· Web viewAnswers of Assignment #4 1. 0.174μF 2. V s =20.375∟1.850, η=95.86%3. A=D=...

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Answers of Assignment #4 1. 0.174μF 2. V s =20.375 1.85 0 , η=95.86% 3. A=D= 0.992 0.1 0 Ω, B= 52.2 75.95 0 , C= 0.0032 90 0 S --nominal T method A=D= 0.992 0.1 0 Ω, B=52.4 75.9 0 , C= 0.00318 90.05 0 S --nominal π method 4.V.R.=11%, η=93.33% 5.V s =142.65 11.76 0 kV, I s =179.8 6.85 0 A, 0.9964 pf lagging.

Transcript of · Web viewAnswers of Assignment #4 1. 0.174μF 2. V s =20.375∟1.850, η=95.86%3. A=D=...

Page 1: · Web viewAnswers of Assignment #4 1. 0.174μF 2. V s =20.375∟1.850, η=95.86%3. A=D= 0.992∟0.10Ω, B= 52.2∟75.950, C= 0.0032∟900S --nominal T method A=D= 0.992∟0.10Ω,

Answers of Assignment #41. 0.174μF

2. Vs=20.375∟1.850, η=95.86%

3. A=D= 0.992∟0.10Ω, B= 52.2∟75.950, C= 0.0032∟900S --nominal T method

A=D= 0.992∟0.10Ω, B=52.4∟75.90, C= 0.00318∟90.050S --nominal π method

4.V.R.=11%, η=93.33%

5.Vs=142.65∟11.760kV, Is=179.8∟6.850A, 0.9964 pf lagging.