fat nice hyperbolically recurrent saturated rectangle.Then Γ admits a First Return Young Tower.
Theorem
Let Λ be a hyperbolic set.Let Γ ⊂ Λ be a fat nice hyperbolically recurrent saturated rectangle.Then Γ admits a Young Tower with Integrable Return Times.
Stefano Luzzatto (ICTP) 14 / 14
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