Probability Theory Review of essential concepts. Probability P(A B) = P(A) + P(B) – P(A B) 0 ≤...
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Transcript of Probability Theory Review of essential concepts. Probability P(A B) = P(A) + P(B) – P(A B) 0 ≤...
Problem 1 Given that P(A)=0.6 and P(B)=0.7,
which of the following cannot be true?
P(A B) = 0.5 = or P(A B) = 0.9 = and P(A B) = 0.2 P(A B) = 0.4 P(A B) = 0.7
Conditional Probability A and B are called independent if
P(A B) = P(A) * P(B)
P(A | B) = P(A B)/P(B) P(A | B) = доля A в B
A and B are independent P(A|B)=P(A)
Complete Probability P(A) = P(A|H1)P(H1) +
P(A|H2)P(H2) + …
P(A|Hn)P(Hn)
H1, H2, … Hn – complete disjoint system of events
A
H1
H2
Hn
Problem 2
Suppose a certain drug test is 99% sensitive and 99% specific, that is, the test will correctly identify a drug user as testing positive 99% of the time, and will correctly identify a non-user as testing negative 98% of the time. Let's assume a corporation decides to test its employees for opium use, and 0.5% of the employees use the drug. What is the probability that, given a positive drug test, an employee is actually a drug user?
Problem 3
We are presented with three doors - red, green, and blue - one of which has a prize. We choose the red door, which is not opened until the presenter performs an action. The presenter who knows what door the prize is behind, and who must open a door, but is not permitted to open the door we have picked or the door with the prize, opens the blue door and reveals that there is no prize behind it and subsequently asks if we wish to change our mind about our initial selection of red. What is the probability that the prize is behind each of the green and red doors?
Random Variables Discrete (Uniform, Binomial, Poisson,
Geometric, Hypergeometric, Negative Binomial,…)
Continuous (Uniform, Normal, Exponential, Gamma, Chi-square, Student, Fisher, Dirchilet,…)
Binomial Distribution
Binomial random number = the number of successes in n independent trials; p=probability of success in one trial
0
0.1
0.2
0.3
0.4
0.5
0.6
0 1 2 3 4 5 6
0
0.05
0.1
0.15
0.2
0.25
0.3
0.35
0 1 2 3 4 5 6
0
0.05
0.1
0.15
0.2
0.25
0.3
0.35
0 1 2 3 4 5 6
p=0.1 p=0.3 p=0.5
Problem 4
The probability that a certain machine will
produce a defective item is 0.20. If a random
sample of 6 items is taken from the output of
this machine, what is the probability that
there will be 5 or more defectives in the
sample?
Problem 5There are 10 patients on the Neo-Natal Ward of
a local hospital who are monitored by 2 staff
members. If the probability (at any one time) of a
patient requiring emergency attention by a staff
member is 0.3, assuming the patients to be
behave independently, what is the probability at
any one time that there will not be sufficient staff
to attend all emergencies?
Cumulative Probability
X = random variableF(x) = P(X ≤ x)
Most of the data analysis tools have a built-in
function for the cumulative
binomial probability
Poisson DistributionPoisson random number = the
number of rare events per unit of time or space
0
0.05
0.1
0.15
0.2
0.25
0.3
0.35
0.4
0 1 2 3 4 5 6 7 8 9 10 11 12 13
0
0.02
0.04
0.06
0.08
0.1
0.12
0.14
0.16
0.18
0.2
0 1 2 3 4 5 6 7 8 9 10 11 12 13
λ=1.5 λ=5
Problem 6
The marketing manager of a company has noted that she usually receives 10 complaint calls during a week (consisting of five working days), and that the calls occur at random. Find the probability that she gets five such calls in one day.
Problem 7 The rate at which a particular defect occurs
in lengths of plastic film being produced by a stable manufacturing process is 4.2 defects per 75 meter length. A random sample of the film is selected and it was found that the length of the film in the sample was 25 meters. What is the probability that there will be at most 2 defects found in the sample?
Other Normal Distributions Z = N(0,1)
Mean = 0 Variance = 1
X = N(μ, σ) Mean = μ Variance = σ2
Z = (X- μ)/σ
Problem 8
The diameters of steel disks produced in a plant are normally distributed with a mean of 2.5 cm and standard deviation of 0.02 cm. What is the probability that a disk picked at random has a diameter greater than 2.54 cm?
Problem 9
The height of an adult male is known to be normally distributed with a mean of 69 inches and a standard deviation of 2.5 inches. What is the height of the doorway such that 96 percent of the adult males can pass through it without having to bend?
Problem 10
The longevity of people living in a certain locality has a standard deviation of 14 years. What is the mean longevity if 30% of the people live longer than 75 years? Assume a normal distribution for life spans.
Normal Approximation to Binomial
X = Binom(n,p) n = number of trials p = probability of a single success
X = N(μ, σ) μ = np σ2 = np(1-p)
n>40np>5n(1-p)>5
Problem 11
The unemployment rate in a certain city is
8.5% . A random sample of 100 people from
the labor force is drawn. Find the approximate
probability that the sample contains at least
ten unemployed people.
Problem 12Companies are interested in the demographics
of those who listen to the radio programs they
sponsor. A radio station has determined that
only 20% of listeners phoning in to a morning
talk program are male. During a particular
week, 200 calls are received by this program.
What is the approximate probability that at least
50 of the callers are male?
Poisson Approximation to Bionomial
X = Binom(n,p) n = number of trials p = probability of a single success
X = Poisson(λ) λ = np
n→∞p→0np=λ=const
Problem 13A certain genetic characteristic will
express itself in 0.001 of the population.
In a sample of n=3000 subjects, k=7 are
observed to display the characteristic,
whereas only three are expected to
display the characteristic. How likely is it
that a rate this great or greater could
occur by mere chance?
Expected Value
x x1 x2 … … xn
p p1 p2 … … pn
E(X) = Σ xi pi = not a random number
x 0 1
P 1/2 1/2
E(X) =0*1/2+1*1/2=1/2
y 0 1
P 1/3 2/3
E(Y) =0*1/3+1*2/3=2/3
X+Y 0 1 2
P 1/6 1/2 1/3
E(X+Y) =1*1/2+2*1/3= = E(X)+E(Y)
X and Y are independent X=a and Y=b are independent events
Variance
Var(X) = E[ (X-E(X))2 ] = E(X2)-(E (X))2
x 0 1
p 1/3 2/3
E(X)=2/3
x-E(X)
-2/3 1/3
p 1/3 2/3
E(X-E(X)) =-2/9+2/9 = 0
(x-E(X))2
4/9 1/9
p 1/3 2/3
Var(X)=4/9*1/3+1/9*2/3=2/9
x2 0 1
P 1/3 2/3
E(X2)=2/3 Var(X)=E(X2)-E2(X)=2/3 – 4/9 = 2/9
Expected Value and VarianceX = random variable
E(X+Y) = E(X) + E(Y) E(cX) = cE(X) E(c) = c If X and Y are independent then E(XY) = E(X)E(Y)
Var(X)=E(X2)-E2(X) Var(cX)=c2Var(X) If X and Y are independent then Var(X+Y) = Var(X)
+Var(Y) For arbitrary X and Y, Var(X+Y) = Var(X) + Var(Y) +
2Cov(X,Y)
Exercises Using properties of E(X) prove that
Var(X) = E[ (X-E(X))2 ] = E(X2)-(E (X))2
Var(X+Y) = Var(X) + Var(Y) + 2Cov(X,Y) where: Cov(X,Y)=E[ (X-E(X))*(Y-E(Y)) ] Cov(X,Y)=E(XY) - E(X)*E(Y)
Find X and Y such that X and Y are dependent but Cov(X,Y)=0
Problem 14 The Attila Barbell Company makes bars for weight
lifting. The weights of the bars are independent and are normally distributed with a mean of 720 ounces (45 pounds) and a standard deviation of 4 ounces. The bars are shipped 10 in a box to the retailers. The weights of the empty boxes are normally distributed with a mean of 320 ounces and a standard deviation of 8 ounces. The weights of the boxes filled with 10 bars are expected to be normally distributed with a mean of 7,520 ounces. What is the standard deviation?
Sampling Distribution
Sample X1, X2, … , Xn
Xi are random numbersPopulation = heights of adult males
X1 X2 X3
176 181 190
181 190 176
190 176 181
… … …
All Xi are: from the same
distribution are independent
Sample Mean
All Xi are: from the same distribution, i.e,
E(Xi)=μ, Var(Xi) = σ2 are independent random numbers
n
XXXX n
...21
timesn
n
n
nXEXEXE
n
n
XXXEXE
...1
)(...)()(1
...)(
21
11
The Law of Large Numbers
n
XXnXVarXVar
)()(/)()(
n
XXXX n
...21
nn
XVarXVarXVarn
n
XXXVarXVar
timesnn
n
2222
2212
11
...1
)(...)()(1
...)(
Illustrative example
X1 X2 X
1 1 1
1 2 1.5
1 3 2
2 1 1.5
2 2 2
2 3 2.5
3 1 2
3 2 2.5
3 3 3
Population = {1,2,3}, sample size n=2
0
0.5
1
1.5
2
2.5
3
3.5
1 2 3
0
0.5
1
1.5
2
2.5
3
3.5
1 1.5 2 2.5 3
Central Limit Theorem
The sum of a sufficiently large number of identically distributed independent random variables is approximately normally distributed regardless of the population distribution
Normal Approximation to Binomial
X = number of successes in n trials
X=X1+X2+…+Xn
successif
successnoifX i ,1
,0
)1()(
)(
pnpX
npXE
Problem 18
There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% of heads. In the second game you win if you can throw more than 80% heads. For each game would you rather flip the coin 30 times or 300 times?
Sampling distribution
X is approximately normal when n>40
X is approximately normal regardless of the original distribution
Problem 15
The average outstanding bill for delinquent customer accounts for a national department store chain is $187.50 with a standard deviation of $54.50. In a simple random sample of 50 delinquent accounts, what is the probability that the mean outstanding bill is over $200?
Problem 16
The average number of daily emergency room admissions at a hospital is 85 with standard deviation of 37. In a simple random sample of 30 days, what is the probability that the mean number of daily emergency admissions is between 75 and 95?
Problem 17
A summer resort rents rowboats to customers but does not allow more than four people to a boat. Each boat is designed to hold no more than 800 pounds. Suppose the distribution of adult males who rent boats, including their clothes and gear, is normal with a mean of 190 pounds and standard deviation of 10 pounds. If the weights of individual passengers are independent, what is the probability that a group of four adult male passengers will exceed the acceptable weight limit of 800 pounds?
Hypothesis testing
H0 – null hypothesis HA – alternative hypothesis
In a court: H0: the person is not guilty HA: the person is guilty
Doctor’s appointment: H0: patient is sick HA: patient is not sick
Type I/II error Type I error (α) It is the error of rejecting a null
hypothesis when it is actually true.
Type II error (β) It is the error of failing to reject a null
hypothesis when it is in fact false.
Decision rule Assume we get many samples
We set up a decision rule which rejects or accepts the hull hypothesis for each sample
Sometimes we will commit Type I error
Sometimes we will commit Type II error
(Of course many times we will be correct!)
Decision rule comes separately from the set of hypotheses
Type I/II error
Actual condition
Infected Not infected
Test shows "infected"
True Positive False Positive (i.e. infection reported but not present)
Type I error
Test shows "not infected"
False Negative (i.e. infection not detected)
Type II error
True Negative
Problem 19
A patient claims that he consumes only 2000 calories per day, but a dietician suspects that the actual figure is higher. The dietician plans to check his food intake for 30 days and will reject the patient's claim if the 30-day-mean is more than 2100 calories. If the standard deviation (in calories per day) is 350, what is the probability that the dietician will mistakenly reject a patient's true claim?
Problem 20 City planners wish to test the claim that shoppers
park for an average of only 47 minutes in the downtown area. The planners have decided to tabulate parking durations for 225 shoppers and to reject the claim if the sample mean exceeds 50 minutes. If the claim is wrong and the true mean is 51 minutes, what is the probability that the random sample will lead to a mistaken failure to reject the claim? Assume that the standard deviation in parking durations is 27 minutes.
P-value P-value is the probability of obtaining a
result at least as extreme as the one that was actually observed, given that the null hypothesis is true.
Если бы то, что мы предполагаем в нулевой гипотезе было верно, то какова была бы вероятность видеть то, что мы видим в выборке (это, или еще «хуже»)
Hypothesis testing
P-value is a function of sample α is a function of decision rule
Reject H0 if p-value< α Small p-value indicates that you see
something very unusual if H0 were true
Problem 21
A service station advertises that its mechanics can change a muffler in only 15 minutes. A consumers group doubts this claim and runs a hypothesis test using 49 cars needing new mufflers. In this sample the mean changing time is 16.25 minutes with a standard deviation of 3.5 minutes. Is this a strong evidence against the 15 minute claim?
Estimators An estimator is a function of the
observable sample data that is used to estimate an unknown population parameter
is an estimator for μ s is an estimator for σ is an estimator for p
X
p
Unbiased effective estimators
Let be the unknown parameter Let be an estimator
is unbiased if is effective if
n
)ˆ( nE
0)ˆ(lim n
nVar
n
n
Unbiased vs. effective
Unbiased but ineffective Effective but biased
We are looking for unbiased and effective estimators
Mean Squared Error
Bias:
Variance:
Mean Squared Error
)ˆ()ˆ( nn Ebias
2)ˆ(ˆ)ˆ( nnn EEVar
2)ˆ()ˆ()ˆ( nnn biasVarMSE
Problem ? A box contains 70 black and 30 white balls.
Ten balls are chosen at random and two estimators of the following form are considered
where n=10. Which estimator is more effective? (i.e., has a smaller MSE?)
2
2#ˆ
#ˆ
2
1
n
ballsblackofp
n
ballsblackofp
Problem 22
A local restaurant owner claims that only 15% of visiting tourists stay for more than 2 days. A chamber of commerce volunteer is sure that the real percentage is higher. He plans to survey 100 tourists and intends to speak up if at least 18 of the tourists stay longer than 2 days. What is the probability of mistakenly rejecting the restaurant owner's claim if it is true?
Two-sample mean
Two independent samples, X1,…, Xn and Y1,…,Ym have independent sample means
YX
YX
ifmn
YXSE
mnYXSE
11)(
)(22
Two-sample proportion Two independent sample proportions
2121
221121
11)1()ˆˆ(
)1()1()ˆˆ(
ppifmn
ppppSE
m
pp
n
ppppSE
Problem 23 A historian believes that the average height of
soldiers in World War II was greater than that of soldiers in World War I. She examines a random sample of records of 100 men in each war and notes standard deviations of 2.5 and 2.3 inches in World War I and World War II, respectively. If the average height from the sample of World War II soldiers is 1 inch greater than that from the sample of World War I soldiers, what conclusion is justified from a two-sample hypothesis test where H0: μ1 = μ2 vs. HA: μ1< μ2?
Confidence intervals Hypothesis testing: A coffee machine is supposed to
deliver 8 ounces of coffee in a cup, but in my sample of 10 cups I get only 7.5 ounces. Is this ok?
Confidence intervals: My sample of 10 cups of coffee contains on average 7.5 ounces of liquid. What is the likely estimate for the mean amount of coffee per cup?
Hypothesis testing and construction of confidence intervals are mutually inverse problems
Confidence intervals
Parameter = Estimate ± critical * SE, SE = standard error
n
ppSESEZpp
nSESEZX
)1(,ˆ
,
2/
2/
Problem 19 revisited
A patient claims that he consumes only 2000 calories per day, but a dietician suspects that the actual figure is higher. The dietician checked his food intake for 30 days and found that the 30-day-mean is more than 2100 calories. What is the 95% confidence interval for the number of calories in patient’s diet?
Assume standard deviation of 350 calories per day.
Problem 22 revisited
A chamber of commerce volunteer is interested in the percentage of visiting tourists staying for more than 2 days in a certain hotel. He surveyed 100 tourists and found that 18 of them stay longer than 2 days. What is the 99% confidence interval for the percentage of visiting tourists who stay for more than 2 days?
Problem 24
In a random sample of 300 high school students, 225 said they managed time effectively, while in a similar sample of 270 college students, only 108 felt they were effective time managers. What is a 99% confidence interval estimate for the difference between the proportions of high school and colleges students who think they manage time effectively?
Problem 25
A medical researcher believes that taking 1000 milligrams of vitamin C per day will result in fewer colds than a daily intake of 500 milligrams will. In a group of 50 volunteers taking 1000 milligrams per day, the numbers of colds per individual during a winter season averaged 1.8 with a variance of 1.5. Similar data from a group of 60 volunteers taking 500 milligrams per day showed an average of 2.4 with a variance of 1.6. What was the P-value of this test?
How do we get σ? Population standard deviation is usually
unknown
If sample size is large (n>40) then we can assume that the sample standard deviation (s) approximates the population standard deviation (σ) well enough
If sample size is small then this assumption is no longer valid, i.e., sampling error in the estimation of σ cannot be ignored
Student t-distribution Student t-distribution has one parameter
called degrees of freedom
When the number of degrees of freedom is large, the t-distribution is close to z-distribution
Problem 26
An article ("Undergraduate Marijuana use and Anger" by Sue Stoner) in a 1988 issue of the Journal of Psychology (Vol. 122, p. 33) reported that in a sample of 17 marijuana users the mean and standard deviation on an anger expression scale were 42.72 and 6.05, respectively. Test whether this result is significantly greater than the established mean of 41.6 for nonusers. What assumptions are necessary for the above test to be valid?
T-test assumptions Random sampling (like in z-test)
Normal population (unlike z-test, where sample mean is automatically normal regardless of the population when sample size is large)
Degrees of freedom = number of independent observations (actually, residuals)
Problem 27
A hospital exercise laboratory technician notes the resting pulse rates of five joggers to be 60, 58, 59, 61, and 67, respectively, while the resting pulse rates of seven non-exercisers are 83, 60, 75, 71, 91, 82, and 84, respectively. Establish a 99% confidence interval estimate for the difference in pulse rates between joggers and non-exercisers.
(Means and standard deviations are: 61, 78, 3.54, and 10.23, respectively)
Equal variances assumption Assume that both populations have the same
standard deviation (i.e., amount of exercise affects mean of the population, not its standard deviation)
YX
YX
ifmn
YXSE
mnYXSE
11)(
)(22
d.f. = min{n,m}-1
d.f. = n + m - 2
2
)1()1(ˆ
22
mn
smsns yx
p
Problem 27 revisited A hospital exercise laboratory technician notes the
resting pulse rates of five joggers to be 60, 58, 59, 61, and 67, respectively, while the resting pulse rates of seven non-exercisers are 83, 60, 75, 71, 91, 82, and 84, respectively. Establish a 99% confidence interval estimate for the difference in pulse rates between joggers and non-exercisers. Assume equal variances.
(Means and standard deviations are: 61, 78, 3.54, and 10.23, respectively)
Problem 28
A researcher believes a new diet should improve weight gain in laboratory mice. If ten control mice on the old diet gain an average of 4 ounces with a standard deviation of 0.3 ounces, while the average gain for the ten mice on the new diet is 4.8 ounces with a standard deviation of 0.2 ounces, what is the p-value?
Dependent samples Trace metals in drinking water wells affect the flavor of
the water and unusually high concentrations can pose a health hazard. In the paper, “Trace Metals of South Indian River Region” (Environmental Studies, 1982, 62-6), trace metal concentrations (mg/L) on zinc were found from water drawn from the bottom and the top of each of 6 wells.
Location Bottom Top
1 0.43 0.415
2 0.266 0.238
3 0.567 0.39
4 0.531 0.41
5 0.707 0.605
6 0.716 0.609
Dependent samples
Location Bottom Top Bottom-Top
1 0.43 0.415 0.015
2 0.266 0.238 0.028
3 0.567 0.39 0.177
4 0.531 0.41 0.121
5 0.707 0.605 0.102
6 0.716 0.609 0.107
Mean 0.0916667
SD 0.0606883
One sample t-test
FAQs Do I have to divide by square root of n?
Yes, if you are looking for P(X>100) No, if you are looking for P(X>100)
Do I have to divide by square root of n in one-proportion or two-proportion tests? No. If you use Standard Error, it already contains the
square root of n
When I compute standard deviation from the sample, do I have to divide it by square root of n? Yes, if your calculations involve sample mean.
Common misconception Sample standard deviation is an
estimator for the population standard deviation
Standard deviation of the sampling distribution is smaller than the population standard deviation
Sample standard deviation is NOT an estimator for the standard deviation of the sampling distribution
Problem 29
A supplier of 100 ohm/cm silicon wafers claims that his fabrication process can produce wafers with sufficient consistency so that the standard deviation of resistance for the lot does not exceed 10 ohm/cm. A sample of 10 wafers taken from the lot has a standard deviation of 13.97 ohm/cm. Is the suppliers claim reasonable?
Problem 30
A container of oil is supposed to contain 1000 ml of oil. We want to be sure that the standard deviation of the oil container is less than 20 ml. We randomly select 10 cans of oil with a mean of 997 ml and a standard deviation of 32 ml. Using these sample construct a 95% confidence interval for the true value of sigma. Does the confidence interval suggest that the variation in oil containers is at an acceptable level?
Estimation of sample size What is a minimum sample size needed
to estimate the population mean within 2 units?
What is a minimum sample size needed to estimate the population proportion within 2 percent units?
Problem 31
An electrical firm which manufactures a certain type of bulb wants to estimate its mean life. Assuming that the life of the light bulb is normally distributed and that the standard deviation is known to be 40 hours, how many bulbs should be tested so that we can be 90 percent confident that the estimate of the mean will not differ from the true mean life by more than 10 hours?
Problem 32
A quality control engineer wants to estimate the fraction of defective bulbs in a large lot of light bulbs. From past experience, he feels that the actual fraction of defective bulbs should be somewhere around 0.2 . How large a sample should be taken if he wants to estimate the true fraction within .02 using a 95% confidence interval?
Problem 33
Many television viewers express doubts about the validity of certain commercials. Let p represent the true proportion of consumers who believe what is shown in Timex television commercials. If Timex has no prior information regarding the true value of p, how many consumers should be included in their sample so that they will be 85% confident that their estimate is within 0.03 of the true value of p?
Non-parametric hypotheses
H0: features are independent HA: features are dependent
Young male
Young female
Older male
Older Female
Satisfied 25 30 135 112
Not satisfied 8 16 22 37
A restaurant owner surveys a random sample of 385 customers to determine whether customer satisfaction is related to gender and age.
Assumption of independence
Young male
Young female
Older male
Older Female TOTAL
Satisfied 25 30 135 112 302
Not satisfied 8 16 22 37 83
TOTAL 33 46 157 149 385
If gender/age and satisfaction were independent thenP(satisfied and young male) = P(satisfied)*P(young male)
P(satisfied) = 302/385P(young male) = 33/385P(satisfied and young male) = 302*33/3852
Expected number of satisfied young males = 302*33/385
Observed and Expected
Young
maleYoung
femaleOlder
maleOlder
Female TOTAL
Satisfied 25.9 36.1 123.1 116.9 302
Not satisfied 7.1 9.9 33.9 32.1 83
TOTAL 33 46 157 149 385
Young male
Young female
Older male
Older Female TOTAL
Satisfied 25 30 135 112 302
Not satisfied 8 16 22 37 83
TOTAL 33 46 157 149 385
Observed
Expected
Chi-square test for independence
1.11...1.36
)1.3630(
9.25
)9.2525(
)(
222
22
E
EO
d.f. = (n-1)x(m-1)
Problem 34 A sociologist conducts a test whether there is a
relationship between cheating on exams and socioeconomic status. A random sample of 750 high school students yields the following results:
What is the conclusion about cheating and socioeconomic status at the 5% significance level?
CheatDon't cheat
High status 118 282
Low status 82 268
Chi-square goodness of fit A grocery store manager wishes to determine
whether a certain product will sell equally well in any of the five locations in the store. Five displays are set up, one for each location, and the resulting numbers of the product sold are noted
Is there enough evidence to claim a difference?
1 2 3 4 5
# sold 43 29 52 34 48
Chi-square goodness of fit
1 2 3 4 5
# sold 43 29 52 34 48
Total = 43+29+…+48=206We expect 206/5=41.2 units sold in each location
H0: The distribution is uniformHA: The distribution is not uniform
9.82.41
)2.4148(...
2.41
)2.4143()( 2222
E
EO
d.f. = n-1
Problem 35
A geneticist claims that four species of fruit flies should appear in the ratio of 1:3:3:9. Suppose that a sample of 4000 fruit flies contained 226, 764, 733, and 2277 flies of each species, respectively. At the 10% significance level, is there sufficient evidence to reject the geneticist’s hypothesis?
Chi-square test: warning Chi-square test is applicable only if the
expected value in each cell is greater than 5 (Compare to Binomial Distribution)
If this doesn’t hold, you might find Fisher exact test more useful
Problem 36 A sample of teenagers might be divided into male and
female on the one hand, and those that are and are not currently dieting on the other. We hypothesize, perhaps, that the proportion of dieting individuals is higher among the women than among the men, and we want to test whether any difference of proportions that we observe is significant.
men women total
dieting 1 9 10
not dieting 11 3 14
totals 12 12 24
Expected < 5
Fisher exact test
men women total
dieting 1 9 10
not dieting 11 3 14
totals 12 12 24
men women total
dieting a b a + b
not dieting c d c + d
totals a + c b + d n
Hypergeometric Distribution
The least squares line A simple data set consists of data pairs
(xi, yi), i = 1, ..., n, where xi is an independent variable and yi is a dependent variable
The model function has the formy = a + bx
We wish to find a and b for which the model "best" fits the data.
Residuals The least squares method defines "best"
as when S = Σ ri2 is at minimum.
A residual ri is defined as the difference between the values of the dependent variable and the predicted values from the estimated model
ri =yi - (a + b xi)
Residual plot
The sum of the residuals is always zero
A pattern in the residual plot indicates that a non-linear model should be used
Influential scores and outliers
In regression, an outlier is a data point with large residual
An influential score is the data point which significantly influences the regression line
If an influential score is removed from the sample, the regression line will change significantly
Regression slope and intercept
xbya
xxxxn
s
yyxxn
s
s
s
xx
yyxxb
iixx
iixy
xx
xy
i
ii
))((1
1
))((1
1
where
,)(
))((2
Coefficient of determination
SST = total sum of squares SSX = sum of squares explained by X SSE = sum of squares of residuals SST = SSX+SSE
The square of the sample correlation coefficient, which is also known as the coefficient of determination, is the fraction of the variance in y that is accounted for by a linear fit of x
SST
SSXrR 22
SE of the regression slope
The regression line is a result of random sampling Different samples produce different lines There is a family of lines for the given population; you get just one
N
ii
eb
XX1
2
2
)(
SE of the regression slope
N
ii
eb
XX1
2
2
)(
MSEn
SSEe
2
where σe is the standard deviation of the regression error
N
ii
b
XX
MSE
1
2)(
Problem 38
1. What is the equation of the fitted line?2. Find an approximate confidence interval for the regression slope?3. Test the hypothesis that the slope is non-zero
Confidence vs. prediction intervals Suppose I fuel my car 7 days a week, from Sunday to
Sunday, each day at a randomly chosen gas station. I get a sample of gasoline prices for 7 days:
Confidence interval is for the average gasoline price on Monday
Prediction interval is for a gasoline price at a randomly chosen gas station on Monday
Confidence interval
Prediction interval
Confidence vs. prediction intervals
2
20
2000 )(
)(1ˆ)(ˆ
XX
XX
ntbXaXY
ien
1)(
)(1ˆ)(ˆ
2
20
2000
XX
XX
ntbXaXY
ien
ANOVA: Analysis of Variance A collection of models, in which the variance
of the observed set is partitioned into components due to explanatory variables
Assumptions: Independence of observations The distributions in each of the groups are
normal Variance homogeneity, called homoscedasticity:
the variance of data in groups should be the same.
One-way ANOVA A manager wishes to determine whether the mean times
required to complete a certain task differ for the three levels of employee training. He randomly selected 10 employees with each of the three levels of training.
Do the data provide sufficient evidence to indicate that the mean times required to complete a certain task differ for at least two of the three levels of training?
Level of Training n s2
Advanced 10
24.2 21.54
Intermediate 10
27.1 18.64
Beginner 10
30.2 17.76
Steiner’s Theorem
n
iin axaxxI
1
21 )(),,...,(
axi
211 )(),,...,(),,...,( axnxxxIaxxI nn
Момент инерции системы точек относительно точки а
Problem 40 Three different milling machines were being considered for purchase by a
manufacturer. Potentially, the company would be purchasing hundreds of these machines, so it wanted to make sure it made the best decision. Initially, five of each machine were borrowed, and each was randomly assigned to one of 15 technicians (all technicians were similar in skill). Each machine was put through a series of tasks and rated using a standardized test. The higher the score on the test, the better the performance of the machine. The data are:
Machine 1 Machine 2 Machine 3
24.5 28.4 26.1
23.5 34.2 28.3
26.4 29.5 24.3
27.1 32.2 26.2
29.9 30.1 27.8
Partition of sum of squares SST = SSA + SSE SST = total sum of squares SSA = sum of squares for factor A SSE = sum of squares of errors
SSASSEXXmXX
XXmXXXXSST
ii
i jiij
i jiiij
n
i
m
iij
22
22
1 1
2
)()(
)()()(
Partition of sum of squares
Machine 1
Machine 2
Machine 3
24.50 28.40 26.10
23.50 34.20 28.30
26.40 29.50 24.30
27.10 32.20 26.20
29.90 30.10 27.80
MEAN 26.28 30.88 26.54 27.9
Machine 1
Machine 2
Machine 3
26.28 30.88 26.54
26.28 30.88 26.54
26.28 30.88 26.54
26.28 30.88 26.54
26.28 30.88 26.54
MEAN 26.28 30.88 26.54 27.9
SSTXXi j
ij 2)(
ii SSAXXm 2)(
SSASSTSSE
The ANOVA table SSA = Sum of squares Factor SSE = Sum of squares Error
MSA = Mean sum of squares Factor MSE = Mean sum of squares Error
SS df MS F
Factor SSA k-1 SSA/(k-1) MSA/MSE
Error SSE N-k SSE/(N-k) .
Total SSA+SSE N-1 .
Problem 40 solution
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 66.772 2 33.386 7.137828 0.009073 3.885294
Within Groups 56.128 12 4.677333
Total 122.9 14
In EXCEL: Tools -> Data Analysis -> Single Factor ANOVA
Two-way ANOVA Group A is given vodka, Group B is given gin, and Group
C is given a placebo. Groups are tested with a memory task. One-way ANOVA
In an experiment testing the effects of expectations, subjects are randomly assigned to four groups:1. expect vodka—receive vodka
2. expect vodka—receive placebo
3. expect placebo—receive vodka
4. expect placebo—receive placebo
Each group is then tested on a memory task. Two-way ANOVA
Partition of sum of squares
SST = SSA + SSB + SSE SST = total sum of squares SSA = sum of squares for factor A SSB = sum of squares for factor B SSE = sum of squares of errors
Partition of sum of squares
SSBSSASSE
XXmXXnXXXX
XXmXX
XXmXXXXSST
ii
jj
i jjiij
ii
i jiij
i jiiij
n
i
m
iij
222
22
22
1 1
2
)()()(
)()(
)()()(
Problem 41 Three different milling machines were being considered for
purchase by a manufacturer…. Machines are operated by 5 different crew technicians:
Machine 1 Machine 2 Machine 3
Crew 1 24.5 28.4 26.1
Crew 2 23.5 34.2 28.3
Crew 3 26.4 29.5 24.3
Crew 4 27.1 32.2 26.2
Crew 5 29.9 30.1 27.8
What is the error term?
MEAN
24.5 28.4 26.1 26.33333
23.5 34.2 28.3 28.66667
26.4 29.5 24.3 26.73333
27.1 32.2 26.2 28.5
29.9 30.1 27.8 29.26667
MEAN 26.28 30.88 26.54 27.9
MEAN
24.713
329.313
3 … 26.33
27.046
7 … … 28.67
… … … 26.73
… 28.5
… … … 29.27
MEAN 26.28 30.88 26.54 27.9
7133.245.24 XXXX jiij
Two-way ANOVA table
Source of Variation SS df MS F P-value F crit
Rows19.8933333
3 44.97333333
31.09802767
10.41993
63.83785
3
Columns 66.772 2 33.3867.37106270
20.01531
2 4.45897
Error36.2346666
7 84.52933333
3
Total 122.9 14At 5% level:
• The variation across rows (crew technicians) is NOT significant
• The variation across columns (machines) is significant
Problem 42 Some varieties of nematodes feed on the roots of
lawn grasses and crops such as strawberries and tomatoes. Four brands of nematocides are to be compared. Twelve plots of land of comparable fertility that were suffering from nematodes were planted with a crop. The yields of each plot were recorded and part of the ANOVA table appears below:
Find the value of F
Source df SS MS F-value
Nematocides * 3.456 * *
Error 8 1.2 *
Total 11 4.656
Extra Problems
All bags entering a research facility are screened. Ninety-seven percent of the bags that contain forbidden material trigger an alarm. Fifteen percent of the bags that do not contain forbidden material also trigger the alarm. If 1 out of every 1,000 bags entering the building contains forbidden material, what is the probability that a bag that triggers the alarm will actually contain forbidden material?
Extra problems
Pepper plants watered lightly every day for a month show an average growth of 27 cm with the standard deviation of 8.3 cm, while pepper plants watered heavily once a week for a month show an average growth of 29 cm with the standard deviation of 7.9 cm. In a sample of 60 plants, half of which were given each of the water treatments, what is the probability that the difference in average growth between the two halves is between -3 and + 3 cm?