Kinematics IIKinematics IIWeek 2Week 2
ContentsContents RadiansRadians Uniform Circular MotionUniform Circular Motion Projectile MotionProjectile Motion Summary of Kinematics I & IISummary of Kinematics I & II
RadiansRadiansA radian is a measure of an angle.A radian is a measure of an angle.
Radius = 1Radius = 1 ӨӨ = = arcarc length length
360˚ = 2360˚ = 2π radiansπ radians 180180˚̊ = π radians = π radians
Unit Circle; radius = 1
ӨӨ
arcarc
Quiz 1Quiz 1Which of the following radian Which of the following radian measures is equivalent to 90measures is equivalent to 90˚?˚?
1.1. 2π2π2.2. ππ3.3. π/2π/24.4. π/3π/35.5. π/4π/4
Quiz 1Quiz 1Which of the following radian Which of the following radian measures is equivalent to 90measures is equivalent to 90˚?˚?
180180˚̊ = π radians = π radians 9090˚̊ = π/2 radians = π/2 radians
ANSWER: π/2ANSWER: π/2
Arc LengthArc Length When radius = 1When radius = 1
arcarc = = ӨӨ When radius = rWhen radius = r
arcarc = r = rӨӨ
* * ӨӨ must be in radians must be in radians
ӨӨ
arcarcrr
Uniform Circular MotionUniform Circular Motion ““Uniform” implies Uniform” implies
constant speed constant speed while moving in a while moving in a circlecircle
Angular Angular FrequencyFrequency
ω = ω = ӨӨ/sec/sec
ӨӨ
Quiz 2Quiz 2An object in circular motion moves An object in circular motion moves 180180˚ per second has an angular ˚ per second has an angular frequency of what?frequency of what?
1.1. 2π2π2.2. 3π/23π/23.3. π/2π/24.4. π/3π/35.5. π/4π/4
Quiz 2Quiz 2An object in circular motion moves An object in circular motion moves 180180˚ per second has an angular ˚ per second has an angular frequency of what?frequency of what?
ANSWER: ANSWER: ω = π/2 radians/secω = π/2 radians/sec
Angular SpeedAngular Speedarc = rarc = rӨӨω = ω = ӨӨ/sec/sec
Angular speed:Angular speed:vv = arc/sec= arc/sec
= (r= (rӨӨ)/sec)/sec= r(= r(ӨӨ/sec)/sec)= rω= rω
ӨӨ
ӨӨ
SummarySummary ӨӨ = arc length (r=1) = arc length (r=1) arc = rarc = rӨӨ ω = ω = ӨӨ/sec/sec v = arc/sec = rωv = arc/sec = rω
ӨӨ
rr
arcarc
Quiz 3Quiz 3An object in circular motion travels An object in circular motion travels at 3 radians/sec in a circle of radius at 3 radians/sec in a circle of radius 5m. What is its angular speed?5m. What is its angular speed?
1.1. 3/5 m/sec3/5 m/sec2.2. 5/3 m/sec5/3 m/sec3.3. 2 m/sec2 m/sec4.4. 8 m/sec8 m/sec5.5. 15 m/sec15 m/sec
Quiz 3Quiz 3An object in circular motion travels at 3 An object in circular motion travels at 3 radians/sec in a circle of radius 5m. What radians/sec in a circle of radius 5m. What is its angular speed?is its angular speed?
ω = 3 radians/secω = 3 radians/secv = rωv = rωv = (5)(3) = 15 m/secv = (5)(3) = 15 m/sec
ANSWER: 15 m/secANSWER: 15 m/sec
Centripital ForceCentripital Force An object An object
travelling in travelling in circular motion circular motion experiences a experiences a centripetal force centripetal force FF
The induced The induced acceleration isacceleration isa = va = v22/r/r
F
Quiz 4Quiz 4Imagine that the centripetal force applied Imagine that the centripetal force applied on an object moving in circular motion is on an object moving in circular motion is suddenly shut off. What would happen?suddenly shut off. What would happen?
1.1. The object spirals outwardsThe object spirals outwards2.2. The object spirals inwardsThe object spirals inwards3.3. The object continues to move in uniform circular The object continues to move in uniform circular
motionmotion4.4. The object decelerates while continuing to move in The object decelerates while continuing to move in
a circlea circle5.5. The object moves away in a straight lineThe object moves away in a straight line
Quiz 4Quiz 4Imagine that the centripetal force Imagine that the centripetal force applied on an object moving in applied on an object moving in circular motion is suddenly shut off. circular motion is suddenly shut off. What would happen?What would happen?
ANSWER: The object moves away in ANSWER: The object moves away in a straight line (Newton’s first law)a straight line (Newton’s first law)
Projectile MotionProjectile Motion An object An object
experiences experiences gravitational gravitational acceleration acceleration g=9.80m/sg=9.80m/s22 downwards as it downwards as it movesmoves
Projectile MotionProjectile Motion Projectile motion is Projectile motion is
really two really two independent 1-D independent 1-D motionsmotions
One in the x One in the x directiondirection
One in the y One in the y directiondirection
x-directionx-directionThe x-direction experiences NO The x-direction experiences NO acceleration, thusacceleration, thus
x = vx = vxxtt
(It’s that simple!)(It’s that simple!)
y-directiony-directionThe y-direction experiences an The y-direction experiences an acceleration downwards, thusacceleration downwards, thus
y = vy = vyyt – ½gtt – ½gt22
Velocity ComponentsVelocity Componentsx = vx = vxxtty = vy = vyyt – ½gtt – ½gt22
vv
vvxx
vvyy
ӨӨ
vvxx = v cos = v cosӨӨvvyy = v sin= v sinӨӨ
Quiz 5Quiz 5At what angle should a cannon be At what angle should a cannon be positioned so that the projectile positioned so that the projectile travels the farthest?travels the farthest?
1.1. 90˚90˚2.2. 60˚60˚3.3. 45˚45˚4.4. 30˚30˚5.5. 0˚0˚
Quiz 5Quiz 5At what angle should a cannon be At what angle should a cannon be positioned so that the projectile positioned so that the projectile travels the farthest?travels the farthest?
ANSWER: 45˚ANSWER: 45˚
Proof of Quiz 5Proof of Quiz 5x = vx = vxxtty = vy = vyyt – ½gtt – ½gt22
vvxx = v cos = v cosӨӨvvyy = v sin= v sinӨӨ
Let y = 0Let y = 0 t = 2vt = 2vyy/g/g x = 2vx = 2vxxvvyy/g/g x = (2vx = (2v2 2 sinsinӨӨ cos cosӨӨ)/g)/g x = (vx = (v2 2 sin2sin2ӨӨ)/g)/g xxmaxmax = v = v22/g when 2/g when 2ӨӨ = 90˚ = 90˚ ӨӨ = 45˚ = 45˚
y = 0 y = 0
* Trig. Identity:* Trig. Identity:sin2sin2ӨӨ = 2sin = 2sinӨӨ cos cosӨӨ
ReviewReview Linear Motion under Linear Motion under
Uniform AccelerationUniform Accelerationx = xx = x00 + v + v00t + ½att + ½at22
v = v = vv00 + at + atΔΔx = vx = vaveavet = [(vt = [(v00 + + v)/2]tv)/2]tvv22 - v - v00
22 = 2a = 2aΔΔxx
Uniform Circular MotionUniform Circular MotionӨӨ = arc length (r=1) = arc length (r=1)arc = rarc = rӨӨω = ω = ӨӨ/sec/secv = arc/sec = rωv = arc/sec = rωa = va = v22/r/r
Projectile MotionProjectile Motionx = vx = vxxtty = vy = vyyt – ½gtt – ½gt22
vvxx = v cos = v cosӨӨvvyy = v sin= v sinӨӨ
Next WeekNext Week Choice 1Choice 1
– Review kinematicsReview kinematics Choice 2Choice 2
– Newton’s lawsNewton’s laws
The EndThe End
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