2-D Motion
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2-D Motion. Vectors. Review of Trig. Find y, H, θ2, when X=4.7 m and θ1=33 ° SOH, CAH, TOA Sinθ =O/H Cosθ =A/H Tanθ =O/A. Review of Trig. Find y, H, θ2, when X=4.7 m and θ1=33 ° SOH, CAH, TOA Opposite and Adjacent refer to being opposite and adjacent of the angle you referring to! - PowerPoint PPT Presentation
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2-D MotionVectorsReview of TrigFind y, H, 2, when X=4.7 m and 1=33SOH, CAH, TOASin=O/HCos=A/HTan=O/AReview of TrigFind y, H, 2, when X=4.7 m and 1=33SOH, CAH, TOAOpposite and Adjacent refer to being opposite and adjacent of the angle you referring to!Hypotenuse is always opposite of the right angleReview of TrigFind y, H, 2, when X=4.7 m and 1=33SOH, CAH, TOAUsing 1=33 and x=4.7We can use CAHReview of TrigFind y, H, 2, when X=4.7 m and 1=33SOH, CAH, TOAAdjacent=4.7 m, Hypotenuse=?, 1=33Cos=A/HCos33=4.7/H H=5.6 mH=3.05 m5Review of TrigFind y, H, 2, when X=4.7 m and 1=33SOH, CAH, TOAH=5.6 mNow we can use the Pythagorean theorem A2 +B2 = C2Review of TrigFind y, H, 2, when X=4.7 m and 1=33SOH, CAH, TOAH=5.6 m, X=4.7 m y=?H is always C4.72 + Y2 = 5.6222.09 + Y2 =31.4Y=3.0 mReview of TrigFind y, H, 2, when X=4.7 m and 1=33SOH, CAH, TOAFind 2The angles of a right triangle = 18033+ 90+ x = 180X=57Or how else can we solve this problem?We can use SOH, CAH, TOA Sin =O/H Sin =4.7/5.6 Take the inverse sin to solve 8Clicker Question ?
Hypotenuse=500 mTheta=20 degreesA-20B-170C-180D-250E-470B9
