Quantum Mechanics II - DESY

2
DESY Theory Group, Hamburg Tutorials for the Lecture Quantum Mechanics II WS 20/21 Prof. Dr. J. Reuter Tutorial 11 (Bldg. 2a/304), 3895 P. Bredt/F. Fabry; B. Richard; S. van Thurenhout; T. Wening; 03.02.2021 Home Exercise 28 Gordon identity for spinors Derive the Gordon identity for spinor solutions of the Dirac equation u(p 0 )γ μ u(p)= u(p 0 ) p μ + p 0 μ 2m + μν q ν 2m u(p) . (1) Here, q is the momentum transfer, q =(p 0 - p), and σ μν = i 2 [γ μ ν ]. Hint: Remember that u(p) is a solution of the Dirac equation, (/ p - m)u(p)=0. Home Exercise 29 Noether currents of the Dirac theory Show that the transformation of the Dirac spinors Ψ exp [-is a sym- metry transformation of the Dirac Lagrangian. Use the exercises from the last sheet, i.e. the general formula for the Noether current, to derive the Noether current for this symmetry transformation. Show that this current is conser- ved. Do you remember what invariance under transformations with complex phases signified in multi-particle quantum mechanics? What needs to be fulfilled that also Ψ exp [-iαγ 5 is a symmetry of the Lagrangian? Home Exercise 30 Projecting out annihilation and creation operators for the Dirac field Use the Fourier decomposition of the Dirac field operator ˆ ψ(x)= Z f dp 2 s=1 ˆ b s p u s (p)e -ipx + ˆ d s p v s (p)e +ipx as well as of the adjoint field operator ψ(x) to project out the creation and annihilation operators for Dirac particles and anti-particles out of them: ˆ b s k = Z d 3 x u s (k) e ikx γ 0 ˆ ψ(x) (2a) ˆ d s k = Z d 3 x ˆ ψ(x) e ikx γ 0 v s (k) (2b) ˆ b s k = Z d 3 x ˆ ψ(x) e -ikx γ 0 u s (k) (2c) ˆ d s k = Z d 3 x v s (k) e -ikx γ 0 ˆ ψ(x) (2d) For this, the different normalization relations of spinor solutions of the Dirac equation might be helpful: u s (k)u s 0 (k)= 2ss 0 , u s (k)u s 0 (k)= 2k 0 δ ss 0 , (3a) v s (k)v s 0 (k)= -2ss 0 , v s (k)v s 0 (k)= 2k 0 δ ss 0 , (3b) u s (k)v s 0 (0) = 0, v s ( ~ k)v s 0 (- ~ k)= 0 (3c)

Transcript of Quantum Mechanics II - DESY

Page 1: Quantum Mechanics II - DESY

DESY Theory Group, Hamburg

Tutorials for the Lecture

Quantum Mechanics II WS 20/21

Prof. Dr. J. Reuter Tutorial 11(Bldg. 2a/304), 3895P. Bredt/F. Fabry; B. Richard; S. van Thurenhout; T. Wening; 03.02.2021

Home Exercise 28 Gordon identity for spinorsDerive the Gordon identity for spinor solutions of the Dirac equation

u(p′)γµu(p) = u(p′)

[pµ + p′µ

2m+iσµνqν

2m

]u(p) . (1)

Here, q is the momentum transfer, q = (p′ − p), and σµν = i2[γµ, γν ]. Hint:

Remember that u(p) is a solution of the Dirac equation, (/p−m)u(p) = 0.

Home Exercise 29 Noether currents of the Dirac theoryShow that the transformation of the Dirac spinors Ψ→ exp [−iα] Ψ is a sym-metry transformation of the Dirac Lagrangian. Use the exercises from the lastsheet, i.e. the general formula for the Noether current, to derive the Noethercurrent for this symmetry transformation. Show that this current is conser-ved. Do you remember what invariance under transformations with complexphases signified in multi-particle quantum mechanics?

What needs to be fulfilled that also Ψ → exp [−iαγ5] Ψ is a symmetry of theLagrangian?

Home Exercise 30 Projecting out annihilation and creation operators for theDirac field

Use the Fourier decomposition of the Dirac field operator

ψ(x) =∫dp

2

∑s=1

(bspu

s(p)e−ipx + dsp†vs(p)e+ipx

)as well as of the adjoint field operator ψ(x) to project out the creation andannihilation operators for Dirac particles and anti-particles out of them:

bsk =∫d3x us(k) eikx γ0ψ(x) (2a)

dsk =∫d3x ψ(x) eikx γ0vs(k) (2b)

bsk† =

∫d3x ψ(x) e−ikx γ0us(k) (2c)

dsk† =

∫d3x vs(k) e−ikx γ0ψ(x) (2d)

For this, the different normalization relations of spinor solutions of the Diracequation might be helpful:

us(k)us′(k) = 2mδss′ , us†(k)us

′(k) = 2k0δss′ , (3a)

vs(k)vs′(k) = −2mδss′ , vs†(k)vs

′(k) = 2k0δss′ , (3b)

us(k)vs′(0) = 0, vs†(~k)vs

′(−~k) = 0 (3c)

Page 2: Quantum Mechanics II - DESY

Repetition QM I Exercise 13 Magnetic moment of the hydrogen atom in itsground state

The Hamiltonian for a hydrogen atom in a homogeneous magnetic field ~B

with ~A(~x) = 12~B × ~x is given by

H =2

∑i=1

{1

2mi

(~pi −

eic~A(~ri)

)2− gi~Si ~B

}+

e1e2|~r1 − ~r2|

. (4)

Here, the numbers 1 and 2 label the electron and the hydrogen nucleus, re-spectively.

(a) Use the exercise from sheet 9 to separate H with respect to relative and center-of-mass coordinates and derive the operator for the total magnetic momentfor the total system. All terms quadratic in the external magnetic field O( ~B2)in the Hamiltonian could be neglected. Why are the terms that are not simplyrelative and total angular momentum in the magnetic moment?

b) The wave function for the ground state shall be given by the following sepa-ration ansatz Ψ0(~R, ~x) = Ψ(~R)e−α|~r|χp(m)χe−(m′), where m and m′ are the zcomponents of the spins of proton and electron, and χ their correspondingspinor wave functions. Calculate the expectation value of the magnetic mo-ment

⟨~µ⟩

in the ground state.