Total Surface Area - mathppt.com · Find the surface area of the cone below. SA BA LA=+ Surface...
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Objective – To find the surface area of pyramids and cones. 10 m 10 m 13 m 12 m SA BA LA = + Surface Area = Base Area + Lateral Area SA l w =• ( ) 1 4 bh 2 + 10 m 2 ( ) 1 SA 10 10 4 10 13 2 = • + • • ( ) 1 SA 100 4 130 2 = + • SA 100 260 = + 2 SA 360 m = Find the surface area of the pyramid below. 6 m Square Base 6 m 5 m 4 m 4 Lateral Triangles + ( ) ( ) 4 1 b h 2 • l w • 6 6 • 36 ( ) 1 4 6 5 2 • • 60 = 2 2 6 5 • • Total Surface Area = 36 + 60 2 96 m = Equilateral Triangular Pyramid 8 8 8 10 8 8 8 8 4 x 2 2 2 a b c + = 2 2 2 x 4 8 + = 2 x 16 64 + = 16 16 x SA BA LA = + 1 SA bh 2 = ( ) 1 3 bh 2 + 16 16 − − x 48 = x 6.93 ≈ 2 x 48 = ( ) 1 1 SA (8 6.93) 3 8 10 2 2 ≈ • + • • SA 27.72 120 ≈ + 2 147.72 un ≈ Surface Area of a Cone SA BA LA = + Surface Area = Base Area + Lateral Area 5m 5m 2 SA r r =π• +π• • l 3 m 5 m 5 m 2 SA 3 3 5 =π• +π• • SA 9 15 = π+ π SA 24 = π 24(3.14) ≈ 2 SA 75.36 m ≈ Find the surface area of the cone below. SA BA LA = + Surface Area = Base Area + Lateral Area 2 SA r r =π• +π• • l 13 in. 12 in. 2 SA 5 5 13 =π• +π• • SA 25 65 = π+ π SA 90 = π 90(3.14) ≈ 2 SA 282.6 in ≈ 5 in. Lesson 10-5 Pre-Algebra Slide Show: Teaching Made Easy As Pi, by James Wenk © 2011
Transcript of Total Surface Area - mathppt.com · Find the surface area of the cone below. SA BA LA=+ Surface...
Objective – To find the surface area of pyramids and cones.
10 m10 m
13 m
12 m SA BA LA= +
SurfaceArea = Base
Area + LateralArea
SA l w= • ( )1 4 bh2+10 m ( )2
( )1SA 10 10 4 10 132= • + • •
( )1SA 100 4 1302= + •
SA 100 260= +2SA 360 m=
Find the surface area of the pyramid below.
6 mSquare Base
6 m
5 m
4 m
4 Lateral Triangles+
( )( ) 4 1 b h2 •l w•
6 6•36 ( )14 6 52 • •
60=
2
2 6 5• •
Total Surface Area = 36 + 60 296 m=
Equilateral Triangular Pyramid
8 8
8 10 8 8
8
8
4
x2 2 2a b c+ =2 2 2x 4 8+ =2x 16 64+ =
16 16
x
SA BA LA= +1SA bh2= ( )1 3 bh2+
16 16− −
x 48=x 6.93≈
2x 48=
( )1 1SA (8 6.93) 3 8 102 2≈ • + • •
SA 27.72 120≈ + 2147.72 un≈
Surface Area of a Cone
SA BA LA= +
SurfaceArea = Base
Area + LateralArea
5 m5 m2SA r r= π• + π• • l
3 m
5 m5 m2SA 3 3 5= π• + π• •
SA 9 15= π+ π
SA 24= π 24(3.14)≈2SA 75.36 m≈
Find the surface area of the cone below.
SA BA LA= +
SurfaceArea = Base
Area + LateralArea
2SA r r= π• + π• • l
13 in.12 in.
2SA 5 5 13= π• + π• •
SA 25 65= π+ π
SA 90= π 90(3.14)≈2SA 282.6 in≈
5 in.
Lesson 10-5
Pre-Algebra Slide Show: Teaching Made Easy As Pi, by James Wenk © 2011
