Post on 18-Jan-2016
Vi = 0 m/s T = 10 s Find d = Find vf =
Lab activity information
Chapter 4 ProblemsGuided Practice Problems
Find the uniform acceleration that causes a car’s velocity to change from 32m/s to change to 76 m/s. In an 8.0 s period.
Problem #1
Given: Vi = 32 m/s Vf = 76 m/s T = 8.0 s
Unknown: a =
Problem #1
Equation: A = Δv Δt
Problem #1
Answer: 5.5 m/s/s
Problem #1
Solution: 76m/s-32m/s / 8 s =
Problem #1
A supersonic jet flying at 155 m/s is accelerated uniformly at the rate of 23.1 m/s2 for 30 s.
A. What is its final velocity? B. The speed of sound in air is 331 m/s. How
many times the speed of sound is the plane’s final speed?
Problem #2
Given: Time = 30 s A = 23.1 m/s2
Vi = 155 m/s ______________ Vf = Speed of sound is
331 m/s
Unknown: Vf =
Problem #2
Equation: A Vf = vi + at
Problem 2
Equation B: N= 848 m/s/331m/s=
Problem #2
Answer to A = 848 m/s
Problem #2
Answer to B:2.56 times
Problem #2
Solutions for A: 155m/s + (23.1 m/s/s)(30.0 s) =vf
Problem #2
Solution for B : 848 m/s/331m/s =
Problem #2
Determine the displacement of a plane that is uniformly accelerated from 66 m/s to 88 m/s in 14 s.
Problem #3
Given: 66 m/s = Vi
88 m/s = Vf
T = 14 s
Unknown: d
Problem #3
Equation D=(vf + vi)t/2 =
Problem #3
Answer #3: 550 m
Problem #3
Solution #3 : (88 m/s + 66 m/s)14 s/2 =
Problem #3
If a bullet leaves the muzzle of a gun with a speed of 500 m/s, and the barrel of the rifle is .9 m long. What is the acceleration of the bullet while in the barrel?
Problem #4
Given: Vf = 500 m/s D = .9 m Vi = 0 m/s
Unknown: A =
Problem #4
Equation: a = Vf
2 – vi2 /2d
Problem #4
Answer :1.38 X 105 m/s/s
Problem #4
Solution: (500 m/s)2-0 /(2) (0.9 m) =
Problem #4
A plane travels 600 m while being accelerated uniformly from rest at the rate of 5.0 m/s2. What final velocity does it attain?
Problem #5
Given: d = 600 m a= 5.0 m/s2
Vi = 0 m/s
Unknown: Vf =
Problem #5
Equation: Vf
2 =vi2 + 2ad
Problem #5
Answer: 77.5 m/s
Problem #5
Solution: Sq root 0 +2(5.0 m/s/s)(600 m) =
Problem #5
Page 82: 1,5, Page 83 : 8,9,10, 16 Page 84: 24, Reviewing concepts: 1,2,3,8, Applying concepts: 3, 8, 9 Due thursday
Assignment
Vf = vi + at d = ½ (vf + Vi)t d = vit + ½ at2
Vf2 = vi
2 + 2ad
Vi vf a t Vi d vf t Vi d a t Vf d vi a
Equations of Motion for Uniform acceleration