Luggage Trolley Design Calculation

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LUGGAGE TROLLEY DESIGN CALCULATION Group members MUHAMMAD ZA’IMUDDIN AMIRUL HAKIM IKHWAN HADI MOHD SHAHRIN MOHAMAD HAFIZAN MOHAMAD HAFIZAN

Transcript of Luggage Trolley Design Calculation

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LUGGAGE TROLLEY DESIGN CALCULATIONGroup membersMUHAMMAD ZA’IMUDDIN AMIRUL HAKIMIKHWAN HADI

MOHD SHAHRINMOHAMAD HAFIZANMOHAMAD HAFIZAN

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Stainless steel X10Cr13

Density,ρ = 7700

Material chosen

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Major plate◦ Length, l = 0.4m◦ Width, w = 0.02m◦ Thickness, t = 0.005m◦ Volume, v = l × w × t

= 0.4m × 0.02m × 0.01m =

◦ Mass, m = v × ρ = )( 7700 )

= 0.616 kg◦ Total mass of two component = 2(0.616 kg)

= 1.232 kg

Base Component

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Minor plate◦ Length, l = 0.3m◦ Width, w = 0.02m◦ Thickness, t = 0.01m◦ Volume, v = l × w × t

= 0.3m × 0.02m × 0.01m =◦ Mass, m = v × ρ

= ( )( 7700 ) = 0. 462 kg Total mass of two component = 2(0.462 kg) = 0.924 kg

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Major pivot joint◦ Length, l = 0.73m◦ Width, w = 0.01m◦ Thickness, t = 0.005m◦ Volume, v = l × w × t

= 0.73m × 0.01m × 0.005m =

◦ Mass, m = v × ρ =( )( 7700 ) = 0.281 kg

◦ Total mass of two component = 2(0.281 kg) = 0.562 kg

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Minor pivot joint◦ Length, l = 0.38m◦ Width, w = 0.01m◦ Thickness, t = 0.005m◦ Volume, v = l × w × t

= 0.38m × 0.01m × 0.005m =

◦ Mass, m = v × ρ = )( 7700 ) = 0.146 kg

◦ Total mass of two component = 2(0.146 kg) = 0.292 kg

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For ,◦ Volume, v = Π( - )0.24 m

=◦ Mass, m = v × ρ

= ( )2700 =0.293 kg For ,

◦ Volume, v = Π( - )0.24 m =

◦ Mass, m = v × ρ = ( )2700 = 0.283 kg Total mass base component = 0.283 kg + 0.293 kg + 0.292 kg

0.562 kg + 0.924 kg + 1.232 kg = 3.586 kg

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Handle Component H-component

◦ Volume, v = Π( - )0.4 m =

◦ Mass, m = v × ρ = ( )2700 = 0.4877 kg

◦ Total mass of two component = 2(0.487kg) = 0.974 kg

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For ,◦ Volume, v = Π( - )0.24 m

=◦ Mass, m = v × ρ

= ( )2700 =0.293 kg For ,

◦ Volume, v = Π( - )0.24 m =

◦ Mass, m = v × ρ = ( )2700 = 0.283 kg Total mass of H-component = 0.283 kg + 0.293 kg + 0.974 kg = 1.55 kg

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Volume, v = Π( - )0.45 m = Mass, m = v × ρ = ( )2700 = 0.535 kg Total mass of two component = 2(0.535kg) = 1.071 kg

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Total mass of handle component = 1.071 kg + 1.55 kg

= 2.62 kg

Total mass overall component = 2.62 kg + 3.586 kg

= 6.206 kg

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Estimate The Center Of The Gravity For The Trolley

In the calculation section, the first step to do is to find the chassis centre of gravity- CG.

The trolley CG will be determined from calculate reaction forces from the rear tyre.

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Estimate the CG

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Calculation

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CG = 0.3906m

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FREE BODY DIAGRAM OF THE TROLLEY

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Reaction Force

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Shear And Moment Diagram

Maximum moment = 104.31 Nm

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Maximum Stress

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Factor of Safety

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The deflection at the base of the trolley were determine by using the finite element.

Design deflection

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E=20,000MPa KQ=F

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the deflection of the trolley

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During the fabrication process some minor change had been done on the design that been calculated cause of

a) Lack of equipmentb) Hard to fabricatec) un stabile design

Fabrication proces

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Fabrication process

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Trolley Handle

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Trolley tyre

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Trolley body

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Expand and compressed system at the trolley body

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Milling process at the trolley body

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Welding process at several joint

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Unfinished yet trolley

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That’s all folks

Q & A