Titik Buhul A

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BEBAN STATIS Mb = 0 (Va x 60) – (0,5 x 60) – 55 – 50 – 45 – 40 – 35 – 30 – 25 – 20 – 15 – 10 – 5 = 0 Va = 6 KN Ma = 0 (-Vb x 60) + (0,5 x 60) – 55 – 50 – 45 – 40 – 35 – 30 – 25 – 20 – 15 – 10 – 5 = 0 Vb = 6 KN

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Transcript of Titik Buhul A

BEBAN STATIS Mb = 0(Va x 60) (0,5 x 60) 55 50 45 40 35 30 25 20 15 10 5 = 0Va = 6 KN Ma = 0(-Vb x 60) + (0,5 x 60) 55 50 45 40 35 30 25 20 15 10 5= 0Vb= 6 KNTitik Buhul A

V = 0Va 0.5 + S1 Sin = 06 0.5 + S1 sin 50,2 = 0S1 = -7,1558 KN H = 0S1 cos + S2 = 0-7,1558 cos 50,2 + S2 = 0S2 = 4,5824 KN

Titik Buhul X

V = 0-S25 + S1 sin = 0-S25 + 7,1558 sin 50,2 = 0S25 = 5,5000KN H = 0S24 + S1 cos = 0S24 + 7,1558 cos 50,2 = 0S24 = -4,5824 KN

Titik Buhul C

V = 0S25 1 + S26 sin = 05,5 1 + S26 sin 50,2 = 0S26 = -5.8572 KN H = 0S3 S2 + S26 cos = 0S3 4,5824 + (-5.8572) cos 50,2 = 0S3 = 8.3316 KN

Titik Buhul W

V = 0-S27 + S26 sin = 0-S27 + 5,8572 sin 50,2 = 0S27 = 4,5000 KN H = 0S24 + S23 + S26 cos = 04,5824 + S23 + 5,8572 cos 50,2 = 0S23 = -8,3316 KN

Titik Buhul D

V = 0S27 1 + S28 sin = 04,5 1 + S28 sin 50,2 = 0S28 = -4,5600 KN H = 0S4 S3 + S28 cos = 0S4 8.3316 + (-4,5600) cos 50,2 = 0S4 = 11.2500 KNTitik Buhul V

V = 0-S29 + S28 sin = 0-S29 + S28 sin 50,2 = 0S29 = 3.5030 KN H = 0S22 S23 + S28 cos = 0S22 + 8.3316 + 4,5600 cos 50,2 = 0S22 = -11.2500 KNTitik Buhul E

V = 0S29 1 + S30 sin = 03.5030 1 + S30 sin 50,2 = 0S30 = -3.2580 KN H = 0S5 S4 + S30 cos = 0S5 11.2500 + (-3.2580) cos 50,2 = 0S5 = 13.3350 KNTitik Buhul U

V = 0-S31 + S30 sin = 0-S31 + 3.2580 sin 50,2 = 0 S31 = 2,503 KN H = 0S21 + S22 + S30 cos = 0S21 + 11.2500 + 2,503 cos 50,2 = 0S21 = -13.3350 KNTitik Buhul F

V = 0S31 1 + S32 sin = 02,503 1 + S32 sin 50,2 = 0S32 = -1,956 KN H = 0S6 S5 + S32 cos = 0S6 13.3350 + (-1,956) cos 50,2 = 0S6 = 14,857 KNRitter Pot 1 1S20 S34Berpotongan di titik GS35S7 Mg = 0Va x 25 0.5 x 25 20 15 10 5 + S20 x 6 = 0S20 = -14,5833 KNS7 S34 Berpotongan di titik TS35S20 Mt = 0Va x 25 0.5 x 25 20 15 10 5 S7 x 6 = 0S7 = 14,5833 KNTitik Buhul G

H = 0S7 S6 + S35 cos = 014,5833 14,54 + S35 cos 50,2 = 0S35 = -0,067 KN V = 0S33 1 + S35 sin = 0S33 1 + (-0,067) sin 50,2 = 0S33 = 1,04 KNTitik Buhul T

V = 0-S33 + S32 sin S34 sin = 0-1,04 + 1,956 sin 50,2 S34 sin 50,2 = 0S34 = 0,602 KNTitik Buhul Y

V = 0S34 sin + S35 sin + S36 sin S37 sin = 00,4625 + 0,0515 + S36 sin 50,2 S37 sin 50,2 = 0S36 x 0.7683 S37 x 0.7683 = -0,514 KN H = 0-S34 cos + S35 cos + S36 cos + S37 cos = 0-0,3854 + 0,0429 + S36 cos 50,2 S37 cos 50,2 = 0S36 x 0,640 S37 x 0,640= 0,3424 KNEleminasiS36 x 0.7683 S37 x 0.7683 = -0,514 KN x 0,640S36 x 0,640 S37 x 0,640= 0,3424 KNx 0,7683 0,492 x S36 0,492 x S37 = -0,3290,492 x S36 + 0,492 x S37 = 0,261 +0,984 S36 = -0,068S36= -0,069 KN 0,492 x (-0,069) 0,492 x S37 + 0,329 = 0S37= 0,73 KNTitik Buhul H

H = 0S7 + S8 + S40 cos S37 cos = 0S8 14,5833 + (-1,956) cos 50,2 = 0S6 = 14,857 KN V = 0S31 1 + S32 sin = 02,503 1 + S32 sin 50,2 = 0S32 = -1,956 KN