Lecture 20: Rotational kinematics and...
Transcript of Lecture 20: Rotational kinematics and...
โข Angular quantities
โข Rolling without slipping
โข Rotational kinetic energy
โข Moment of inertia
โข Energy problems
Lecture 20:
Rotational kinematics and energetics
Angle measurement in radians
๐(in radians) = ๐ /๐
s is an arc of a circle of radius ๐
Complete circle:
๐ = 2๐๐ , ๐=2๐
Angular Kinematic Vectors
Position: ฮธ
Angular displacement:
ฮฮธ = ฮธ2 โ ฮธ1
Angular velocity:
ฯ๐ง =๐ฮธ
๐๐ก
Angular velocity vector
perpendicular to the plane of
rotation
Angular acceleration
ฮฑ๐ง =๐ฯ๐ง๐๐ก
Angular kinematics
For constant angular acceleration:
๐ = ๐0 + ๐0๐ง๐ก +1
2๐ผ๐ง๐ก2
๐๐ง = ๐0๐ง + ๐ผ๐ง๐ก
๐๐ง2 = ๐0๐ง
2 + 2 ๐ผ๐ง ๐ โ ๐0
๐ฅ = ๐ฅ0 + ๐ฃ0๐ฅ๐ก + ยฝ๐๐ฅ๐ก2
๐ฃ๐ฅ = ๐ฃ0๐ฅ + ๐๐ฅ๐ก
๐ฃ๐ฅ2 = ๐ฃ0๐ฅ
2 + 2๐๐ฅ(๐ฅ โ ๐ฅ0)
Compare constant ๐๐ฅ:
Relationship between angular and linear motion
๐๐๐๐ =๐ฃ2
๐= ๐2 ๐
Angular speed ๐ is the same for all points of a rigid
rotating body!
๐ฃ =๐๐
๐๐ก=๐
๐๐ก๐๐ = ๐
๐๐
๐๐ก
linear velocity tangent to circular path:
๐ฃ = ๐๐
๐ distance of particle
from rotational axis
๐๐ก๐๐ = ฮฑ๐
Rolling without slipping
Translation of CMRotation about CM
If ๐ฃ๐๐๐ = ๐ฃ๐ถ๐: ๐ฃ๐๐๐ก๐ก๐๐ = 0 no slipping
๐ฃ๐ถ๐ = ๐๐
Rolling w/o slipping
Rotational kinetic energy
๐พ๐๐๐ก๐๐ก๐๐๐ = โยฝ๐๐๐ฃ๐2 = โยฝ๐๐ (ฯ๐๐๐)
2
= โยฝ๐๐ (ฯ ๐๐)2 = ยฝ [ โ๐๐๐๐
2] ๐2
๐ผ =
๐
๐๐๐๐2
Moment of inertia
๐พ๐๐๐ก = ยฝ ๐ผ๐2
with
Moment of inertia
๐ผ =
๐
๐๐๐๐2
๐๐ perpendicular distance from axis
Continuous objects:
๐ผ =
๐
๐๐๐๐2โถ ๐2๐๐
Table p. 291* No calculation of moments of inertia
by integration in this course.
Properties of the moment of inertia
1. Moment of inertia ๐ผ depends upon the axis of
rotation. Different ๐ผ for different axes of same object:
Properties of the moment of inertia
2. The more mass is farther from the axis of rotation,
the greater the moment of inertia.
Example:
Hoop and solid disk of the same radius R and mass M.
Properties of the moment of inertia
3. It does not matter where mass is along the
rotation axis, only radial distance ๐๐ from the axis
counts.
Example:
๐ผ for cylinder of mass ๐ and radius ๐ : ๐ผ = ยฝ๐๐ 2
same for long cylinders and short disks
Parallel axis theorem
๐ผ๐ = ๐ผ๐๐||๐ +๐๐2
Example:
๐ผ๐ =1
12๐๐ฟ2 +๐
๐ฟ
2
2
=1
12๐๐ฟ2 +
1
4๐๐ฟ2 =
1
3๐๐ฟ2
Rotation and translation
๐พ = ๐พ๐ก๐๐๐๐ + ๐พ๐๐๐ก = ยฝ๐๐ฃ๐ถ๐2 + ยฝ ๐ผ๐2
๐ฃ๐ถ๐ = ๐๐ with
Hoop-disk-race
Demo: Race of hoop and disk down incline
Example: An object of mass ๐, radius ๐ and
moment of inertia ๐ผ is released from rest and is
rolling down incline that makes an angle ฮธ with the
horizontal. What is the speed when the object has
descended a vertical distance ๐ป?