TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations...

41
TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement φ) of driven elemen. Warsaw University of Technology, The Faculty of Automotive and Construction Machinery Engineering Institute of Machine Design Fundamentals, Department of Mechanics, http://www.ipbm.simr.pw.edu.pl/, Sebastian Korczak, PhD Eng. φt) A B C D e h O

Transcript of TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations...

Page 1: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC - Winter 2019/2020

velocities and accelerations in planar mechanismsEXAMPLE

Given: mechanism geometry andangular displacement φ(t)t)) of driven element.of of driven element.driven of driven element.element).

Warsaw University of Technology, The Faculty of Automotive and Construction Machinery EngineeringInstitute of Machine Design Fundamentals, Department of Mechanics, http://www.ipbm.simr.pw.edu.pl/,

Sebastian Korczak, PhD Eng.

φ(t)t)

A B

C

D

e

h

O

Page 2: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 2

φ(t)t)

AB

C

D

e

h

1

23 4

5

O

Page 3: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 3

φ(t)t)

AB

C

D

e

h

1

23 4

5

O

X

Y

Page 4: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 4

φ(t)t)

AB

C

D

e

h

1

23 4

5

O

X

Y

r

ha

Page 5: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 5

φ(t)t)

AB

C

D

e

h

1

23 4

5

O

X

Y

r

ha

c b

d

e

Page 6: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 6

φ(t)t)

X

Y

r

ha

cb

d

e

Page 7: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 7

φ(t)t)

X

Y

r

ha

cb

d

e

φh

Page 8: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 8

φ(t)t)

X

Y

r

ha

cb

d

e

φhφ

h=90o

Page 9: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 9

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa

φh=90o

Page 10: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 10

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)

φa(t)t) ≠ const.

Page 11: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 11

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)

φa(t)t) ≠ const.

φr

Page 12: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 12

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)

φa(t)t) ≠ const.

φr(t)t)

Page 13: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 13

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)

φa(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

Page 14: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 14

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)

φa(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb

Page 15: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 15

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)

φa(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const.

Page 16: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 16

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const.

φc(t)t)

φc(t)t) = φ

a(t)t)

Page 17: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 17

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)

φa(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const.

φc(t)t)

φc(t)t) = φ

a(t)t)

φd

Page 18: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 18

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)

φa(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const.

φc(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

Page 19: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 19

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)

φa(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const.

φc(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

φe

Page 20: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 20

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)

φa(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const.

φc(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

φeφ

e=180o

Page 21: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 21

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)φ

a(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const. φ

c(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

φe

φe=180o

Page 22: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 22

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)φ

a(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const. φ

c(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

φe

φe=180o

|r| = |AB| = r = const.

Page 23: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 23

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)φ

a(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const. φ

c(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

φe

φe=180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

Page 24: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 24

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)φ

a(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const. φ

c(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

φe

φe=180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

|a| = |OB| = a(t)t)

Page 25: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 25

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)φ

a(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const. φ

c(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

φe

φe=180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

|a| = |OB| = a(t)t)

|c| = |OC| = c = const.

Page 26: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 26

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)φ

a(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const. φ

c(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

φe

φe=180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

|a| = |OB| = a(t)t)

|c| = |OC| = c = const.

|b| = |CD| = b = const.

Page 27: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 27

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)φ

a(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const. φ

c(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

φe

φe=180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

|a| = |OB| = a(t)t)

|c| = |OC| = c = const.

|b| = |CD| = b = const.

|d| = d(t)t)

Page 28: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 28

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)φ

a(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const. φ

c(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

φe

φe=180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

|a| = |OB| = a(t)t)

|c| = |OC| = c = const.

|b| = |CD| = b = const.

|d| = d(t)t)

|e| = e = const.

Page 29: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 29

φ(t)t)

X

Y

r

h

a

cb

d

e

φh

φa(t)t)

φh=90o

φa(t)t)φ

a(t)t) ≠ const.

φr(t)t)

φr(t)t) = 90o - φ(t)t)

φb(t)t)

φb(t)t) ≠ const. φ

c(t)t)

φc(t)t) = φ

a(t)t)

φd

φd=270o

φe

φe=180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

|a| = |OB| = a(t)t)

|c| = |OC| = c = const.

|b| = |CD| = b = const.

|d| = d(t)t)

|e| = e = const.

h + r = ac + b + d + e = 0

Page 30: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 30

φh=90o

φa(t)t) ≠ const.

φr(t)t) = 90o - φ(t)t)

φb(t)t) ≠ const.

φc(t)t) = φ

a(t)t)

φd= 270o

φe= 180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

|a| = |OB| = a(t)t)

|c| = |OC| = c = const.

|b| = |CD| = b = const.

|d| = d(t)t)

|e| = e = const.

h + r = ac + b + d + e = 0

Page 31: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 31

φh=90o

φa(t)t) ≠ const.

φr(t)t) = 90o - φ(t)t)

φb(t)t) ≠ const.

φc(t)t) = φ

a(t)t)

φd= 270o

φe= 180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

|a| = |OB| = a(t)t)

|c| = |OC| = c = const.

|b| = |CD| = b = const.

|d| = d(t)t)

|e| = e = const.

h + r = ac + b + d + e = 0

x : hcos ϕ h+r cosϕ r(t )=a(t)cosϕ a(t)y : hsin ϕ h+r sin ϕ r(t)=a(t)sin ϕ a(t)

Page 32: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 32

φh=90o

φa(t)t) ≠ const.

φr(t)t) = 90o - φ(t)t)

φb(t)t) ≠ const.

φc(t)t) = φ

a(t)t)

φd= 270o

φe= 180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

|a| = |OB| = a(t)t)

|c| = |OC| = c = const.

|b| = |CD| = b = const.

|d| = d(t)t)

|e| = e = const.

h + r = ac + b + d + e = 0

x : hcos ϕ h+r cosϕ r(t )=a(t)cosϕ a(t)y : hsin ϕ h+r sin ϕ r(t)=a(t)sin ϕ a(t)

x : c cosϕ c(t)+bcosϕ b(t)+d(t)cosϕ d+e cosϕ e=0y : c sin ϕ c(t )+b sinϕ b (t)+d (t)sin ϕ d+e sin ϕ e=0

Page 33: TM&AC - Winter 2019/2020 - myinventions.pl · TM&AC - Winter 2019/2020 velocities and accelerations in planar mechanisms EXAMPLE Given: mechanism geometry and angular displacement

TM&AC, of driven element.Wint)er of driven element.2019/2020, of driven element.Sebast)ian of driven element.Korczak of driven element.PhD of driven element.Eng. 33

φh=90o

φa(t)t) ≠ const.

φr(t)t) = 90o - φ(t)t)

φb(t)t) ≠ const.

φc(t)t) = φ

a(t)t)

φd= 270o

φe= 180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

|a| = |OB| = a(t)t)

|c| = |OC| = c = const.

|b| = |CD| = b = const.

|d| = d(t)t)

|e| = e = const.

h + r = ac + b + d + e = 0

x : hcos ϕ h+r cosϕ r(t )=a(t)cosϕ a(t)y : hsin ϕ h+r sin ϕ r(t)=a(t)sin ϕ a(t)

x : c cosϕ c(t)+bcosϕ b(t)+d(t)cosϕ d+e cosϕ e=0y : c sin ϕ c(t )+b sinϕ b (t)+d (t)sin ϕ d+e sin ϕ e=0

x : hcos 90o+r cos(90o−ϕ(t ))=a(t)cosϕ a(t)

y : hsin 90o+r sin(90o−ϕ (t))=a(t)sin ϕ a(t)x : c cosϕ a(t)+bcosϕ b(t)+d (t)cos270

o+e cos180o=0

y : c sin ϕ a(t)+b sin ϕ b(t)+d (t)sin270o+e sin180o=0

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φh=90o

φa(t)t) ≠ const.

φr(t)t) = 90o - φ(t)t)

φb(t)t) ≠ const.

φc(t)t) = φ

a(t)t)

φd= 270o

φe= 180o

|r| = |AB| = r = const.

|h| = |OA| = h = const.

|a| = |OB| = a(t)t)

|c| = |OC| = c = const.

|b| = |CD| = b = const.

|d| = d(t)t)

|e| = e = const.

h + r = ac + b + d + e = 0

x : hcos ϕ h+r cosϕ r(t )=a(t)cosϕ a(t)y : hsin ϕ h+r sin ϕ r(t)=a(t)sin ϕ a(t)

x : c cosϕ c(t)+bcosϕ b(t)+d(t)cosϕ d+e cosϕ e=0y : c sin ϕ c(t )+b sinϕ b (t)+d (t)sin ϕ d+e sin ϕ e=0

x : hcos 90o+r cos(90o−ϕ(t ))=a(t)cosϕ a(t)

y : hsin 90o+r sin(90o−ϕ (t))=a(t)sin ϕ a(t)x : c cosϕ a(t)+bcosϕ b(t)+d (t)cos270

o+e cos180o=0

y : c sin ϕ a(t)+b sin ϕ b(t)+d (t)sin270o+e sin180o=0

x : r sinϕ (t)=a(t)cosϕ a(t)y : h+r cosϕ (t )=a(t )sin ϕ a(t )x : c cosϕ a(t)+bcosϕ b(t)−e=0y : c sin ϕ a(t)+b sin ϕ b(t)−d (t)=0

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x : r sinϕ (t)=a(t)cosϕ a(t)y : h+r cosϕ (t )=a(t )sin ϕ a(t )x : c cosϕ a(t)+bcosϕ b(t)−e=0y : c sin ϕ a(t)+b sin ϕ b(t)−d (t)=0

123

1

4

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x : r sinϕ (t)=a(t)cosϕ a(t)y : h+r cosϕ (t )=a(t )sin ϕ a(t )x : c cosϕ a(t)+bcosϕ b(t)−e=0y : c sin ϕ a(t)+b sin ϕ b(t)−d (t)=0

a ( t )=√ r2 sin2( t )+(h+r cosϕ ( t ) )

2

ϕ a ( t )=atan( h+r cosϕ ( t )

r sin ϕ ( t ) )

ϕ b ( t )=arccose−c cosϕ a ( t )

b

d ( t )=c sin ϕ a ( t )+b √ 1−( e−c cosϕ a( t )

b )2

123

1

4

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x : r sinϕ (t)=a(t)cosϕ a(t)y : h+r cosϕ (t )=a(t )sin ϕ a(t )x : c cosϕ a(t)+bcosϕ b(t)−e=0y : c sin ϕ a(t)+b sin ϕ b(t)−d (t)=0

a ( t )=√ r2 sin2( t )+(h+r cosϕ ( t ) )

2

ϕ a ( t )=atan( h+r cosϕ ( t )

r sin ϕ ( t ) )

ϕ b ( t )=arccose−c cosϕ a ( t )

b

vD ( t )=d ( t )

aD ( t )=d ( t )

123

1

4

d ( t )=c sin ϕ a ( t )+b √ 1−( e−c cosϕ a( t )

b )2

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d ( t )=c sin ϕ a ( t )+b √ 1−( e−c cosϕ a( t )

b )2

r= 0,3 [m]

h= 0,4 [m]

c= 1 [m]

e= 0,4 [m]

b= 1 [m]

ω= 1 [rad/s]

a ( t )=√ r2 sin2( t )+(h+r cosϕ ( t ) )

2

ϕ ( t )

[m ]

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ϕ a ( t )=atan( h+r cosϕ ( t )

r sin ϕ ( t ) )

ϕ b ( t )=arccose−c cosϕ a ( t )

b

ϕ ( t )

r= 0,3 [m]

h= 0,4 [m]

c= 1 [m]

e= 0,4 [m]

b= 1 [m]

ω= 1 [rad/s]

[rad ]

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ϕ ( t )

r= 0,3 [m]

h= 0,4 [m]

c= 1 [m]

e= 0,4 [m]

b= 1 [m]

ω= 1 [rad/s]vD ( t )=d ( t )

ms

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r= 0,3 [m]

h= 0,4 [m]

c= 1 [m]

e= 0,4 [m]

b= 1 [m]

ω= 1 [rad/s]

ϕ ( t )

aD ( t )=d ( t )

m

s2