Unit 9: Alternating-current circuits - UPV 9/Slides Unit 9 Alternating... · Unit 9:...
Transcript of Unit 9: Alternating-current circuits - UPV 9/Slides Unit 9 Alternating... · Unit 9:...
Unit 9: Alternating-current circuits
Introduction. Alternating current features.
Behaviour of basic dipoles (resistor, inductor,
capacitor) to an alternating current.
RLC series circuit. Impedance and phase lag.
Power on A.C.
Resonance.
Niagara
Falls
Nikola Tesla 1856-1943
Coil turning inside a magnetic field B.
NBSwsenwtdt
d=−=
φε
N S
S
B
ω ω ω ω
ωωωω·t
wtNBS cos== SBNrr
φ
%ωωωω
Um
Symbol:
Alternating-current generation
N1 N2
V1 ~ V2 ~
The transformer The current on primary produces a current and then a flux varying on time.
This flux is completely driven by the ferromagnetic material, producing an inducedelectromotive force on terminals of secondary. The flux on each loop φu is the same forprimary and secondary.
It works due to electromagnetic induction and then it doesn’t work on D.C.
Primary
winding
Secondary
windingdt
dNV u
111
Φ==ε
dt
dNV u
222
Φ==ε
1
2
1
2
2
2
1
1 V
N
N
VN
V
N
V==
Voltage ratio or ratio
of transformation
equals the turns ratio
On an ideal transformer the power on primary equals the power on secondary
On an real transformer there are three type of losses:
On windings: Joule heating
On core: Magnetic Histeresys
and Eddy currents
In order to minimize Eddy currents the core is built with
sheets isolated between them
B
r
i
Period T = 2π/ω (s)
Frequency f = 1/T (Hz)
Angular frequency
w = 2πf (rad/s)
Phase wt+ϕ
Initial phase ϕ (degrees or radians) (phase at t=0)
Amplitude=Maximum voltage Um (V)
ωt
T
ϕ
Um
u(t) = Um cos(ωt + ϕ)u(t)
f Europe: 50 Hz
f North America: 60 Hz
Sinusoidal alternating-current features
ωt
ϕϕϕϕu =0
u(t) = Um cos(ωt + ϕu)
u(t)
Initial phase. Examples.
ωt
u(t)
ϕϕϕϕu=90º (ππππ/2 rad)
ωt
u(t)
ϕϕϕϕu=-90º (-ππππ/2 rad)
ωt
u(t)
ϕϕϕϕu=-45º (-ππππ/4 rad)
To simplify the analysis of A.C. circuits, a graphical representation of sinusoidalfunctions called phasor diagram can be used.
A phasor is a vector whose modulus (length) is proportional to the amplitude ofsinusoidal function it represents.
The vector rotates counterclockwise at an angular speed equal to ω. The anglemade up with the horizontal axis is the phase (ωt+φ).
Therefore, depending if we are working with the function sinus or the functioncosinus, this function will be repreented by the vertical projection or thehorizontal projection of the rotating vector.
ωt
T
ϕ
Um
u(t) = Um cos(ωt + ϕ)
u(t)
Phasor diagram
U
ωt+φ
Um
ω
+
+
)sin(:
)cos(:Pr
ϕω
ϕω
tUVertical
tUHorizontalojections
m
m
As the position of phasor is different for any time considered, the graphicalrepresentations are done on time t=0 and then, the initial phase φ is the anglebetween vector and horizontal axis. In this way, the phasor is a unique vector(not changing on time) for a given function:
ωt
T
ϕ
Um
u(t) = Um cos(ωt + ϕ)
u(t)
Phasor diagram
U
φ
Um
Phasor diagram
u(t) = Um cos(ωt + ϕu )i(t) = Im cos(ωt+ϕi)
ϕ ωt
iu ϕϕϕ −=
Phase lag between two waves (voltage and intensity)
Phase lag is defined as
ϕϕϕϕi=0 ϕϕϕϕu<0
0<ϕ
Voltage u(t) goes behind intensity i(t)
Intensity i(t) goes ahead voltage u(t)
To be compared, both functions
must be sin or cosand with equal
angular frequency
Uφu
Phasor diagram
I
ϕ ωt
iu ϕϕϕ −=
Phase lag between two waves (voltage and intensity)
ϕϕϕϕi=0ϕϕϕϕu>0
0>ϕ
ϕ ωt
ϕϕϕϕi<0ϕϕϕϕu=0
0>ϕ
Uφ =φu
I
Uφ =-φi
I
Behaviour of basic dipoles. Resistor
Resistor
ωt
i
u
u(t) = R i(t) = RIm cosωt = Um cosωt
i(t) = Im cosωt
Ri(t)
u(t)
Um = R Im
ϕ = 0
Tipler, chapter 29.1
uR = iR
U
I
Behaviour of basic dipoles. Inductor
i(t) = Im cosωt
Li(t)
u(t)
Um = LωIm
ϕ = π/2
Tipler, chapter 29.1
Inductor
ωt
iu
)2
tcos(U)2
tcos(ILtsenILdt
)t(diL)t(u mmm
πωπωωωω +=+=−==
XL = Lω Inductance (Ω)
dt
)t(diLuL =
U
I
Behaviour of basic dipoles. Capacitor
Ci(t)
u(t)
φ = - π/2
Tipler, chapter 29.1
Capacitor
ωt
i
u
u(t) = Um cosωt
)2
tcos(I)2
tcos(CU)t(senCUdt
)t(Cdu
dt
)t(dq)t(i mmm
πω
πωωωω +=+=−===
ω=
C
IU m
mXC = 1/Cω Capacitance (Ω)
Cuq =
U
I
R
L
C
)cos( umL wtLwIu ϕ+=
)cos( umR wtRIu ϕ+=
)cos( um
C wtCw
Iu ϕ+=
+=
=
2πϕ
mLLm IXU
=
=
0ϕ
mRm IRU
−=
=
2πϕ
mCCm IXU
Behaviour of basic dipoles. Review
Voltage and intensity go on phase
Voltage goes ahead intensity 90º
Voltage goes behind intensity 90º
Sinusoidal functions are interesting because additionof (S.F.) is another S.F.
On the other hand, Fourier’s law says that anyperiodic function can be split in S.F. of differentfrequencies. This is the main reason why behaviourof S.F. is studied.
Knowing response of basic dipoles to a sinusoidalcurrent, we know response to any (no sinusoidal)current.
Sinusoidal functions (S.F.) and Fourier’s law.
L R C
uLuR uC
i(t)= Im cos (wt)
u(t) = uL (t)+ uR (t)+ uC (t)= Um cos (wt+ϕ)
Let’s take a circuit with resistor, inductor and capacitor inseries. If a sinusoidal intensity i(t)=Imcos(wt) is flowingthrough such devices, voltage on terminals of circuit will bethe addition of voltages on each device:
RLC series circuit. Impedance of dipole
u(t)
Addition of sinusoidal
functions is another
sinusoidal function
RLC series circuit. Impedance of dipole
Um cos (wt+ϕ) = LwIm cos (wt +π/2)+RIm cos (wt)+(1/Cw)Im cos (wt -π/2)
UL
I URUC
UL-UC
I UR
U
ϕ Um
(Lω-1/Cω) Im
RIm
ϕ Um
ZXRXXRI
U
CwLwRIU CL
m
mmm =+=−+=−+= 222222 1
)()((
ϕϕ tgR
X
R
XX
R
CwLw
tg CL ==−
=
−
=
1Z Is called Impedance of dipole (Ω)
ϕ is phase lag of dipole
Z and ϕ are depending not only on parameters of R, L and C, but also on frequency of applied current.
R
XL=Lw
ZX
ϕϕϕϕ
X<0 (ϕϕϕϕ<0)
R
ZX
ϕϕϕϕ
Impedance triangle.
All equations of a RLC dipole can be summarized on Impedance Triangle of a dipole for a given frequency:
2222 1XR
CwLwRZ +=−+= )((
R
X
R
XX
R
CwLw
tg CL =−
=
−
=
1
ϕ
XC=1/Cw X=XL-XC=Lw-1/Cw
InductiveReactance
CapacitiveReactance
Dipole Reactance
X>0 (ϕϕϕϕ>0)
Power on A.C.
Power consumed on a device on A.C. can be computed multiplying voltage and
intensity on each time. This is the Instantaneous power:
)tsin(I)t(i m ω=
)tsin(u)t(u m ϕω +==⋅+=⋅= )tsin(I)tsin(U)t(i)t(u mm ωϕω
t2sinsin2
IUtsincosIUtsin]sintcoscost[sinIU mm2
mmmm ωϕωϕωϕωϕω⋅
+⋅=⋅+⋅⋅=
Reactive powerActive or
Real power
p(t)
)(tp
Instantaneous power = Active power + Reactive power
Frequency of reactive power doubles that of active power
tIU mm ωϕ 2sincos⋅ tIU mm ωϕ 2
2sinsin
⋅= +
Power on A.C.
> 0 and < 0 zero on a cycleAlways > 0
Active power + Reactive power = Instantaneous power
=+
t2sinsin2
IU mm ωϕ⋅
)t(p+ =
Example taking: Im = 1 A Um = 1 V ω = 1 rad/s ϕ = 0,6 rad
Average value on a cycle:
ϕωϕ cos2
IUtdtsincosIU
T
1dt)t(p
T
1PP mm
T
0
2
mm
T
0
a
av
⋅=⋅===
Power on A.C.
-0,4
-0,2
0
0,2
0,4
0,6
0,8
1
0 2 4 6 8 10 12
wt (rad)
Po
wer
(w)
Active pow er
Power on A.C.
-0,4
-0,2
0
0,2
0,4
0,6
0,8
1
0 2 4 6 8 10 12
wt (rad)P
ow
er
(w)
Reactive pow er
Power on A.C.
-0,4
-0,2
0
0,2
0,4
0,6
0,8
1
0 2 4 6 8 10 12
wt (rad)
Po
wer
(w)
Inst. pow er
cos ϕ ≡ Power factor
tsincosIU mm ωϕ 2⋅
=
TT
dtwt0
2
2)(sin
DipoleActive
power Pa(t)Average
Paav
Reactive power Pr(t)
Average Prav
P(t) Pav
Rϕ=0
Cos ϕ=1
Sin ϕ=00 0
Lϕ=90º
Cos ϕ=0
Sin ϕ=10 0 0 0
Cϕ=-90º
Cos ϕ=0
Sin ϕ=-10 0 0 0
Rms magnitudes. Power for basic dipoles
Consumed power on basic dipoles (R, L and C):
)(2sinsin2
sincos 2tpt
IUtIU mm
mm =⋅
+⋅ ωϕωϕ
An A.C. current consumes the same power than a D.C. current having the rms magnitudes
ϕϕ cosIUcos2
IUpowerAverage rmsrms
mm =⋅
=2
mrms
UU =
2
mrms
II =
tsinIU2
mm ωR
Um
2
2
tsinIU2
mm ωR
Um
2
2
t2sinL2
U2
m ωω
t2sinL2
U2
m ωω
t2sinC2
U2
m ωω− t2sinC2
U2
m ωω−
Tipler, chapter 29.1
22 1)((
CwLwR
I
UZ
m
m −+==
RLC series circuit. Resonance
Drawing Z v.s frequency
Z v.s. freq
0
100
200
300
400
500
600
0 500 1000 1500 2000 2500 3000 3500 4000
frequency (Hz)Z
(O
hm
)
Example taking: R = 80 Ω L = 100 mH C = 20 μF
Resonance: f0=707 Hz Z=80 Ω
On resonance, impedance of circuit is minimum, and
amplitude of intensity reaches a maximum (for a given
voltage). Intensity and voltage on terminals of RLC
circuit go then on phase. cos ϕ=1 and consumed
power on RLC dipole is maximum.
There is a frequency where XL=XC and then the impedance gets its minimum value (Z=R).
This frequency is called Frequency of resonance (f0) and can be easily computed:
LCf
LCCL
1
2
11100
0
0π
ωω
ω ===