1. Menghitung Volume
a. Volume Bola
V = 4/3 π r3
= 4/3 (3,14) (12,7)3
= 4/3 (6431,9)
=8575,9 mm3
b. Volume Balok
V = p x l x t
= 31,1 x 22,9 x 15,65
= 7561,9 mm3
c. Volume Kubus
V = s x s x s = s3
= 23,53
= 12977,9 mm3
2. Menghitung Luas Permukaan
a. Luas Permukaan Bola
L = 4 π r2
L = 4 (3,14) (12,7)2
L =2025,8 mm2
b. Luas Permukaan Balok
L = 2(p x l) + 2(l x t) + 2(p x t)
L = 2(31,1 x 22,4) + 2(22,4 x 15,65) + 2(31,1 x 15,65)
L = 3181,9 mm2
c. Luas Permukaan Kubus
L = 6 x S2
L = 6 x 23,52
L = 3321,9 mm2
3. Menghitung Selisih Massa ∆M
Rumus : ∆M = Wo - W
a. Sampel Bola = 18,613 – 17,43 = 1,183 gram
b. Sampel Balok = 21,401 – 19,75 = 1,651 gram
c. Sampel Kubus = 25,042 – 23,54 = 1,502 gram
4. Menghitung persen reduksi CaCO3
Rumus : %R = Wo – W x 100%
Wo
a. Sampel bola
Wo = Massa CaCO3 = 18,613 gram
W = Massa CaO = 17,43 gram
R = 18,613 – 17,43 x 100% = 6,356%
18,613
b. Sampel Balok
Wo = Massa CaCO3 = 21,401 gram
W = Massa CaO = 19,75 gram
R = 21,401 – 19,75 x 100% = 7,715%
21,401
c. Sampel kubus
Wo = Massa CaCO3 = 25,042gram
W = Massa CaO = 23,54 gram
R = 25,042 – 23,54 x 100% = 5,998%
25,042
5. Menghitung PCO₂
T = 900⁰C = 1173 K
ΔG⁰T = 40.250 – 34,4 T
ΔG⁰T = 40.250 – 34,4 (1173 K)
= 40.250 – 40.351,2
= -101,2 K/mol
∆GoT = -RT ln K
K = [ CaO] [CO2]
[CaO]
K = [CO2]
K = PCO₂
∆GoT = -RT ln K
∆GoT = -RT ln PCO₂
-101,2 = - 8,314 (1173) ln K
ln K = -101,2
8,314 x 1173
ln K = 0,014
K = 1,044
PCO₂ = 1,044 atm
Top Related