MULTIPLE INTEGRALS

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MULTIPLE INTEGRALS MULTIPLE INTEGRALS 15

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15. MULTIPLE INTEGRALS. POLAR COORDINATES. In plane geometry, the polar coordinate system is used to give a convenient description of certain curves and regions. See Section 10.3. POLAR COORDINATES. The figure enables us to recall the connection between polar and Cartesian coordinates. - PowerPoint PPT Presentation

Transcript of MULTIPLE INTEGRALS

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MULTIPLE INTEGRALSMULTIPLE INTEGRALS

15

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POLAR COORDINATES

In plane geometry, the polar coordinate system is used to give a convenient description of certain curves and regions.

See Section 10.3

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POLAR COORDINATES

The figure enables us to recall the connection between polar and Cartesian coordinates.

If the point P has Cartesian coordinates (x, y) and polar coordinates (r, θ), then

x = r cos θ y = r sin θ

r2 = x2 + y2 tan θ = y/x

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CYLINDRICAL COORDINATES

In three dimensions there is a coordinate system, called cylindrical coordinates, that:

Is similar to polar coordinates.

Gives a convenient description of commonly occurring surfaces and solids.

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15.7Triple Integrals in

Cylindrical Coordinates

MULTIPLE INTEGRALS

In this section, we will learn about:

Cylindrical coordinates and

using them to solve triple integrals.

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CYLINDRICAL COORDINATES

In the cylindrical coordinate system, a point P in three-dimensional (3-D) space is represented by the ordered triple (r, θ, z), where:

r and θ are polar coordinates of the projection of P onto the xy–plane.

z is the directed distance from the xy-plane to P.

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CYLINDRICAL COORDINATES

To convert from cylindrical to rectangular coordinates, we use:

x = r cos θ y = r sin θ

z = z

Equations 1

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CYLINDRICAL COORDINATES

To convert from rectangular to cylindrical coordinates, we use:

r2 = x2 + y2 tan θ = y/x

z = z

Equations 2

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CYLINDRICAL COORDINATES

a. Plot the point with cylindrical coordinates (2, 2π/3, 1) and find its rectangular coordinates.

b. Find cylindrical coordinates of the point with rectangular coordinates (3, –3, –7).

Example 1

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CYLINDRICAL COORDINATES

The point with cylindrical coordinates (2, 2π/3, 1) is plotted here.

Example 1 a

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CYLINDRICAL COORDINATES

From Equations 1, its rectangular coordinates are:

The point is (–1, , 1) in rectangular coordinates.

2 12cos 2 13 2

2 32sin 2 33 2

1

x

y

z

3

Example 1 a

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CYLINDRICAL COORDINATES

From Equations 2, we have:

Example 1 b

2 23 ( 3) 3 23 7tan 1, so 2

3 47

r

n

z

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CYLINDRICAL COORDINATES

Therefore, one set of cylindrical coordinates is:

Another is:

As with polar coordinates, there are infinitely many choices.

(3 2,7 / 4, 7)

(3 2, / 4, 7)

Example 1 b

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CYLINDRICAL COORDINATES

Cylindrical coordinates are useful in problems that involve symmetry about an axis, and the z-axis is chosen to coincide with this axis of symmetry.

For instance, the axis of the circular cylinder with Cartesian equation x2 + y2 = c2 is the z-axis.

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CYLINDRICAL COORDINATES

In cylindrical coordinates, this cylinder has the very simple equation r = c.

This is the reason for the name “cylindrical” coordinates.

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CYLINDRICAL COORDINATES

Describe the surface whose equation in cylindrical coordinates is z = r.

The equation says that the z-value, or height, of each point on the surface is the same as r, the distance from the point to the z-axis.

Since θ doesn’t appear, it can vary.

Example 2

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CYLINDRICAL COORDINATES

So, any horizontal trace in the plane z = k (k > 0) is a circle of radius k.

These traces suggest the surface is a cone.

This prediction can be confirmed by converting the equation into rectangular coordinates.

Example 2

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CYLINDRICAL COORDINATES

From the first equation in Equations 2, we have:

z2 = r2 = x2 + y2

Example 2

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CYLINDRICAL COORDINATES

We recognize the equation z2 = x2 + y2

(by comparison with the table in Section 12.6) as being a circular cone whose axis is the z-axis.

Example 2

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EVALUATING TRIPLE INTEGS. WITH CYL. COORDS.

Suppose that E is a type 1 region whose projection D on the xy-plane is conveniently described in polar coordinates.

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EVALUATING TRIPLE INTEGRALS

In particular, suppose that f is continuous and

E = {(x, y, z) | (x, y) D, u1(x, y) ≤ z ≤ u2(x, y)}

where D is given in polar coordinates by:

D = {(r, θ) | α ≤ θ ≤ β, h1(θ) ≤ r ≤ h2(θ)}

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EVALUATING TRIPLE INTEGRALS

We know from Equation 6 in Section 15.6 that:

2

1

( , )

( , )

( , , )

, ,

E

u x y

u x yD

f x y z dV

f x y z dz dA

Equation 3

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EVALUATING TRIPLE INTEGRALS

However, we also know how to evaluate double integrals in polar coordinates.

In fact, combining Equation 3 with Equation 3 in Section 15.4, we obtain the following formula.

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TRIPLE INTEGN. IN CYL. COORDS.

f x, y, z dVE

f r cos ,r sin , z r dz dr du1 r cos ,r sin

u2 r cos ,r sin h1 ( )

h2 ( )

Formula 4

This is the formula for triple integration in cylindrical coordinates.

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TRIPLE INTEGN. IN CYL. COORDS.

It says that we convert a triple integral from rectangular to cylindrical coordinates by:

Writing x = r cos θ, y = r sin θ.

Leaving z as it is.

Using the appropriate limits of integration for z, r, and θ.

Replacing dV by r dz dr dθ.

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TRIPLE INTEGN. IN CYL. COORDS.

The figure shows how to remember this.

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TRIPLE INTEGN. IN CYL. COORDS.

It is worthwhile to use this formula:

When E is a solid region easily described in cylindrical coordinates.

Especially when the function f(x, y, z) involves the expression x2 + y2.

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EVALUATING TRIPLE INTEGRALS

A solid lies within:

The cylinder x2 + y2 = 1

Below the plane z = 4

Above the paraboloid z = 1 – x2 – y2

Example 3

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EVALUATING TRIPLE INTEGRALS

The density at any point is proportional to its distance from the axis of the cylinder.

Find the mass of E.

Example 3

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EVALUATING TRIPLE INTEGRALS

In cylindrical coordinates, the cylinder is r = 1 and the paraboloid is z = 1 – r2.

So, we can write:

E = {(r, θ, z)| 0 ≤ θ ≤ 2π, 0 ≤ r ≤ 1, 1 – r2 ≤ z ≤ 4}

Example 3

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EVALUATING TRIPLE INTEGRALS

As the density at (x, y, z) is proportional to the distance from the z-axis, the density function is:

where K is the proportionality constant.

2 2, ,f x y z K x y Kr

Example 3

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EVALUATING TRIPLE INTEGRALS

So, from Formula 13 in Section 15.6, the mass of E is:

2

2 2

2 1 4

0 0 1

2 1 2 2

0 0

2 1 2 4

0 0

153

0

( )

4 1

3

1225 5

E

r

m K x y dV

Kr r dz dr d

Kr r dr d

K d r r dr

r KK r

Example 3

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EVALUATING TRIPLE INTEGRALS

EvaluateExample 4

2

2 2 2

2 4 2 2 2

2 4

x

x x yx y dz dy dx

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EVALUATING TRIPLE INTEGRALS

This iterated integral is a triple integral over the solid region

The projection of E onto the xy-plane is the disk x2 + y2 ≤ 4.

2 2 2 2{ , , | 2 2, 4 4 , 2}

E

x y z x x y x x y z

Example 4

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EVALUATING TRIPLE INTEGRALS

The lower surface of E is the cone

Its upper surface is the plane z = 2.

Example 4

2 2z x y

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EVALUATING TRIPLE INTEGRALS

That region has a much simpler description in cylindrical coordinates:

E = {(r, θ, z) | 0 ≤ θ ≤ 2π, 0 ≤ r ≤ 2, r ≤ z ≤ 2}

Thus, we have the following result.

Example 4

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EVALUATING TRIPLE INTEGRALS

2

2 2 2

2 4 2 2 2

2 4

2 2 22 2 2

0 0

2 2 3

0 0

24 51 12 5 0

165

2

2

x

x x y

rE

x y dz dy dx

x y dV r r dz dr d

d r r dr

r r

Example 4