Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C...

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Heat Integration Chapt. 10

Transcript of Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C...

Page 1: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Heat Integration

Chapt. 10

Page 2: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Costs

• Heat Exchanger Purchase Cost– CP=K(Area)0.6

• Annual Cost– CA=im[ΣCp,i+ ΣCP,A,j]+sFs+(cw)Fcw

• im=return on investment• Fs= Annual Flow of Steam,

– $5.5/ston to $12.1/ston

• Fcw=Annual Flow of Cold Water– $0.013/ston

Page 3: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Lost Work = Lost Money

• Transfer Heat from T1 to T2

• ΔT approach Temp. for Heat Exchanger

• To= Temperature of Environment

• Use 1st and 2nd laws of Thermodynamics

• LW=QToΔT/(T1T2)

T1

T2

Q

Page 4: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Minimize UtilitiesFor 4 Streams

Page 5: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Simple HEN

Page 6: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Adjust Hot Stream Temperatures to Give ΔTmin

Page 7: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Enthalpy Differences for Temperature Intervals

Page 8: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Interval Heat Loads

Page 9: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Pinch Analysis

Minimum Utilities

Page 10: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Pinch Analysis

Page 11: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.
Page 12: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

4 Heat ExchangerHEN for Min. Utilities

Page 13: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Minimum Utilities HEN

Page 14: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Too Many Heat Exchangers

• Sometimes fewer Heat exchangers and increased utilities leads to a lower annual cost

• NHx,min= Ns + NU - NNW

– No. streams– No. discrete Utilities– No. independent Networks (1 above the pinch, 1 below the

pinch

• Solution to Too Many Heat Exchangers– Break Heat Exchanger Loops– Stream Splitting

• Attack small Heat Exchangers First

Page 15: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Break Heat Exchanger Loops

Page 16: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Example

Page 17: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Change ΔTmin

CP=K(Area)0.6

Area=Q/(UF ΔTmin)

Page 18: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Distillation Columns

Page 19: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Position a Distillation Column Between Composite Heating and

Cooling Curves

Page 20: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Heat Integration

Page 21: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

Multi-effect DistillationAdjust Pressure in C2 for ΔTmin

Page 22: Heat Integration Chapt. 10. Costs Heat Exchanger Purchase Cost – C P =K(Area) 0.6 Annual Cost –C A =i m [ΣC p,i + ΣC P,A,j ]+sF s +(cw)F cw i m =return.

• Heat Pumps in Distillation