Experimental Techniques for Nuclear and Particle …If the energy is deposited by a particle passing...
Transcript of Experimental Techniques for Nuclear and Particle …If the energy is deposited by a particle passing...
Basic detector principles and counting statistics
Experimental Techniques for
Nuclear and Particle Physics
Statistical models of signal generation –short review
The binomial distribution
( )∑ −=−=
=
−⎟⎟⎠
⎞⎜⎜⎝
⎛=−
−= −−
)1()(
)1()1(!)!(
!)(
22 pnpxPxx
pnx
ppxn
ppxxn
nxP xnxxnx
σ
Roll a die Success=3,4,5 or 6
P=4/6 N=10
The Poisson distribution
( )
xpnx
xexxPxx
=
=
=−
2
)(!
)(
σ
Birthday today P=1/365 N=1000
The distribution of times between successive events
A detector detects a reaction rate, rAn event has ocurred at time t = 0 Then the distribution function to describe the time intervals between adjacent random events is:I(t)dt = P(0)rdtThen the probability to have no events during the time t is:
P(0) =rt( )0 e−rt
0!= e−rt
The probability to have the next event in the time period dtI(t)dt = P(0)rdt = re−rtdt
The Gaussian distribution
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σ
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The Chi-squared distribution χ 2 =
1xe
xi − xe( )2=
(N −1)s2
xei=1
N
∑
(where xe =1N
xi and s2 =1
N −1i=1
N
∑ xi − xe( )2
i=1
N
∑ )
The degree to which χ 2 differs from N -1 is a measure of the departure of the data from thepredictions of the Poisson model. Set χ 2 = u, then it can be shown that:
P(u)du =u / 2( ) ν /2( )−1 exp(−u / 2)
2Γ(ν / 2)du
µ =ν, σ 2 = 2ν
The Chi-squared distribution χ 2 =
1xe
xi − xe( )2=
(N −1)s2
xei=1
N
∑
(where xe =1N
xi and s2 =1
N −1i=1
N
∑ xi − xe( )2
i=1
N
∑ )
The degree to which χ 2 differs from N -1 is a measure of the departure of the data from thepredictions of the Poisson model.
The reduced χ 2 is defined as:
χ 2red =
χ 2
ν(where ν = N-1 is the number of degress of freedom)which should be close to 1 for a good fit
Maximum likelihood method - how to estimate the parameters of a probabilistic
model from measured data
L(θ, x) = f (θ, x1) f (θ, x2 ) f (θ, x3) f (θ, x4 )... f (θ, xn )is the probability for observing the sequence of valuesx1,...xnThe maximum likelihood principle states that this probability is maximumfor the observed values. Then:dLdθ
= 0 ⇒ θ̂, the estimator for the parameter θ.
Alternatively one can solve d(lnL)dθ
= 0
The uncertainty in θ̂ is given by σ 2 (θ̂ ) = − d 2 lnLdθ 2
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−1
The method works if the form of the theoretical distribution is known. If the theoretical distribution is f(θ,x), where x is the observable for which independent measurements are made then:
Error Propagation
Standard deviation follows the Error propagation formula:
x, y, z… independent variables
u: quantity to be obtained from the data:
Mean value of multiple measurements (Poisson statistics)
Σ = xi σ Σ2 = σ xi
2
i=1
N
∑i=1
N
∑
σ xi= xi ⇒σ Σ
2 = xi = Σ ⇒i=1
N
∑ σ Σ = Σ
x = ΣN⇒ σ x =
NxN
=xN
The standard deviation expected for the sum of all the counts is the same as if the measurement had been carried out by performing a single count extended over the entire period.
σ xi= xi
σ x =NxN
=xN
The mean value based on N independent counts will have an smaller error compared with any single measurement
Combination of multiple measurements with unequal errors
What is the best value for a given measured quantity if N measurementshave been made, each with a different uncertainty?Each measurement is given a weight, ai.
Then the weighted mean becomes: xopt=
aixii=1
N
∑
aii=1
N
∑
aj =1σ x j
21σ xi
2i=1
N
∑"
#$$
%
&''
−1
(here aj are normalized)
1σ x
2 =1σ xi
2i=1
N
∑ Each data point should be weighted inversely as the square of its own error.
ai should be chosen to minimize the error
Optimization of Counting experiments The principle of error propagation can be applied in the design of counting experiments to minimize the associated statistical uncertainty.
Example: S: counting rate due to the source alone without background B: counting rate due to background
N1 and N2 are the total counts in each measurement
Optimum time:
Detector energy resolution: Response function for different detectors
Full Width at Half Maximum of the peak (FWHM) = 2.35 σ
Resolution = ΔE/E
H0 = KN σ = KN1/2
K: proportionality cte
Detector energy resolution: The Fano factor
When the energy of incoming radiation is measured in a detectorthe signal is typically formed by a large number of charge carriers or photons.If the energy is deposited by a particle passing through the detector the fluctuationsare given by the Poisson distribution: i.e. σ 2 = J, where J is the number of charge
carriers or photons (E /w) and the energy resolution is: R = 2.35 JJ
But if the full energy is absorbed the fluctuations can be limited since the ionisation eventsthen are not independent. Then σ 2 = FJ, where the Fano factor F is a number less than 1.Different materials have different Fano factors.The energy resolution is given by:
R = 2.35 FJJ
= 2.35 FwE
,
where w is the energy needed to produce one charge carrier or photon.For germanium detectors, F is typically around 0.1 whereas scintillators have F ≈1.
Detector energy resolution: The Fano factor
The Fano factor for Ge detectors is about 0.12 and the energy needed to create a pair e-h at 77K is 2.96 eV. Which will be the resolution for 1.33 MeV γ rays?
R = AEE
= 2.35 FwE
= 2.35 0.12*2.961.33*106
= 0.12%
Detector energy resolution:
NaI ≈ 9% Ge ≈ 0.1 %
Scinitillator & HPGe detector
Detector dead time
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Limits of Detectability Detection limit: Smallest signal that can be detected reliably
Minimum detectable activity (MDA) is defined as three standard deviations of the background count rate where the sample is counted for the same period of time
Activity: Rate at which a source of unstable nuclei decays measured in decays per second (1Bq=1 decay per second)
Rb: backg. count rate (cpm) Tb: backg. counting period (m) γ: correction factor
Limits of Detectability
Fukhusima accident: 11/03/2011
The radioactivity of the aerosol particles after the Fukushima Daiichi nuclear power plant accident in Tsukuba, Japan
Limits of Detectability
Fukhusima accident: 11/03/2011
Gamma ray spectra of particles in Seattle´s air (31/03/2011)
Examples
Solution:
Solution:
Solution:
Solution:
Solution:
Solution:
Solution:
E.g. solve graphically à n = 2.0 MHz or 120 kHz
Example: pulse shaping of a semiconductor detector
0 1000 2000 3000 4000 50000
0.2
0.4
0.6
0.8
1Preamp response
-1000 0 1000 2000 3000 4000 5000-1
-0.5
0
0.5
1
Amplifier response
0 500 1000 1500 20000
5
10
15
20x 10-3 Raw signal
0 1000 2000 3000 4000 5000 60000
0.2
0.4
0.6
0.8
1
time, ns
Preamp signal
0 1000 2000 3000 4000 5000 6000-400
-200
0
200
400
600
800Amplifier signal
ADC methodologies Peak sensing – maximum voltage
Charge sensing – integrated current
Wave-form digitization
ADC techniques - Ramp / Wilkinson: time-based techniques (capacitor based)
- Successive approximation: comparator-DAC system (reference voltages)
- Flash ADC (direct conversion)
“Digitizing” the magnitude of a detector pulse:
Analogue to digital Converters (ADCs)
Direct conversion (Flash) ADC
“Digitizing” the time of arrival of detector pulse wrt a reference signal:
Time to digital Converters (TDCs)