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2 1 2 1 4 2 4 2s 4x2 4 2 4x2x R x 1 R S dx =2π x dx π x +1) dx π x π +4 3 · PDF filey = 1 4 x2 − 1 2 lnx ⇒ dy dx = x 2 ... 4x2 = x2 4 + 1 2 + 1 4x2 = x 2 + 1 2x 2. So S =
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