APENDICE absorcion gaseosa

APENDICECada de presin tericaEMPAQUE SECO Q= 0,50RED= (dp*Vm*)/ (1-E)*RED= (0,007848*0,028*1,21)/(1-0,367)*1,8RED=23 ,34

A = =

A = 0,005026V = = = 0,028 m/sE= 0,367De= 0,007848

= Pgas = Patm + Hg *H liqPgas =1 atm + (133074,59*0,01m)1330,7459 Pa 0,013 atmPgas =1,013 atm= = 1,21 Kg/m3

= 57,55 = 6,51 =62,45Q= 1

V = = = 0,055m/sE= 0,363De= 0,007848

= Pgas = Patm + Hg *H liqPgas =1 atm + (133074,59*0,05m)6653,73Pa 0,06566 atmPgas =1,07 atm= = 1,28 Kg/m3

= 119,35 = 26,59 =141,95RED= (0,007848*0,055*1,28)/(1-0,363)*1,8RED=48,19Q= 1,5

V = = = 0,083m/sE= 0,35De= 0,007848

= Pgas = Patm + Hg *H liqPgas =1 atm + (133074,59*0,09m)11976,7131Pa 0,118 atmPgas =1,12atm= = 1,34 Kg/m3 = 209,68 = 75,05 =277,6RED= (0,007848*0,083*1,34)/(1-0,35)*1,8RED=74,60

Q= 2

V = = = 0,11m/sE= 0,344De= 0,007848

= Pgas = Patm + Hg *H liqPgas =1 atm + (133074,59*0,09m)18630,44Pa 0,18 atmPgas =1,18atm= = 1,40Kg/m3

= 293,21 = 83,66 =367,4

RED= (0,007848*0,11*1,40)/(1-0,344)*1,79RED=102,92200 L/H Q=V = = = 0,028 m/s

E= 0,30De= 0,007848


= 128,90 = 10,80 =136,20RED= (0,007848*0,028*1,24)/(1-0,344)*1,85RED=22,45

Q= 1

V = = = 0,055m/sE= 0,28De= 0,007848


= 338,47 = 69,17 =397,45

RED= (0,007848*0,055*1,30)/(1-0,28)*1,8RED=42,12

Q= 1,5 V = = = 0,083m/sE= 0,265De= 0,007848

= Pgas = Patm + Hg *H liqPgas =1 atm + (133074,59*0,10m)13307,459Pa 0,13 atmPgas =1,13atm= = 1,36 Kg/m3

= 638,083 =198,44 =815,60

RED= (0,007848*0,083*1,36)/(1-0,265)*1,8RED=64,11

Q= 2 V = = = 0,11m/sE= 0,252De= 0,007848

= Pgas = Patm + Hg *H liqPgas =1 atm + (133074,59*0,09m)26615,098Pa 0,26atmPgas =1,26atm= = 1,49Kg/m3 = 975,15 = 412,50*0,975=1352,95RED= (0,007848*0,11*1,49)/(1-0,252)*1,8RED=95,53240 L/HQ=V = = = 0,028 m/s

E= 0,27De= 0,007848


= 194,35 = 19,33 =208,34RED= (0,007848*0,028*1,24)/(1-0,27)*1,82RED=20,51

Q= 1 V = = = 0,055m/sE= 0,245De= 0,007848


= 555,56 = 108,27 =647,23

RED= (0,007848*0,055*1,30)/(1-0,245)*1,8RED=40,17

Q= 1,5 V = = = 0,083m/sE= 0,22De= 0,007848

= Pgas = Patm + Hg *H liqPgas =1 atm + (133074,59*0,13m)17299,6967Pa 0,17 atmPgas =1,17atm= = 1,40Kg/m3 = 1202,48 =378,88(1202,48+378,88)*0,975= 1541,83

RED= (0,007848*0,083*1,40)/(1-0,22)*1,8RED=64,95Q= 2 V = = = 0,11m/sE= 0,205De= 0,007848

= Pgas = Patm + Hg *H liqPgas =1 atm + (133074,59*0,23m)20607,1557Pa 0,30atmPgas =1,30atm= = 1,52Kg/m3 = 1966,60= 910,18975=2804,86RED= (0,007848*0,11*1,52)/(1-0,205)*1,73RED=95,407Caida de presin experimentalEMPAQUE SECO ACEITE - -AIRE)Q=0,58830 N/m3 12,671 N/m3)

Q=18830 N/m3 12,671 N/m3) PaQ=1,58830 N/m3 12,671 N/m3)

Q= 28830 N/m3 12,671 N/m3)

Figura 1. Log P terico vs Log G empaque seco

200 L/HQ=0,58830 N/m3 12,671 N/m3)

Q=18830 N/m3 12,671 N/m3) PaQ=1,58830 N/m3 12,671 N/m3)

Q= 28830 N/m3 12,671 N/m3)

Figura 2. Log P terico vs Log G 200 l/h

240 L/HQ=0,58830 N/m3 12,671 N/m3) PaQ=18830 N/m3 12,671 N/m3) PaQ=1,58830 N/m3 12,671 N/m3)

Q= 28830 N/m3 12,671 N/m3)

%Error %Error =( )*100

Figura 3. Log P terico vs Log G 240 l/h

EMPAQUE SECO Q=0,5%Error =( )*100%24,9%Tabla No . Errores obtenidos entre los resultados experimentales y tericos EMPAQUE SECO % Error

0,524,9%

143,5%

1,533,3%

244,7%

200 L/H

0,545,4%

140,26%

1,566,18%

274,17%

240 L/H

0,596,8%

181%

1,578,44%

280,72%

G= Q*EMPAQUE SECOG= 0,5*1,24G= 0,62

QQQ QGQG GLog G

0,50,62-0,207

11,300,11

1,52,040,309

22,980,47

PteoricoLog PPexperimentalLog P

62,451,7983.171,92

141,952,15249,512,39

277,622,44415,862,63

367412,56665,382,82

Q= 200 L/H

136,202,13249,522,40

397,452,6665,392,82

815,602,92412,0253,38

1352,953,135239,93,72

Q= 240 L/H

208,342,316653,863,82

647,232,83410,113,53

1541,833,197152,903,85

2804,863,4414555,334,16

Figura 4. Log P experimental vs Log G empaque seco

Figura 5 Log P experimental vs Log G 200 l/h

Figura 6 Log P experimental vs Log G 240 l/h

APENDICE absorcion gaseosa

Documents

Transcript of APENDICE absorcion gaseosa