Lecture 3 Isomerism. STRUCTURE CHANGE (ISOMERIZATION) and CONFORMATION CHANGE COMPOSITION C k H l O...
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Transcript of Lecture 3 Isomerism. STRUCTURE CHANGE (ISOMERIZATION) and CONFORMATION CHANGE COMPOSITION C k H l O...
STRUCTURE CHANGE (ISOMERIZATION) and CONFORMATION CHANGE
COMPOSITIONCkHlOm
STRUCTURE 1 STRUCTURE 2 STRUCTURE 3Reaction 1→2 Reaction 2→3
HC
H
O
C O
HH
C O
H
H
C O
H
H
3n-6=12-6=6
A molecule may change its structure without bound breaking and with bound breaking. The former one leads to different
conformers the latter change produces isomers. If σ-bounds are broken then we may have structural isomers and if π-bounds are
broken then we may have geometrical isomers.
Geometrical Isomers Structural IsomersConformers
CO2 + H2O
C + H2 + O2
A̶ 2706.6
A̶ 2709.8
A̶ 3.2A̶ 3.8
A̶ 2877
A̶ 125
A̶ 2875
A̶ 3000
A̶ 134
9
C C
H
CH3
H3C
H
C C
CH3
H
H3C
H
C C
CH3
H
CH3
H
HH
C C
H
CH3
H3C
H
H
H
C C
HCH3
H
H3C
HH
CO2+H2O CO2+H2O
Δ‡H=
ΔcH=
7. 4 Relative Stabilities of Alkenes
CH2
H
CH2H3C
H
H3C
H
CH3
H
H3C
CH3
H
1 .0
1 .7
-3 0 .3 -2 8 .6 -2 7 .6
CH3
CH2CH2
CH3
H
Figure 7.3 Enthalpies (DH) of hydrogenation (in units of Kcal/mol) for the isomeric n-butenes.
Figure 7.3 shows the heats or enthalpies of hydrogenation of three isomeric butenes. The enthalpies of hydrogenation are a measure of the molecular stabilities of unsaturated
hydrocarbons.
Two things should be noted: 1) Disubstituted carbon-carbon double bonds (at the middle and right hand
side of Figure 7.3) are more stable than mono-substituted olefinic double bonds.
2) The trans isomer (at the extreme right in Figure 7.3) is more stable than the cis isomer.
In Chapter 4, we saw that the stabilities of isomeric saturated hydrocarbons (CnH2n+2) can be assessed from their heat or enthalpy of combustion (c.f. Figure 4.2). In this chapter, we see that the heat or enthalpy of hydrogenation may be used to measure the stability of unsaturated hydrocarbons (CnH2n), as shown in Figure 7.3.
The results of these two methods can be put together, as illustrated for cis - and trans - 2 - butene and n - butane in Figure 7.4. As far as stabilities are concerned, the greater the substitution, the more stable the alkene. Of the disubstituted cases, 1,1 - disubstituted ethylene is more stable than 1,2-disubstituted ethylene. For the latter, the trans - isomer is more stable than the cis - isomer. These stabilities are presented in Figure 7.5 in terms of enthalpies of hydrogenation in a schematic fashion.
Figure 7.4 Comparison of enthalpies of formation, enthalpies of
hydrogenation and enthalpies of combustion for selected
hydrocarbons.
Me
Me
Me
MeMe
Et
Me
H Et
Et
H
HH
Et
Et
HH
Et
H
EtH
n -Bu
H
H
H
Figure 7.5 A schematic illustration of the relative stabilities of olefinic double bonds with the extent of substitution as measured by the enthalpies of
hydrogenation.
One may wonder if an alkyl substitution on an olefinic double bond can be carried out that will make it more stable. The answer lies in the concept of hyperconjugation.
We saw in Chapter 1 that conjugation of two carbon-carbon double bonds leads to stabilization (c.f. [1.42] and Figure 1.28). We can now assess the magnitude of such conjugative
stabilization to be of a few Kcal/mol. The example in Figure 7.6 shows the stabilization for butadiene to be 3.5 Kcal/mol.
2 C H2=C H–C H2–C H3 + 2 H2C H3–C H2–C H2–C H3
+C H2=C H–C H2=C H2 + 2 H2
-3.5 kcal/mol
-57.1 kcal/mol-60.6 kcal/mol
2 C H3–C H2–C H2–C H3
Figure 7.6 Conjugative stabilization (-3.5 Kcal/mol) of 1, 3 - butadiene with respect to two moles of 1-butene as measured by the difference in enthalpies of hydrogenation.
The structural isomerism requires a large initial energy input even though the energy is recovered at the end of the reaction.
Clearly this is not a spontaneous isomerization.„Tautomers” represent a special structural isomers which earn be formed quite easily without large energy investment. The two isomers differ from each other only in the position of a proton.
C C
C C
C C
C +CH3
+H C C
C H
CH3
0 Appr. 650 kJ/mol 9kJ
The ketoo-enol tautomerization is formed easily with acid catalysis.
CC
O
CC
O
O
H
C
C
OH
O
H
H
O
H
C
C
OH
O H
H
In general, most chemical reaction starts with a complex formation which is called the REACTANT COMPLEX. Usually the in
the pen-ultimate step a PRODUCT COMPLEX is formed. These two coplexes separated by a transition state (TS) as shown
below.
A + B → A···B → [TS]± → C···D → C + DReactants Reactant
ComplexTransition
StateProductComplex
Products
A schematic energy change is shown below
A+B A···B TS C···D C+DReaction
Coordinata
Ener
gy o
r Fre
e En
ergy
Product complex
Reactant complex
This situation dominantly occur in biological reactions which involve specific enzyme.
The first step is the ENZYME-SUBSTRATE complex formation which is converted via a TS to an ENZYME-PRODUCT comlex. The assiciated energy
profile and mechanistic equation is analogons to the shown below.
The following figure shows a bacterial enzyme which is able to oxidise CH4 to H3C-OH. The figure also shows the ENZYME-PRODUCT comlex. Since the H
atoms are not shown H3C-OH is shown in the the complex as C-O.
A given molecular structure, such as C4H6 has numerous isomers, as few of them are illustrated below.
They may have numerous molecular fragments some of them a complete organic molecules while some of them contein two valent carbons, called carbenes.
CH3 CH3
H C C H CH
H
CH
H
CH4
+
C C
+
C
Nevertheless the potential energy surface associated with the particular chemical composition (like C4H6) does contain all these entities as local minimum.
1 2 3( , , ,... )DE f x x x x
k l m nC H N O
3 6D N
N k l m n
The function of the total PEHS is:
If the number of atoms have the following form:
The degrees of freedom (D) of the system given of N number of atoms:
where the N is:
The number of stretches, bends and the torsion add up to 3N-6.
1 2 3 2 3 2 2 3 6( , , ,... , ... )
reaction conformationalsubspace subspace
N N NE f x x x x x x
F + C Cl
H
H H
H
Et
Cl
MeH
Et
Cl
Me
H
2
1
3
H
2
1
3
S-isomer
clockwisecounterclockwise
R-isomer
H
Me
Et
Cl H
Me
Et
Cl
R S
R S
R S
RS
enantiomers
diastereomers
enantiomers
Me
Et
H
ClH
Cl
Me
Et
Cl
HCl
H
Me
Cl H
Et
H Cl
Me
H Cl
Et
Cl H
mirror
Me
Et
H
HCl
Cl
Me
Et
Cl
ClH
H
Me
Cl H
Et
Cl H
Me
H Cl
Et
H Cl
mirror
Me
Me
H
FH
F
Me
Me
F
HF
H
Me
F H
Me
H F
Me
H F
Me
F H
mirror
Me
Me
H
HF
F
Me
Me
F
FH
H
Me
F H
Me
F H
Me
H F
Me
H F
mirror
mirror
mirror
RR
SS
RS
SR
=
enantiomeric pair meso-structure
Y
R H· H
Y
R · R H
Y·Y
R H·
H
Y
R · R H
Y
·Y
R H·
0o 60o 120o 180o 240o 300o 360o
-360o -300o -240o -180o -120o -60o -0o
Y
H R· R
Y
H · H R
Y·Y
H R·
R
Y
H · H R
Y
·Y
H R·
clockwise
counter clockwise
R-enatiomer
S-enatiomer