metodo hardy croos para redes de tuberias

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PRIMERA ITERACION CIRCUITO I tramo D (pulg) L(Km) Qo hfo(m) 1--2 4 0.4 100 220 3459.698 2--4 4 0.2 120 60 111.589 3--4 4 0.4 120 -60 -223.178 1--3 4 0.2 100 -200 -1450.213 Σ 1897.897 CIRCUITO II tramo D (pulg) L(Km) Qo hfo(m) 2--5 6 0.4 100 100 111.684 6--5 6 0.2 100 -20 -2.844 6--4 4 0.4 120 20 29.240 2--4 4 0.2 120 -60 -111.589 Σ 26.492 CH CH

description

un metodo iterativo para el calculo de caudales en redes de tuberias

Transcript of metodo hardy croos para redes de tuberias

Page 1: metodo hardy croos para redes de tuberias

PRIMERA ITERACION

CIRCUITO Itramo D (pulg) L(Km) Qo hfo(m) hfo/Qo

1--2 4 0.4 100 220 3459.698 15.726

2--4 4 0.2 120 60 111.589 1.860

3--4 4 0.4 120 -60 -223.178 3.720

1--3 4 0.2 100 -200 -1450.213 7.251

Σ 1897.897 28.556

CIRCUITO II

tramo D (pulg) L(Km) Qo hfo(m) hfo/Qo

2--5 6 0.4 100 100 111.684 1.117

6--5 6 0.2 100 -20 -2.844 0.142

6--4 4 0.4 120 20 29.240 1.462

2--4 4 0.2 120 -60 -111.589 1.860Σ 26.492 4.581

CIRCUITO III

tramo D (pulg) L(Km) Qo hfo(m) hfo/Qo

CH

CH

CH

Page 2: metodo hardy croos para redes de tuberias

6--4 4 0.4 120 -20 -29.240 1.462

9--6 4 0.2 100 -180 -1193.385 6.630

9--8 4 0.4 100 180 2386.769 13.260

8--4 4 0.2 100 20 20.485 1.024Σ 1184.629 22.376

CIRCUITO IV

tramo D (pulg) L(Km) Qo hfo(m) hfo/Qo

3--4 4 0.4 120 60 223.178 3.720

8--4 4 0.2 100 -20 -20.485 1.024

8--7 6 0.4 100 20 5.687 0.284

3--7 4 0.2 100 -60 -156.353 2.606Σ 52.027 7.634

NOTATramo Caudal COMO VEMOS LA CONDICION ΔQ<1%Q CUMPLE EN LA SEPTIMA ITERACIÓN1--2 177.560

2--4 48.396 CAUDAL3--4 -74.349

1--3 -242.440

2--5 69.164

6--5 -50.836

6--4 21.867

9--6 -212.703

9--8 147.297

8--4 15.388

8--7 -8.091

3--7 -88.091

CH

1 2

2 4

3 4

1 3

2 5

6 5

6 4

9 6

9 8

8 4

8 7

3 7

177.560

48.396

74.349

242.440

69.164

50.836

21.867

212.703

147.297

15.388

8.091

88.091

lQ slQ slQ slQ slQ slQ slQ slQ slQ slQ slQ slQ s

Page 3: metodo hardy croos para redes de tuberias

CONDICION ΔQ<1%QΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE tramo

-35.925 184.075 1.841 NO 1--2-32.799 27.201 0.272 NO 2--4-32.241 -92.241 -0.922 NO 3--4-35.925 -235.925 -2.359 NO 1--3

ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE tramo

-3.126 96.874 0.969 NO 2--5-3.126 -23.126 -0.231 NO 6--525.491 45.491 0.455 NO 6--432.799 -27.201 -0.272 NO 2--4

ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE tramo

Page 4: metodo hardy croos para redes de tuberias

-25.491 -45.491 -0.455 NO 6--4-28.617 -208.617 -2.086 NO 9--6-28.617 151.383 1.514 NO 9--8-24.933 -4.933 -0.049 NO 8--4

ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE tramo

32.241 92.241 0.922 NO 3--424.933 4.933 0.049 NO 8--4-3.684 16.316 0.163 NO 8--7-3.684 -63.684 -0.637 NO 3--7

COMO VEMOS LA CONDICION ΔQ<1%Q CUMPLE EN LA SEPTIMA ITERACIÓN

1 2

2 4

3 4

1 3

2 5

6 5

6 4

9 6

9 8

8 4

8 7

3 7

177.560

48.396

74.349

242.440

69.164

50.836

21.867

212.703

147.297

15.388

8.091

88.091

lQ slQ slQ slQ slQ slQ slQ slQ slQ slQ slQ slQ s

Page 5: metodo hardy croos para redes de tuberias

SEGUNDA ITERACION

CIRCUITO ID (pulg) L(Km) Qo hfo(m) hfo/Qo ΔQ

4 0.4 100 184.075 2487.691 13.515 -0.967

4 0.2 120 27.201 25.824 0.949 21.077

4 0.4 120 -92.241 -494.518 5.361 19.359

4 0.2 100 -235.925 -1968.603 8.344 -0.967

Σ 50.394 28.169

CIRCUITO II

D (pulg) L(Km) Qo hfo(m) hfo/Qo ΔQ

6 0.4 100 96.874 105.311 1.087 -22.044

6 0.2 100 -23.126 -3.720 0.161 -22.044

4 0.4 120 45.491 133.733 2.940 -21.329

4 0.2 120 -27.201 -25.824 0.949 -21.077Σ 209.500 5.137

CIRCUITO III

D (pulg) L(Km) Qo hfo(m) hfo/Qo ΔQ

CH

CH

CH

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4 0.4 120 -45.491 -133.733 2.940 21.329

4 0.2 100 -208.617 -1567.922 7.516 -0.716

4 0.4 100 151.383 1732.596 11.445 -0.716

4 0.2 100 -4.933 -1.538 0.312 19.610Σ 29.404 22.212

CIRCUITO IV

D (pulg) L(Km) Qo hfo(m) hfo/Qo ΔQ

4 0.4 120 92.241 494.518 5.361 -19.359

4 0.2 100 4.933 1.538 0.312 -19.610

6 0.4 100 16.316 3.902 0.239 -20.326

4 0.2 100 -63.684 -174.574 2.741 -20.326Σ 325.384 8.653

CH

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TERCERA ITERACION

CONDICION ΔQ<1%QQ1 =Qo + ΔQ 0.01Q CUMPLE tramo D (pulg)

183.108 1.831 SI 1--2 448.278 0.483 NO 2--4 4-72.883 -0.729 NO 3--4 4-236.892 -2.369 SI 1--3 4

Q1 =Qo + ΔQ 0.01Q CUMPLE tramo D (pulg)74.830 0.748 NO 2--5 6-45.170 -0.452 NO 6--5 624.163 0.242 NO 6--4 4-48.278 -0.483 NO 2--4 4

Q1 =Qo + ΔQ 0.01Q CUMPLE tramo D (pulg)

Page 8: metodo hardy croos para redes de tuberias

-24.163 -0.242 NO 6--4 4-209.333 -2.093 SI 9--6 4150.667 1.507 SI 9--8 414.677 0.147 NO 8--4 4

Q1 =Qo + ΔQ 0.01Q CUMPLE tramo D (pulg)72.883 0.729 NO 3--4 4-14.677 -0.147 NO 8--4 4-4.009 -0.040 NO 8--7 6-84.009 -0.840 NO 3--7 4

Page 9: metodo hardy croos para redes de tuberias

TERCERA ITERACION

CIRCUITO IL(Km) Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ

0.4 100 183.108 2463.568 13.454 -4.572 178.536

0.2 120 48.278 74.642 1.546 -2.209 46.069

0.4 120 -72.883 -319.834 4.388 -3.545 -76.428

0.2 100 -236.892 -1983.557 8.373 -4.572 -241.464Σ 234.819 27.762

CIRCUITO II

L(Km) Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ

0.4 100 74.830 65.317 0.873 -2.363 72.467

0.2 100 -45.170 -12.836 0.284 -2.363 -47.533

0.4 120 24.163 41.484 1.717 0.401 24.564

0.2 120 -48.278 -74.642 1.546 2.209 -46.069Σ 19.324 4.420

CIRCUITO III

L(Km) Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ

CH

CH

CH

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0.4 120 -24.163 -41.484 1.717 -0.401 -24.564

0.2 100 -209.333 -1577.885 7.538 -2.765 -212.097

0.4 100 150.667 1717.476 11.399 -2.765 147.903

0.2 100 14.677 11.555 0.787 -1.738 12.939Σ 109.662 21.441

CIRCUITO IV

L(Km) Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ

0.4 120 72.883 319.834 4.388 3.545 76.428

0.2 100 -14.677 -11.555 0.787 1.738 -12.939

0.4 100 -4.009 -0.291 0.073 -1.027 -5.036

0.2 100 -84.009 -291.430 3.469 -1.027 -85.036Σ 16.558 8.717

CH

Page 11: metodo hardy croos para redes de tuberias

CUARTA ITERACION

CONDICION ΔQ<1%Q0.01Q CUMPLE tramo D (pulg) L(Km)1.785 NO 1--2 4 0.40.461 NO 2--4 4 0.2-0.764 NO 3--4 4 0.4-2.415 NO 1--3 4 0.2

0.01Q CUMPLE tramo D (pulg) L(Km)0.725 NO 2--5 6 0.4-0.475 NO 6--5 6 0.20.246 NO 6--4 4 0.4-0.461 NO 2--4 4 0.2

0.01Q CUMPLE tramo D (pulg) L(Km)

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-0.246 NO 6--4 4 0.4-2.121 NO 9--6 4 0.21.479 NO 9--8 4 0.40.129 NO 8--4 4 0.2

0.01Q CUMPLE tramo D (pulg) L(Km)0.764 NO 3--4 4 0.4-0.129 NO 8--4 4 0.2-0.050 NO 8--7 6 0.4-0.850 NO 3--7 4 0.2

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CIRCUITO I CONDICION ΔQ<1%QQo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q

100 178.536 2350.977 13.168 -0.297 178.239 1.782

120 46.069 68.447 1.486 2.393 48.463 0.485

120 -76.428 -349.210 4.569 2.236 -74.192 -0.742

100 -241.464 -2054.961 8.510 -0.297 -241.761 -2.418Σ 15.253 27.733

CIRCUITO II

Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q

100 72.467 61.553 0.849 -2.691 69.776 0.698

100 -47.533 -14.106 0.297 -2.691 -50.224 -0.502

120 24.564 42.769 1.741 -2.453 22.111 0.221

120 -46.069 -68.447 1.486 -2.393 -48.463 -0.485Σ 21.768 4.373

CIRCUITO III

Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q

CH

CH

CH

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120 -24.564 -42.769 1.741 2.453 -22.111 -0.221

100 -212.097 -1616.654 7.622 -0.238 -212.335 -2.123

100 147.903 1659.629 11.221 -0.238 147.665 1.477

100 12.939 9.152 0.707 2.295 15.234 0.152Σ 9.359 21.292

CIRCUITO IV

Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q

120 76.428 349.210 4.569 -2.236 74.192 0.742

100 -12.939 -9.152 0.707 -2.295 -15.234 -0.152

100 -5.036 -0.443 0.088 -2.533 -7.569 -0.076

100 -85.036 -298.053 3.505 -2.533 -87.569 -0.876Σ 41.561 8.870

CH

Page 15: metodo hardy croos para redes de tuberias

QUINTA ITERACION

CONDICION ΔQ<1%Q CIRCUITO ICUMPLE tramo D (pulg) L(Km) Qo

SI 1--2 4 0.4 100 178.239NO 2--4 4 0.2 120 48.463NO 3--4 4 0.4 120 -74.192SI 1--3 4 0.2 100 -241.761

Σ

CIRCUITO II

CUMPLE tramo D (pulg) L(Km) QoNO 2--5 6 0.4 100 69.776NO 6--5 6 0.2 100 -50.224NO 6--4 4 0.4 120 22.111NO 2--4 4 0.2 120 -48.463

Σ

CIRCUITO III

CUMPLE tramo D (pulg) L(Km) Qo

CH

CH

CH

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NO 6--4 4 0.4 120 -22.111SI 9--6 4 0.2 100 -212.335SI 9--8 4 0.4 100 147.665NO 8--4 4 0.2 100 15.234

Σ

CIRCUITO IV

CUMPLE tramo D (pulg) L(Km) QoNO 3--4 4 0.4 120 74.192NO 8--4 4 0.2 100 -15.234NO 8--7 6 0.4 100 -7.569NO 3--7 4 0.2 100 -87.569

Σ

CH

Page 17: metodo hardy croos para redes de tuberias

CONDICION ΔQ<1%Qhfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE2343.740 13.149 -0.561 177.678 1.777 SI75.170 1.551 -0.333 48.130 0.481 SI-330.548 4.455 -0.408 -74.600 -0.746 SI-2059.644 8.519 -0.561 -242.322 -2.423 SI28.718 27.675

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE57.391 0.823 -0.228 69.548 0.695 SI-15.619 0.311 -0.228 -50.452 -0.505 SI35.204 1.592 0.074 22.185 0.222 SI-75.170 1.551 0.333 -48.130 -0.481 SI1.806 4.277

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE

Page 18: metodo hardy croos para redes de tuberias

-35.204 1.592 -0.074 -22.185 -0.222 SI-1620.006 7.629 -0.302 -212.637 -2.126 SI1654.700 11.206 -0.302 147.363 1.474 SI12.380 0.813 -0.149 15.085 0.151 SI11.871 21.240

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE330.548 4.455 0.408 74.600 0.746 SI-12.380 0.813 0.149 -15.085 -0.151 SI-0.942 0.125 -0.153 -7.722 -0.077 NO-314.685 3.594 -0.153 -87.722 -0.877 SI2.541 8.986

Page 19: metodo hardy croos para redes de tuberias

SEXTA ITERACION

CIRCUITO Itramo D (pulg) L(Km) Qo hfo(m) hfo/Qo

1--2 4 0.4 100 177.678 2330.114 13.114

2--4 4 0.2 120 48.130 74.219 1.542

3--4 4 0.4 120 -74.600 -333.920 4.476

1--3 4 0.2 100 -242.322 -2068.493 8.536

Σ 1.919 27.669

CIRCUITO II

tramo D (pulg) L(Km) Qo hfo(m) hfo/Qo

2--5 6 0.4 100 69.548 57.044 0.820

6--5 6 0.2 100 -50.452 -15.750 0.312

6--4 4 0.4 120 22.185 35.422 1.597

2--4 4 0.2 120 -48.130 -74.219 1.542Σ 2.497 4.271

CIRCUITO III

tramo D (pulg) L(Km) Qo hfo(m) hfo/Qo

CH

CH

CH

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6--4 4 0.4 120 -22.185 -35.422 1.597

9--6 4 0.2 100 -212.637 -1624.272 7.639

9--8 4 0.4 100 147.363 1648.443 11.186

8--4 4 0.2 100 15.085 12.157 0.806Σ 0.906 21.228

CIRCUITO IV

tramo D (pulg) L(Km) Qo hfo(m) hfo/Qo

3--4 4 0.4 120 74.600 333.920 4.476

8--4 4 0.2 100 -15.085 -12.157 0.806

8--7 6 0.4 100 -7.722 -0.978 0.127

3--7 4 0.2 100 -87.722 -315.701 3.599Σ 5.083 9.008

CH

Page 21: metodo hardy croos para redes de tuberias

CONDICION ΔQ<1%QΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE tramo

-0.037 177.640 1.776 SI 1--20.279 48.409 0.484 SI 2--40.268 -74.333 -0.743 SI 3--4-0.037 -242.360 -2.424 SI 1--3

ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE tramo

-0.316 69.232 0.692 SI 2--5-0.316 -50.768 -0.508 SI 6--5-0.293 21.892 0.219 NO 6--4-0.279 -48.409 -0.484 SI 2--4

ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE tramo

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0.293 -21.892 -0.219 NO 6--4-0.023 -212.660 -2.127 SI 9--6-0.023 147.340 1.473 SI 9--80.282 15.367 0.154 NO 8--4

ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE tramo

-0.268 74.333 0.743 SI 3--4-0.282 -15.367 -0.154 NO 8--4-0.305 -8.027 -0.080 NO 8--7-0.305 -88.027 -0.880 SI 3--7

Page 23: metodo hardy croos para redes de tuberias

SEPTIMA ITERACION

CIRCUITO ID (pulg) L(Km) Qo hfo(m) hfo/Qo ΔQ

4 0.4 100 177.640 2329.204 13.112 -0.067

4 0.2 120 48.409 75.015 1.550 -0.044

4 0.4 120 -74.333 -331.707 4.462 -0.047

4 0.2 100 -242.360 -2069.085 8.537 -0.067

Σ 3.426 27.661

CIRCUITO II

D (pulg) L(Km) Qo hfo(m) hfo/Qo ΔQ

6 0.4 100 69.232 56.566 0.817 -0.023

6 0.2 100 -50.768 -15.934 0.314 -0.023

4 0.4 120 21.892 34.561 1.579 0.013

4 0.2 120 -48.409 -75.015 1.550 0.044Σ 0.178 4.259

CIRCUITO III

D (pulg) L(Km) Qo hfo(m) hfo/Qo ΔQ

CH

CH

CH

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4 0.4 120 -21.892 -34.561 1.579 -0.013

4 0.2 100 -212.660 -1624.598 7.639 -0.035

4 0.4 100 147.340 1647.966 11.185 -0.035

4 0.2 100 15.367 12.581 0.819 -0.015Σ 1.387 21.222

CIRCUITO IV

D (pulg) L(Km) Qo hfo(m) hfo/Qo ΔQ

4 0.4 120 74.333 331.707 4.462 0.047

4 0.2 100 -15.367 -12.581 0.819 0.015

6 0.4 100 -8.027 -1.051 0.131 -0.020

4 0.2 100 -88.027 -317.735 3.610 -0.020Σ 0.341 9.022

CH

Page 25: metodo hardy croos para redes de tuberias

OCTAVA ITERACION

CONDICION ΔQ<1%QQ1 =Qo + ΔQ 0.01Q CUMPLE tramo D (pulg)

177.573 1.776 SI 1--2 448.364 0.484 SI 2--4 4-74.379 -0.744 SI 3--4 4-242.427 -2.424 SI 1--3 4

Q1 =Qo + ΔQ 0.01Q CUMPLE tramo D (pulg)69.209 0.692 SI 2--5 6-50.791 -0.508 SI 6--5 621.904 0.219 SI 6--4 4-48.364 -0.484 SI 2--4 4

Q1 =Qo + ΔQ 0.01Q CUMPLE tramo D (pulg)

Page 26: metodo hardy croos para redes de tuberias

-21.904 -0.219 SI 6--4 4-212.696 -2.127 SI 9--6 4147.304 1.473 SI 9--8 415.352 0.154 SI 8--4 4

Q1 =Qo + ΔQ 0.01Q CUMPLE tramo D (pulg)74.379 0.744 SI 3--4 4-15.352 -0.154 SI 8--4 4-8.047 -0.080 SI 8--7 6-88.047 -0.880 SI 3--7 4

Page 27: metodo hardy croos para redes de tuberias

OCTAVA ITERACION

CIRCUITO IL(Km) Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ

0.4 100 177.573 2327.580 13.108 -0.005 177.569

0.2 120 48.364 74.888 1.548 0.033 48.397

0.4 120 -74.379 -332.092 4.465 0.032 -74.348

0.2 100 -242.427 -2070.143 8.539 -0.005 -242.431Σ 0.234 27.660

CIRCUITO II

L(Km) Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ

0.4 100 69.209 56.532 0.817 -0.037 69.171

0.2 100 -50.791 -15.947 0.314 -0.037 -50.829

0.4 120 21.904 34.598 1.580 -0.035 21.869

0.2 120 -48.364 -74.888 1.548 -0.033 -48.397Σ 0.295 4.259

CIRCUITO III

L(Km) Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ

CH

CH

CH

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0.4 120 -21.904 -34.598 1.580 0.035 -21.869

0.2 100 -212.696 -1625.097 7.640 -0.002 -212.698

0.4 100 147.304 1647.235 11.183 -0.002 147.302

0.2 100 15.352 12.558 0.818 0.034 15.386Σ 0.097 21.221

CIRCUITO IV

L(Km) Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ

0.4 120 74.379 332.092 4.465 -0.032 74.348

0.2 100 -15.352 -12.558 0.818 -0.034 -15.386

0.4 100 -8.047 -1.055 0.131 -0.036 -8.084

0.2 100 -88.047 -317.872 3.610 -0.036 -88.084Σ 0.606 9.024

CH

Page 29: metodo hardy croos para redes de tuberias

NOVENA ITERACION

CONDICION ΔQ<1%Q0.01Q CUMPLE tramo D (pulg) L(Km)1.776 SI 1--2 4 0.4 1000.484 SI 2--4 4 0.2 120-0.743 SI 3--4 4 0.4 120-2.424 SI 1--3 4 0.2 100

0.01Q CUMPLE tramo D (pulg) L(Km)0.692 SI 2--5 6 0.4 100-0.508 SI 6--5 6 0.2 1000.219 SI 6--4 4 0.4 120-0.484 SI 2--4 4 0.2 120

0.01Q CUMPLE tramo D (pulg) L(Km)

CH

CH

CH

Page 30: metodo hardy croos para redes de tuberias

-0.219 SI 6--4 4 0.4 120-2.127 SI 9--6 4 0.2 1001.473 SI 9--8 4 0.4 1000.154 SI 8--4 4 0.2 100

0.01Q CUMPLE tramo D (pulg) L(Km)0.743 SI 3--4 4 0.4 120-0.154 SI 8--4 4 0.2 100-0.081 SI 8--7 6 0.4 100-0.881 SI 3--7 4 0.2 100

CH

Page 31: metodo hardy croos para redes de tuberias

CIRCUITO I CONDICION ΔQ<1%QQo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q

177.569 2327.469 13.107 -0.008 177.561 1.77648.397 74.982 1.549 -0.005 48.392 0.484-74.348 -331.829 4.463 -0.005 -74.353 -0.744-242.431 -2070.215 8.539 -0.008 -242.439 -2.424

Σ 0.407 27.659

CIRCUITO II

Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q69.171 56.475 0.816 -0.003 69.169 0.692-50.829 -15.968 0.314 -0.003 -50.831 -0.50821.869 34.496 1.577 0.002 21.871 0.219-48.397 -74.982 1.549 0.005 -48.392 -0.484

Σ 0.020 4.257

CIRCUITO III

Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q

Page 32: metodo hardy croos para redes de tuberias

-21.869 -34.496 1.577 -0.002 -21.871 -0.219-212.698 -1625.132 7.641 -0.004 -212.702 -2.127147.302 1647.184 11.182 -0.004 147.298 1.47315.386 12.609 0.820 -0.002 15.384 0.154Σ 0.164 21.220

CIRCUITO IV

Qo hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q74.348 331.829 4.463 0.005 74.353 0.744-15.386 -12.609 0.820 0.002 -15.384 -0.154-8.084 -1.064 0.132 -0.002 -8.086 -0.081-88.084 -318.114 3.612 -0.002 -88.086 -0.881

Σ 0.041 9.026

Page 33: metodo hardy croos para redes de tuberias

DECIMA ITERACION

CONDICION ΔQ<1%Q CIRCUITO ICUMPLE tramo D (pulg) L(Km) Qo

SI 1--2 4 0.4 100 177.561SI 2--4 4 0.2 120 48.392SI 3--4 4 0.4 120 -74.353SI 1--3 4 0.2 100 -242.439

Σ

CIRCUITO II

CUMPLE tramo D (pulg) L(Km) QoSI 2--5 6 0.4 100 69.169SI 6--5 6 0.2 100 -50.831SI 6--4 4 0.4 120 21.871SI 2--4 4 0.2 120 -48.392

Σ

CIRCUITO III

CUMPLE tramo D (pulg) L(Km) Qo

CH

CH

CH

Page 34: metodo hardy croos para redes de tuberias

SI 6--4 4 0.4 120 -21.871SI 9--6 4 0.2 100 -212.702SI 9--8 4 0.4 100 147.298SI 8--4 4 0.2 100 15.384

Σ

CIRCUITO IV

CUMPLE tramo D (pulg) L(Km) QoSI 3--4 4 0.4 120 74.353SI 8--4 4 0.2 100 -15.384SI 8--7 6 0.4 100 -8.086SI 3--7 4 0.2 100 -88.086

Σ

CH

Page 35: metodo hardy croos para redes de tuberias

CONDICION ΔQ<1%Qhfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE2327.276 13.107 -0.001 177.560 1.776 SI74.967 1.549 0.004 48.396 0.484 SI-331.875 4.463 0.004 -74.349 -0.743 SI-2070.341 8.540 -0.001 -242.440 -2.424 SI

0.028 27.659

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE56.471 0.816 -0.004 69.164 0.692 SI-15.970 0.314 -0.004 -50.836 -0.508 SI34.501 1.577 -0.004 21.867 0.219 SI-74.967 1.549 -0.004 -48.396 -0.484 SI0.035 4.257

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE

Page 36: metodo hardy croos para redes de tuberias

-34.501 1.577 0.004 -21.867 -0.219 SI-1625.192 7.641 0.000 -212.703 -2.127 SI1647.097 11.182 0.000 147.297 1.473 SI12.607 0.819 0.004 15.388 0.154 SI0.011 21.220

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ 0.01Q CUMPLE331.875 4.463 -0.004 74.349 0.743 SI-12.607 0.819 -0.004 -15.388 -0.154 SI-1.065 0.132 -0.004 -8.091 -0.081 SI-318.131 3.612 -0.004 -88.091 -0.881 SI0.072 9.026

Page 37: metodo hardy croos para redes de tuberias

Tramo Caudal1 1--2 177.5602 2--4 48.3963 3--4 -74.3494 1--3 -242.4405 2--5 69.1646 6--5 -50.8367 6--4 21.8678 9--6 -212.7039 9--8 147.297

10 8--4 15.38811 8--7 -8.09112 3--7 -88.091