Matti Hotokka Department of Physical Chemistry...
Transcript of Matti Hotokka Department of Physical Chemistry...
Jyväskylä 2008
AtomsMatti Hotokka
Department of Physical ChemistryÅbo Akademi University
Jyväskylä 2008
Dark lines in the sun’s spectrum
� First observed by Wollaston 1802
� Rediscovered by Fraunhofer 1814Fraunhofer’s notation is used still today
What is seen?
Hα
Hβ
Hγ
Hδ
FC f h
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Fraunhofer’s notationA few examples of lines
Symbol Atom Wavelength [nm]C H 656.3D Na 589.6 & 589.0F H 486.1
A (band) O2 760B (band) O2 687E Fe 527.0b Mg 518.4 & 517.3c Fe 495.8f H 434.0g Ca 422.7h H 410.2H Ca 396.8
See http://www.harmsy.freeuk.com/fraunhofer.html
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λ =−
=nn
G n2
2 43 4 5, , , �
1 4 12
1 12
1 3 4 52 2 2 2λ= −
��
�
��
�= −
��
�
��
�
=G n
Rn
nH , , , �Discovered by Wollaston/FraunhoferMathematical formulation by JohannBalmer in 1885
Balmer series
Generalised by Johannes Rydberg 1888
Rydberg’s constant RH = 109 668 cm-1.
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Rutherford (1911)
Classical physicsBohr (1913)
Non-classical particlesDeBroglie (1925)
Electrons as standing wavesSchrödinger and Heisenberg (1926, 1925)
Modern quantum theory
Atom modelsReasonably accurate models
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Electrons follow only certain paths (orbits)Energy is absorbed/emitted at transitionsfrom one orbit to another. Transitionenergy is EEmitted frequency is E/hCoulomb attraction and centrifugal forceThe electron’s energy is a multiple of ½h ,
= circulation frequency
Bohr
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E m en hn
e= −4
2 2028 ε
∆E m eh n
e= −
��
��
�4
202 2 28
12
1ε
Energy of the electron
Bohr
(Or �)
Transition energy from level 2 to level nModern quantum theory gives the same answer.
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Modern quantum theory
�
1s
3s
2p2s
3p 3d
Hydrogen atom only: The orbitalenergy depends only on theprincipal quantum number n.
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What is seen?
Lyman 121.58 nm102.58 nm97.26 nm
Balmer 656.53 nm486.32 nm434.21 nm
Paschen 1.8758 �m1.2822 �m1.0942 �m
Brackett 2467.5 cm-1
3807.9 cm-1
4616.1 cm-1
Pfund 1304.4 cm-1
2148.6 cm-1
2673.1 cm-1
In the visible
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Almost like hydrogen: one valence nselectronDifference: 2s and 2p have differentorbital energies; likewise 3s, 3p and 3d etc
Alkali metals
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0
-1
-2
-3
-4
-5
-6
0
-10000
-20000
-30000
-40000
-50000
2 S 2 P 2 D 2 F
2s
3s
4s
5s
6s
2p
3p
4p
5p
6p
3d
4d
5d6d7d
4f
5f6f7f
671
323
274256
813
497
427399
611
460413
1870
Principal
Diffuse
Sharp
FundamentalEnergy levelsand transitionsof lithium
Selection rule:qn � goes to
�+1 or �-1
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M L
MJL
Spectral terms
M = 2S+1 = spin multiplicity; S = total electronic spin
L = total orbital angular quantum number
Can be calculated in several ways. However, this may betrickier than for molecules because atomic orbitals mayincorporate more degenerate electrons.
Sum of spin and orbital angular momenta, J, may be added. It is important if relativistic effects need to be considered.
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The totally filled orbitals may be ignored.
Spectral termsFor a few simple cases
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Previously: � = ±1Quite strict rule: S = 0
More selection rules
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Relativity splits levels that should have thesame energy
Sodium energy levels
E
3s 2 S1/2
0.0
3p 2 P1/216956.183
3p 2 P3/216973.379
589.7554 nm589.1579 nm
E
3p 2 P1/216956.183
3p 2 P3/216973.379
4d 2 D5/234548.754
4d 2 D3/234548.789
568.4206 nm568,9768 nm568.9779 nm
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Emission spectrum of sodium
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The orbital angular momenta of the twoelectrons are combined as a vector sumThe spin angular momenta likewise
� Two electrons give a singlet or a triplet state
Many-electron atom: helium
S=0
� � � �S=1 S=1
� � � �
S=1
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0
-1
-2
-3
-4
-5
0
-10000
-20000
-30000
-40000
1 S 1 P 0 1 D 1 F 0 3 S 3 P 0 3 D 3 F 0
1s 2
2s; metastable state
2s2p
2p
3s3s 3p 3d3d3p
4s4s 4p 4d4d 4f4f4p5s
58.4 nm
2058
728
505
668
492
502
1870
1083
389
319707
471588
447
1869
Helium: Two completelyseparate sets of levels, onefor singlet and one for triplet.
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Electron configuration
� E.g., N: (1s)2 (2s)2 (2p)3
Atoms generally
� [J]
-6.81x10-17
-2.47x10-18
-4.12x10-18
1s
2px, 2py, 2pz
2s
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Electronic statesNitrogen atom
E
(1s)2(2s)2(2p)2(3p)
(1s)2(2s)2(2p)3
(1s)2(2s)2(2p)2(3s)
4S
2D
4S
2P
4P2P
2D
4P
4D2S 2P
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The transitions shown here are forbidden.Relativity makes them occur anyway, butthey are quite weak.
Transitions
E
Oxygen3 P 0.0
1 D 15867.7
1 S 33792.4
630 nm
558 nm
E
Nitrogen4 S 0.0
2 D 19223
2 P 28840
520 nm
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Ψ Ψm el m mr s r s( , ) ( ) ( ),
� �= χ
< >=< >< >Ψ Ψ Ψ Ψmel
n el mel
el m m nr s r s r r s s( , )| | ( , ) ( )| | ( ) ( )| ( ), ,
� � � �µ µ χ χ
In non-relativistic approximation the wf ofstate m can be written as
Transition moment
The transition moment is
Thus there is the selection rule S=0.The remaining selection rules can bederived from the spatial transition moment.
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L=0,±1; however not L=0 � L=0i
�
i even � odd or odd � even (Laporte)J=0,±1; however not J=0 � J=0S=0
Selection rulesNon-relativistic theory
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AASLaser ablation (LIBS)ICP-MS (or other detection)
Plasma