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presentation for mec32

### Transcript of Normal Stress

• Bautista, Eldin E. Mec 32/ C5

• Rod AB:

AB=

=175 MPa

A= d1

4

P= 40kN + 30kN = 70kN = 70000N

175MPa= 70000N

d1

4

• Rod BC:

BC=

=150 MPa

A= d2

4

P= 30kN = 30000N

150MPa= 30000N

d2

4

• A rod is composed of an aluminum section rigidly attached between steel and bronze sections, as shown in Fig. P-107. Axial loads are applied at the positions indicated. If P = 3000 lb and the cross sectional area of the rod is 0.5 in2, determine the stress in each section.

• For steel: stAst=Pst st(0.5)=12 st=24 ksi answer

• For aluminum: alAal=Pal al(0.5)=12 al=24 ksi answer For bronze: brAbr=Pbr br(0.5)=9 br=18 ksi answer

• An aluminum rod is rigidly attached between a steel rod and a bronze rod as shown in Fig. P-108. Axial loads are applied at the positions indicated. Find the maximum value of P that will not exceed a stress in steel of 140 MPa, in aluminum of 90 MPa, or in bronze of 100 MPa.

• For bronze: brAbr=2P100(200)=2P P=10000N

• For aluminum: alAal=P 90(400)=P P=36000N For Steel: stAst=5P P=14000N For safe value of P, use the smallest above. Thus, P=10 000N answer

• The homogeneous bar shown in Fig. P-106 is supported by a smooth pin at C and a cable that runs from A to B around the smooth peg at D. Find the stress in the cable if its diameter is 0.6 inch and the bar weighs 6000 lb.

• MC=0 5T+10(334T)=5(6000) T=2957.13lb