Physics I 95.141 LECTURE 10 3/3/10

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rtment of Physics and Applied Physics 95.141, F2010, Lecture 10 Physics I 95.141 LECTURE 10 3/3/10

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Physics I 95.141 LECTURE 10 3/3/10. Exam Prep Problem (Conical Pendulum). A small mass (m) suspended on a cord ( l =1m ) revolves in a circle of radius r. ( θ =30º) A) (10pts) Draw a free body diagram for the mass, labeling your coordinate system - PowerPoint PPT Presentation

Transcript of Physics I 95.141 LECTURE 10 3/3/10

Page 1: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Physics I95.141

LECTURE 103/3/10

Page 2: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Exam Prep Problem (Conical Pendulum)• A small mass (m) suspended on a cord (l=1m) revolves in a circle of

radius r. (θ=30º) – A) (10pts) Draw a free body diagram for the mass, labeling your

coordinate system– B) (5pts) What is the acceleration of the ball, and in what direction?– C) (5pts) What is the tangential velocity of the ball?– D) (5pts) (5pts) If you want the frequency of oscillation to double, what

could you change the cord length to, assuming a constant angle?

m

Page 3: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Exam Prep Problem (Conical Pendulum)• A small mass (m) suspended on a cord (l=1m) revolves

in a circle of radius r. (θ=30º) – A) (10pts) Draw a free body diagram for the mass, labeling your

coordinate system

m

Page 4: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Exam Prep Problem (Conical Pendulum)• A small mass (m) suspended on a cord (l=1m) revolves

in a circle of radius r. (θ=30º) – B) (5pts) What is the acceleration of the ball, and in what

direction?

m

Page 5: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Exam Prep Problem (Conical Pendulum)• A small mass (m) suspended on a cord (l=1m) revolves

in a circle of radius r. (θ=30º) – C) (5pts) What is the tangential velocity of the ball?

m

Page 6: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Exam Prep Problem (Conical Pendulum)• A small mass (m=2kg) suspended on a cord revolves in

a circle of radius r=0.5m. (θ=30º) – D) (5pts) If you want the frequency of oscillation to double,

what could you change the cord length to, assuming a constant angle?

m

Page 7: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Banked Curves• Can a car make a turn on a banked frictionless surface

without skidding? For speed v, radius R, what angle is required?

• Coordinate system!!

Page 8: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Example Problem

• A car goes around an unbanked curve (R=100m) at a speed of 50m/s. The concrete/tire interface has a coefficient of static friction of 1. Can the car make this turn?

Page 9: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Example Problem

• A car goes around an banked curve (R=100m) at a speed of 50m/s. Ignoring friction, what angle should the curve be banked at to allow the car to make the curve?

Page 10: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Outline• Newton’s Law of Universal Gravitation• Weightlessness• Kepler’s Laws

• What do we know?– Units– Kinematic equations– Freely falling objects– Vectors– Kinematics + Vectors = Vector Kinematics– Relative motion– Projectile motion– Uniform circular motion– Newton’s Laws– Force of Gravity/Normal Force– Free Body Diagrams– Problem solving– Uniform Circular Motion

Page 11: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Newton’s Law of Universal Gravitation

• We know that falling objects accelerate. • We also know that if an object accelerates, there

must be a force acting on it.• The Force that accelerates falling bodies is

gravity.• But what exerts this force?• Since all falling objects fall towards the center of

the Earth, Newton suggested that it is the Earth itself which is exerting this Force.

Page 12: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Newton’s Law of Universal Gravitation• What form does this Force take? • 1) Dependence on distance

– Newton knew that the moon orbited the Earth. – We know that a circular motion requires an inward radial

acceleration

RvaRmoon2

daysTkmR

3.27000,384

sT

mR6

8

1036.2

1084.3

ga

v

sm

moon

sm

moon

43 1078.21072.2

1022

2

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Newton’s Law of Universal Gravitation

• So if the Force causing the moon to orbit the Earth, is the same force which causes object to accelerate at the surface of the Earth, then this Force goes as the inverse square of the distance from the center of the Earth

gamoon 36001

mR

mR

Earth

moon

6

8

1038.6

1084.3

601

Moon

Earth

RR

Page 14: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Newton’s Law of Universal Gravitation

• The other thing we should note, is that the Force due to gravity produces the same acceleration for ALL OBJECTS, regardless of mass. So this is a Force which must scale with the mass of the object.

• Symmetry also suggests that this Force must depend on the mass of the Earth, or the second body.

Page 15: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Newton’s Law of Universal Gravitation

• Finally, Newton argues that if this is the Force causing the moon to orbit the Earth, perhaps it is also the Force causing the planets to Orbit the sun. In fact, perhaps every mass exerts a gravitational force on every other mass in the universe.

• And we can write this force as

221

RMM

GF objectobjectg

22111067.6 kg

NmG

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Direction of Gravitational Force

• Force is a vector, and therefore has a magnitude and direction.

• Direction is along line connecting two masses.

Page 17: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Example Problem

• Imagine 3 Blocks, of equal mass, placed at three corners of a square. Draw the gravitational Force vectors acting on each block.

1

2 3

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Gravitational Attraction Between Two People

• Tom Cruise (160lbs) and Katie Holmes (118lbs) are dancing (about 0.5 m apart). What is attractive Force of Gravity between them?

kglbskglbs

5411873160

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Gravity at Earth’s Surface

• If this law is correct, what should we get for Fg at the Earth’s surface?

2211

6

24

1067.6

1038.6

1098.5

kgNm

EARTH

EARTH

G

mR

kgM

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Satellites

• Imagine I throw a ball with some horizontal velocity vo.• In previous chapters, we studied projectile motion, which

tells us the ball will accelerate towards earth and eventually fall to Earth.

• But this is an approximation…the Earth is not flat, and the Force of gravity is not “downward”, but towards the center of the Earth.

Page 21: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Satellites

• In order for an object to travel with uniform circular motion, a radial Force is required.

• What speed would the ball need to have to travel in a circular path at the surface of the Earth?

Page 22: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Satellites

• The uniform circular motion due to gravitation is known as an “orbit”, and an orbiting object is often referred to as a “satellite”.

• We can calculate the speed of a satellite for a given orbital radius

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Geosynchronous Orbit• A geosynchronous orbit, is one that orbits at the same

speed the Earth rotates, so that the satellite stays at the same position with respect to Earth as it orbits. How can we calculate the height of a satellite of mass M in geosynchronous orbit?

shrsdayT 400,86241

TRv 2

2

2

RmGM

RmvF E

Page 24: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Weightlessness

• Remember, we define weight as the magnitude of the Force of gravity acting on an object.

• At the surface of Earth this is mg.• But we measure weight, by measuring the Force a mass

exerts on a scale.• Imagine we are weighing a mass in

an elevator.• If the elevator is at rest, or moving

at a constant velocity, what does the scale read?

Page 25: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Weightlessness

• Now, if the elevator is accelerating upwards with a=g/2.• What is the mass’ apparent weight?

Page 26: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Weightlessness

• Now, if the elevator is in freefall (a=-g).• What is the mass’ apparent weight?

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Weightlessness

• The “weightlessness” one experiences in orbit is exactly the same one would feel in a freely falling elevator.

• Remember, the Force causing a satellite to orbit is the Force of Gravity….in essence, the satellite is freely falling.

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Kepler’s Laws• Kepler’s laws of planetary motion

– Empirical (Experimental)

• Kepler’s 1st Law: The path of each planet around the sun is an ellipse with the sun at one focus

a b

a semi-major axisb semi-minor axise eccentricitye es/a

es

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Kepler’s Laws• Kepler’s 2nd Law: Each planet moves so that an

imaginary line drawn from the sun to the planet sweeps out equal areas in equal periods of time

t

t

t

t

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Kepler’s Laws• Kepler’s 3rd Law: The ratio of the squares of the periods

of any two planets revolving around the sun is equal to the ratio of the cubes of their semi-major axes.

3

2

1

2

2

1

ss

TT

32

22

31

21

sT

sT

s1

s2

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Newton’s Synthesis

• Newton was able to derive Kepler’s experimental laws from his Universal Law of Gravity.

• Perturbations

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Department of Physics and Applied Physics95.141, F2010, Lecture 10

Kepler’s 3rd Law: Circular Orbit

• Earth’s orbit around sun has e=0.017, almost circular. Can we prove Kepler’s third law for circular orbits?

vRT

Rva

maF

r

2

2

Page 33: Physics I 95.141 LECTURE 10 3/3/10

Department of Physics and Applied Physics95.141, F2010, Lecture 10

Example Problem

• If we know the Earth’s distance from the sun, can we determine the sun’s mass from Kepler’s laws?

syrT

mr

E

ES

7

11

1015.31

105.1