Laborator 3 SS

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Laborator 3 SS Analiza semnalelor aperiodice cu ajutorul Transformatei Fourier Spectre de amplitudini si de faze 1. Generalitati: Transformata Fourier directa a unui semnal aperiodic este definita astfel: Transformata Fourier inversa este definita : Proprietati ale Transformatei Fourier folosite in acest laborator: a.) X(ω) este o functie continua, iar b.) Schimbarea de scara: c.) Teorema deplasarii in timp: Semnalele analizate in prezentul laborator sunt : 1. x(t) Cu cele doua cazuri : - x 1 (t), A>0 (A= +1) - x 2 (t), A<0 (A= -1) Page 1 of 21

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Transcript of Laborator 3 SS

Laborator 3 SSAnaliza semnalelor aperiodice cu ajutorul Transformatei Fourier

Spectre de amplitudini si de faze

1. Generalitati:

Transformata Fourier directa a unui semnal aperiodic este definita astfel:

Transformata Fourier inversa este definita :

Proprietati ale Transformatei Fourier folosite in acest laborator:

a.) X(ω) este o functie continua, iar

b.) Schimbarea de scara:

c.) Teorema deplasarii in timp:

Semnalele analizate in prezentul laborator sunt :

1. x(t)

Cu cele doua cazuri :- x1(t), A>0 (A= +1)- x2(t), A<0 (A= -1)

2. y(t)

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2. Analiza semnalului x(t) utilizand transformarea Fourier:

Se va construi schema electrica:

Semnalul generat de sursa de tensiune este x(t) (impuls dreptunghiular de latime τ

si amplitudine A)

Stiind ca transformata Fourier a lui x(t) este:

Sa se determine* spectrele de amplitudini si de faze( ),

spectrele de amplitudini ale partii reale si partii imaginare ( X(ω)=Re{X(ω)} + j Im{X(ω)}) si spectrul de energie pentru urmatoarele cazuri:

(2.1) A = 1 τ = 10m(2.2) A = 10 τ = 10m(2.3) A = 1 τ = 20m(2.4) A = -1 τ = 10m

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(2.5) A = -1 τ = 20m

Energia semnalului are urmatoarea expresie:

Folosindu-se valorile de la punctul (2.1) pentru A si τ se va lua pentru analiza si cazul (2.6) cu semnalul intarziat cu 20ms. Se vor determina cele 5 spectre si pentru cazul (2.6). Intarzierea semnalului se va realiza utilizand componenta IDEAL TIME DELAY

(2.7) I se va impune un prag de 4% (din valoarea amplitudinii pentru f=0) si in functie de acest prag se vor determina banda semnalului Bs si banda energetica Be. In Bs sau Be se vor regasi toate componentele cu aplitudinea mai mare decat 0.04Aτ

3. Se va analiza semnalul y(t) format din doua semnale x(t) (τ=10ms; A=1; T=20ms)

*Se va utiliza analiza: Analysis – Fourier Analysis – Fourier Spectrum unde se va tine cont de faptul ca functia sinc(ωτ/2) se anuleaza pentru f=k/τ

Cunascandu-se faptul ca transformata Fourier a unui tren de impulsuri dreptunghiulare (n impulsuri) este urmatoarea :

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Unde

si

Se vor determina cele 5 spectre (analog punctului 2) pentru semnalul y(t) format din doua impulsuri dreptunghiulare. Schema electrica va contine doua surse de semnal identice, circuitul de intarziere, o sursa de tensiune comandata in tensiune si doua rezistoare de sarcina.

4.Continutul referatului

4.1. Platforma de laborator (prezentul document)4.2. Schemele electrice si formele de unda ale semnalelor analizate (la punctele 2

si 3).4.3 Cerintele punctului 2 (2.1 – 2.7) precum si concluziile ce se pot desprinde la

analizarea spectrelor abtinute ( modificarile ce apar in spectre la modificarile survenite asupra amplitudinii, latimii impulsului si momentului de aparitie)

4.4. Cerintele punctului 3 (analog cu cerintele punctului 2)4.5. Concluzii generale (transformata Fourier si analiza spectrala)4.6. Data limita de predare/prezentare a referatului este data efectuarii lucrarii de

laborator nr. 4.

Exercitiul 2:

2.1

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2.2 T

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-spectrul de energie-

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Exercitiul 3:

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