Report - kahrbjy.files.wordpress.com · or 212 1 2 2 122 2 2 1 1 (1) ω ω ω ω −=+ −= + rr r r rr r So 2 2 1 22 1 1 r r r ω ω + = − Substituting into (3), we find 222 12 2 2 1 22

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