Revisiting stabilities of 5D Myers-Perry black holes in numerical relativity · 2014. 3. 26. ·...
Transcript of Revisiting stabilities of 5D Myers-Perry black holes in numerical relativity · 2014. 3. 26. ·...
Revisiting stabilities of 5D Myers-Perry black holes in numerical relativity
Masaru Shibata (YITP, Kyoto)
With H. Yoshino (KEK)
ds2 = −dt2 + Gdµrd−5Σ
dt + asin2θdϕ( )2+ΣΔdr2 +Σdθ 2
+ r2 + a2( )sin2θdϕ 2 + r2 cos2θdΩd−42
Σ = r2 + a2 cos2θ; Δ = r2 + a2 −Gdµrd−5
%
&'
(
)*
µ : mass parameter, a : spin parameter
⇒ M =d − 2( )Ωd−2
16πGdµ, J = 2
d − 2Ma
2 parameters (µ, a) exist; but scale invariance exists
⇒ q := a
Gdµ( )1/(d−3)
: nondim. spin
Myers-Perry black hole with single spin
5D Myers-Perry BH: Reminder
• Spin parameter q = a/µ1/2 = [0,1) # For q= 1, a naked singularity appears
• For q à 1 , black hole is pancake-like
A =ΩD-2rh µ à 0 for q à 1
Cp / Ceq à 0 Cp(φ)
Ceq “Axial ratio”
ηm =1Cp
Cp ϕ( )exp imϕ( )dϕ∫“Deformation”
• Emparan & Myers gave a conjecture based on Thermodynamical argument (2003)
• High-spin BH seems to be unstable for any
dimension including D=5 case with q ~ 1
A =ΩD-2rhµ à 0 for high-spin
A = 2Ao >0
Previous studies for the stability of MP BH (1)
Likely to be more stable
M, J fixed
?
• Is higher-dimensional spinning BH unstable ? • Yes, for more than 6D cases: Consensus ü For axisymmetric perturbation (Dias et al. 09) ü For non-axisymmetric case (SY 10, Dias + 14) • But, could be “No” for 5D case ü For axisymmetric perturbation, it is No ü SY 10 suggested in numerical relativity it could be
“Yes” à However, simulation time was too short à We have been revisiting since last year
ü Dias + 14 show it “No”.
Previous studies for the stability of MP BH (2)
II Summary of our previous higher-dim numerical-relativity results:
• Use BSSN formulation with cartoon method: impose SU(D-3) symmetry for extra-dim space
• Excise a region deep inside horizon • Fixed mesh refinement algorithm • “Puncture gauge” with appropriate choice of
coefficients ∂tα = −1.5αK
∂tβi =
13Bi
∂tBi = Γi −
CBµBi : CB =1− 2
Evolution of deformation of AH: 6D (SY10) U
nstable D
efor
mat
ion
(m=2
)
q=0.74
Marginal
The result does agree with Dias+ 14
Evolution of deformation of AH: 7D (SY10) U
nstable
q=0.96 D
efor
mat
ion
(m=2
)
q=0.735
The result does agree with Dias+ 14
6D Evolution of Cp / Ce for high spin
q > 0.74
q=0.74
q ~ 0.6
q ~ 1 Cp
Ce
Critical value =NOT very small A
xial
rat
io SY10
Evolution of deformation of AH in 5D U
nstable? D
efor
mat
ion
(m=2
) Looks exponential growth
Exponential decay
Stable
Crash
The result does not agree with Dias+ 14
SY10
III New numerical simulations
• Long-term simulations are obviously required for high-spin case; this will be the case for studying black ring
• Employ Z4c formulation in which constraint violation can propagate
• For 4D black holes, Z4c has been proven to be robust for evolving high-spin BHs for a long term
12
Z4c formulation (Bernuzzi & Hilditch): 5D version
(∂t −βl∂l ) γ ij = −2α Aij + γ ilβ ,j
l + γ jlβ ,il −
12γ ijβ ,l
l
(∂t −βl∂l )χ =
χ2αK −β ,l
l( )(∂t −β
l∂l ) Aij =αχ Rij −14γ ijR
#
$%
&
'(− χ DiDjα −
14γ ijΔα
#
$%
&
'(
+α K Aij − 2 Ail Ajl( )+ Ail∂ jβ l + Ajl∂iβ l − 1
2β ,ll Aij
(∂t −βl∂l ) K =α Aij A
ij +14K 2
#
$%
&
'(−Δα : K = K − 2Θ
∂t −βk∂k( )Γi = 2α Γ jk
i A jk − 14γ ij 3K − 4Θ( ), j
− 2χ , jAij
#
$%
&
'(
−Γ jβ, ji +
12Γiβ, j
j + γ jkβ, jki +
12γ ikβ, jk
j
(∂t −βl∂l )Θ =αH : H =
12R+ K 2 − Ki
jK ji( )
Vacuum
13
ADM, BSSN: constraint violation cannot propagate Z4C: constraint violation can propagate à “error” is washed out à long-term simulation
Constraint violation obeys wave equations
Essence of Z4C formulation (Bernuzzi & Hilditch) H = 0 : Hamiltonian constraint Hi = 0 : Momentum constraint
⇒ADM, BSSN: ∂tH ~ −DiH
i , ∂tHi ~ 0
Z4c: ∂tΘ ~ H , Hi ~ −∂iΘ
%&'
('
⇒∂tH ~ −DiHi , ∂tH
i ~ −DiH
0.0001
0.001
0.01
0.1
0 50
dm
=2
t / µ1/2
q=0.92q=0.915q=0.91q=0.90q=0.89(t-1.5)2
1 Evolution of bar-mode (m=2): Add bar perturbation and evolve as SY10
q=0.92
q=0.91
q=0.90
q=0.89 Numerical results agree with Dias+ 14 (black dot-dot)
t / µ1/2
The growth are not exponential
Preliminary q=0.915
50 0
Approx. linear
1 Study for Bar-mode (m=2 mode)
• For stable BHs, q < ~0.90, oscillation frequency and damping rate agree with Dias+ 14 e.g., ωr ~ 1.3, ωi ~ 0.028 for q = 0.90
à For q < =0.90, 5D BH are stable (our previous analysis was incorrect)
However, for q > ~0.91, we s2ll find an instability à This is associated with other unstable mode.
0.28 0.29
0.3 0.31 0.32 0.33 0.34 0.35 0.36 0.37 0.38
0 50 100 150 200 250 300
C p /
C eq
t / (µ1/2)
q=0.900q=0.910q=0.915q=0.920
t / µ1/2
Stationary states q ~ 0.89
q = 0.90
2 Evolution of axial ratio with no initial perturbation: Instability is not due to m=2
q ~ 0.875
Preliminary
q = 0.91
q = 0.92 Axi
al r
atio
of
hori
zon
Looks stable
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
-0.3 -0.2 -0.1 0 0.1 0.2 0.3
y
x
t=86.0
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
-0.3 -0.2 -0.1 0 0.1 0.2 0.3
y
x
t=96.3
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
-0.3 -0.2 -0.1 0 0.1 0.2 0.3
y
x
t=75.8Evolution of the shape of apparent horizon
This is not gauge-invariant. But, it may show something.
q=0.92
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
-0.3 -0.2 -0.1 0 0.1 0.2 0.3
y
x
t=65.5
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
-0.3 -0.2 -0.1 0 0.1 0.2 0.3
y
x
t=106.5Preliminary
0.0001
0.001
0.01
0.1
0 50 100 150 200 250 300
dm
=4
t / µ1/2
q=0.900q=0.910q=0.915q=0.920q=0.925
m=4 mode perturbation by Cartesian grid
Unstable !?
Stable
Noise level
t / µ1/2
Preliminary
Growing mode still exists: Real frequency is by 10% smaller than in linear analysis for it
0.28 0.29
0.3 0.31 0.32 0.33 0.34 0.35 0.36 0.37 0.38
0 50 100 150 200
C p /
C eq
t / µ1/2
q=0.90
q=0.92
N=60,q=0.92N=48,q=0.92N=40,q=0.92N=60,q=0.90N=48,q=0.90N=40,q=0.90
Results depend only weakly on resolution
Stable q=0.92:Unstable !?
q=0.92 à ~ 0.875
Preliminary
-0.02 0
0.02 0.04 0.06 0.08
0.1 0.12 0.14
0 50 100 150 200 250 300
r + /
r +ex
act -
1
t / µ1/2
q=0.900q=0.910q=0.915q=0.920
Evolution of area of apparent horizon
Preliminary t / µ1/2
q=0.90, Stable
q=0.91, Unstable ?
q=0.915, Unstable ?
q=0.92, Unstable ? A A
H/A
exac
t - 1
Checking 1st law of BH thermodynamics
κδA= 8π δM −ΩHδJ( ) > 0 : κ = rhµ=µ − a2( )
1/2
µAssume monotonic wave emission
⇒ δM =σδJ : σ =ωm
; Here, ΩH =qµ1/2
>σ is needed
⇒ δq = 32δµµ
1µ1/2σ
− q"
#$$
%
&''
⇒ δAA=
δq1− q2
µ1/2 σ −ΩH( )1−σµ1/2q
=δq
1− q2σµ1/2 − q1−σµ1/2q
I checked this relation between δA & δq is satisfied for m=4 approximately: σ ~ 0.8
Summary • Z4c formalism enables us long-term simulations • For q < =0.9, 5D Myers-Perry BH appears stable
(I am very sorry for our previous result): This new result agrees with Dias+ 14 i.e., our results for ωr & ωi agree with Dias+ 14
• However, simulations still find a non-axisym. instability (m=4) for 5D high-spin MP BH !?!?
v New possible critical value is q ~ 0.91 (a/rh ~ 2.2) v The instability is NOT associated with bar-mode v Unstable BH evolves to a less spinning BH Ø To be honest, I do not still believe this result:
Please do not believe as well …
A concern • Theory in Z4c formalism is different from GR in
the presence of a constraint violation • If a large constraint violation is continuously
generated (e.g., near the BH horizon), something wrong such as bypassing might occur
• We have to be careful and need more studies
Solution space in GR
A solu2on Another solu2on
Prohibited in GR Direc2on of constraint viola2on
24
A concern in Z4c formulation
(∂t −βl∂l ) γ ij = −2α Aij + γ ilβ ,j
l + γ jlβ ,il −
12γ ijβ ,l
l
(∂t −βl∂l )χ =
χ2αK −β ,l
l( )(∂t −β
l∂l ) Aij =αχ Rij −14γ ijR
#
$%
&
'(− χ DiDjα −
14γ ijΔα
#
$%
&
'(
+α K + nΘ( ) Aij − 2 Ail Ajl( )+ Ail∂ jβ l + Ajl∂iβ l − 1
2β ,ll Aij
(∂t −βl∂l ) K =α Aij A
ij +14K 2
#
$%
&
'(−Δα : K = K − 2Θ
∂t −βk∂k( )Γi = 2α Γ jk
i A jk − 14γ ij 3K − 4Θ( ), j
− 2χ , jAij
#
$%
&
'(
−Γ jβ, ji +
12Γiβ, j
j + γ jkβ, jki +
12γ ikβ, jk
j
(∂t −βl∂l )Θ =αH : H =
12R+ K 2 − Ki
jK ji( )
Add constraint
0.28 0.3
0.32 0.34 0.36 0.38
0.4 0.42 0.44
0 50 100 150 200
C p /
C eq
t / µ1/2
q=0.90
q=0.92
Z4cn=-1n=1n=2
Final state depends on n for q=0.92 Need more researches
Preliminary
No spin: Check of 4th-order convergence
-0.08-0.07-0.06-0.05-0.04-0.03-0.02-0.01
0
0 200 400 600 800 1000
AA
H /
Aex
act -
1
t / µ1/2
6x=1.2µ1/2/N
N=30N=24N=20
N=24, (4/5)4
N=20, (2/3)4
Δx=1.2=µ1/2 / N