Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski...

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Principal Bundles Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1/9

Transcript of Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski...

Page 1: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Principal BundlesDay 5: Vector Bundles

Bradley Zykoski

June 19, 2020

Bradley Zykoski Vector Bundles June 19, 2020 1 / 9

Page 2: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Course summary

Today is the last day! Let’s summarize what we’ve learned so far.

1 A principal G -bundle is a fiber bundle π : P → B with a rightG -action P y G so that the fibers of P are G -torsors.

2 A principal connection is a G -equivariant splitting

0 VP TP π∗TB 0,dπ

ω

and since VP ∼= P × g, we may write ω ∈ Ω1(P, g)G .

3 We have a covariant exterior derivative dω = d h⊗k acting onΩk(P, g), where h is the projection TP → HP = kerω. We definedωω = Ω ∈ Ω2

hor(P, g)G , which vanishes if and only if HP isintegrable.

4 The curvature Ω descends to a form Fω ∈ Ω2(P, gP) with Ω = π∗Fω,where gP = (P × g)/G for the adjoint action G y g. In the caseG = U(1) we have c1(P) = [Fω] ∈ H2(B;R).

Bradley Zykoski Vector Bundles June 19, 2020 2 / 9

Page 3: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Course summary

Today is the last day! Let’s summarize what we’ve learned so far.

1 A principal G -bundle is a fiber bundle π : P → B with a rightG -action P y G so that the fibers of P are G -torsors.

2 A principal connection is a G -equivariant splitting

0 VP TP π∗TB 0,dπ

ω

and since VP ∼= P × g, we may write ω ∈ Ω1(P, g)G .

3 We have a covariant exterior derivative dω = d h⊗k acting onΩk(P, g), where h is the projection TP → HP = kerω. We definedωω = Ω ∈ Ω2

hor(P, g)G , which vanishes if and only if HP isintegrable.

4 The curvature Ω descends to a form Fω ∈ Ω2(P, gP) with Ω = π∗Fω,where gP = (P × g)/G for the adjoint action G y g. In the caseG = U(1) we have c1(P) = [Fω] ∈ H2(B;R).

Bradley Zykoski Vector Bundles June 19, 2020 2 / 9

Page 4: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Course summary

Today is the last day! Let’s summarize what we’ve learned so far.

1 A principal G -bundle is a fiber bundle π : P → B with a rightG -action P y G so that the fibers of P are G -torsors.

2 A principal connection is a G -equivariant splitting

0 VP TP π∗TB 0,dπ

ω

and since VP ∼= P × g, we may write ω ∈ Ω1(P, g)G .

3 We have a covariant exterior derivative dω = d h⊗k acting onΩk(P, g), where h is the projection TP → HP = kerω. We definedωω = Ω ∈ Ω2

hor(P, g)G , which vanishes if and only if HP isintegrable.

4 The curvature Ω descends to a form Fω ∈ Ω2(P, gP) with Ω = π∗Fω,where gP = (P × g)/G for the adjoint action G y g. In the caseG = U(1) we have c1(P) = [Fω] ∈ H2(B;R).

Bradley Zykoski Vector Bundles June 19, 2020 2 / 9

Page 5: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Course summary

Today is the last day! Let’s summarize what we’ve learned so far.

1 A principal G -bundle is a fiber bundle π : P → B with a rightG -action P y G so that the fibers of P are G -torsors.

2 A principal connection is a G -equivariant splitting

0 VP TP π∗TB 0,dπ

ω

and since VP ∼= P × g, we may write ω ∈ Ω1(P, g)G .

3 We have a covariant exterior derivative dω = d h⊗k acting onΩk(P, g), where h is the projection TP → HP = kerω. We definedωω = Ω ∈ Ω2

hor(P, g)G , which vanishes if and only if HP isintegrable.

4 The curvature Ω descends to a form Fω ∈ Ω2(P, gP) with Ω = π∗Fω,where gP = (P × g)/G for the adjoint action G y g. In the caseG = U(1) we have c1(P) = [Fω] ∈ H2(B;R).

Bradley Zykoski Vector Bundles June 19, 2020 2 / 9

Page 6: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Course summary

Today is the last day! Let’s summarize what we’ve learned so far.

1 A principal G -bundle is a fiber bundle π : P → B with a rightG -action P y G so that the fibers of P are G -torsors.

2 A principal connection is a G -equivariant splitting

0 VP TP π∗TB 0,dπ

ω

and since VP ∼= P × g, we may write ω ∈ Ω1(P, g)G .

3 We have a covariant exterior derivative dω = d h⊗k acting onΩk(P, g), where h is the projection TP → HP = kerω. We definedωω = Ω ∈ Ω2

hor(P, g)G , which vanishes if and only if HP isintegrable.

4 The curvature Ω descends to a form Fω ∈ Ω2(P, gP) with Ω = π∗Fω,where gP = (P × g)/G for the adjoint action G y g. In the caseG = U(1) we have c1(P) = [Fω] ∈ H2(B;R).

Bradley Zykoski Vector Bundles June 19, 2020 2 / 9

Page 7: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Induced connections

Let π : P → B be a principal G -bundle. Recall that our notion ofconnection was developed so that we could construct a notion of paralleltransport: for any path γ : [0, 1]→ B and p ∈ P with π(p) = γ(0), weconstruct a unique lift γp : [0, 1]→ P satisfying γp(0) = p.

Equipped with such notion of parallel transport, we can induce a notion ofparallel transport on any associated bundle to P. Recall that if G y F , wehave an action (p, f ).g = (p.g , g−1.f ) of G on P × F , and the quotientE = (P × F )/G is a bundle π : E → B with fiber F .

The let γ : [0, 1]→ B be a path, let e = (p, f ) modG ∈ E such thatπ(e) = γ(0). We define

γe(t) = (γp(t), f ) modG .

Since principal connections are G -equivariant, we have γp.g (t) = γp(t).g ,and hence if we write e = (p.g , g−1.f ) modG instead, we get

(γp.g (t), g−1.f ) modG = (γp(t).g , g−1.f ) modG = (γp(t), f ) modG .

Bradley Zykoski Vector Bundles June 19, 2020 3 / 9

Page 8: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Induced connections

Let π : P → B be a principal G -bundle. Recall that our notion ofconnection was developed so that we could construct a notion of paralleltransport: for any path γ : [0, 1]→ B and p ∈ P with π(p) = γ(0), weconstruct a unique lift γp : [0, 1]→ P satisfying γp(0) = p.

Equipped with such notion of parallel transport, we can induce a notion ofparallel transport on any associated bundle to P. Recall that if G y F , wehave an action (p, f ).g = (p.g , g−1.f ) of G on P × F , and the quotientE = (P × F )/G is a bundle π : E → B with fiber F .

The let γ : [0, 1]→ B be a path, let e = (p, f ) modG ∈ E such thatπ(e) = γ(0). We define

γe(t) = (γp(t), f ) modG .

Since principal connections are G -equivariant, we have γp.g (t) = γp(t).g ,and hence if we write e = (p.g , g−1.f ) modG instead, we get

(γp.g (t), g−1.f ) modG = (γp(t).g , g−1.f ) modG = (γp(t), f ) modG .

Bradley Zykoski Vector Bundles June 19, 2020 3 / 9

Page 9: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Induced connections

Let π : P → B be a principal G -bundle. Recall that our notion ofconnection was developed so that we could construct a notion of paralleltransport: for any path γ : [0, 1]→ B and p ∈ P with π(p) = γ(0), weconstruct a unique lift γp : [0, 1]→ P satisfying γp(0) = p.

Equipped with such notion of parallel transport, we can induce a notion ofparallel transport on any associated bundle to P. Recall that if G y F , wehave an action (p, f ).g = (p.g , g−1.f ) of G on P × F , and the quotientE = (P × F )/G is a bundle π : E → B with fiber F .

The let γ : [0, 1]→ B be a path, let e = (p, f ) modG ∈ E such thatπ(e) = γ(0). We define

γe(t) = (γp(t), f ) modG .

Since principal connections are G -equivariant, we have γp.g (t) = γp(t).g ,and hence if we write e = (p.g , g−1.f ) modG instead, we get

(γp.g (t), g−1.f ) modG = (γp(t).g , g−1.f ) modG = (γp(t), f ) modG .

Bradley Zykoski Vector Bundles June 19, 2020 3 / 9

Page 10: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Induced connections

Let π : P → B be a principal G -bundle. Recall that our notion ofconnection was developed so that we could construct a notion of paralleltransport: for any path γ : [0, 1]→ B and p ∈ P with π(p) = γ(0), weconstruct a unique lift γp : [0, 1]→ P satisfying γp(0) = p.

Equipped with such notion of parallel transport, we can induce a notion ofparallel transport on any associated bundle to P. Recall that if G y F , wehave an action (p, f ).g = (p.g , g−1.f ) of G on P × F , and the quotientE = (P × F )/G is a bundle π : E → B with fiber F .

The let γ : [0, 1]→ B be a path, let e = (p, f ) modG ∈ E such thatπ(e) = γ(0). We define

γe(t) = (γp(t), f ) modG .

Since principal connections are G -equivariant, we have γp.g (t) = γp(t).g ,and hence if we write e = (p.g , g−1.f ) modG instead, we get

(γp.g (t), g−1.f ) modG = (γp(t).g , g−1.f ) modG = (γp(t), f ) modG .

Bradley Zykoski Vector Bundles June 19, 2020 3 / 9

Page 11: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Induced connections

Since the horizontal lifting of vectors from TB up to TE is simply theinfinitesimal version of parallel transport, we may also express our notionof induced connection as follows.

Let π : P → B be a principal G -bundle with parallel transport (γ, p) 7→ γpgiven by a connection ω. Then any associated bundleπ : E = (P × F )/G → B has an induced connection given by the splitting

0 VE TE π∗TB 0,dπ

where hω is defined as follows. Every (e,X ) ∈ π∗TB is of the form ∂∂t γ for

some path γ in B with γ(0) = π(e). We define hω(∂∂t γ)

= ∂∂t γe ∈ TE .

Bradley Zykoski Vector Bundles June 19, 2020 4 / 9

Page 12: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Induced connections

Since the horizontal lifting of vectors from TB up to TE is simply theinfinitesimal version of parallel transport, we may also express our notionof induced connection as follows.

Let π : P → B be a principal G -bundle with parallel transport (γ, p) 7→ γpgiven by a connection ω. Then any associated bundleπ : E = (P × F )/G → B has an induced connection given by the splitting

0 VE TE π∗TB 0,dπ

where hω is defined as follows. Every (e,X ) ∈ π∗TB is of the form ∂∂t γ for

some path γ in B with γ(0) = π(e). We define hω(∂∂t γ)

= ∂∂t γe ∈ TE .

Bradley Zykoski Vector Bundles June 19, 2020 4 / 9

Page 13: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Induced connections

Both a right-splitting and a left-splitting of a short exact sequence ofvector bundles are equivalent to a direct sum decompositionTE = VE ⊕ HE of the middle term. Given such a right-splittinghω : π∗TB → TE , consider the associated left-splitting

0 VE TE π∗TB 0.dπ

When the fiber F of E = (P × F )/G is a vector space, with F x G bylinear maps, then it is an exercise to see that VE ∼= π∗E .

Given a section (s : B → E ) ∈ Ω0(B,E ), we may define a 1-form(∇s : TB → E ) ∈ Ω1(B,E ) via

∇s : TBds−→ s∗TE

s∗vω−−−→ s∗VE = s∗π∗E = E .

In words, for X = ∂∂t γ, the vector ∇s(X ) is the infinitesimal vertical

displacement along s γ.

Bradley Zykoski Vector Bundles June 19, 2020 5 / 9

Page 14: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Induced connections

Both a right-splitting and a left-splitting of a short exact sequence ofvector bundles are equivalent to a direct sum decompositionTE = VE ⊕ HE of the middle term. Given such a right-splittinghω : π∗TB → TE , consider the associated left-splitting

0 VE TE π∗TB 0.dπ

When the fiber F of E = (P × F )/G is a vector space, with F x G bylinear maps, then it is an exercise to see that VE ∼= π∗E .

Given a section (s : B → E ) ∈ Ω0(B,E ), we may define a 1-form(∇s : TB → E ) ∈ Ω1(B,E ) via

∇s : TBds−→ s∗TE

s∗vω−−−→ s∗VE = s∗π∗E = E .

In words, for X = ∂∂t γ, the vector ∇s(X ) is the infinitesimal vertical

displacement along s γ.

Bradley Zykoski Vector Bundles June 19, 2020 5 / 9

Page 15: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Induced connections

Both a right-splitting and a left-splitting of a short exact sequence ofvector bundles are equivalent to a direct sum decompositionTE = VE ⊕ HE of the middle term. Given such a right-splittinghω : π∗TB → TE , consider the associated left-splitting

0 VE TE π∗TB 0.dπ

When the fiber F of E = (P × F )/G is a vector space, with F x G bylinear maps, then it is an exercise to see that VE ∼= π∗E .

Given a section (s : B → E ) ∈ Ω0(B,E ), we may define a 1-form(∇s : TB → E ) ∈ Ω1(B,E ) via

∇s : TBds−→ s∗TE

s∗vω−−−→ s∗VE = s∗π∗E = E .

In words, for X = ∂∂t γ, the vector ∇s(X ) is the infinitesimal vertical

displacement along s γ.

Bradley Zykoski Vector Bundles June 19, 2020 5 / 9

Page 16: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Induced connections

Both a right-splitting and a left-splitting of a short exact sequence ofvector bundles are equivalent to a direct sum decompositionTE = VE ⊕ HE of the middle term. Given such a right-splittinghω : π∗TB → TE , consider the associated left-splitting

0 VE TE π∗TB 0.dπ

When the fiber F of E = (P × F )/G is a vector space, with F x G bylinear maps, then it is an exercise to see that VE ∼= π∗E .

Given a section (s : B → E ) ∈ Ω0(B,E ), we may define a 1-form(∇s : TB → E ) ∈ Ω1(B,E ) via

∇s : TBds−→ s∗TE

s∗vω−−−→ s∗VE = s∗π∗E = E .

In words, for X = ∂∂t γ, the vector ∇s(X ) is the infinitesimal vertical

displacement along s γ.Bradley Zykoski Vector Bundles June 19, 2020 5 / 9

Page 17: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Covariant derivatives

The map ∇ = vω d : Ω0(B,E )→ Ω1(B,E ) is a covariant derivative.

Definition

A covariant derivative on a vector bundle π : E → B is an R-linear map∇ : Ω0(B,E )→ Ω1(B,E ) satisfying the Leibniz rule:

∇(fs) = df ⊗ s + f∇s, ∀f ∈ C∞(B), s ∈ Ω0(M,E ).

We can come full circle and use a connection to define a notion of paralleltransport. Given a path γ : [0, 1]→ B, a section s : B → E satisfying∇s(γ′(t)) = 0 for each t ∈ [0, 1] gives a lift s γ of γ.

From now on, we will write ∇X s instead of ∇s(X ).

Bradley Zykoski Vector Bundles June 19, 2020 6 / 9

Page 18: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Covariant derivatives

The map ∇ = vω d : Ω0(B,E )→ Ω1(B,E ) is a covariant derivative.

Definition

A covariant derivative on a vector bundle π : E → B is an R-linear map∇ : Ω0(B,E )→ Ω1(B,E ) satisfying the Leibniz rule:

∇(fs) = df ⊗ s + f∇s, ∀f ∈ C∞(B), s ∈ Ω0(M,E ).

We can come full circle and use a connection to define a notion of paralleltransport. Given a path γ : [0, 1]→ B, a section s : B → E satisfying∇s(γ′(t)) = 0 for each t ∈ [0, 1] gives a lift s γ of γ.

From now on, we will write ∇X s instead of ∇s(X ).

Bradley Zykoski Vector Bundles June 19, 2020 6 / 9

Page 19: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Covariant derivatives

The map ∇ = vω d : Ω0(B,E )→ Ω1(B,E ) is a covariant derivative.

Definition

A covariant derivative on a vector bundle π : E → B is an R-linear map∇ : Ω0(B,E )→ Ω1(B,E ) satisfying the Leibniz rule:

∇(fs) = df ⊗ s + f∇s, ∀f ∈ C∞(B), s ∈ Ω0(M,E ).

We can come full circle and use a connection to define a notion of paralleltransport. Given a path γ : [0, 1]→ B, a section s : B → E satisfying∇s(γ′(t)) = 0 for each t ∈ [0, 1] gives a lift s γ of γ.

From now on, we will write ∇X s instead of ∇s(X ).

Bradley Zykoski Vector Bundles June 19, 2020 6 / 9

Page 20: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Curvature in the language of covariant derivatives

Given a covariant derivative ∇ : Ω0(B,E )→ Ω1(B,E ), we define thecurvature tensor R∇ ∈ Ω2(B,End(E )) by

R∇(X ,Y )(s) = ∇X∇Y s −∇Y∇X s −∇[X ,Y ]s

for vectors X ,Y ∈ TB and sections s : B → E .

We have not strayed from our original definition of curvature. IfE = (P × V )/G where G y V by a representation ρ : G → GL(V ), thenone may check that we have an isomorphismΩ∗(B,End(E )) ∼= Ω∗hor(B,End(V ))G . Then for a connection ω on P and∇ = vω d , we have

ρ Ω = R∇ ∈ Ω2hor(B,End(V ))G ,

where ρ : g→ End(V ) is the induced map on Lie algebras.

Bradley Zykoski Vector Bundles June 19, 2020 7 / 9

Page 21: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Curvature in the language of covariant derivatives

Given a covariant derivative ∇ : Ω0(B,E )→ Ω1(B,E ), we define thecurvature tensor R∇ ∈ Ω2(B,End(E )) by

R∇(X ,Y )(s) = ∇X∇Y s −∇Y∇X s −∇[X ,Y ]s

for vectors X ,Y ∈ TB and sections s : B → E .

We have not strayed from our original definition of curvature. IfE = (P × V )/G where G y V by a representation ρ : G → GL(V ), thenone may check that we have an isomorphismΩ∗(B,End(E )) ∼= Ω∗hor(B,End(V ))G . Then for a connection ω on P and∇ = vω d , we have

ρ Ω = R∇ ∈ Ω2hor(B,End(V ))G ,

where ρ : g→ End(V ) is the induced map on Lie algebras.

Bradley Zykoski Vector Bundles June 19, 2020 7 / 9

Page 22: Principal Bundles - Day 5: Vector Bundleszykoskib/day5.pdf · Day 5: Vector Bundles Bradley Zykoski June 19, 2020 Bradley Zykoski Vector Bundles June 19, 2020 1 / 9. Course summary

Moduli of curves and the Hodge bundle

(switch to virtual drawing board)

Bradley Zykoski Vector Bundles June 19, 2020 8 / 9

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References

G. Forni, C. Matheus, A. Zorich, Lyapunov spectrum of invariantsubbundles of the Hodge bundle

P. Griffiths and J. Harris, Principles of algebraic geometry

S. Kobayashi and K. Nomizu, Foundations of Differential Geometry,Vol. 1

F. Labourie, Lectures on Representations of surface groups

P. Michor, Topics in differential geometry

T. Walpuski, Notes on the geometry of manifolds, https://math.mit.edu/~walpuski/18.965/GeometryOfManifolds.pdf

My notes on tangent spaces to character varieties on my website

Bradley Zykoski Vector Bundles June 19, 2020 9 / 9