NASTASSIA P.

& LENA B.

THE QUESTION

• How many buildings the size of the CN Tower would a mole of jelly beans fill up?

THE GIVEN• A mole = 6.0221415 × 10^23 mol^-1

• Average volume of jelly bean: 0.015m x 0.01m x 0.01m = 0.0000015m^3

• Volume of Cone: 1/3 π r^2 h• Radius at the base of the tower = 33.2m• Height of the CN Tower = 553.33m

• Main level floor is 256 square feet

• Main level height = 7 stories • 1 story = 10 feet• 1 foot = 0.3048 meters• Main level height = 7 x 10 x 0.3048 = 21.336m

} 7 stories

}

Radius of 33.2m

Height of 553.55m

Find volume of the “cone” part. Name it Volume C.

• Volume of Cone: 1/3 π (33.2m)^2 x (553.33m)

• Volume C = around 638 688m^3

Find volume of Sky Pod. Name it Volume P.

• Volume of Sky Pod = 21.336m x 256m^2

• Volume P = around 5462m^3

Total volume of CN Tower = Volume C + Volume P

• Total volume = 638 688 + 5462

• Total volume = 644 150m^3

THE CALCULATIONS

THE CALCULATIONS

Multiply Avagadro’s consant by volume of jelly bean.

Divide it by volume of CN Tower.

• # of CN Towers = Avogadro’s constant x volume of jelly bean volume of 1 CN Tower

• Number of CN Towers = (6.022 x 10^23)(0.0000015)

644 150

• Number of CN Towers = 1.402313126 x 10^12

= 1 402 313 126 000

THE END

Therefore, 1 402 313 126 000 buildings the size of the CN Tower will fill up a mole of jelly beans.