Quadrilateral s

11
QUADRILATERALS

Transcript of Quadrilateral s

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QUADRILATERALS

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QUADRILATERAL

ParallelogramTrapezoidTrapezium

RectangleRhombus

Square

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EXERCISESEXERCISES

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422 = 832 + 682 -2(68)(83)CosΘ

Θ = 30.27Ο

(COSINE LAW)

30.27Ο + β = 180ο30.27Ο + β = 180ο

β = 149.73ο

d22 = 832 + 682 -2(83)(68)Cos149.73ο

d2 = 148.81 cm

d2

(COSINE LAW)

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A = ½ d 1d2132cm2 = ½ (12 cm)d 2132cm2 = ((6cm)d 2)

6 cm 6cm d2 = 22 cm

(Area of

Rhombus)

Pythagorean

s = √ (11)2 + (6)2

Pythagorean

Theorem

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ο

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tan 60Ο = h / 3h = 5.2 cm

A = 1 / 2 (a + b) hA = 1 / 2 (8 + 11) (5.2)A = 49.4 cm2

ο

(SOHCAHTOA)

(Area of Trapezoid)

cos 60 = 3 / cc = 6 cm

A = 49.4 cm2

P = 8 + 11 +5.2 + 6P = 30.2 cm

(SOHCAHTOA)

(Perimeter)

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s = 10 + 5 + 14.14 + 152

s = 22.07 cm

A = √ (s-a)(s-b)(s-c)(s-d) - abcd cos 2 [½(A+C)]

A =√(22.07-10)(22.07-5)(22.07-14.14)(22.07-15) – (10)(5)(14.14)(15) cos 2 [½(225)]

A = √(12.07)(17.07)(7.93)(7.07) – (10)(5)(14.14)(15) cos 2 [½(225)]

A = 99.9 m2

(General Formula for Area of Quadrilaterals)


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