Formulario cuantica 2
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Transcript of Formulario cuantica 2
Abraham Prado A01213521
∫|Ψ(x, t)|2 Φ(p, t) = 1√
2π~
∫∞−∞ e
−ipx~ Ψ(x, t)dx [f(x), p] = i~ dfdx L± ≡ Lx ± iLy
[Lx, Ly] = i~Lz [Ly, Lz] = i~Lx
[Lz, Lx] = i~Ly i~ ∂∂tΨ(ξ, t) =
(− ~
2m∇2 + V (ξ)
)Ψ(ξ, t) = EΨ(ξ, t)
ψn(x) =√
2L sin(nπxL );En = π2~2n2
2mL2 ψ0(x) =(mωπ~) 1
4 e−mωx2
2~ ;E0 = 12~ω [x, p] = i~
ax =√
mω2~(x+ i
mω px)
a†x =√
mω2~(x− i
mω px) [
ax, a†x
]= 1
〈f〉 =∫
Ψ(r, t)fΨ(r, t) = 〈Ψ|f |Ψ〉 j = − i~2m (Ψ∗∇Ψ−Ψ∇Ψ∗)
ρ(r, t) = Ψ∗(r, t)Ψ(r, t) p = ~k V (x) = 12mω
2x2 〈H〉 = 〈p2〉2m
〈x〉 =∫∞−∞ xρ(x)dx =
∫∞−∞ x |Ψ(x, t)|2 dx 〈T 〉 = − ~2
2m∫∞−∞Ψ∗ ∂
2Ψ(x,t)∂x2 dx
Ψ(x, t) =∑∞n=1 cnψ(x)e−
iEnt~
cn =∫ψn(x)∗f(x)dx cn =
√2a
∫ a0 sin(nπa x)Ψ(x, 0)dx 〈H〉 =
∑∞n=1 |cn|
2En =
∫Ψ(x, 0)∗HΨ(x, 0)dx
ψn(x) =(mωπ~) 1
4 1√2nn!Hn(ξ)e−
ξ22
|S(t)〉 = e−iE1t
~ |s1〉 |S(0)〉 =∑cn|sn〉
σ2P = 〈p2〉 − 〈p〉2 ci = 〈φi|ψ〉.∫x sin ax dx = sin ax
a2 − x cos axa
∫xn sin ax dx = −x
n
a cos ax+ na
∫xn−1 cos ax dx∫
x cos ax dx = cos axa2 + x sin ax
a + C∫xn cos ax dx = xn sin ax
a − na
∫xn−1 sin ax dx∫
sin b1x sin b2x dx = sin((b1−b2)x)2(b1−b2) − sin((b1+b2)x)
2(b1+b2)∫
sinn ax dx = − sinn−1 ax cos axna + n−1
n
∫sinn−2 ax dx∫
cosn ax dx = cosn−1 ax sin axna + n−1
n
∫cosn−2 ax dx
∫cos a1x cos a2x dx = sin(a1−a2)x
2(a1−a2) + sin(a1+a2)x2(a1+a2) + C
φ(x) =√mα~ e−mα|x|/~
2 ; E = −mα2
2~2
Φ(x, t) = 1√2π
∫∞−∞ φ(k)ei(kx−ωt)dk
ω =(
~k2
2m
)φ(k) = 1√
2π
∫∞−∞ e−ikxΨ(x, 0)dx
Φ(x, t) = 1√2π
∫∞−∞ ei(kx−
~k22m t)ψ(k)dk
pdav =√
2meqe |∆V |
λ = hmv
nλ = 2πr
hν = − me4
8ε20h
2
[ 1n2 − 1
m2
]K = mH2OCp∆T1−mH2OfrCp∆T2
∆T2
−Q = mCp∆T +Kcal∆T
∆T1 = Tmezcla − TH2Ocal
1
λ =√
2m(V0−E)~2
k =√
2mE~2
tan zz = tanh
√α2−z2
√α2−z2
si = −soMTds1ds0
= − −f2
(s0−f)2
2πλ ∆L.C.O. =
ψnlm = Rnl(r)Y ml (θ, φ)
Rnl(r) = −{(
2Zna0
)3 (n−l−1)!2n[(n+l)!]3
}(1/2)e−ρ/2ρlL2l+1
n+1 (ρ)
En = −Z2e2
2n2a0
〈rk〉 ≡∫∞
0 drr2+k[Rnl(r)]2
Y ml (θ, φ) = (−1)m√
2l+14π
(l−m)!(l+m)!P
ml (cos θ)eimφ
Pml (cos θ) = (1− cos2 θ)m/2 dm
d(cos θ)mPl(cos θ)
T = 1{1+[(k′2−k2)/4k2k′2] sin2 2k′a}
k =√
2mE~2
k′ =√
2m(E+V0)~2
T = 1{1+[(k2+κ2)2/4k2κ2] sinh2 2κa}
k =√
2m(−|E|+V0)~2
κ =√
2m|E|~2
T = 4kk′(k+k′)2
k =√
2mE~2
k′ =√
2m(E−V0)~2
T = exp
{−2∫ badx√
2m[V (x)−E]~2
}m d2
dx2 〈x〉 = −〈∇V (x)〉
exp(−iHt
~)
=∑K′ |K ′〉 exp
(−iEK′ t
~
)〈K ′|
|α, t0 = 0; t〉 = |a′〉 exp(−iEa′ t
~
)wa′′a′ = (Ea′′−Ea′ )
~
w = |e|Bmec
H|±〉 =(±~w
2)|±〉
〈x′|n〉 =(
1π1/4√
2nn!
)(1
xn+1/20
)(x′ − x2
0d
dx′)n exp
[− 1
2
(x′
x
)2]
x0 ≡√
~mω
L =√l(l + 1)~
S =√s(s+ 1)~
2
x′ = x−ut√1−u2/c2
t′ = t−(u/c2)x√1−u2/c2
v′x = vx−u1−vxu/c2 v′y = vy
√1−u/c2
1−vxu/c2
∆t′ = uL/c2√1−u2/c2
K = mc2√1−v2/c2
−mc2
p = mv√1−v2/c2
E =√
(pc)2 + (mc2)2
cn =( 2n+1
2) (n−m)!
(n+m)!∫ 1−1 f(z)Pmn (z)dz
Cn,m =∫ 2πϕ=0
∫ πθ=0 g(θ, ϕ)[Y mn (θ, ϕ)]∗ sin θdθdϕ
x = r√
2π3 (Y −1
1 − Y 11 ) y = ir
√2π3 (Y −1
1 + Y 11 ) z = r
√4π3 (Y 0
1 )
[Lx, Ly] = ~Lz[Li, Lj ] = ~εijkLk[L2, Li] = 0.
L± = Lx ± iLy [L2, L±] = 0
L±Ylm = ~√l(l + 1)−m(m± 1)Yl(m±1)
|L| =√l(l + 1)~
L2 = L+L− + L2z − ~Lz
[L+, L−] = 2~Lz
J+|j,m〉 =√j(j + 1)−m(m+ 1)~|j,m+ 1〉
J2 = J2x + J2
y + J2z
L2fmin = ~2[−l(−l − 1)]fmin
a = bmin(bmin − ~)
J+|a, bmax〉 = 0
[H,Lz] = 0
Lz = ~i
(x ∂∂y − y
∂∂x
)= ~
i∂∂ϕ
L± = ~e±iφ(± ∂∂θ + i cot(θ) ∂
∂φ
)Lx = L++L−
2
Ly = L+−L−2i
〈ψ|Lx|ψ〉
L+Yll = 0 [Li, r2] = [Li, p2] = [Li, r · p] = 0
L−Yl−l = 0 −l ≤ m ≤ l
Lzfml = ~mfml
L±fml = ~
√(l ∓m)(l ±m+ 1)fm±1
l
3
L2 = −~2[
1sin θ
∂∂θ
(sin θ ∂∂θ
)+ 1
sin2 θ∂2
∂φ2
][Li, rj ] = i~
∑k εijkLk
[Li, pj ] = i~∑k εijkpk∣∣∆k
k
∣∣� 1
4