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EAMCET ENGINEERING MODEL GRAND TEST
No. of Questions: 160 Marks: 160 Time: 3 Hrs.
MATHEMATICS1. If f (x) = cos [π] x + cos [πx] where [ . ] denotes the greatest integer function.
Then f ( π2 ) =
1) cos 4 2) cos 3 3) 0 4) None of these
2. f (2x + 3y, 2x − 7y) = 20x. Then f (x, y) =
1) 7x − 3y 2) 7x + 3y 3) 3x − 7y 4) x − y
3. The domain of f(x) =
√
is v°æü˨¡ç4x + 8
2−3
(x − 2)− 13 − 2
2(x − 1)
1) [1, ∞) 2) [0, ∞)
3) [2, ∞) 4) does not exist ´u -Æœnûªç é¬ü¿’
a b c
4. For a ∆ ABC, if b c a = 0, then sin1/3
A + sin1/3
B + sin1/3
C =
c a b
a b c
vA¶µº’ïç ABC ™ b c a = 0, Å®·ûË sin1/3
A + sin1/3
B + sin1/3
C =
c a b
1) 3 (12)
1/3
2) 3 (√3
2 )
1/3
3) (12)
1/3
4) (√3
2 )
1/3
0 a + 1 b − 2
5. If A = [ 2a − 1 0 c − 2 ] is a skew symmetric then a + b + c =
2b + 1 2 + c 0
0 a + 1 b − 2
A = [ 2a − 1 0 c − 2 ] Å≤˘-≠æd´ ´÷vAéπ Å®·ûË a + b + c =
2b + 1 2 + c 0
1) 3 2) −3 3) 73
4) 13
6. The number of solutions of the system x +y + z = 0, 2x + 5y + 7z = 0, 2x−5y + 3z = 0 is
x + y + z = 0, 2x + 5y + 7z = 0, 2x − 5y + 3z = 0 ´u´Ææn ≤ƒüµ¿-†© Ææçêu
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1) 1 2) 2 3) 3 4) Infinite (ņçûªç)
1 x x + 1
7. If f(x) = 2x x(x − 1) (x + 1)x 3x(x − 1) x(x−1)(x−2) x(x−1)(x + 1)
then f(50) + f(51) + ... + f(99) =
1 x x + 1
If f(x) = 2x x(x − 1) (x + 1)x 3x(x − 1) x(x−1)(x−2) x(x−1)(x + 1)
-Å®·-ûË f(50) + f(51) + ... + f(99) =
1) 3725 2) 0 3) 1275 4) None àD-é¬ü¿’
8. The number of different nine digit numbers can be formed from the number
223355888 by rearranging its digits. So that the odd digits occupy even position is
223355888 ™E ÅçÈé-©†’ Ö°æ-ßÁ÷-TÆæ÷h à®Ωp-JîË 9 ÅçÈé© Ææçêu™x ¶‰Æœ Ææçêu©’ ÆæJ-≤ƒnØ√™xÖçúË Ææçêu© Ææçêu
1) 16 2) 36 3) 180 4) 60
17 17 1 7(1 + 17) [1 + ] [1 + ]........... [1 + ]2 3 19
9. The value of =19 19 19
(1 + 19) [1 + ] [1 + ]........... [1 + ]2 3 17
1) 1 2) 36C17 3) 36C19 4) 219
10. The greatest number of points of intersection of 8 lines and 4 circles is
8 Ææ®Ω-∞¡-Í®-ê©’, 4 ´%û√h©’ í∫J-≠æeçí¬ êçúÕç--èπ◊ØË êçúø† Gçü¿’-´¤© Ææçêu
1) 64 2) 92 3) 104 4) 96
11. If f(x) is a periodic function having period 7 and g(x) is a periodic function
having period 11, then the period of
f(x) ÅØËC 7 Ç´-®Ωh-†çí¬ Ö†o Ç´-®Ωh† v°æ¢Ë’ߪ’ç, g (x) ÅØËC 11 Ç´-®Ωh-†çí¬ Ö†o Ç´®Ωh†v°æ¢Ë’ߪ’ç Å®·ûË
xf(x) f ( )3
D(x) = x is Ç´-®Ωh†çg(x) g( )5
1) 77 2) 231 3) 385 4) 1155
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12. 15C2 + 2.15C3 + 3.15C4 + ... + 14.15C15 =
1) 14.215 + 1 2) 13.214 + 1 3) 14.215 − 1 4) 13.214 − 1
13. The last two digits of the number 3400 are
3400 ™E *´J È®çúø’ Ææçêu©’
1) 39 2) 29 3) 01 4) 43
14. If α, β are roots of x2 − p (x + 1) − c = 0 then
α2 + 2α + 1 β2 + 2β + 1the value of + =
α2 + 2α + c β2 + 2β + c
α2 + 2α + 1 β2 + 2β + 1x2 − p (x + 1) − c = 0 ´‚™«©’ α, β Å®·ûË + =
α2 + 2α + c β2 + 2β + c
1) 1 2) −1 3) 2 4) 0
β2 + γ2
15. If α, β, γ are the roots of x3 + px2 + qx + r = 0, then ∑ =βγ
β2 + γ2
x2 + px2 + qx + r = 0 ´‚™«©’ α, β, γ Å®·ûË ∑ =βγ
pq pq pq pq1) − 1 2) − 2 3) − 3 4) − 4
r r r r
16. The geometric mean of 3, 32, .......................... 3
nis
3, 32, .......................... 3
ní∫’ù ´’üµ¿u´’ç
1) 3n/2
2) 3
n( n+1
2)
3) 4n/2
4) 3
n+12
17. Variance of the data 2, 4, 6, 8, 10 is
2, 4, 6, 8, 10 © NÆæh %A
1) 6 2) 7 3) 8 4) 9
x2 + 5x + 1 A B C18. If = + + then B =
(x + 1)(x + 2)(x + 3) x +1 (x +1) (x + 2) (x + 1) (x + 2) (x + 3)
x2 + 5x + 1 A B C = + + Å®·ûË B =(x + 1)(x + 2)(x + 3) x +1 (x +1) (x + 2) (x + 1) (x + 2) (x + 3)
1) 1 2) −5 3) 4 4) 0
19. A determinant is chosen at random from the set of all determinants of order
2 × 2 with elements 0 or 1 only. The probability that the determinant is positive
is
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0 ™‰ü∆ 1 ´‚©-é¬-©ûÓ ´÷vûªç à®ΩpúË 2 × 2 ûª®Ω-í∫A E®√l¥-®Ω-鬩 †’ç* ߪ÷ü∑¿%-*a ¥-éπçí¬ äéπE®√l¥®Ωé¬Eo ᆒo-èπ◊çõ‰ ü∆E E®√l¥-®Ωéπç N©’´ üµ¿Ø√-ûªtéπç é¬ -ú≈-EéÀ Ææ綵«- uûª
3 3 5 71) 2) 3) 4)
16 8 8 8
20. The probability that in a random arrangement of the letters of the word COLLEGE,
the two E's and two L's do not come together.
COLLEGE ÅØË °æü¿ç-™E Åéπ~-®√-©†’ ߪ÷ü∑¿%-*a ¥-éπçí¬ äéπ ´®Ω’-Ææ™ Å´’-JaûË 2 E ©’, 2 L ©’äÍé-îÓô Öçúø-éπ-§Ú- -ú≈-EéÀ Ææ綵«´uûª
18 20 191) 2) 3) 4) None
21 21 21
21. If α, β are the roots of the equation x2 − 15x + 1 = 0 then the value of
1 1( − 15)−2+ ( − 15)−2
isα β
1 1x2 − 15x + 1 = 0 ´‚™«©’ α, β Å®·ûË ( − 15)−2
+ ( − 15)−2=
α β
1) 225 2) 900 3) 223 4) 0
22. Match the following: éÀçC¢√-öÀE ïûª-°æ-®Ω-îªçúÕ:
List - I List - II
A) Number of distinct terms 1) 212
in the expansion of (x + y − z)16
(x + y − z)16 ™E NGµ†o °æü∆© Ææçêu
B) Number of terms in the expansion 2) 97
(x + √x2 −1)6
+ (x − √x2 −1)6
(x + √x2 −1)6
+ (x − √x2 −1)6
™E °æü∆© Ææçêu
C) The number of irrational terms in ( 8√
5 +
6√
2 )
1003) 4
( 8√
5 +
6√
2 )
100™E Åéπ-®Ω-ùÃߪ’ °æü∆© Ææçêu
D) The sum of numerical 4) 153
coefficients in (1 +x3
+ 2y3 )
12
(1 + x3
+ 2y3 )
12í∫’ù-鬩 ¢Á·ûªhç 5) 1
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A B C D
1) 2 1 3 4
2) 1 2 3 4
3) 4 3 2 1
4) 1 4 3 2
23. A letter is known to have come from "INDORE or BANGLORE". On the post
mark only three consecutive letters ORE are visible. The probability that the
letter came from BANGLORE is
INDORE †’ç* ™‰ü∆ BANGLORE †’ç* äéπ Öûªh®Ωç ´*açC ÅE ûÁL-ÆœçC. Ç Öûªh®ΩçO’C §ÚÆæd™¸ ´·vü¿™ ORE ÅØË ´‚úø’ ´®Ω’Ææ Åéπ~-®√©’ ´÷vûª¢Ë’ éπE°œÆæ÷h Öçõ‰ ÅCBANGLORE †’ç* ´*a Öçúø-ö«-EéÀ Ææ綵«- uûª
1) 35
2) 15
3) 25
4)45
24. If the variance of the random variable X is 9, then the S.D. of the random
variable −4x + 8 is
äéπ ߪ÷ü∑¿%-*a ¥éπ -®√P X NÆæh %A 9 Å®·ûË −4x + 8 ÅØË îª©-®√P véπ´’ Nîª-©†ç
1) 144 2) 27 3) 12 4) 16
25. If x is a random poisson variate such that 2P(x = 0) + P(x = 2) = 2P(x = 1) then
E(x) =
2P(x = 0) + P(x = 2) = 2P(x = 1) ÅßË’u™« x ߪ÷ü∑¿%-*a ¥é𠧃®·-ñ«Ø˛ -®√P Å®·ûËE(x) =
1) 4 2) 3 3) 2 4) 1
26. If tan π9
, x, tan 5π18
are in A.P. and tan π9
, y, tan 7π18
are in A.P. Then
tan π9
, x, tan 5π18
©’ A.P.™ -Ö-Ø√o®· -´’-J-ߪ· tan π9
, y, tan 7π18
©’ A.P.™ Öçõ‰
1) y = 2x 2) x = 2y 3) x = y 4) None
27. The number of solutions of 16sin2x + 16cos2x = 10, 0 ≤ x ≤ 2π
0 ≤ x ≤ 2π Å®·ûË 16sin2x + 16cos2x = 10 ≤ƒüµ¿†© Ææçêu
1) 4 2) 6 3) 8 4) None
28. If A = cot−1 √
tanθ − tan−1 √
tanθ then tan ( π
4
−A2 ) =
A = cot−1 √
tanθ − tan−1 √
tanθ Å®·ûË tan ( π
4
−A2 ) =
1) √cot θ 2) tanθ 3) cotθ 4) √
tan θ
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a cos A + b cos B + c cos C29. In a ∆ABC, =
a + b + c
a cos A + b cos B + c cos C∆ ABC ™ =
a + b + c
1) Rr
2) R2r
3) rR
4)2rR
30. In a ∆ABC, ∠B = π3
and ∠C = π4
and D divides BC internally in the
sin ∠BADratio 1 : 3, then =
sin ∠CAD
∆ ABC ™, ∠B = π3
, ∠C = π4
Å´¤ûª÷ BCE D Åçûª-®Ωçí¬ N¶µº->çîË
sin ∠BADE≠æpAh 1 : 3 Å®·ûË =
sin ∠CAD
1 1 1 √21) 2) 3) 4)
3 √3 √
6 3
(k + 1) + √k2+1
31. If sec.h−1 (2/3) = log [ ], then k =k
1) 2 2) 3 3) 5 4) 6
32. A spherical balloon of radius 5 subtends an angle 60° at the eye of the observer
while the angle of elevation of its centre is 30°. The height of the centre of the
balloon is
¢√u≤ƒ®Ωl¥ç 5 Ö†o äéπ íÓ∞«-é¬-®Ω°æ¤ ¶„©÷Ø˛ °æJ-Q-©-èπ◊úÕ éπçöÀ ´ü¿l îËÊÆ éÓùç 60°, ¶„©÷Ø˛ Íéçvü¿çÜ®Ωl¥ y-éÓùç 30° Å®·ûË Íéçvü¿ç ´ü¿l ¶„©÷Ø˛ áûª’h
1) 5 Units 2) 10 Units 3) 15 Units 4) 20 Units
α α33. If fr (α) = (cos + i sin )r2 r2
2α 2α α α(cos + i sin )................. (cos + i sin ) then limn→∞
fn(π) =r2 r2 r r
1) −1 2) 1 3) −i 4) i
2n
(1 + i)2n34. If n ∈ I, then + =
(1 + i)2n 2n
1) 0 2) 2 3) (1 + (−1)n).in
4) None of these
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35. The maximum value of 3z + 9 − 7i if z + 2 − i = 5 is
z + 2 − i = 5 Å®·ûË 3z + 9 − 7i í∫J≠æe N©’´
1) 10 2) 15 3) 20 4) 5
36. If r−
= 3i−
+ 2 j−
− 5 k−
, a− = 2i−
− j−
+ k−
, b−
= i−
+ 3 j−
− 2k−
and c−
= −2i−
+ j−
−
3 k−
such that r−
= λ a− + µ b−
+ ν c−
then
1) µ, λ−2
, ν are in A.P. 2) λ, µ, ν are in A.P.
3) λ, µ, ν are in H.P. 4) µ, λ, ν are in G.P.
37. Let V−
= 2 i−
+ j−
− k−
and W−
= i−
+ 3 k−
, if U−
is a unit vector, then the
maximum value of [ U−
V−
W−] is
U−
ߪ‚Eö¸ ÆæC¨¡ Å´¤ûª÷ V−
= 2 i−
+ j−
− k−
, W−
= i−
+ 3 k−
Å®·ûË [ U−
V−
W−] í∫J≠æe
N©’´
1) −1 2) √10 + √
6 3) √
59 4) √
60
38. The vectors AB−
= 3i−
+ 4k−
and AC−
= 5i−
− 2j−
+ 4k−
are the sides of a triangle
ABC. The length of the median through A is
AB−
= 3i−
+ 4k−
, AC−
= 5i−
− 2j−
+ 4 k−
©’ vA¶µº’ïç ABC ™ ¶µº’ñ«©’ Å®·ûË A O’ü¿’í¬
¢Á∞Ïx ´’üµ¿u-í∫-ûª-Í®ê §Òúø´¤
1) √72 2) √
33 3)√
288 4) √
18
−r
39. If a−
= i−
+ j−
, b−
= 2j−
− k−
and r−
× a−
= b−
× a−
, r−
× b−
= a−
× b−
then =r−
1 11) ( i
−+ 3 j
−− k
−) 2) ( i
−− 3 j
−+ k
−)
√11 √
11
13) ( i
−− j−
+ k−
) 4) None√
3
40. If (b−
× c−
) × (c−
× a−
) = 3c−
then [ b−
× c−
c−
× a−
a−
× b−
] =
1) 2 2) 7 3) 9 4) 11
1n
41. If ak = for k = 1, 2, 3, ...........n then ( Σ ak)2
=k (k + 1) k = 1
1 n
k = 1, 2, 3, ... ...........n èπ◊ ak = Å®·ûË ( Σ ak)2
=k(k + 1) k = 1
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n n2 n4 n61) 2) 3) 4)
n + 1 (n + 1)2 (n + 1)4 (n + 1)6
cosθ sinθ a b42. If = then + =
a b sec 2θ cosec 2θa
1) a 2) b 3) 4) a + bb
43. The locus of the point (r cos α cos β, r cos α sinβ, r sinα) is
(r cos α cos β, r cos α sinβ, r sinα) Gçü¿’´¤ Gçü¿’-°æü∑¿ç
1) x2 − y2 − z2 = r2 2) x2 + y2 + z2 = r2
3) x2 + y2 − z2 = r2 4) x2 − y2 + z2 = r2
44. When the angle of rotation of axes is tan−12, then transformed equation of
4xy − 3x2 = a2 is
Åé~¬-©†’ tan−1 2 éÓùç™ v¶µº´’ù °æJ- -®Ωh† îËÊÆh 4xy − 3x2 = a2 †÷ûª† ÆæO’-éπ-®Ωùç
1) X2 − 4Y2 = a2 2) 2X2 − Y2 = a2
3) 2X2 − 3Y2 = a2 4) 3X2 − 2Y2 = a2
45. The coordinates of a point on x + y + 3 = 0 whose distance from x + 2y + 2 = 0
is √5 are
x + 2y + 2 = 0 †’ç* √5 ü¿÷®Ωç™ Öçô÷ x + y + 3 = 0 O’ü¿ Ö†o Gçü¿’´¤
1) (9, 6) 2) (−9, 6) 3) (6, −9) 4) (−9, −6)
46. If a ≠ b ≠ c and if ax + by + c = 0, bx + cy + a = 0, cx + ay + b = 0
are concurrent then 2a2b−1c−1
. 2b2c−1a−1
. 2c2a−1b−1
=
a ≠ b ≠ c- Å®·u ax + by + c = 0, bx + cy + a = 0, cx + ay + b = 0 -Å-†’-≠æé¬h-™„j-ûË
2a2b−1c−1
. 2b2c−1a−1
. 2c2a−1b−1
=
1) 8 2) 0 3) 2 4) None
47. If (−4, 5) is one vertex and 7x − y + 8 = 0 is one diagonal of a square then the
perpendicular distance from (−3, 4) to the other diagonal is
îªûª’®ΩvÆæç™E äéπ Q®Ωç (–4, 5), äéπ éπ®Ωgç 7x − y + 8 = 0 Å®·ûË (–3, 4) Gçü¿’´¤ †’ç*È®çúÓ éπ®√g-EéÀ Ö†o ©ç•-ü¿÷®Ωç
4√2 2 √
2 √
2 3√
2
1) 2) 3) 4) 5 5 5 5
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48. The distance between the parallel lines given by
(x + 7y)2 + 4√2(x + 7y) − 42 = 0
(x + 7y)2 + 4√2(x + 7y) − 42 = 0 Ææ÷*çîË Ææ´÷ç-ûª®Ω Í®ê© ´’üµ¿u ü¿÷®Ωç
41) 2) 4 √
2 3) 2 4) 10 √
2
5 49. The reflection of the point p(1, 0, 0) in the line
x − 1 y + 1 z + 10 = = is
2 −3 8
x − 1 y + 1 z + 10 = = Í®ê°j p (1, 0, 0) Gçü¿’´¤ v°æA-Gç•ç
2 −3 8
1) (3, −4, −2) 2) (5, −8, −4) 3) (1, −1, −10) 4) (2, −3, 8)
50. A piece of ice in the form of a cube melts so that the percentage error in the side
is 0.7, then the percentage error in the volume is
äéπ °∂æ’Ø√-é¬-®Ω°æ¤ ´’ç-í∫úøf éπJ-Íí-ô-°æ¤púø’ v°æA¶µº’ïç™ 0.7% ûª®Ω’-í∫’-ü¿© éπE-°œÊÆh, Ç °∂æ’†ç°∂æ’†°æJ-´÷-ùç-™E Ææ’´÷®Ω’ üÓ≠æ-¨»ûªç
1) 0.7 2) 1.4 3) 2.1 4) None
51. The value of
1 2 n − 1 n n nlim 1 e e e
n→∞ [ + + + ...... + ]isn n n n
1) 1 2) 0 3) e + 1 4) e − 1
[(a − n)nx − tan x ] sin nx52. If lim = 0, n ≠ 0 then a =
x→0 x2
1 11) 0 2) n + 3) 1 + 4) n
n n
x2 − x d f −1(x)53. If f(x) = then =
x2 + 2x dx
3 −3 3 −31) 2) 3) 4)
1− x2 1 − x2 (1 − x)2 (1 − x)2
1 + x 1 dy54. If y = log(
1
)4 − tan−1 x then =
1 − x 2 dx
x2 2x21) 2)
1 − x4 1 − x4
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x23) 4) None of these
2(1 − x4)
55. Minimum value of f(x) = (sin−1 x)3 + (cos−1 x)3 (−1 < x < 1)
7π3 3π3 π3 3π31) 2) 3) 4)
8 8 32 16
56. The acute angle between the curves y = x2 − 1 and y = x2 − 3 at their point
of intersection when x > 0 is
x > 0 Å®·-†-°æ¤púø’ y = x2 − 1, y = x2 − 3 © êçúø† Gçü¿’´¤ ´ü¿l ´v鬩 Å©p-éÓùç
4 4√2
1) tan−1 () 2) tan−1()7√2 7
43) tan ( ) 4) None
7
dx57. ∫ =
x(xn + 1)
1 xn 1 xn + 11) log ( ) + c 2) log ( ) + c
n xn + 1 n xn
xn3) log ( ) + c 4) None
xn + 1
(x2 − 1)dx 58. ∫ =
(x4 + 3x2 + 1) tan−1 x2 + 1( )x1 1
1) log tan (x + ) + C 2) log tan−1(x + ) + Cx x
13) log sec−1(x + ) + C 4) None of these
x3π−2
2x59. ∫
0sin [ ] dx where [ . ] denotes the greatest integer
π
1) π−2
(sin 1 + cos 1) 2) π−2
(sin 1 − cos 2)
3) π−2
(sin 1 − cos 1) 4) π−2
(sin 1 + cos 2)
cos3x60. If ∫ dx = log sin x+ A sin x + c then A =
sin2x + sin x
1) 0 2) 1 3) −1 4) 2
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61. If the area lying between the curves y = ax2 and x = ay2 is 1 square unit. Then a =
y = ax2, x = ay2 ´v鬩 ´’üµ¿u v°æü˨¡ ¢Áj¨»©uç 1 îª.ߪ‚-Eö¸ Å®·ûË a =
1) 1−√
3
2) 1−2
3) 1−3
4) √3
62. For x > 0 the integrating factor of x2 dydx
+ 3xy − 1 = 0
x > 0 Å®·ûË x2 dydx
+ 3xy − 1 = 0 Ææ´÷-éπ-©† 鬮Ω-ù«çéπç
1) x 2) x2 3) x3 4)1x3
63. The general solution of ey dydx
+ 2 ey
x
= sin x
1) xey = −x cos x + sin x + c
2) x2ey = −x2 cos x − 2x sin x − cos x + c
3) xey = x cos x − sin x + c
2 sin x cos x c4) ey = −cos x + + +
x x2 x2
64. Equation of circle whose radius is 5 and which touch the circle x2 + y2 − 2x− 4y −20 = 0 at (5, 5) is
´%ûªh ¢√u≤ƒ®Ωl¥ç 5 Ö†o x2 + y2 −2x −4y − 20 = 0 ´%û√hEo (5, 5) Gçü¿’´¤ ´ü¿l Ææp %PçîË´%ûªh ÆæO’éπ®Ωùç
1) (x − 9)2 + (y − 8)2 = 5 2) (x − 9)2 + (y + 8)2 = 25
3) (x − 1)2 + (y − 2)2 = 25 4) (x − 9)2 + (y − 8)2 = 25
65. Equations of the tangents of
x2 + y2 + 4x + 6y − 12 = 0 perpendicular to 4x + 3y + 1 = 0 are
4x + 3y + 1 = 0 Í®êèπ◊ ©ç•çí¬ ÖçúË x2 + y2 + 4x + 6y − 12 = 0 Ææp®Ωz-Í®-ê©’
1) 3x − 4y − 31 = 0, 3x − 4y + 19 = 0
2) 3x − 4y + 31 = 0, 3x − 4y − 19 = 0
3) 3x − 4y − 21 = 0, 3x − 4y + 20 = 0
4) 3x − 4y − 41 = 0, 3x − 4y − 20 = 0
66. If (a, −3), ( 8−15
, 2) are conjugate points w.r.to
circle 2x2 + 2y2 + 7x + 14y + 8 = 0 the value of a is
2x2 + 2y2 + 7x + 14y + 8 = 0 ´%ûªhç ü¿%≥ƒd u (a, −3), ( 8−15
, 2) Ææçߪ·í∫t Gçü¿’-´¤©’
Å®·ûË a N©’´
1) −2 2) −3 3) 2 4) 3
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67. The circles whose equations are x2 + y2 + 10x − 2y + 22 = 0 and
x2 + y2 + 2x − 8y + 8 = 0 touch each other, the circle which touch both circles
at the point of contact and passes through (0, 0) is
x2 + y2 + 10x − 2y + 22 = 0, x2 + y2 + 2x − 8y + 8 = 0 ÅØË ´%û√h©†’ Ææp®Ωz Gçü¿’´¤´ü¿l Ææp %PÆæ÷h (0, 0) O’ü¿’í¬ ¢Á∞Ïx ´%ûªh ÆæO’-éπ-®Ωùç
1) 9(x2 + y2) − 15x − 20y = 0 2) 5(x2 + y2) − 18x − 80y = 0
3) 7(x2 + y2) − 18x − 80y = 0 4) x2 + y2 − 9x − 40y = 0
68. The radical axis of two circles x2 + y2 + 4x + 2y − 4 = 0,
x2 + y2 − 2x − 4y − 20 = 0 divides the line segment joining the centres of circle
in the ratio is
x2 + y2 + 4x + 2y − 4 = 0, x2 + y2 − 2x − 4y − 20 = 0 ÅØË ´%û√h© ´‚™«éπ~ç´%ûªhÍéçvü∆-©†’ éπLÊ° Í®ë«-êç-ú≈Eo N¶µº>çîË E≠æpAh
1) 1 : 4 2) 4 : 1 3) 1 : 17 4) 17 : 1
69. If the ends of a focal chord of the parabola y2 = 4ax are (x1, y1) and (x2, y2) then
x1 x2 + y1y2 =
y2 = 4ax °æ®√- -©ßª’ç Ø√Gµ ñ«u * -®Ω©’ (x1, y1), (x2, y2) Å®·ûË x1 x2 + y1y2 =
1) a2 2) −3a2 3) 5a2 4) −5a2
70. Match the eccentricities of the following.
éÀçC¢√öÀ ÖûË\ç-vü¿-ûª-©†’ ïûª-°æ-®Ω-îªçúÕ.
List - I List - II
x2 y2 7A) + = 1 1) √
9 16 10
x2 y2√
3
B) + = 1 2) 25 9 2
C) 3(x − 1)2 + 12(y − 1)2 = 36 3) 45
√7
D) 3x3 + 10y2 = 30 4) 4
1) A−3, B−1, C−2, D−4
2) A−3, B−2, C−1, D−4
3) A−4, B−1, C−3, D−2
4) A−4, B−3, C−2, D−1
71. If e1 and e2 are the eccentricities of the hyperbola xy = c2, x2 − y2 = c2
then e12+ e
22 =
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xy = c2, x2 − y2 = c2 ÅA °æ®√-´-©-ߪ÷© ÖûË\ç-vü¿-ûª©’ e1, e2 Å®·ûË e12 + e
22 =
1) 1 2) 4 3) 6 4) 8
72. The tangent at any point on the curve x = acos3θ, y = asin3θ meets the axes in
P and Q. The locus of the midpoint of PQ is
x = acos3θ, y = asin3θ ´vé¬-©èπ◊ àüÁjØ√ Gçü¿’´¤ †’ç* UÆœ† Ææp®Ωz-Í®ê Åé~¬-©†’ P, Q © ´ü¿lÆæp %PÊÆh PQ ´’üµ¿u Gçü¿’´¤ Gçü¿’-°æü∑¿ç
1) x3−2 + y
3−2 = a
3−2 2) x
2−3 + y
2−3 = a
2−3
3) 4(x + y) = a 4) 4 (x2 + y2) = a2
73. If β is the acute angle between the lines px + qy = p + q and
p(x − y) + q(x + y) = 2q. Then the value of sin β
px + qy = p + q, p(x − y) + q(x + y) = 2q ÅØË Í®ê© ´’üµ¿u Å©p-éÓùç β Å®·ûË sin β N©’´
√3 1
1) 2) 34
3) 12
4) 2 √
2x − 3 y − 8 z − 3
74. The shortest distance between lines = = and3 −1 1
x + 3 y + 7 z − 6 = = is−3 2 4
x − 3 y − 8 z − 3 x + 3 y + 7 z − 6 = = , = = ÅØË Í®ê© ´’üµ¿u éπE≠æe ü¿÷®Ωç
3 −1 1 −3 2 4
1) 3 √30 2) √
30 3) 2 √
30 4) 4√
30
75. 72n + 3n − 1. 23n − 3 is divisible by
72n + 3n − 1. 23n − 3 †’ ¶µ«TçîË Ææçêu
1) 24 2) 25 3) 9 4) 13
76. f(x) = kx3 − 9x2 + 9x + 3 is increasing for all x then
x ÅEo N©’-´-©èπ◊ f(x) = kx3 − 9x2 + 9x + 3 -Ǯӣæ«ùç Å®·ûË
1) k < 3 2) k < −1 3) k > 3 4) k < −2
77. On the interval [0, 1] the function x25(1 − x)75 takes maximum value at
[0, 1] Åçûª-®Ωç™ x25(1 − x)75 v°æ¢Ë’ߪ’ç í∫J≠æeç 鬢√-©çõ‰
1) x = 0 2) x = 12
3) x = 1 4) x = 14
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78. If α, β, γ, δ are four solutions of the equation tan (θ + π4) = 3 tan 3θ, no two of
which have equal tangents then the value of tan α + tan β + tan γ + tan δ is
à È®çúø’ Ææp®Ωz-Í®-ê©’ Ææ´÷†ç é¬E tan (θ + π4) = 3 tan 3θ ÆæO’-éπ-®Ω-ù«-EéÀ 4 ´‚™«©’
α, β, γ, δ Å®·ûË tan α + tan β + tan γ + tan δ =
1) 1 2) 0 3) −2 4) None
9 √x
79. ∫ dx =
4 √x − 1
1) 7 + 2 log 2 2) 5 + 2 log 2 3) 2 + log 2 4) None
80. f is function such that f(x + y) = f(x) + f(y) ∀ x, y and f(1) = 2
If φ (x) =x
0∫ ƒ (2t) dt then φ'(3) =
xy ÅEo N©’-´-©èπ◊ f(x + y) = f(x) + f(y), f(1) = 2 ÅßË’u™« f äéπ v°æ¢Ë’ߪ’ç Å´¤ûª÷
φ (x) = x
0∫ ƒ (2t) dt Å®·ûË φ'(3) =
1) 3 2) 4 3) 6 4) 12
PHYSICS1000V
81. The current, voltage relation of a diode is given by i = (e T - 1) mA, where
the applied voltage 'V' is in volts and the temperature 'T' is in kelvin. If a student
makes an error measuring ± 0.01 V while measuring the current of 5 mA at
300 K. The error in measuring the current value in mA will be
1000V
äéπ úøßÁ÷ú˛ Nü¿’uû˝, ¢Ó™‰d>© ´’üµ¿u Ææç•ç-üµ∆Eo Ææ÷*çîË ÆæO’-éπ-®Ωùç i = (e T - 1) mA,
v°æßÁ÷-Tç-*† ¢Ó™‰d> 'V' 㙸d©™, Ö≥Úg-ví∫ûª 'T' ÈéLy-Ø˛™ ÖØ√o®·. äéπ Nü∆uJn 300 K
Ö≥Úg-ví∫ûª ´ü¿l 5 mA Nü¿’uû˝ v°æ¢√-£æ…Eo éÌL-îË-ô-°æ¤púø’ îËÆœ† üÓ≠æç ± 0.01VÅ®·ûË, Nü¿’uû˝v°æ¢√-£æ…Eo éÌ©-´-ôç™ üÓ≠æç N’Mx Çç°œ-ߪ’-®Ωx™
1) 0.5 2) 0.2 3) 0.05 4) 0.02
82. The special number π is defined as the ratio of circumference of a circle to its
diameter. The number of significant digit in it
v°æûËuéπ Ææçêu π E äéπ ´%ûªhç °æJ-CµéÀ, ü∆E ¢√u≤ƒ-EéÀ Ö†o E≠æpAhí¬ E®Ωy-*ÊÆh, Åçü¿’-™E ≤ƒ®Ωnéπ
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Ææçêu©’
1) 1 2) 2 3) 3 4) infinity (ņçûªç)
83. Six coplanar forces having magnitudes 1 N, 2 N, 3 N, 4 N, 5 N and 6 N are
acting simultaneously on a particle. If their directions are represented by the six
sides of a regular hexagon taken in order, the magnitude of their resultant is
1 N, 2 N, 3 N, 4 N, 5 N, 6 N °æJ-´÷-ù«©’†o Ç®Ω’ Ææûª-Mߪ’ •™«©’ àéπ-é¬-©ç™ äéπ éπùçO’ü¿ °æE-îËÆæ’hØ√o®·. ¢√öÀ C¨¡-©†’ äéπ véπ´’ç™ BÆæ’èπ◊çõ‰, äéπ véπ´’-≠æ-úø’s¥> Ç®Ω’ ¶µº’ñ«©’Ææ÷*ÊÆh, ¢√öÀ °∂æLûª •© °æJ-´÷ùç
1) zero (Ææ’Ø√o) 2) 3√3 N 3) 6 N 4) 9 N
84. The position of an object moving along X - axis is given by x = a + bt2 where
a = 8.5 m, b = 2.5 ms−2 and 't' is in seconds. The average velocity of the object
between t = 2.0 s and t = 4.0 s is
X- Åéπ~ç ¢Áç•úÕ v°æߪ÷-ùÀçîË äéπ ´Ææ’h´¤ ≤ƒnØ√Eo Ææ÷*çîË ÆæO’-éπ-®Ωùç x = a + bt2 ™a = 8.5 m, b = 2.5 ms−2, 't' ÂÆéπ-†x™ ÖØ√o®·. t = 2.0 s, t = 4.0 s ´’üµ¿u ´Ææ’h´¤ Ææí∫ô’¢Ëí∫ç
1) 0 ms−1 2) 10 ms−1 3) 1.5 ms−1 4) 15 ms−1
85. A body moves with a speed t − 2 ms−1, the distance travelled by it in first four
seconds is
äéπ ´Ææ’h´¤ ´úÕ t − 2 ms−1 Å®·ûË ¢Á·ü¿öÀ Ø√©’í∫’ ÂÆéπ-†x™ ÅC v°æߪ÷-ùÀçîË ü¿÷®Ωç
1) 4 m 2) 8 m 3) 2 m 4) 0 m
86. For a particle thrown slantwise from a point on the ground, the time of flight is
T. At time t = T4
and t = T2
, it is found to be at heights 'h' and 'H' above the
ground respectively. The ratio hH is
¶µº÷N’ O’ü¿ Ö†o Gçü¿’´¤ †’ç* àô-¢√©’í¬ v°æéÀ~°æhç îËÆœ† äéπ éπù«-EéÀ °æ™«-ߪ’† 鬩ç T.
鬩ç t = T4, t = T2 ´ü¿l ÅC ¶µº÷N’ †’ç*´®Ω’-Ææí¬ 'h', 'H' áûª’h© ´ü¿l Öçõ‰ h
HE≠æpAh N©’´
4 3 2 11) 2) 3) 4)
5 4 3 2
87. A force 'F' acting on a body depends on its displacement 'S' as F ∝ (S)−1/3. The
power delivered by 'F' will depend on displacement as
äéπ ´Ææ’h-´¤Â°j °æE-îËÊÆ •©ç 'F' ü∆E ≤ƒn†-v¶µºç¨¡ç 'S' O’ü¿ F ∝ (S)−1/3 ÅßË’u Nüµ¿çí¬Çüµ∆®Ω°æúø’-ûª’çC. •©ç 'F' ´©x éπLÍí ≤ƒ´’®Ωn uç, ≤ƒn†-v¶µºç- ¡ç°j éÀçC Nüµ¿çí¬ Çüµ∆-®Ω-°æ-úø’-ûª’çC
1) S1/2
2) S0 3) S2/3
4) S−5/3
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88. When a ball is released from a height 'h' above a horizontal sand surface, it
penetrates into the sand to a depth of h−8
. If 'g' is acceleration due to gravity the
initial vertical speed that must be given to the ball from that point, so that it again
rises to the initial point of release is
éÀ~Aï Ææ´÷ç-ûª®Ω ÉÆæ’éπ ûª©ç †’ç* 'h' áûª’h† Ö†o äéπ Gçü¿’´¤ †’ç* äéπ •çAE éÀçCéÀñ«®Ω-N-úÕ-*-†-°æ¤púø’, •çA ÉÆæ’-éπ-™éÀ h−
8™ûª’èπ◊ îÌa-éÌ-E-§Ú-ûª’çC. •çA ¢Á·ü¿ô ñ«®Ω-N-úÕ-*†
Gçü¿’-´¤èπ◊ îË®√-©çõ‰, ÉÆæ’-éπ-™E Ç Gçü¿’´¤ †’ç* •çAE Eôd-E-©’´¤í¬ °jéÀ NÆæ-®√-Lq† ûÌL´úÕ N©’´ (g í∫’®Ω’ûªy ûªy®Ωùç)
9gh1) √
2) √4gh 3) √
9gh 4) √
8gh
2
89. A particle of mass 1 kg and carrying a charge 0.01 C is at rest on an inclined
490plane of angle 30° with horizontal when an electric field of NC
−1is applied
√3
parallel to horizontal. The coefficient of friction between the particle and inclinedplane is
490éÀ~Aï Ææ´÷ç-ûª®Ω C¨¡™ NC
−1 °æJ-´÷ùç Ö†o äéπ Nü¿’uû˝ Íé~vû√Eo v°æßÁ÷-Tç-*-†-°æ¤púø’ √3
1 Kg vü¿´u-®√P, 0.01 C Nü¿’u-ü∆-¢Ë¨¡çûÓ Ö†o äéπ éπùç éÀ~Aï Ææ´÷ç-ûª-®ΩçûÓ 30° éÓùç îËÆæ’h†o¢√©’-ûª©ç°j E¨¡a© ÆœnA™ ÖçC. éπùç, ¢√©’-ûª©ç ´’üµ¿u °∂æ’®Ωù í∫’ùéπç
√3 1 1 √
3
1) 2) 3) 4) 2 2 √
3 7
90. An inclined plane makes an angle of 30° with the horizontal. The upper half of
the inclined plane is perfectly smooth and the lower half is rough. Starting from
rest a small block begins to slide down the inclined plane from the top and comes
to rest at the bottom. The coefficient of friction in the lower half is
äéπ ¢√©’-ûª©ç éÀ~Aï Ææ´÷ç-ûª-®ΩçûÓ 30° éÓùç îË≤ÚhçC. ¢√©’-ûª©ç áí∫’´ Ææí∫ç †’†oí¬, Cí∫’´Ææí∫ç í∫®Ω’-èπ◊í¬ ÖØ√o®·. ¢√©’-ûª©ç °j¶µ«-í¬† E¨¡a© ÆœnA™ Ö†o äéπ *†o C¢Á’t ¢√©’-ûª©ç¢Áç•úÕ éÀçCéÀ ñ«®Ω’ûª÷ ´*a ¢√©’-ûª©ç Åúø’-í∫’-¶µ«-í¬† E¨¡a© ÆœnAéÀ ´*açC. ¢√©’-ûª©ç Cí∫’´Ææí¬-EéÀ °∂æ’®Ωù í∫’ùéπç
1 2 4 11) 2) 3) 4)
2√3 √
3 √
3 √
3
91. A neutron of mass 'm' is approaching a stationary deuterium nucleus of mass
'2 m'. The ratio of the de Broglie wavelengths of the neutron and deuterium
nucleus in the frame of reference of the centre of mass of the system is
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m vü¿´u-®√P Ö†o äéπ †÷uvö«Ø˛, E¨¡a© ÆœnA™ Ö†o 2 m vü¿´u-®√P Ö†o äéπ úø’uöÃ-Jߪ’çÍéçvü¿-é¬Eo ÆæO’-°œ-≤ÚhçC. ´u´Ææn vü¿´u-®√P Íéçvü¿ EÍ®l¨¡ îªvôç ü¿%≥ƒd u †÷uvö«Ø˛, úø’uöÃ-Jߪ’çÍéçvü¿-鬩 úŒ v¶-Ux ûª®Ωç-í∫-üÁj-®√` u© E≠æpAh
1) 1 : 2 2) 2 : 1 3) 1 : 1 4) √2 : 1
92. Two particles moving in the opposite direction along the same horizontal with
velocities v1 and v2 collide with each other. If 'e' is the coefficient of restitution,
then their distance of separation at time 't' after collision is
È®çúø’ éπù«©’ äéπ éÀ~Aï Ææ´÷ç-ûª®Ω Í®ê ¢Áç•úÕ v1, v2 ¢Ëí¬-©ûÓ °æ®Ω-Ææp®Ωç ´uA-Í®éπ C¨¡™xv°æߪ÷-ùÀÆæ÷h ÅGµ-°∂æ÷ûªç îÁçü∆®·. v°æû√u- -≤ƒn† í∫’ùéπç 'e' Å®·ûË, ÅGµ-°∂æ÷ûªç ïJ-T† 't' 鬩çûª®√yûª ¢√öÀ ´’üµ¿u ü¿÷®Ωç
1) te (v1 + v2) 2) te (v1 − v2) 3) te(v2 − v1) 4) te ( v1v2)
93. A uniform solid sphere of radius 0.2 m and mass 5 kg rotates about its diameter.
Angular velocity of the sphere changes with time 't' according to the equation
ω = (3 + 5t) rad s−1. The tangential force applied to the sphere is
0.2 m ¢√u≤ƒ®Ωl¥ç, 5 kg vü¿´u-®√P Ö†o äéπ àéπ-KA °∂æ’†-íÓ∞¡ç ü∆E ¢√uÆæç ü¿%≥ƒd u v¶µº´’-ù«©’îË≤ÚhçC. íÓ∞¡ç éÓùÃߪ’¢Ëí∫ç 鬩ç 't' ü¿%≥ƒd u ω = (3 + 5t) rad s−1 ÆæO’-éπ-®Ωùç ü¿%≥ƒd u´÷®Ω’-ûÓçC. íÓ∞¡ç°j °æE-îËÊÆ Ææp®Ωz-Í®-&ߪ’ •©ç
1) 4 N 2) 2 N 3) 3 N 4) 1 N
94. Two blocks of masses 3 kg and 6 kg are kept on a smooth horizontal floor. The
blocks are connected together by a light spring of force constant 20 N/m. Steady
forces of 5 N and 5 N are applied on the blocks to stretch the spring. If the
applied forces are suddenly removed, the minimum time after which the spring
will have its minimum length (π2 = 10)
3 kg, 6 kg vü¿´u-®√¨¡Ÿ©’†o È®çúø’ C¢Á’t©†’ éÀ~Aï Ææ´÷ç-ûª®Ω †’†’°j† ûª©ç°j Öçî√®Ω’.È®çúø’ C¢Á’t©†’ 20 N/m •©-Æœn-®√çéπç Ö†o äéπ ûËL-Èéj† vÆœpçí∫’ Ææ£æ…-ߪ’çûÓ éπL§ƒ®Ω’. vÆœpçí∫’≤ƒÍíNüµ¿çí¬ 5 N, 5 N Æœn®Ω •™«©†’ C¢Á’t-©Â°j v°æßÁ÷-Tç-î√®Ω’. v°æßÁ÷-Tç-*† •™«-©†’Åéπ-≤ƒtûª’hí¬ ûÌ©-TÊÆh, vÆœpçí∫’ éπE≠æe §Òúø-´¤†’ §Òçü¿-ú≈-EéÀ °æõ‰d éπFÆæ Æ洒ߪ’ç (π2 = 10)
1) 2 S 2) 1 S 3) 14
S 4) 12
S
95. If the minimum and maximum distances of an orbiting satellite from the Earth's
centre are 2 R and 4 R respectively (R = Radius of Earth), then the ratio of
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smooth floor
5 N5 N
3 kg 6 kgK = 20 N/m
→
→
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minimum to maximum speed of the satellite is
¶µº÷N’ ô÷d °æJ-v¶µº-N’-Ææ’h†o äéπ Ö°æ-ví∫-£æ…-EéÀ ¶µº÷N’ Íéçvü¿ç †’ç* Ö†o éπE≠æe, í∫J≠æe ü¿÷®√©’´®Ω’-Ææí¬ 2 R, 4 R (R = ¶µº÷N’ ¢√u≤ƒ®Ωl¥ç) Å®·ûË, Ö°æ-ví∫£æ«ç éπE≠æe ´úÕéÀ, í∫J≠æe ´úÕéÀ Ö†oE≠æpAh
1) 1 : 3 2) 2 : 3 3) 1 : 2 4) 3 : 5
96. A uniform metal wire elongates by 2 mm when a load of weight W is suspended
from its free end. If this wire is passed over a smooth, light pulley and weights
each of W are hung at two free ends of the wire, then the elongation of the wire is
äéπ àéπ-KA ™£æ«°æ¤ Bí∫ ÊÆyî√a ¥ é̆ †’ç* W ¶µ«®Ωç Ö†o äéπ C¢Á’t†’ ¢Ë™«úø-D-Æœ-†-°æ¤púø’Bí∫-™E ≤ƒí∫’-ü¿© 2 mm. Ñ Bí∫†’ äéπ ûËL-Èéj†, °∂æ’®Ω-ù-®Ω-£œ«ûª éπ°‘p O’ü¿’í¬ §ÚE*a, Bí∫ È®çúø’ÊÆyî√a ¥ é̆© †’ç* äéÌ\-éπ\öÀ W ¶µ«®Ωç Ö†o È®çúø’ C¢Á’t-©†’ ¢Ë™«úø-DÊÆh Bí∫-™E ≤ƒí∫’-ü¿©
1) 12
mm 2) 4 mm 3) 1 mm 4) 2 mm
97. When a soap bubble is blown, the work done per unit volume of the bubble is (P
is excess pressure inside the soap bubble)
äéπ Ææ•’s •’úø-í∫†’ ÜC-†-°æ¤púø’, •’úøí∫ àé¬çéπ °∂æ’†-°æ-J-´÷-ù«-EéÀ ïJT† °æE (Ææ•’s •’úø-í∫-™EÅü¿-†°æ¤ °‘úø†ç P)
3P 3P 2P P1) 2) 3) 4)
2 4 3 2
98. From the given graph between centigrade (°C) and
Fahrenheit (°F) temperature of a body, the angle
made by the graph line with Fahrenheit axis is
äéπ ´Ææ’h´¤ ÂÆçöÃ-vÍíú˛ Ö≥Úg-ví∫ûª (°C), §∂ƒÈ®-Ø˛-£‘«ö¸
Ö≥Úg-ví∫ûª (°F) ©èπ◊ UÆœ† ví¬°∂ˇ †’ç* ví¬°∂ˇ Í®ê
§∂ƒÈ®-Ø˛-£‘«ö¸ Åéπ~çûÓ îËÊÆ éÓùç
5 5 5 51) tan−1 () 2) cos−1() 3) sin−1() 4) cos−1 ()106 106 √
106 √
106
99. An insulated container contains 4 moles of an ideal diatomic gas at a
temperature T. Heat Q is supplied to this gas, due to which 2 moles of the gas are
dissociated into atoms, but temperature of the gas remains constant. Then
(R = universal gas constant)
äéπ Ö≠æg-•ç-üµ¿é𠧃vûª™ T Ö≥Úg-ví∫ûª ´ü¿l 4 ¢Á÷™¸© äéπ Çü¿®Ωz Cy°æ-®Ω-´÷-ù’éπ ¢√ߪ·´¤ ÖçC.Ñ ¢√ߪ·-´¤èπ◊ Q Ö≠æg-¨¡-éÀhE Åçü¿ñ‰ßª’úøç ´©x 2 ¢Á÷™¸© ¢√ߪ·´¤ °æ®Ω-´÷-ù’-´¤-©’í¬NúÕ§Úûª’çC. R ≤ƒ®Ωy-vAéπ ¢√ߪ· Æœn®√çéπç Å®·ûË
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°C
α°F
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1) Q = 2RT 2) Q = RT 3) Q = 4RT 4) Q = 3RT
100. Nitrogen though a diatomic gas exhibits vibrations at higher temperatures. The ratio
of the specific heat at constant pressure to the specific heat at constant volume is
ØÁjvö-ïØ˛ Cy°æ-®Ω-´÷-ù’éπ ¢√ߪ·´¤ Å®·-†-°æp-öÀéÃ, ÅCµéπ Ö≥Úg-ví∫-ûª© ´ü¿l éπç°æ-Ø√-©†’ v°æü¿-Jz-Ææ’hçC.Æœn®Ω-°‘-úø†ç ´ü¿l ¢√ߪ· NP-≥Úd-≥ƒg-EéÀ, Æœn®Ω °∂æ’†-°æ-J-´÷ùç ´ü¿l ¢√ߪ· NP-≥Úd--≥ƒg-EéÀ Ö†o E≠æpAh
1) 9−7
2) 5−3
3) 7−5
4) 8−6
101. A transverse wave of amplitude 10 cm is generated at one end (x = 0) of a long
stretched string by a tuning fork of frequency 500 Hz. At a certain instant of time,
the displacement of a particle at 'A' (at x = 100 cm) is −5 cm and of a particle B
(at x = 200 cm) is +5 cm. The speed of the wave is
500 Hz §˘†”-°æ¤†uç Ö†o äéπ ¨¡%A ü¿çúøç Ææ£æ…-ߪ’çûÓ äéπ §Òúø-¢Áj† ≤ƒí∫-D-Æœ† Bí∫ äéπ é̆ (x = 0) ´ü¿l 10 cm éπç°æ† °æJ-N’A Ö†o äéπ A®Ωué˙ ûª®Ωç-í¬Eo à®Ωp-J-î√®Ω’. äé¬-ØÌéπ 鬩ç'A' ´ü¿l Ö†o äéπ éπùç (x = 100 cm ´ü¿l) ≤ƒn†-v¶µºç¨¡ç −5 cm, B ´ü¿l Ö†o ´’®Ó éπùç(x = 200) ≤ƒn†-v¶µºç¨¡ç +5 cm -Å®·-ûË ûª®Ωçí∫ ¢Ëí∫ç
1) 500 ms−1 2) 1000 ms−1 3) 750 ms−1 4) 250 ms−1
102. In a closed organ pipe of length l air particles are vibrating with a maximum
amplitude A in the third overtone. Then the amplitude of vibration for the air
lparticles at a distance of from the closed end is
14
l §Òúø ¤†o äéπ ´‚Æœ† íÌôdç™E í¬LÆæh綵ºç ´‚úÓ ÅAÆæy®√Eo ¢Á©’- -Jç-*-†-°æ¤púø’ Åç-ü¿’™E
lí¬L éπù«©’ A í∫J≠æe éπç°æ† °æJ-N’-AûÓ éπç°æ-Ø√©’ îË≤ÚhçC. íÌôdç ´‚Æœ† é̆ †’ç*
14
ü¿÷®Ωç™ Ö†o í¬L éπù«© éπç°æ† °æJ-N’A
A A1) A 2) 2 A 3) 4)
2 √2
103. A point object is placed at 8 cm infront of a glass slab of thickness 6 cm whose
back face is silvered. If the final image is formed 10 cm behind the silvered face,
then the refractive index of the glass is
6 cm ´’çü¿ç Ö†o äéπ í¬V C¢Á’t ´·çü¿’ äéπ Gçü¿’-®Ω÷°æ ´Ææ’h-´¤†’ 8 cm ü¿÷®Ωç™
Öçî√®Ω’. í¬V C¢Á’t ¢Á†’éπ ûª™«-EéÀ éπ∞«®· °æ‹¨»®Ω’. ûª’C v°æA-Gç•ç éπ∞«®· °æ‹Æœ† ûª™«-EéÀ
¢Á†’éπ 10 cm ü¿÷®Ωç™ à®Ωp-úÕûË, í¬V ´véÃ-¶µº- † í∫’ùéπç N©’´
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2 5 √3
1) 1.5 2) 3) 4) 3 4 2
104. A rectangular block of glass is placed on a printed page lying on a horizontal
surface. The minimum value of refractive index of glass for which the letters on
the page are not visible from any of the vertical faces of the block will be
äéπ éÀ~Aï Ææ´÷ç-ûª®Ω ûª©ç°j Åéπ~-®√©’ ´·vCç-*† é¬T-û√Eo °öÀd, é¬T-ûªç°j äéπ D®Ω`-îª-ûª’-®Ω-v≤ƒé¬®Ωí¬V-C-¢Á’t†’ Öçî√®Ω’. C¢Á’t à E©’´¤ ûª©ç ü∆y®√ èπÿú≈ é¬T-ûªç°j Ö†o Åéπ~-®√©’éπE°œçîªèπ◊çú≈ Öçú≈©çõ‰ í¬V éπE≠æe ´véÃ-¶µº- † í∫’ùéπç N©’´
1) 1.732 2) 1.414 3) 1.5 4) 1.707
105. White light may be considered to be a mixture of waves of wavelength ranging
between 3000 A° and 7800 A°. An oil film of thickness 10,000 A° is examined
normally by the reflected light. If refractive index of oil is 1.4, then the film
appears bright for the wavelengths
ûÁ©’-°æ¤-®Ωçí∫’ é¬çAE 3000 A°, 7800 A° ûª®Ωçí∫ üÁj®Ω` u Å -Cµ-™E é¬çA ûª®Ωç-í¬© Ææ¢Ë’t-∞¡-†çí¬¶µ«Nç-îª- -a. 10,000 A° ´’çü¿´·†o äéπ ûÁj©°æ¤ §Ò®Ω†’ ÅGµ©ç• °æ®√- -®Ωh† é¬çAûÓ°æKéÀ~≤ƒh®Ω’. ûÁj©ç ´véÃ-¶µº- † í∫’ùéπç 1.4, Å®·ûË ûÁj©°æ¤ §Ò®Ω Ñ ûª®Ωçí∫ üÁj®√` u-©èπ◊ é¬çA-´ç-ûªçí¬ éπE-°œ-Ææ’hçC.
1) 4308 A°, 5091 A°, 6222 A° 2) 4000 A°, 5091 A°, 5600 A°
3) 4667 A°, 6222 A°, 7000 A° 4) 4000 A°, 4667 A°, 5600 A°, 7000 A°
106. Three identical charges each of + 0.1 C are placed at three vertices of an
equilateral triangle of side 1 m. Energy is supplied to the system at a rate of 1
kilowatt and the charge at any one of the three vertices is taken to top the mid
point of the line joining the other two charges. The number of days required to do
so is nearly
äéÌ\-éπ\öÀ + 0.1 C Ö†o ´‚úø’ Ææ®Ωy-Ææ- ÷† Nü¿’u-ü∆-¢Ë- »-©†’ 1 m ¶µº’ïç Ö†o äéπ Ææ ’-¶«£æ›vA¶µº’ïç ´‚úø’ Q®√© ´ü¿l Öçî√®Ω’. ´u -Æænèπ◊ 1 éÀ™-¢√ö¸ Í®ô’™ ¨¡éÀhE ÅçCç*, ´‚úø’ Q®√©´ü¿l Ö†o Nü¿’u-ü∆-¢Ë »™x àüÁjØ√ äéπü∆Eo N’T-L† È®çúø’ Ç¢Ë- »-©†’ éπLÊ° Ææ®Ω-∞¡-Í®ê ´’üµ¿u Gçü¿’´¤´ü¿lèπ◊ BÆæ’èπ◊ ´î√a®Ω’. Å™« îËߪ’ú≈-EéÀ °æõ‰d ®ÓV© Ææçêu Ææ’´÷-®Ω’í¬
1) 20 2) 28 3) 2 4) 4
107. A parallel plate condenser consists of two circular plates each of radius 2 cm
separated by a distance of 0.1 mm. A time varying potential difference of
5 × 1013 VS−1 is applied across the plates of the condenser. The displacement
current is
äéπ Ææ´÷ç-ûª®Ω °æ©-éπ© È駃-Æœô®˝ È®çúø’ °æ©-éπ© ´’üµ¿u ü¿÷®Ωç 0.1 mm, äéÌ\-éπ\öÀ 2 cm
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¢√u≤ƒ®Ωl¥ç Ö†o È®çúø’ ´%û√h-é¬®Ω °æ©-éπ©’. È®çúø’ °æ©-éπ© ´’üµ¿u 鬩ç-ûÓ-§ƒô’5 × 1013 VS−1 Í®ô’™ ´÷®Ω’-ûª’†o äéπ §Òõ„-E-ߪ’™¸ --¶µ‰-ü∆Eo éπ©-í∫-ñ‰-¨»®Ω’. ≤ƒn†-v¶µºç¨¡ Nü¿’uû˝v°æ¢√£æ«ç
1) 5.50 A 2) 2.28 × 104 A
3) 5.56 × 102 A 4) 5.56 × 103
108. In the circuit shown, the cell is ideal with an emf of 30 V, each resistance is
3 ohm. The electric charges stored on the
capacitor of capacity 3 µF is
°æôç™ îª÷°œ† ´©-ߪ’ç™ Nü¿’uû˝ °∂æ’ôç Çü¿-®Ωz-°∂æ’ôç,
ü∆E Nî√• 30 V, v°æA-E-®Óüµ¿ç -N©’´ 3 㢒©’.
3 µF È駃-Æœô®˝ O’ü¿ E©y Ö†o Nü¿’u-ü∆-¢Ë¨¡ç N©’´
1) Zero 2) 72 µC
3) 18 µC 4) 36 µC
109. In an oscillating LC circuit the maximum charge on the capacitor is Q. The
charge on the capacitor when the energy is stored equally between the electric
and magnetic field is
äéπ éπç°æ-Ø√-ûªtéπ LC ´©ßª’ç™E È駃-Æœô®˝ O’ü¿ í∫J≠æe Nü¿’u-ü∆-¢Ë¨¡ç Q. Nü¿’uû˝, Åߪ’-≤ƒ\çûªÍé~vû√© ´’üµ¿u ¨¡éÀh Ææ´÷-†çí¬ E©y Ö†o-°æ¤púø’ È駃-Æœô®˝ O’ü¿ Nü¿’u-ü∆-¢Ë¨¡ç
Q Q Q1) 2) Q 3) 4)
√3 2 √
2
110. Each cell has emf 2 V and internal resistance 1 Ω. Minimum number of such cells
required to supply a maximum current of 2 A in a load resistance of 6 Ω is
äéÌ\éπ\ Nü¿’uû˝ °∂æ’ôç Nî√• 2 V, Åçûª-Jo-®Óüµ¿ç 1 Ω . 6 Ω ¶µ«®Ω E®Óüµ¿ç ü∆y®√ 2 A í∫J≠æeNü¿’u-û˝†’ v°æ´-£œ«ç-°æ---ñ‰-ߪ’-ú≈-EéÀ Å´-Ææ-®Ω-¢Á’i† Å™«ç-öÀ Nü¿’uû˝ °∂æ’ö«© éπE≠æe Ææçêu
1) 24 2) 48 3) 12 4) 6
111. An electron moves with a constant speed V along a circle of circumference 2 πr.
Its gyromagnetic ratio is (m is mass of electron, 'e' is magnitude of charge on
electron)
2 πr °æJCµ Ö†o äéπ ´%û√h-é¬®Ω ´÷®Ω_ç™ äéπ á©-é¬ZØ˛ V Æœn®Ω úÕûÓ °æJ-v¶µº-N’-≤ÚhçC. ü∆E v¶µº´’ùÅߪ’-≤ƒ\çûª E≠æpAh N©’´ (m á©-é¬ZØ˛ vü¿ u-®√P, 'e' á©-é¬ZØ˛ O’-C Nü¿’u-ü∆-¢Ë ¡ °æJ- ÷ùç)
e m e 2e1) − 2) − 3) − 4) − m e 2m m
112. Two conducting circular loops of radii R1 and R2 are placed in the same plane with
their centres coinciding. Assuming R2 << R1 the mutual inductance between them is
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R R
E
RR
CR
−+
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R1, R2 ¢√u≤ƒ-®√l¥©’ Ö†o È®çúø’ ´%û√h-é¬®Ω ¢√£æ«-éπ°æ¤ Bí∫--ôd-©†’ ¢√öÀ Íéçvü∆©’àéöµºNçîËôô’xí¬ äÍé ûª©ç™ Öçî√®Ω’. R2 << R1í¬ ¶µ«NÊÆh, ¢√öÀ ´’üµ¿u ÅØÓu†u vÊ°®Ω-éπûªyí∫’ùéπç
µ0πR22
µ0πR21
µ0πR1R2
2 µ0πR2R
21
1) 2) 3) 4) 2R1 2R2 2 2
113. Two moving coil galvanometers have the following particulars. Both the meters
have same spring constants. The ratio of voltage sensitivity of second meter to
that of first meter is
È®çúø’ éπC™‰ Bí∫-ôd í¬™yØ√ ´÷°æ鬩 N´-®√©’ éÀçü¿ îª÷°œ† Nüµ¿çí¬ ÖØ√o®·. È®çúø’´÷°æ-鬩’ äÍé vÆœpçí˚ Æœn®√çé¬Eo éπLT ÖØ√o®·. È®çúÓ ´÷°æéπç ¢Ó™‰dñ¸ Ææ’Eo-ûª-û√y-EéÀ, ¢Á·ü¿öü∆E ¢Ó™‰dñ¸ Ææ’Eo-ûª-û√y-EéÀ Ö†o E≠æpAh
R1 = 10 Ω, N1 = 30, A1 = 3.6 × 10−3 m2 and
B1 = 0.25 T; R2 = 14 Ω, N2 = 42.
A2 = 1.8 × 10−3 m2 and B2 = 0.50 T
1) 5 : 7 2) 7 : 5 3) 2 : 1 4) 1 : 1
114. An ac circuit contains a resistor R, an inductor L and a capacitor C connected in
series with each other. When it is connected to an ac generator of fixed output
voltage and variable frequency, the current in the circuit is found to be leading
the applied voltage by π4
radians when the frequency is 'ƒ1'. When the
frequency of generator is increased to ƒ2, the current is found to be lagging
behind the applied voltage by π4
radians. The resonant frequency of the circuit
is
äéπ àé¬ç-ûª®Ω Nü¿’uû˝ ´©ßª’ç™, äéπ E®Óüµ¿ç R, äéπ vÊ°®Ωéπç L, äéπ È駃-Æœô®˝ C äéπü∆E-ûÓ-´’-®Ì-éπöÀ v¨ÏùÀ™ éπL°œ ÖØ√o®·. DEo Æœn®Ω- E-®Ω_´’ ¢Ó™‰dñ¸, îª®Ω §˘†”-°æ¤†uç Ö†o äéπ àé¬ç-ûª®ΩNü¿’uû˝ ï†-é¬-EéÀ éπL-°œ-†-°æ¤púø’, §˘†”-°æ¤†uç 'ƒ1' Å®·-†-°æ¤púø’ ´©ßª’ç™E Nü¿’uû˝ v°æ¢√£æ«çv°æßÁ÷-Tç-*† 㙉d> éπçõ‰ π
4 Í®úÕߪ’†’x -´·ç-ü¿’ ÖçC. ï†éπ §˘†”-°æ¤-Ø√uEo ƒ2 éÀ °ç*-†-°æ¤púø’
Nü¿’uû˝ v°æ¢√£æ« 㙉dñ¸ éπçõ‰ π4
Í®úÕߪ’-Ø˛©’ ¢Á†’-éπ-•úÕ ÖçC. ´©ßª’ç ņ’--Ø√ü¿ §˘†”-°æ¤†uçN©’´
ƒ1ƒ2 2ƒ1ƒ2 ƒ1 + ƒ21) 2) 3) √
ƒ1ƒ2 4)
ƒ1 + ƒ2 ƒ1 + ƒ2 2
115. If a magnet is suspended at an angle 30° to the magnetic meridian, the dip
needle makes an angle of 45° with the horizontal. The real dip is
äéπ Åߪ’-≤ƒ\ç-û√Eo Åߪ’-≤ƒ\çûª ߪ÷¢Á÷u-ûªh-®ΩçûÓ 30° éÓùç îËÊÆ-™« ÊÆyîªa ¥í¬ ¢Ë™«-úø-D-Æœ-†-°æ¤púø’,
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úÕ°ˇ Ææ÷*éπ éÀ~Aï Ææ´÷ç-ûª-®ΩçûÓ 45° éÓùç îËÆæ’hçõ‰, Eï úÕ°ˇ N©’´
√2 3 3
1) tan−1 ( ) 2) tan−1 ( ) 3) tan−1(√3 ) 4) tan−1 ( )√
3 2 √2
116. Two radioactive nucleii x and y initially contain equal number of atoms. Their
half lives are 1 hour and 2 hours respectively. The ratio of their rates of
disintegration after 2 hours from the start is
x, y ÅØË È®çúø’ Í®úÕ-ßÁ÷-üµ∆-Jtéπ Íéçvü¿-鬩’ ûÌ©’ûª Ææ´÷-†-Ææç-êu™ °æ®Ω-´÷-ù’-´¤-©†’ éπLTÖØ√o®·. ¢√öÀ Å®Ωl¥@Nûª 鬙«©’ ´®Ω’-Ææí¬ 1 í∫çô, 2 í∫çô©’. v§ƒ®Ω綵ºç †’ç* 2 í∫çô©ûª®√yûª ¢√öÀ N°∂æ’-ô† Í®ôx E≠æpAh
1) 1 : 1 2) 1 : 3 3) 1 : 2 4) 2 : 3
117. The de Broglie wavelength of a particle moving with a velocity
2.25 × 108 ms−1 is equal to the wavelength of photon. The ratio of kinetic
energy of the particle to the energy of the photon is (Speed of light in vacuum =
3 × 108 ms−1)
2.25 × 108 ms−1 ¢Ëí∫çûÓ îªL-Ææ’h†o äéπ éπùç úŒ v¶--Ux ûª®Ωçí∫üÁj®Ω` uç, §∂Úö«Ø˛ ûª®Ωçí∫üÁj®√` u-EéÀÆæ´÷†ç. éπùç í∫A-ï- ¡-éÀhéÀ, §∂Úö«Ø˛ ¨¡éÀhéÀ Ö†o E≠æpAh
(¨¡⁄†uç™ é¬çA ´úÕ = 3 × 108 ms−1).
5 3 7 11) 2) 3) 4)
8 8 8 8
118. The ionization potential of Hydrogen is 13.6 eV. When it is excited from ground
state by a monochromatic radiation of wavelength 970.6 A°. The number of
emission lines according to Bohr's theory will be
£j«vúÓ-ïØ˛ °æ®Ω-´÷-ù’´¤ Åߪ’-F-éπ-®Ωù §Òõ„-E-ߪ’™¸ N©’´ 13.6 eVÖç-C. 970.6 A° ûª®Ωç-í∫-üÁj®Ω` uçÖ†o äéπ àéπ- ®Ωg NéÀ-®Ω-ùçûÓ ü∆Eo ¶µº÷≤ƒn®· †’ç* ÖûËhïç îÁçCÊÆh, ¶®˝ Æœü∆l¥ç-û√-Eo ņ’-Ææ-Jç* Öü∆_-®Ω-Í®-ê© Ææçêu
1) 4 2) 6 3) 3 4) 10
119. A transmitting antenna has a height of 40 m and the receiving antenna has height
of 60 m. The maximum distance between them for satisfactory communication is
nearly
äéπ v°æ≤ƒ®Ω ߪ÷çõ„Ø√o áûª’h 40 m, ÊÆéπ-JùÀ ߪ÷çõ„Ø√o áûª’h 60 m. Ææçûª%-°œh-éπ®Ω v°æ≤ƒ-®√-EéÀ¢√öÀ ´’üµ¿u Öçú≈Lq† í∫J≠æe ü¿÷®Ωç Ææ’´÷-®Ω’í¬
1) 50 km 2) 25 km 3) 22.5 km 4) 27.5 km
1 1
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120. For the transistor, x = and y = where α and β are current gains in common α β
base and common emitter configuration of the transistor. Then
1 1äéπ vö«Eq-Ææd-®˝èπ◊ x = , y = , Ééπ\úø α, β ©’ vö«EqÆæd®˝ Ö´’túÕ Çüµ∆®Ω NØ√uÆæç, Ö´’túÕ
α β
Öü∆_®Ω NØ√u≤ƒ© Nü¿’uû˝ v°æ¢√£æ« ´%Cl¥ Å®·ûË
1) x + y = 0 2) x + y = 1 3) 2x + y = 1 4) x − y = 1
CHEMISTRY
121. The first ionization enthalpy values of the elements Na, Mg and Si are 496, 737 and
786 KJ.mol−1 respectively. Then the first ionization enthalpy of 'Al' will be (in
KJ.mol−1)
Na, Mg, Si © v°æü∑¿´’ ÅßÁ·-ØÁj-ñ‰-≠æØ˛ áçü∑∆-Lp N©’-´©’ ´®Ω’-Ææí¬ 496, 737, 78 KJ.mol −1
Å®·ûË 'Al' v°æü∑¿´’ ÅßÁ·-ØÁj-ñ‰-≠æØ˛ áçü∑∆-Lp N©’´.
1) 419 2) 575 3) 762 4) 1061
122. According to MO theory, Lithium molecule (Li2) is
Åù’ -ÇJs-ö«™¸ Æœü∆l¥çûªç v°æ鬮Ωç LC∑ߪ’ç Åù’´¤ (Li2)
1) stable and paramagnetic
Æœn®Ω-¢Á’içC, §ƒ®√ Åߪ’-≤ƒ\çûª üµ¿®Ωtç Ö†oC.
2) unstable and paramagnetic
ÅÆœn-®Ω-¢Á’içC, §ƒ®√ Åߪ’-≤ƒ\çûª üµ¿®Ωtç Ö†oC.
3) stable and diamagnetic
Æœn®Ω-¢Á’içC, v°æûªu-ߪ’-≤ƒ\çûª üµ¿®ΩtçûÓ Öçô’çC.
4) unstable and does not exist
ÅÆœn-®Ω-¢Á’içC, Åù’´¤ à®ΩpúË Å´-鬨¡ç Öçúøü¿’.
123. 360 cm3 of methane gas diffused through a porous membrane in 15 minutes.
Under similar conditions, 120 cm3 of another gas 'X' is diffused in 10 minutes.
The molar mass of the gas 'X' is
360 cm3 -O’ü∑ËØ˛ ¢√ߪ·´¤ äéπ Ææ*avü¿ §ƒvûª †’ç* 15 EN’-≥ƒ™x ¢√u°æ†ç îÁçCçC. ÅüË°æJ-Æœnûª’™x 120 cm3 äéπ ¢√ߪ·´¤ 10 EN’-≥ƒ™x ¢√u°æ†ç îÁçCûË Ç ¢√ߪ·´¤ ¢Á÷™«®˝ vü¿´u-®√P
1) 16 2) 32 3) 64 4) 72
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124. The energy associated with the first orbit of He+ is
He+ ¢Á·ü¿öÀ éπéπ~u ¨¡éÀh
1) −8.72 × 10−18 J 2) −4.36 × 10−18 J
3) −5.45 × 10−19 J 4) −10.9 × 10−19 J
125. The species that does not show disproportionation reaction among the following is
éÀçC-¢√-öÀ™ ņ-†’-§ƒûª Ωu ï®Ω°æ-EC
1) ClO− 2) ClO2− 3) ClO3
− 4) ClO4−
126. The enthalpy of combustion of benzene at 298 K and 1 atm. is −3261 KJ. Standard
enthalpies of formation of CO2 and H2O are −393 KJ and −285 KJ respectively.
Then the standard enthalpy of formation (∆f H0) of benzene is
298 K, 1 Åö«t -°‘-úø†ç ´ü¿l äéπ ¢Á÷™¸ ¶„ç-@Ø˛ ü¿£æ«†ç îÁçC −3261 KJ Ö≥ƒgEo Núø’-ü¿©îËÆæ’hçC. CO2, H2O © v°æ´÷ù Ææç°∂æ’-ô† áçü∑∆Lp N©’-´©’ ´®Ω’-Ææí¬ −393 KJ, −285 KJ
Å®·ûË ¶„ç-@Ø˛ v°æ´÷ù Ææç°∂æ’-ô† áçü∑∆-Lp N©’´
1) −48 KJ 2) +48 KJ 3) +24.83 KJ 4) −24.83 KJ
127. The value of Kc for the reaction, 2A B + C is 2 × 10−3. At a given time, the
composition of reaction mixture is [A] = [B] = [C] = 3 × 10−4 M. In which
direction the reaction will proceed?
2A B + C Ωuèπ◊ Kc N©’´ 2 × 10−3. äéπ EÍ®l-Pûª é¬©ç ´ü¿l √u- N’-v¨¡-´’ç™[A] = [B] = [C] = 3 × 10−4 M. Å®·ûË à C¨¡™ Ωu °æ¤®Ó-í∫-N’-Ææ’hçC?
1) Will proceed in reverse direction.
Ωu A®Ó-í¬N’ C¨¡í¬ ï®Ω’-í∫’-ûª’çC.
2) Will proceed in forward direction.
Ωu °æ¤®Ó-í¬N’ C¨¡í¬ ï®Ω’-í∫’-ûª’çC.
3) Equilibrium is established.
Ωu™ Ææ´’-û√-ÆœnA à®Ωp-úø’-ûª’çC.
4) Cannot be predicted.
Ωu í∫´’† C¨¡†’ ûÁ©’-Ææ’-éÓ™‰ç.
128. A solution of HCl has [H+] = 10−3 M. If 1 ml of it is diluted to 1 litre, then the
pH of the resulting solution will be
HCl vü∆ -ùç™ [H+] = 10−3 M. Ñ vü∆´ùç †’ç* 1 ml vü∆´-ù«Eo 1 Mô-®Ω’èπ◊ NM†çîËÊÆh °∂æLûª vü∆´-ù pH N©’´
1) 3 2) 6 3) 8 4) 11
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129. Electron-rich hydride among the following is
éÀçC-¢√-öÀ™ á©-é¬Z-Ø˛©’ ÅCµ-éπçí¬ Ö†o £j«v-úÁjú˛
1) MgH2 2) CH4 3) NH3 4) B2H6
130. The alkali metal that imparts crimson red colour to an oxidizing flame is
ÇéÃq-éπ-®Ωù ñ«y©™ Èéç°æ¤- ®Ωçí∫’-†’ ÉîËa é~¬®Ω ™£æ«ç
1) Li 2) Na 3) K 4) Rb
131. 'Plaster of paris' is
'§ƒxÆæd®˝ Ç°∂ˇ §ƒJÆˇ— ÅØËC
1) CaSO4.2H2O 2) 2 CaSO4.H2O
3) CaSO4.H2O 4) (CaSO4.H2O)2
132. Incorrect statement about orthoboric acid is
--Ç®Ón-¶-Jé˙ -Ç´’xç í∫’Jç* ÆæJ-é¬-E -¢√u-êu
1) It is a protonic acid and a strong acid
ÉC äéπ v§Úö«Ø˛ ü∆ûª Ç´’xç, •©¢Á’içC.
2) It is a white crystalline solid with soapy touch.
ÉC Ææ•’s™« ´’%ü¿’- ¤í¬ ÖçúË, ûÁ©xE Ææp¥öÀéπ °æü∆®Ωnç
3) It has a layer structure in which planar BO3 units are joined by hydrogen
bonds.
DEéÀ §Ò®Ω© E®√tùç Öçô’çC. Ñ E®√t-ùç™ Ææ´’-ûª© BO3 ߪ‚Eô’x £j«vúÓ-ïØ˛ •çüµ¿çûÓéπL°œ Öçö«®·.
4) It acts as a Lewis acid.
ÉC ©÷®·Æˇ Ç´’xçí¬ °æE-îË-Ææ’hçC.
133. The basic structural unit of silicates is
'ÆœL-Íé-ö¸—-©-™E v§ƒü∑¿-N’éπ E®√t-ù«-ûªtéπ ߪ‚Eö¸
1) SiO2 2) SiO32− 3) SiO4
4− 4) [− R2SiO−]
134. The maximum limit of nitrate in drinking water is 50 ppm. Excess nitrate in
drinking water can cause the disease known as
û√Íí FöÀ™ ØÁjvõ‰ö¸ í∫J≠æe í¬úµøûª 50 ppm í¬ ÖçúÌa. ØÁjvõ‰ö¸ í¬úµøûª ÅCµéπ °æJ- ÷-ùç™ Öçõ‰-- -îËa ¢√uCµ
1) cataract é¬ô-®√é˙d 2) skin cancer Ωt- é¬u-†q®˝
3) fluorosis §∂Úx®Ó-ÆœÆˇ 4) 'blue baby' syndrome FL -Gúøf ÆœçvúÓ¢’
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135. An aqueous solution of sodium acetate on electrolysis gives
≤ÚúÕߪ’ç áÆœ-õ‰ö¸ ï©-vü∆-´-ù«Eo Nü¿’uû˝ N¨Ïx-≠æù îËÊÆh à®ΩpúËC
1) methane -O’ü∑ËØ˛ 2) ethane Ñü∑ËØ˛
3) ethylene áC∑-LØ˛ 4) acetylene áÆœ-öÀ-LØ˛
136. Glycerol can be separated from spent-lye in soap industry by using the technique
Ææ•’s© °æJ-v¨¡-´’™ Ö°æ-ßÁ÷TçîË í¬úµø é~¬®Ω vü∆´ùç †’ç* Tx-ï-®√-™¸†’ ¢Ë®Ω’îËÊÆ °æü¿l¥A
1) steam distillation ï©--¶«≠æp ÊÆyü¿†ç
2) fractional distillation -ÅçPéπ ÊÆyü¿†ç
3) differential extraction -¶µ‰-ü∆ûªtéπ E≠æ \-®Ωù
4) distillation under reduced pressure ûªèπ◊\´ °‘úø-†çûÓ ÊÆyü¿†ç
137. Which of the following compounds will show cis-trans isomerism?
éÀçC-¢√-öÀ™ 'ÆœÆˇ – -vö«Ø˛q— ≤ƒü¿%-¨»uEo v°æü¿-Jzç-îËN
A) (CH3)2 C = CH − C2H5 B) CH2 = CBr2
C) C6H5CH = CH − CH3 D) CH3 − CH = CClCH3
1) A and B 2) C and D 3) A only 4) D only
138. Ortho and para directing group among the following is
éÀçC-¢√-öÀ™ Ç®Ón, §ƒ®√ ≤ƒn† EÍ®l-¨¡éπ Ææ´‚£æ«ç
1) −OH 2) −NO2 3) −CHO 4) −SO3H
139. 20 ml of 0.1 M NH4OH is added to 20 ml of 1 M NH4Cl solution. The pH of the
resulting solution is 8.2. The pKb of NH4OH is
20 ml 0.1 M NH4OH vü∆´-ù«Eo 20 ml 1 M NH4Cl vü∆´-ù«-EéÀ éπL-§ƒ®Ω’. °∂æLûª vü∆´-ù°æ¤pH N©’´ 8.2 Å®·ûË NH4OH pKb N©’´ ---
1) 8.2 2) 4.8 3) 5.8 4) 3.8
140. The correct set of quantum numbers for the valence shell electron of Rb (Z = 37)is
®Ω’H-úÕߪ’ç °æ®Ω-´÷--ù’-´¤ (Z = 37) ¢Ë©Fq ≤ƒn®·-™E á©-é¬Z-Ø˛èπ◊ Ö†o Ø√©’í∫’ é¬yçôç Ææçêu©ÆæN’A
1) 5, 0, 0, + 12
2) 5, 1, 0, +12
3) 5, 1, 1, ---−12
4) 6, 0, 0, − 12
141. The sulphur modification that shows paramagnetic behaviour is
§ƒ®√ Åߪ’-≤ƒ\çûª üµ¿®Ωtç Ö†o Ææ©p¥®˝ ®Ω÷§ƒç-ûª®Ωç
1) S2 2) S4 3) S6 4) S8
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142. The chemical compound formed in the brown ring test of nitrate ions is
ØÁjvõ‰ö¸ Åߪ÷Ø˛© ñ‰í∫’®Ω’ ®Ωçí∫’ ´©ßª’ °æK-éπ~™ à®ΩpúË ®Ω≤ƒ-ߪ’† Ææ¢Ë’t-∞¡†ç
1) Fe[NO3]2 2) Fe2[SO4]3.NO
3) [Fe(H2O)6]3+ 4) [Fe(H2O)5NO]2+
143. The time required for the completion of 90% of a first order reaction is
60 minutes. Then the time required for the completion of 99% of the same
reaction is
äéπ v°æü∑¿´’ véπ´÷çéπ Ωu 90% °æ‹Jh 鬴-ú≈-EéÀ 60 EN’-≥ƒ©’ °æúø’-ûª’çC. ÅüË îª®Ωu 99%
°æ‹Jh 鬴-ú≈-EéÀ °æõ‰d 鬩ç
1) 60 min 2) 66 min 3) 90 min 4) 120 min
144. With hot and concentrated alkalies, chlorine gives
éÓxJØ˛ ¢ËúÕ í¬úµø, é~¬®Ω vü∆´-ù«-©ûÓ îª®Ωu ïJ-°œ-†-°æ¤púø’ à®ΩpúËN
1) a mixture of chloride and hypochlorite
éÓxÈ®jú˛, £j«§ÚéÓxÈ®j-ö¸© N’v¨¡´’ç
2) a mixture of chloride and chlorate
éÓxÈ®jú˛, éÓxÍ®-ö¸© N’v¨¡´’ç
3) a mixture of chloride and perchlorate
éÓxÈ®jú˛, °æ®˝-éÓx-Í®-ö¸© N’v¨¡´’ç
4) a mixture of hypochlorite and perchlorate
£j«§ÚéÓxÈ®j-ö¸, °æ®˝-éÓx-Í®-ö¸© N’v¨¡´’ç
145. XeOF4 is a colourless, volatile liquid and has a
XeOF4 ®Ωçí∫’-™‰E -¶«≠æpQ© vü¿´ç, DE Åù’ E®√tùç
1) distorted octahedral structure N®Ω÷-°æù Å≠æd-´·-&ߪ’ç
2) square pyramidal structure îªûª’-®ΩvÆæ °œ®Ω-N’-úø™¸
3) square planar structure Ææ´’-ûª© îªûª’-®ΩvÆæç
4) distorted tetrahedral structure N®Ω÷-°æù îªûª’®Ω’t-&ߪ’ç
146. 'Argyrol' is a silver sol, used
'ÇJb-®√™¸— ÅØË Æœ©y®˝ ≤ƒ™¸ Ö°æ-ßÁ÷í∫ç
1) as an eye lotion
éπçöÀ ™≠æ-Ø˛í¬ ¢√úø-û√®Ω’
2) in curing kala azar
鬙« Åñ«®˝ ÅØË ¢√uCµE ûªT_ç-îª-ú≈-EéÀ ¢√úø-û√®Ω’
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3) as an intramuscular injection
éπçúø-®√ç-ûª®Ω Éçñ-éπ~-Ø˛í¬ ¢√úø-û√®Ω’
4) for stomach disorders
Öü¿®Ω ÅÆæy-Æænûª-©èπ◊ ¢√úø-û√®Ω’
147. Carboxylic acids having an α - hydrogen are halogenated at the α - position on
treatment with chlorine or bromine in the presence of small amount of red
phosphorus to give α - halocarboxylic acids. The reaction is known as
α - £j«vúÓ-ï-Ø˛-©’†o 鬮√s-éÀq-Lé˙ Ç´÷x™x α - ≤ƒn†ç™ £æ…™-ï-Ø˛†’ v°æA-Íé~-°œç-îª-´îª’a. ÑÇ´÷x©†’ éÓxJØ˛ ™‰ü∆ v¶N’Ø˛ûÓ áv®Ω §∂ƒÆæp¥-®ΩÆˇ Ææ´’-éπ~ç™ îª®Ωu ïJ-°œûË α - £æ…™-é¬-®√s-éÀq-Lé˙Ç´÷x-©†’ à®Ωp-®Ω’-≤ƒh®·. Ñ îª®Ωu
1) Gattermann - Koch reaction í¬ô-®˝-´’-Ø˛ - -éÓî˝ îª®Ωu
2) Etard reaction Éö«® f Ωu
3) Hell - Volhard - Zelinsky reaction £«™¸ - -¢Ó-™«-®˝f - -ñ„-©-Ø˛Æœ\ Ωu
4) Stephen reaction Æ‘d°∂Ø˛ Ωu
dil. NaOH ∆148. 2CH3 − CHO A → But - 2 - enal
−H2O
The compound 'A' in the reaction is
dil.NaOH ∆2CH3 − CHO A → •’uö¸– 2 – -É-Ø√™¸.−H2O
°j Ωu™ 'A' ÅØËC
1) aldol Ç™«f™¸ 2) ketol éÃ-ö™¸
3) mesityloxide ¢Á’iÆœ-õ„j™¸ ÇÈéj qú˛ 4) crotonaldehyde véÓô-Ø√-Lf-£j«ú˛
149. The compound with highest boiling point among the following is
éÀçC-¢√-öÀ™ Åûªu-Cµé𠶫≠‘p-¶µº- † ≤ƒn†ç Ö†oC
1) pentan - 1 - ol °çô-Ø˛ – 1 – -㙸 2) n - butane n - -•÷uõ‰Ø˛
3) pentanal °çô-Ø√™¸ 4) ethoxyethane Éü∑∆-éÃq-Ñ-ü∑ËØ˛
150. The amine produced by the Hoffmann degradation of benzamide is
£æ…°∂ˇ-´’Ø˛ EO’o-éπ-®Ωù Ωu™ ¶„çï-¢Á’iú˛ †’ç* à®ΩpúË áO’Ø˛
1) phenyl ethanamine °∂œØÁj™¸ Éü∑¿-†-¢Á’iØ˛
2) benzenamine ¶„ç@-†-O’Ø˛
3) N - N - dimethyl aniline N - N - úÁ--O’-ü∑Áj™¸ áE-LØ˛
4) hexan - 1, 6 - diamine £«é¬qØ˛ – 1, 6 – úÁjá-O’Ø˛
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151. Match the following:
éÀçC-¢√-öÀE ïûª°æ®Ω-îªçúÕ:
Compound Ææ¢Ë’t-∞¡†ç Geometry ñ«uN’AI) [Ni(CO)4] A) Octahedral
Çé¬d-£«-vúø™¸
II) [PtCl4]2− B) Trigonal bipyramidal
wõ„jíÓ-†-™¸ -¶„j-°œ-®Ω-N’-úø™¸
III) [Fe(CO)5] C) Square planar
Ææ´’-ûª© îªûª’-®ΩvÆæç
IV) [Co(NH3)6]3+ D) Tetrahedral
õ„vö«-£«-vúø™¸
1) I-C, II-D, III-B, IV-A 2) I-B, II-A, III-D, IV-C
3) I-A, II-B, III-C, IV-D 4) I-D, II-C, III-B, IV-A
152. 1.00 g of a non electrolyte solute dissolved in 50 g of benzene lowered the
freezing point by 0.40 K. The freezing point depression constant of benzene is
5.12 K kg mol −1. The molar mass of solute is
50 ví¬. ¶„ç-@Ø˛™ 1.00 ví¬. ÅN-ü¿’uû˝ N¨Ïx--≠æuéπ vü∆N-û√Eo éπJ-Tç-*-†-°æ¤púø’, °∂æ’F-¶µº- † Ö≥Úg-ví∫ûª0.40 K ûªT_çC. ¶„ç-@Ø˛ ¢Á÷™«®˝ E´’oA Æœn®√çéπç 5.12 K kg mol−1. Å®·ûË vü∆Nûª°æ¤¢Á÷™«®˝ ¶µ«®Ωç
1) 41 2) 392 3) 180 4) 256
153. Λ0m for NaCl, HCl and CH3COONa are 126.4, 425.9 and 91.0 S cm2 mol−1.
Λ0 for CH3COOH is (in S cm2 mol−1)
NaCl, HCl, CH3COONa © Λ0m N©’-´©’ ´®Ω’-Ææí¬ 126.4, 425.9, 91.0 S cm2
mol −1 Å®·ûË CH3COOH ¢Á÷™«®˝ ¢√£æ«-éπûª
1) 643.3 2) 228.5 3) 451.3 4) 390.5
154. The electronic configuration of cerium is
'Æ‘Jߪ’ç— ´‚©éπç á©-é¬ZØ˛ NØ√uÆæç
1) [Xe]4f05d16s2 2) [Xe]4f
15d16s2
3) [Xe]4f25d06s2 4) 2 and 3
155. RNA does not contain
RNA ™ ÖçúøEC
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1) Thymine ü∑Áj-O’Ø˛ 2) Uracil ߪ·®√-Æœ™¸
3) Cytosine ÂÆjö-ÆœØ˛ 4) Adenine áúÕ-ØÁjØ˛
156. Nylon − 6, 6 is obtained by condensation polymerization of
éÀçC Åù’-´¤©’ Ææç°∂æ’†† §ƒL´’-K-éπ-®Ωùç îÁçCûË
ØÁj™«Ø˛ − 6, 6 §ƒL-´’®˝ à®Ωp-úø’-ûª’çC
1) Adipic acid and hexamethylene diamine
áúÕ-°œé˙ Ç´’xç, £«é¬q-N’-C∑-MØ˛ úÁjá-O’Ø˛
2) Phenol and formaldehyde °∂‘Ø√™¸, §∂ƒ®√t-Lf-£j«ú˛
3) Terephthalic acid and ethylene glycol
õ„J-ü∑∆-Lé˙ Ç´’xç, áC∑-M--Ø˛ Èíkx-鬙¸
4) Caprolactam and formaldehyde
é¬v§Ò-™«éπdç, §∂ƒ®√t--Lf-£j«ú˛
157. The antibiotic that is supposed to be toxic towards certain strains of cancer cells
is
éÌEo ®Ω鬩 NÆæh %ûª ®Ω÷°æ é¬u†q®˝ éπù«-©èπ◊ N≠æ-°æü∆-®Ωnçí¬ °æE-îËÊÆ ßª÷ç-öà -•--ߪ÷-öÀé˙
1) Vancomycin ¢√çéÓ-¢Á’i-ÆœØ˛
2) Ofloxacin ã§∂Úx-é¬q-ÆœØ˛
3) Dysidazirine úÕÆœ-ú≈->-JØ˛
4) Prontosil v§ƒØ -ö-Æœ™¸
158. If the ore alone but not the gangue is soluble in some suitable solvent, then ore
is concentrated by
êEï ´÷L†uç é¬èπ◊çú≈ ´·úÕ-ê-Eïç ´÷vûª¢Ë’ àüÁjØ√ äéπ vü∆ -ùÀ™ éπJ-T-ûË, Ç êE-ñ«Eo ¨¡ŸCl¥îËÊÆ°æü¿l¥A
1) Levigation FöÀûÓ é~¬∞¡†ç îËߪ’úøç
2) Leaching Eé~¬-∞¡†ç
3) Froth floatation method °æx´† v°ævéÀߪ’ °æü¿l¥A
4) Liquation í∫©-Eéπ °æ%-ü∑¿-éπ\-®Ωùç
159. The incorrect statement among the following is éÀçC-¢√-öÀ™ Ææ-J é¬E -¢√u-êu
1) Under certain conditions, Mg can reduce Al2O3 and Al can reduce MgO.
éÌEo °æJ-Æœnûª’™x ¢Á’Uo-≠œßª’ç, Al2O3 †’ éπ~ߪ’-éπ-®Ωùç îËߪ’í∫-©ü¿’, Å©÷u-N’-Eߪ’ç, MgO †’éπ~ߪ’-éπ-®Ωùç îËߪ’-í∫-©ü¿’.
2) The reaction, Cr2O3 + 2 Al → Al2O3 + 2 Cr is thermodynamically feasible.
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Cr2O3 + 2 Al → Al2O3 + 2 Cr, Ñ îª®Ωu Ö≠æg-í∫-A-éπçí¬ ïJÍí Å´-é¬-¨¡-´·çC.
3) Ellingham diagram normally consists of plots of ∆G0 Vs T for formation of
oxides of elements
äéπ áLxç-í -£æ…¢’ °æôç™, ≤ƒüµ∆-®Ωù ™£æ…© ÇéÃq-éπ-®Ω-ù«-EéÀ Öç-úË ∆G0, Ö≥Úg-ví∫ûª (T)©ví¬°∂椩’çö«®·.
4) Ellingham diagram explains the kinetics of the reduction process.
áLxç-í˚-£æ…¢’ °æôç éπ~ߪ’-éπ-®Ωù v°ævéÀߪ’ í∫A-ï-¨»ÆæYç í∫’Jç* ûÁL-ߪ’-ñ‰-Ææ’hçC.
160. The crystal system of a compound with unit cell dimensions a = 0.387, b = 0.387
and c = 0.504 nm and α = β = 90° and γ = 120° is
äéπ Ææ¢Ë’t-∞¡-†ç™E ߪ‚Eö¸ ÂÆ™¸™ a = 0.387, b = 0.387, c = 0.504 nm, α = β = 90°,
γ = 120° Å®·ûË ü∆E Ææp¥öÀéπ E®√tùç
1) cubic °∂æ’†ç 2) hexagonal ≠æö\-ùÃߪ’
3) orthorhombic Ææ´’-îª-ûª’-®Ω’s¥ï 4) rhombohedral Ææ´÷ç-ûª®Ω ≠æôp¥-©-éÃߪ’
KEY1-1; 2-2 ; 3-3; 4-2; 5-4 ; 6-1 ; 7-2 ; 8-4 ; 9-1 ; 10-4; 11-4; 12-2; 13-3; 14-1; 15-3;
16-4; 17-3; 18-4; 19-1; 20-3; 21-3; 22-3; 23-3; 24-3; 25-3; 26-1; 27-3; 28-4; 29-3;
30-3; 31-1; 32-1; 33-4; 34-3; 35-3; 36-1; 37-3; 38-2; 39-1; 40-3; 41-2; 42-1; 43-2;
44-1; 45-2; 46-1; 47-4; 48-3; 49-2; 50-3; 51-4; 52-2; 53-3; 54-1; 55-3; 56-2; 57-1;
58-2; 59-4; 60-3; 61-1; 62-3; 63-4; 64-4; 65-1; 66-3; 67-3; 68-3; 69-2; 70-4; 71-2;
72-4; 73-4; 74-1; 75-2; 76-3; 77-4; 78-2; 79-1; 80-4; 81-2; 82-4; 83-3; 84-4; 85-1;
86-2; 87-2; 88-1; 89-4; 90-2; 91-3; 92-1; 93-2; 94-2; 95-3; 96-4; 97-1; 98-3; 99-2;
100-1; 101-2; 102-4; 103-1; 104-2; 105-1; 106-3; 107-4; 108-2; 109-4; 110-1; 111-3;
112-1; 113-4; 114-3; 115-2; 116-1; 117-2; 118-2; 119-1; 120-4; 121-2; 122-3;
123-3; 124-1; 125-4; 126-2; 127-1; 128-2; 129-3; 130-1; 131-2; 132-1; 133-3; 134-4;
135-2; 136-4; 137-2; 138-1; 139-2; 140-1; 141-1; 142-4; 143-4; 144-2; 145-2; 146-1;
147-3; 148-1; 149-1; 150-2; 151-4; 152-4; 153-4; 154-2; 155-1; 156-1; 157-3; 158-2;
159-4; 160-2.
(-Ñ -†-´‚-Ø√ -v°æ-¨¡o°æ-vû√-Eo ®Ω÷-§Òç-Cç-*-†-¢√®Ω’: -öÀ. éÀ---≥Ú®˝, ->.-N. -îªç-vü¿-¨Ï-ê®˝, --â. -ÅçéÓ-@®√--´¤ – -Ø√®√ߪ’-ù -N-ü∆uÆæçÆæn-©’, -ØÁ-©÷x®Ω’)
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