Neraca Energi
15
NERACA ENERGI PROSES DENGAN REAKSI KIMIA
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neraca energi
Transcript of Neraca Energi
Menghitung Entalpi CO2 (H6) : T = 1000 C
Cp = 36.11 x10-3 + 4.233 x10-5 T – 2.887x10-8 T2 + 7.464x10-8 T3
Cp = a + bT + cT2 + dT3
H6 = 48.6 kJ/mol
ΔH = ξ x ΔHro + {(no2 H4 + nN2 H5 + nCO2 H6 + nH2O H7) –
(nC3H8 H1 + nO2 H2 + nN2 H3)}
ΔH = -1.26 x105 kJ/s
Q – Ws = ΔH + ΔEk + ΔEp
Q = ΔH = -1.26 x105 kJ/sPanas harus diambil dari reaktor sebesar ....
Menghitung Entalpi CO2 (H6) : T = 1000 C
Cp = 36.11 x10-3 + 4.233 x10-5 T – 2.887x10-8 T2 + 7.464x10-8 T3
Cp = a + bT + cT2 + dT3
H6 = -393.5 + 48.1 kJ/mol = -345.4 kJ/mol
ΔHfo = -393.5 kJ/mol