Report - Chapter 17, Solution 1. 2 periodic ω πω · Hence f(t) = sin(n t) n 10 1 n 1 π π + ∑ ∞ = 5 Chapter 17, Solution 5. T =2π, ω=2π/T =1 [1x 2x ] 0.5 2 1 z(t)dt T 1 a T 0 o

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