Minimal muon anomalous magnetic moment · 2018. 11. 16. · Broggio et al. 14 In a particular 2HDM!...

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Minimal muon anomalous magnetic moment Based on JHEP 02 (2015) 099 in collaboration with M. Bordone Carla Biggio Universita` di Genova INVISIBLES15 Workshop Madrid, 22-26 June 2015

Transcript of Minimal muon anomalous magnetic moment · 2018. 11. 16. · Broggio et al. 14 In a particular 2HDM!...

Page 1: Minimal muon anomalous magnetic moment · 2018. 11. 16. · Broggio et al. 14 In a particular 2HDM! if lighter than 200 GeV (from S 1 and S 2 results) leptoquarks Only these because

Minimal muon anomalous magnetic moment

Based on JHEP 02 (2015) 099 in collaboration with M. Bordone

Carla Biggio Universita` di Genova

INVISIBLES15 Workshop Madrid, 22-26 June 2015

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The (g-2)μ anomaly

3.1

Brookhaven 2006

Jegerlehner, Nyffeler 2009 (e+e- annih.)

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The (g-2)μ anomaly

3 ways out: - theoretical: bad estimation of hadronic contribution ➛ disfavoured - experimental: ➛ wait for new experiment - new physics !!!

Brookhaven 2006

Jegerlehner, Nyffeler 2009 (e+e- annih.)

Passera et al. 2008-09Fermilab J-PARC

3.1 �

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The (g-2)μ anomaly

3 ways out: - theoretical: bad estimation of hadronic contribution ➛ disfavoured - experimental: ➛ wait for new experiment - new physics !!!

adopt this optimistic option :)

Brookhaven 2006

Jegerlehner, Nyffeler 2009 (e+e- annih.)

Passera et al. 2008-09Fermilab J-PARC

3.1 �

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Explaining Δaμ with a single new particleAssumptions: 1. add only 1 particle to the SM

2. consider only fermions and scalars

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Explaining Δaμ with a single new particle

In the SM (g-2) is a D=6 operator

At 1 loop, for example:

Assumptions: 1. add only 1 particle to the SM 2. consider only fermions and scalars

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Explaining Δaμ with a single new particle

In the SM (g-2) is a D=6 operator

At 1 loop, for example:

Assumptions: 1. add only 1 particle to the SM 2. consider only fermions and scalars

Requirements: 1. Lorentz invariance 2. Gauge invariance 3. Renormalizability

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New fermions

NR (1, 1, 0)�R (1, 3, 1)E4 (1, 1,�1)L4 (1, 2,�1/2)T (1, 3,�1)D (1, 2,�3/2)

typeI seesawtypeIII seesaw

4th generation.}

All vector-like: masses indep. of EWSB, no anomalies

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New fermions

NR (1, 1, 0)�R (1, 3, 1)E4 (1, 1,�1)L4 (1, 2,�1/2)T (1, 3,�1)D (1, 2,�3/2)

typeI seesawtypeIII seesaw

4th generation.}

✘CB 09

All vector-like: masses indep. of EWSB, no anomalies

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New fermions

NR (1, 1, 0)�R (1, 3, 1)E4 (1, 1,�1)L4 (1, 2,�1/2)T (1, 3,�1)D (1, 2,�3/2)

typeI seesawtypeIII seesaw

4th generation.}

✘✘

CB 09, Freitas et al. 14

All vector-like: masses indep. of EWSB, no anomalies

Freitas et al. 14

Freitas et al. 14

Only L4 gives a positive contribution but too small (EWPT)

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New fermions

NR (1, 1, 0)�R (1, 3, 1)E4 (1, 1,�1)L4 (1, 2,�1/2)T (1, 3,�1)D (1, 2,�3/2)

typeI seesawtypeIII seesaw

4th generation.}

✘✘

CB 09, Freitas et al. 14

All vector-like: masses indep. of EWSB, no anomalies

Freitas et al. 14

Only L4 gives a positive contribution but too small (EWPT)

Freitas et al. 14

?

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The contribution of D ∼ (1,2,-3/2)

Q=1

Q=2

SM

CB, Bordone 14

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The contribution of D ∼ (1,2,-3/2)

Q=1

Q=2

The new contribution is negative it cannot explain the discrepancy

SM

CB, Bordone 14

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New fermions

NR (1, 1, 0)�R (1, 3, 1)E4 (1, 1,�1)L4 (1, 2,�1/2)T (1, 3,�1)D (1, 2,�3/2)

typeI seesawtypeIII seesaw

4th generation.}

✘✘

CB 09, Freitas et al. 14

All vector-like: masses indep. of EWSB, no anomalies

Freitas et al. 14 CB, Bordone 14

Freitas et al. 14

✘ CB, Bordone 14

It’s not possible to explain the discrepancy adding to the SM a single fermion

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New scalars

type II seesaw

S1 (1, 1, 1)S2 (1, 1, 2)H2 (1, 2, 1/2)� (1, 3, 1)

T 1/3c (3, 3,�1/3)

S1/3c (3, 1,�1/3)

S4/3c (3, 1,�4/3)

D7/6c (3, 2, 7/6)

D1/6c (3, 2, 1/6)

II Higgs doublet

leptoquarks

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New scalars

type II seesaw

S1 (1, 1, 1)S2 (1, 1, 2)H2 (1, 2, 1/2)� (1, 3, 1)

T 1/3c (3, 3,�1/3)

S1/3c (3, 1,�1/3)

S4/3c (3, 1,�4/3)

D7/6c (3, 2, 7/6)

D1/6c (3, 2, 1/6)

II Higgs doublet

Coaraza Perez et al. 95

Gunion et al. 89

(from S1 and S2 results)

leptoquarks

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New scalars

type II seesaw

S1 (1, 1, 1)S2 (1, 1, 2)H2 (1, 2, 1/2)� (1, 3, 1)

T 1/3c (3, 3,�1/3)

S1/3c (3, 1,�1/3)

S4/3c (3, 1,�4/3)

D7/6c (3, 2, 7/6)

D1/6c (3, 2, 1/6)

II Higgs doublet

Chakraverty et al. 01 Cheung 01

Coaraza Perez et al. 95

Gunion et al. 89

(from S1 and S2 results)

leptoquarks

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New scalars

type II seesaw

S1 (1, 1, 1)S2 (1, 1, 2)H2 (1, 2, 1/2)� (1, 3, 1)

T 1/3c (3, 3,�1/3)

S1/3c (3, 1,�1/3)

S4/3c (3, 1,�4/3)

D7/6c (3, 2, 7/6)

D1/6c (3, 2, 1/6)

II Higgs doublet

Chakraverty et al. 01 Cheung 01

Coaraza Perez et al. 95

Gunion et al. 89

(from S1 and S2 results)

leptoquarks

Only these because they have both L and R couplings ➢ enhancement with top (charm) mass

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New scalars

type II seesaw

S1 (1, 1, 1)S2 (1, 1, 2)H2 (1, 2, 1/2)� (1, 3, 1)

T 1/3c (3, 3,�1/3)

S1/3c (3, 1,�1/3)

S4/3c (3, 1,�4/3)

D7/6c (3, 2, 7/6)

D1/6c (3, 2, 1/6)

II Higgs doublet

Chakraverty et al. 01 Cheung 01

Coaraza Perez et al. 95

Gunion et al. 89

Broggio et al. 14

In a particular 2HDM if lighter than 200 GeV

(from S1 and S2 results)

leptoquarks

Only these because they have both L and R couplings ➢ enhancement with top (charm) mass

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The bR of the Higgsinoless MSSM∼

Riva, CB, Pomarol 12

It’s a SUSY model without R-parity (with U(1)R) where there are NO chiral Higgs superfields: the Higgs is identified with a sneutrino

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The bR of the Higgsinoless MSSM∼

Riva, CB, Pomarol 12

It’s a SUSY model without R-parity (with U(1)R) where there are NO chiral Higgs superfields: the Higgs is identified with a sneutrino

W � YdL�QD L� = (�̃� � H, ��)

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The bR of the Higgsinoless MSSM∼

Riva, CB, Pomarol 12

It’s a SUSY model without R-parity (with U(1)R) where there are NO chiral Higgs superfields: the Higgs is identified with a sneutrino

W � YdL�QD L� = (�̃� � H, ��)

Ydh0bLbR + Ydl�tLb̃R + ...

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The bR of the Higgsinoless MSSM∼

Riva, CB, Pomarol 12

It’s a SUSY model without R-parity (with U(1)R) where there are NO chiral Higgs superfields: the Higgs is identified with a sneutrino

W � YdL�QD L� = (�̃� � H, ��)

Ydh0bLbR + Ydl�tLb̃R + ...

l� � µIn our case , the bR coupling is fixed to be Yb

aLQµ � v2Y 2

b

M2LQ

we have a prediction for MLQ

Mb̃R� 500GeV

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The bR of the Higgsinoless MSSM∼

CB Bordone 14

In the Higgsinoless MSSM we can explain the (g-2) anomaly with a sbottom of mass Mb̃R

� 500 GeV

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The bR of the Higgsinoless MSSM∼

CB Bordone 14

In the Higgsinoless MSSM we can explain the (g-2) anomaly with a sbottom of mass

Which are the current bounds?

Mb̃R� 500 GeV

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The bR of the Higgsinoless MSSM∼

CB Bordone 14

Bounds from decay into bv: Br=1 M>620 GeV Br=0.6 M>520 GeV

ATLAS 13

In the Higgsinoless MSSM we can explain the (g-2) anomaly with a sbottom of mass

Which are the current bounds?

Mb̃R� 500 GeV

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The bR of the Higgsinoless MSSM∼

CB Bordone 14

Bounds from decay into bv: Br=1 M>620 GeV Br=0.6 M>520 GeV

ATLAS 13

In the Higgsinoless MSSM we can explain the (g-2) anomaly with a sbottom of mass

Which are the current bounds?

In our model: b̃R � bL�L

tLlL(bRG̃)

same BR

Mb̃R� 500 GeV

This possibility is viable, to confirm/exclude it look for final states with top and charged leptons!!!

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ConclusionsWe have considered single particle extensions of the SM (scalar & fermion)

A single new fermion cannot explain the (g-2)μ anomaly

Only 3 scalars -2 leptoquarks and a second Higgs doublet- can do it

The bR of the Higgsinoless MSSM could solve the (g-2)μ puzzle and we have a prediction for its mass:

Most of these solutions are going to be tested @ LHC13

Wait for new LHC run and new (g-2)μ experiment!

Mb̃R� 500 GeV

Muchas gracias

!

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