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1. Our calculation is similar to that shown in Sample Problem 42-1. We set ( )( )0 Cu min5.30MeV= 1/ 4 /K U q q rαε= = π and solve for the closest separation, rmin: (…
1. (a) Eq. 28-3 leads to v F eB B = = × × × ° = × − − −sin . . . sin . . .φ 650 10 160 10 2 60 10 230 4 00 10 17 19 3 5N C T m sc hc h (b) The kinetic energy…
1. 1. (a) An Ampere is a Coulomb per second, so 84 84 3600 30 105 A h C h s s h C⋅ = ⋅F HG I KJF HG I KJ = ×. . (b) The change in potential energy is ∆U = q∆V =…
1. 1. The amplitude of the induced emf in the loop is 6 2 0 0 4 (6.8 10 m )(4 T m A)(85400/ m)(1.28 A)(212 rad/s) 1.98 10 V. m A niε µ ω − − = = × × ⋅ = × −7…
ECE302 Spring 2007 Practice Problems for Final May 2, 2007 1 Problem 7.4.1 • X1, . . . ,Xn are n independent identically distributed samples of random variable X with PMF…
5.3 (a) Looking into the base of Q 1 we see an equivalent resistance of r π1 , so we can draw the following equivalent circuit for finding R in : R in R 1 R 2 r π1 R in…
3.1 (a) IX = VX R1 0 VX < 0 VX > 0 IX VX (V) Slope = 1/R1 3.2 IX = Plotting IX (t), we have VX R1 0 VX < 0 VX > 0 V0 IX (t) for VB = 1 V (Solid) 0 0 −V0 /R1…
4.4 According to Equation (4.8), we have IC = AE qDn n2 VBE /VT i −1 e NB WB 1 ∝ WB We can see that if WB increases by a factor of two, then IC decreases by a factor…
3.1 (a) IX = { VX R1 VX < 0 0 VX > 0 VX (V) IX Slope = 1/R1 3.2 IX = { VX R1 VX < 0 0 VX > 0 Plotting IX(t), we have 0 −V0/R1I X (t ) fo r V B = 1 V (S ol id…
University of California, Berkeley Physics H7B Spring 1999 (Strovink) SOLUTION TO PROBLEM SET 5 Solutions by P. Pebler 1 Purcell 1.16 A sphere of radius a was filled with…
University of California, Berkeley Physics H7B Spring 1999 (Strovink) SOLUTION TO PROBLEM SET 6 Solutions by P. Pebler 1 Purcell 2.27 The electrostatic potential at a point…
Journal de Théorie des Nombres de Bordeaux 00 (XXXX), 000–000 Computing fundamental domains for Fuchsian groups par John Voight Résumé. Nous exposons un algorithme…
Numerical Solution of a Non-Smooth Eigenvalue Problem An Operator-Splitting Approach A. Caboussat & R. Glowinski 1. Formulation. Motivation Our main objective is the…
1. A Presentation on Operations Management Course Code: MGT-312 Topics: Waiting Line Management Group: Campus4/7/2014 2. Group Members Roll No. Authorized By, MD. Abu Zafor…
Problem Solutions – Chapter 11 Problem 11.1.1 Solution For this problem, it is easiest to work with the expectation operator. The mean function of the output is E Y t =…
Boyce/DiPrima 9th ed, Ch 7.7: Fundamental Matrices Elementary Differential Equations and Boundary Value Problems, 9th edition, by William E. Boyce and Richard C. DiPrima,…
Classical Mechanics Problem 1: Central Potential Solution a Integrals of motion for a central potential V r: Angular Momentum L = rvt = r2φ̇ Energy per unit mass E = 12…
Pomiary Automatyka Robotyka nr 1/2013 63 Solution of the Kalman filtering problem in control and modeling of a double inverted pendulum with rolling friction Paweł Olejnik*,…
Dark Matter and Dark Energy from the solution of the strong CP problem Roberto Mainini, L. Colombo & S.A. Bonometto Universita’ di Milano Bicocca Mainini & Bonometto…