The principal inverse of the gamma function

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The principal inverse of the gamma function Mitsuru Uchiyama Shimane University 2013/7 Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 1 / 25

Transcript of The principal inverse of the gamma function

Page 1: The principal inverse of the gamma function

The principal inverse of the gamma function

Mitsuru Uchiyama

Shimane University

2013/7

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Introduction

The gamma function Γ(x) is usually defined by the Euler form

Γ(x) =

∫ ∞

0e−ttx−1dt

for x > 0. This is extended to ℜz > 0. By Γ(z + 1) = zΓ(z) forz = 0,−1,−2, · · · it is defined and holomorphic on C \ {0,−1,−2, · · · }

The Weierstrass form

1

Γ(x)= xeγx

∞∏n=1

(1 +x

n)e−

xn (1)

is useful, where γ is the Euler constant defined by

γ = limn→∞

(1 +1

2+ · · ·+ 1

n− log n) = 0.57721 · · · .

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Introduction

The gamma function Γ(x) is usually defined by the Euler form

Γ(x) =

∫ ∞

0e−ttx−1dt

for x > 0. This is extended to ℜz > 0. By Γ(z + 1) = zΓ(z) forz = 0,−1,−2, · · · it is defined and holomorphic on C \ {0,−1,−2, · · · }The Weierstrass form

1

Γ(x)= xeγx

∞∏n=1

(1 +x

n)e−

xn (1)

is useful, where γ is the Euler constant defined by

γ = limn→∞

(1 +1

2+ · · ·+ 1

n− log n) = 0.57721 · · · .

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Introduction

From (1) (Weierstrass form) it follows that

log Γ(x) = − log x − γx +∞∑n=1

(xn− log(1 +

x

n)),

Γ′(x)

Γ(x)= −γ +

∞∑n=0

(1

n + 1− 1

n + x) (psifunction) (2)

on C \ {0,−1,−2, · · · }.

By (2), Γ′(z)Γ(z) maps the open upper half plane Π+ into itself, namely Γ′(z)

Γ(z)

is a Pick (Nevanlinna) function. Γ′(z) does not vanish on Π+.

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Introduction

From (1) (Weierstrass form) it follows that

log Γ(x) = − log x − γx +∞∑n=1

(xn− log(1 +

x

n)),

Γ′(x)

Γ(x)= −γ +

∞∑n=0

(1

n + 1− 1

n + x) (psifunction) (2)

on C \ {0,−1,−2, · · · }.By (2), Γ′(z)

Γ(z) maps the open upper half plane Π+ into itself, namely Γ′(z)Γ(z)

is a Pick (Nevanlinna) function.

Γ′(z) does not vanish on Π+.

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Introduction

From (1) (Weierstrass form) it follows that

log Γ(x) = − log x − γx +∞∑n=1

(xn− log(1 +

x

n)),

Γ′(x)

Γ(x)= −γ +

∞∑n=0

(1

n + 1− 1

n + x) (psifunction) (2)

on C \ {0,−1,−2, · · · }.By (2), Γ′(z)

Γ(z) maps the open upper half plane Π+ into itself, namely Γ′(z)Γ(z)

is a Pick (Nevanlinna) function. Γ′(z) does not vanish on Π+.

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Introduction

-2 2 4

-20

-10

10

20

Figure : Gamma function

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Introduction

Γ(1) = Γ(2) = 1, Γ′(1) = −γ, Γ′(2) = −γ + 1.

Denote the unique zero in (0,∞) of Γ′(x) by α.

α = 1.4616 · · · , Γ(α) = 0.8856 · · ·.

We call the inverse function of the restriction of Γ(x) to (α,∞) theprincipal inverse function and write Γ−1.Γ−1(x) is an increasing and concave function defined on (Γ(α),∞).

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Introduction

Γ(1) = Γ(2) = 1, Γ′(1) = −γ, Γ′(2) = −γ + 1.

Denote the unique zero in (0,∞) of Γ′(x) by α.

α = 1.4616 · · · , Γ(α) = 0.8856 · · ·.

We call the inverse function of the restriction of Γ(x) to (α,∞) theprincipal inverse function and write Γ−1.Γ−1(x) is an increasing and concave function defined on (Γ(α),∞).

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Introduction

Main Theorem

Theorem 1

The principal inverse Γ−1(x) of Γ(x) has the holomorphic extensionΓ−1(z) to D := C \ (−∞, Γ(α)], which satisfies

(i) Γ−1(Π+) ⊂ Π+ and Γ−1(Π−) ⊂ Π−,

(ii) Γ−1(z) is univalent,

(iii) Γ(Γ−1(z)) = z for z ∈ D.

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kernel function

Definition 2

Let I be an interval in R and K (x , y) a continuous function defined onI × I . Then K (x , y) is said to be a positive semidefinite (p.s.d.) kernelfunction on an interval I × I (on I for short) if∫∫

I×IK (x , y)ϕ(x)ϕ(y)dxdy ≧ 0 (3)

for every complex continuous function ϕ with compact support in I .

• K (x , y) is p.s.d. if and only if for each n and for all n points xi ∈ I ,

n∑i ,j=1

K (xi , xj)zizj ≧ 0

for n complex numbers zi .

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kernel function

Definition 2

Let I be an interval in R and K (x , y) a continuous function defined onI × I . Then K (x , y) is said to be a positive semidefinite (p.s.d.) kernelfunction on an interval I × I (on I for short) if∫∫

I×IK (x , y)ϕ(x)ϕ(y)dxdy ≧ 0 (3)

for every complex continuous function ϕ with compact support in I .

• K (x , y) is p.s.d. if and only if for each n and for all n points xi ∈ I ,

n∑i ,j=1

K (xi , xj)zizj ≧ 0

for n complex numbers zi .

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kernel function

Definition 3

K (x , y) is said to be conditionally (or almost) positive semidefinite(c.p.s.d.) on I × I (on I for short) if (3) holds for every continuousfunction ϕ on I such that the support of ϕ is compact and

∫I ϕ(x)dx = 0.

K (x , y) is said to be conditionally negative semidefinite (c.n.s.d.) on I if−K (x , y) is c.p.s.d.

• K (x , y) is c.p.s.d. if and only if

n∑i ,j=1

K (xi , xj)zizj ≧ 0 (4)

for each n, for all n points xi ∈ I and for n complex numbers zi with∑ni=1 zi = 0.

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kernel function

Definition 3

K (x , y) is said to be conditionally (or almost) positive semidefinite(c.p.s.d.) on I × I (on I for short) if (3) holds for every continuousfunction ϕ on I such that the support of ϕ is compact and

∫I ϕ(x)dx = 0.

K (x , y) is said to be conditionally negative semidefinite (c.n.s.d.) on I if−K (x , y) is c.p.s.d.

• K (x , y) is c.p.s.d. if and only if

n∑i ,j=1

K (xi , xj)zizj ≧ 0 (4)

for each n, for all n points xi ∈ I and for n complex numbers zi with∑ni=1 zi = 0.

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kernel function

Facts

K (x , y) = f (x)f (y) is p.s.d.

If K (x , y) is p.s.d. on [a, b] and h : [c , d ] 7→ [a, b] is increasing and(differentiable), then so is K (h(t), h(s)) on [c , d ].

If Kt(x , y) is p.s.d. for each t, then so is∫Kt(x , y)dµ(t).

(Schur) If K1(x , y) and K2(x , y) are both p.s.d. on I , then so is theproduct K1(x , y)K2(x , y).

If K (x , y) is p.s.d. on I , then K (x , y) is c.p.s.d. on I .

K (x , y) = x + y is not p.s.d. but c. p. s. d. and c. n. s. d. on any I .

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kernel function

Definition 4

Suppose K (x , y) ≧ 0 for every x , y in I . Then K (x , y) is said to be infinitely divisible on I × I (on I for short) if K (x , y)a is positivesemi-definite for every a > 0.

K (x , y) is infinitely divisible if and only if for each n, for all n points xi ∈ Iand for every a > 0matrix

(K (xi , xj)a)

is positive semi-definite.

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kernel function

Definition 4

Suppose K (x , y) ≧ 0 for every x , y in I . Then K (x , y) is said to be infinitely divisible on I × I (on I for short) if K (x , y)a is positivesemi-definite for every a > 0.

K (x , y) is infinitely divisible if and only if for each n, for all n points xi ∈ Iand for every a > 0matrix

(K (xi , xj)a)

is positive semi-definite.

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kernel function

Cauchy kernel1

x + y

is infinitely divisible on (0,∞)× (0,∞).

∵ 1

(x + y)a=

1

Γ(a)

∫ ∞

0e−txe−ty ta−1dt

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kernel function

Cauchy kernel1

x + y

is infinitely divisible on (0,∞)× (0,∞).

∵ 1

(x + y)a=

1

Γ(a)

∫ ∞

0e−txe−ty ta−1dt

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kernel function

Lemma 5

(Fitzgerald, Horn) Let K (x , y) > 0 for x , y ∈ I and suppose −K (x , y) isc.p.s.d. on I × I . Then exp(−K (x , y)) and the reciprocal function 1

K(x ,y)are infinitely divisible there.

Example K (x , y) := x + y on (0,∞)× (0,∞)K (x , y) > 0 and −K (x , y) is c.p.s.d. on (0,∞)× (0,∞).(exp(−K (x , y)))a = e−axe−ay is p.s.d. for every a > 0.

1K(x ,y) =

1x+y is the Cauchy kernel .

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kernel function

Lemma 5

(Fitzgerald, Horn) Let K (x , y) > 0 for x , y ∈ I and suppose −K (x , y) isc.p.s.d. on I × I . Then exp(−K (x , y)) and the reciprocal function 1

K(x ,y)are infinitely divisible there.

Example K (x , y) := x + y on (0,∞)× (0,∞)K (x , y) > 0 and −K (x , y) is c.p.s.d. on (0,∞)× (0,∞).(exp(−K (x , y)))a = e−axe−ay is p.s.d. for every a > 0.

1K(x ,y) =

1x+y is the Cauchy kernel .

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kernel function

The Lowner kernel

Definition 6

Let f (x) be a real C 1-function on I . Then the Lowner kernel function isdefined by

Kf (x , y) =

{f (x)−f (y)

x−y (x = y)

f ′(x) (x = y).

Example

(i) For f (x) = x , Kf (x , y) = 1 is p. s. d. on R2.

(ii) For f (x) = − 1x+λ , Kf (x , y) =

1(x+λ)(y+λ) is p. s. d. on

(−λ,∞)× (−λ,∞) and on (−∞,−λ)× (−∞,−λ).

(iii) For f (x) = x2, Kf (x , y) = x + y is not p. s. d. but c. p. s. d. and c.n. s. d.

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kernel function

The Lowner kernel

Definition 6

Let f (x) be a real C 1-function on I . Then the Lowner kernel function isdefined by

Kf (x , y) =

{f (x)−f (y)

x−y (x = y)

f ′(x) (x = y).

Example

(i) For f (x) = x , Kf (x , y) = 1 is p. s. d. on R2.

(ii) For f (x) = − 1x+λ , Kf (x , y) =

1(x+λ)(y+λ) is p. s. d. on

(−λ,∞)× (−λ,∞) and on (−∞,−λ)× (−∞,−λ).

(iii) For f (x) = x2, Kf (x , y) = x + y is not p. s. d. but c. p. s. d. and c.n. s. d.

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kernel function

(Lowner Theorem) (also Koranyi)

Let f (x) be a real C 1-function on I . Then the Lowner kernel functionKf (x , y) is p.s.d. on I × I if and only if f (x) has a holomorphic extensionf (z) to Π+ which is a Pick (Nevanlinna) function.

We will showKΓ−1(x , y)

is p. s. d. on (Γ(α),∞)× (Γ(α),∞).

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kernel function

(Lowner Theorem) (also Koranyi)

Let f (x) be a real C 1-function on I . Then the Lowner kernel functionKf (x , y) is p.s.d. on I × I if and only if f (x) has a holomorphic extensionf (z) to Π+ which is a Pick (Nevanlinna) function.

We will showKΓ−1(x , y)

is p. s. d. on (Γ(α),∞)× (Γ(α),∞).

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Proof

Lemma 7

(Known result)

Klog x(x , y) :=

{log x−log y

x−y (x = y)1x (x = y)

is p.s.d. on (0,∞)× (0,∞)

Proof. By the formula

log x =∫∞0 ( −1

x+t +t

t2+1)dt (x > 0),

we obtain

Klog x(x , y) =∫∞0

1(x+t)(y+t)dt

for x , y > 0. □

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Proof

Lemma 7

(Known result)

Klog x(x , y) :=

{log x−log y

x−y (x = y)1x (x = y)

is p.s.d. on (0,∞)× (0,∞)

Proof. By the formula

log x =∫∞0 ( −1

x+t +t

t2+1)dt (x > 0),

we obtain

Klog x(x , y) =∫∞0

1(x+t)(y+t)dt

for x , y > 0. □

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Proof

Lemma 7

(Known result)

Klog x(x , y) :=

{log x−log y

x−y (x = y)1x (x = y)

is p.s.d. on (0,∞)× (0,∞)

Proof. By the formula

log x =∫∞0 ( −1

x+t +t

t2+1)dt (x > 0),

we obtain

Klog x(x , y) =∫∞0

1(x+t)(y+t)dt

for x , y > 0. □

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Proof

Lemma 8

Klog Γ(x)(x , y) :=

{log Γ(x)−log Γ(y)

x−y (x = y)Γ′(x)Γ(x) (x = y).

−Klog Γ(x)(x , y) is c.p.s.d. on (0,∞).

Proof.

log Γ(x) = − log x − γx +∑∞

n=1

(xn − log(1 + x

n ))

g(x) :=∑∞

k=1

(xk − log(1 + x

k ))

log Γ(x) = − log x − γx + g(x)−Klog Γ(x)(x , y) = Klog x(x , y) + γ − Kg (x , y).

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Proof

Lemma 8

Klog Γ(x)(x , y) :=

{log Γ(x)−log Γ(y)

x−y (x = y)Γ′(x)Γ(x) (x = y).

−Klog Γ(x)(x , y) is c.p.s.d. on (0,∞).

Proof.

log Γ(x) = − log x − γx +∑∞

n=1

(xn − log(1 + x

n ))

g(x) :=∑∞

k=1

(xk − log(1 + x

k ))

log Γ(x) = − log x − γx + g(x)−Klog Γ(x)(x , y) = Klog x(x , y) + γ − Kg (x , y).

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Proof

Lemma 8

Klog Γ(x)(x , y) :=

{log Γ(x)−log Γ(y)

x−y (x = y)Γ′(x)Γ(x) (x = y).

−Klog Γ(x)(x , y) is c.p.s.d. on (0,∞).

Proof.

log Γ(x) = − log x − γx +∑∞

n=1

(xn − log(1 + x

n ))

g(x) :=∑∞

k=1

(xk − log(1 + x

k ))

log Γ(x) = − log x − γx + g(x)−Klog Γ(x)(x , y) = Klog x(x , y) + γ − Kg (x , y).

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Proof

−Klog Γ(x)(x , y) = Klog x(x , y) + γ − Kg (x , y).

Klog x(x , y) is p.s.d. and a constant function γ is c.p.s.d.We will see −Kg (x , y) is c.p.s.d.

gn(x) :=∑n

k=1

(xk − log(1 + x

k )).

(i) −Kgn(x , y) is c.p.s.d.

(ii) g ′n(x) =

∑nk=1

xk(k+x) ⇒

∑∞k=1

xk(k+x) = g ′(x) on any finite interval

[0,M].

(iii) Kgn(x , y)− Kg (x , y) =

1

x−y

∫ xy (g ′

n(t)− g ′(t)) dt (x = y)

g ′n(x)− g ′(x) (x = y)

Therefore, −Kg (x , y) is c.p.s.d. on (0,∞). □

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Proof

−Klog Γ(x)(x , y) = Klog x(x , y) + γ − Kg (x , y).

Klog x(x , y) is p.s.d. and a constant function γ is c.p.s.d.We will see −Kg (x , y) is c.p.s.d.gn(x) :=

∑nk=1

(xk − log(1 + x

k )).

(i) −Kgn(x , y) is c.p.s.d.

(ii) g ′n(x) =

∑nk=1

xk(k+x) ⇒

∑∞k=1

xk(k+x) = g ′(x) on any finite interval

[0,M].

(iii) Kgn(x , y)− Kg (x , y) =

1

x−y

∫ xy (g ′

n(t)− g ′(t)) dt (x = y)

g ′n(x)− g ′(x) (x = y)

Therefore, −Kg (x , y) is c.p.s.d. on (0,∞). □

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Proof

−Klog Γ(x)(x , y) = Klog x(x , y) + γ − Kg (x , y).

Klog x(x , y) is p.s.d. and a constant function γ is c.p.s.d.We will see −Kg (x , y) is c.p.s.d.gn(x) :=

∑nk=1

(xk − log(1 + x

k )).

(i) −Kgn(x , y) is c.p.s.d.

(ii) g ′n(x) =

∑nk=1

xk(k+x) ⇒

∑∞k=1

xk(k+x) = g ′(x) on any finite interval

[0,M].

(iii) Kgn(x , y)− Kg (x , y) =

1

x−y

∫ xy (g ′

n(t)− g ′(t)) dt (x = y)

g ′n(x)− g ′(x) (x = y)

Therefore, −Kg (x , y) is c.p.s.d. on (0,∞). □

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Proof

−Klog Γ(x)(x , y) = Klog x(x , y) + γ − Kg (x , y).

Klog x(x , y) is p.s.d. and a constant function γ is c.p.s.d.We will see −Kg (x , y) is c.p.s.d.gn(x) :=

∑nk=1

(xk − log(1 + x

k )).

(i) −Kgn(x , y) is c.p.s.d.

(ii) g ′n(x) =

∑nk=1

xk(k+x) ⇒

∑∞k=1

xk(k+x) = g ′(x) on any finite interval

[0,M].

(iii) Kgn(x , y)− Kg (x , y) =

1

x−y

∫ xy (g ′

n(t)− g ′(t)) dt (x = y)

g ′n(x)− g ′(x) (x = y)

Therefore, −Kg (x , y) is c.p.s.d. on (0,∞). □

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Proof

−Klog Γ(x)(x , y) = Klog x(x , y) + γ − Kg (x , y).

Klog x(x , y) is p.s.d. and a constant function γ is c.p.s.d.We will see −Kg (x , y) is c.p.s.d.gn(x) :=

∑nk=1

(xk − log(1 + x

k )).

(i) −Kgn(x , y) is c.p.s.d.

(ii) g ′n(x) =

∑nk=1

xk(k+x) ⇒

∑∞k=1

xk(k+x) = g ′(x) on any finite interval

[0,M].

(iii) Kgn(x , y)− Kg (x , y) =

1

x−y

∫ xy (g ′

n(t)− g ′(t)) dt (x = y)

g ′n(x)− g ′(x) (x = y)

Therefore, −Kg (x , y) is c.p.s.d. on (0,∞). □

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 17 / 25

Page 37: The principal inverse of the gamma function

Proof

Lemma 9

1

Klog Γ(x)(x , y)

is infinitely divisible on (α,∞).

Proof

By the previous lemmaKlog Γ(x)(x , y) > 0

is c.n.s.d. on (α,∞). By Fitzgerald and Horn’s result, we get the requiredresult.

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 18 / 25

Page 38: The principal inverse of the gamma function

Proof

Lemma 9

1

Klog Γ(x)(x , y)

is infinitely divisible on (α,∞).

Proof

By the previous lemmaKlog Γ(x)(x , y) > 0

is c.n.s.d. on (α,∞). By Fitzgerald and Horn’s result, we get the requiredresult.

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 18 / 25

Page 39: The principal inverse of the gamma function

Proof

Lemma 10

Let K1(x , y) be the kernel function defined on (α,∞)× (α,∞) by

K1(x , y) =

{x−y

Γ(x)−Γ(y) (x = y)1

Γ′(x) (x = y).

Then K1(x , y) is p.s.d. on (α,∞).

Proof.

K1(x , y) =

{log Γ(x)−log Γ(y)

Γ(x)−Γ(y)x−y

log Γ(x)−log Γ(y) (x = y)1

Γ(x)Γ(x)Γ′(x) (x = y)

= Klog x(Γ(x), Γ(y)) ·1

Klog Γ(x)(x , y)□

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 19 / 25

Page 40: The principal inverse of the gamma function

Proof

Lemma 10

Let K1(x , y) be the kernel function defined on (α,∞)× (α,∞) by

K1(x , y) =

{x−y

Γ(x)−Γ(y) (x = y)1

Γ′(x) (x = y).

Then K1(x , y) is p.s.d. on (α,∞).

Proof.

K1(x , y) =

{log Γ(x)−log Γ(y)

Γ(x)−Γ(y)x−y

log Γ(x)−log Γ(y) (x = y)1

Γ(x)Γ(x)Γ′(x) (x = y)

= Klog x(Γ(x), Γ(y)) ·1

Klog Γ(x)(x , y)□

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 19 / 25

Page 41: The principal inverse of the gamma function

Proof

Proof of Theorem

We have shown

K1(x , y) =

{x−y

Γ(x)−Γ(y) (x = y)1

Γ′(x) (x = y).

is p.s.d. on (α,∞). Hence

KΓ−1(x , y) =

{Γ−1(x)−Γ−1(y)

x−y (x = y)

(Γ−1)′(x) (x = y)= K1(Γ

−1(x), Γ−1(y))

is p.s.d. on (Γ(α),∞)× (Γ(α),∞).Thus by the Lowner theorem, Γ−1(x) has the holomorphic extensionΓ−1(z) onto Π+, which is a Pick function.By reflection Γ−1(x) has also holomorphic extension to Π− and the rangeis in it.

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 20 / 25

Page 42: The principal inverse of the gamma function

Proof

Γ(Γ−1(z)) is thus holomorphic on the simply connected domainD := C \ (−∞, Γ(α)], and Γ(Γ−1(x)) = x for Γ(α) < x < ∞. By theunicity theorem, Γ

(Γ−1(z)

)= z for z ∈ D. It is clear that Γ−1(z) is

univalent. □

Corollary 11

There is a Borel measure µ so that

Γ−1(x) = a+ bx +

∫ Γ(α)

−∞(

1

t − x− t

t2 + 1)dµ(t), (5)

where∫ Γ(α)−∞

1t2+1

dµ(t) < ∞, and a, b are real numbers and b ≧ 0.

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 21 / 25

Page 43: The principal inverse of the gamma function

Proof

Γ(Γ−1(z)) is thus holomorphic on the simply connected domainD := C \ (−∞, Γ(α)], and Γ(Γ−1(x)) = x for Γ(α) < x < ∞. By theunicity theorem, Γ

(Γ−1(z)

)= z for z ∈ D. It is clear that Γ−1(z) is

univalent. □Corollary 11

There is a Borel measure µ so that

Γ−1(x) = a+ bx +

∫ Γ(α)

−∞(

1

t − x− t

t2 + 1)dµ(t), (5)

where∫ Γ(α)−∞

1t2+1

dµ(t) < ∞, and a, b are real numbers and b ≧ 0.

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 21 / 25

Page 44: The principal inverse of the gamma function

Application

Matrix inequality

Theorem 12

The principal inverse Γ−1(x) of Γ(x) is operator monotone on[Γ(α),∞); i.e.,and hence for bounded self-adjoint operators A,B whose spectra are in[Γ(α),∞)

A ≦ B ⇒ Γ−1(A) ≦ Γ−1(B).

Proof A ≦ B implies that −(A− tI )−1 ≦ −(B − tI )−1 for t < Γ(α). From

Γ−1(x) = a+ bx +∫ Γ(α)−∞ ( −1

x−t −t

t2+1)dµ(t)

we have Γ−1(A) ≦ Γ−1(B). □

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 22 / 25

Page 45: The principal inverse of the gamma function

Application

Matrix inequality

Theorem 12

The principal inverse Γ−1(x) of Γ(x) is operator monotone on[Γ(α),∞); i.e.,and hence for bounded self-adjoint operators A,B whose spectra are in[Γ(α),∞)

A ≦ B ⇒ Γ−1(A) ≦ Γ−1(B).

Proof A ≦ B implies that −(A− tI )−1 ≦ −(B − tI )−1 for t < Γ(α). From

Γ−1(x) = a+ bx +∫ Γ(α)−∞ ( −1

x−t −t

t2+1)dµ(t)

we have Γ−1(A) ≦ Γ−1(B). □

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 22 / 25

Page 46: The principal inverse of the gamma function

Application

K2(x , y) := Klog Γ(x)(x , y) =

{log Γ(x)−log Γ(y)

x−y (x = y)Γ′(x)Γ(x) (x = y).

Then

e−K2(x ,y) =

(Γ(y)Γ(x))1

x−y (x = y)

e− Γ′(x)

Γ(x) (x = y)

is infinitely divisible. Since Γ(x + 1) = xΓ(x),

Γ′(1)

Γ(1)= −γ,

Γ′(m + 1)

Γ(m + 1)=

Γ′(m)

Γ(m)+

1

m,Γ(n)

Γ(m)=

(n − 1)!

(m − 1)!.

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 23 / 25

Page 47: The principal inverse of the gamma function

Application

matrix

The following (n+ 1)× (n+ 1) matrix is therefore not only p.s.d. but alsoinfinitely divisible. (

e−K2(i ,j))=

=

eγ (1!1!)−1 (2!)−

12 (3!)−

13 · · · (n!)−

1n

(1!1!)−1 eγ−1 (2!1!)

−1 (3!1!)− 1

2 · · · (n!1! )− 1

n−1

(2!)−12 (2!1!)

−1 eγ−1− 12 (3!2!)

−1 · · · (n!2! )− 1

n−2

(3!)−13 (3!1!)

− 12 (3!2!)

−1 eγ−1− 12− 1

3 · · · (n!3! )− 1

n−3

......

......

. . ....

(n!)−1n (n!1! )

− 1n−1 (n!2! )

− 1n−2 (n!3! )

− 1n−3 · · · eγ−1− 1

2−···− 1

n

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 24 / 25

Page 48: The principal inverse of the gamma function

Application

R. Bhatia, Infinitely divisible matrices, Amer. Math. Monthly, 113, 221–235(2006).

R. Bahtia and H. Kosaki, Mean matrices and infinite divisibility, Linear Algebra Appl., 424,

36–54(2007).

C. Berg, H. L. Pedersen, Pick functions related to the gamma function, Rocky Mountain J. of Math.

32(2002)507–525.

A, Koranyi, On a theorem of Lowner and its connections with resolvents of selfadjoint

transformations, Acta Sci. Math. 17, 63–70(1956).

K. Lowner, Uber monotone Matrixfunctionen, Math. Z. 38(1934)177–216.

W. F. Donoghue, Monotone Matrix Functions and Analytic Continuation, Springer-Verlag, 1974.

C. H. Fitzgerald, On analytic continuation to a Schlicht function, Proc. Amer. Math. Soc., 18,

788–792(1967).

R. A. Horn, Schlicht mapping and infinitely divisible kernels, Pacific J. of Math. 38, 423–430(1971).

R. A. Horn and C. R. Johnson, Topics in Matrix Analysis, Cambridge University Press, 1991.

M. Uchiyama, Operator monotone functions, positive definite kernels and majorization, Proc. Amer.

Math. 138(2010)3985–3996

M. Uchiyama, The principal inverse of the gamma function, PAMS (2012) 1343–1348.

Mitsuru Uchiyama (Shimane University) The principal inverse of the gamma function 2013/7 25 / 25