Exercises of course ELEC0029 Power flow computation and...
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Exercises of course ELEC0029
Power flow computation and sensitivity analysisin a simple system
T. Van Cutsem
February 2018
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System data
Lines data
UN (kV) X (/km) X/R C/2 (S/km) SN (MVA) km
380 0.3 10 1.5 1350 50150 0.4 5 1.2 300 50
Transformers data
orig extr R (pu) X (pu) B (pu) SN (MVA) n (extr side)
A B 0 0.14 0 500 1.08F B 0 0.14 0 250 1.08D B 0 0.14 0 300 1.00E C 0 0.14 0 600 1.00
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Operating point data
I generators:I voltage at bus A: 15 kVI voltage at bus F: 15 kVI production of F: 150 MW
I loads:I at bus E: 400 MW / 120 MvarI at bus D: 100 MW / 30 Mvar
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I Specify the data at all buses and run a power flow computation todetermine the electrical state of the system. In this computationassume that transformers D-B and E-C are of Yd11 type, and takeinto account the phase angle of their transformer ratios.
The data are available in the file 6bus.dat, while the results can bedisplayed on the one-line diagram by using the file 6bus.svg
I Detail the active and reactive power balances of the system.
I Check that line D-E and transformer C-E operate below theirthermal ratings.
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Transformers D-B et E-C of type Yd11; complex ratios
150 kV
380 kVpuissances ractives (Mvar)
puissances actives (MW)
D E
A
B
C
modules tensions (pu)15 kV phases tensions (deg)
F
0.9912
1.0000
106
14
53
14
54
352
163
348
128347
137
154
56
1.0363
1.0134
1.0194
347
5.9 7.8
20.2
0.0
100
30
1.0000
150
79
0.9
400
120
17.6
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I Simulate the misuse of a transformer E-C of type Yy0, whiletransformer D-B is of type Yd11. Show that the resulting electricalstate is unacceptable.
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Transformer D-B of type Yd11 and E-C of type Yy0
150 kV
380 kVpuissances ractives (Mvar)
puissances actives (MW)
D E
A
B
C
modules tensions (pu)15 kV phases tensions (deg)
F
0.9205
1.0000
207
87
310
20
332
372
296
90
20690
221
432
147
0.9967
0.9495
0.9732
90
6.5 6.9
11.2
0.0
100
30
1.0000
150
145
1.3
400
120
8.3
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I Getting back to the correct configuration of the transformers,perform a new power flow computation in which the phase angles ofthe transformer ratios are set to zero. Comment on the resultsobtained.
Unless otherwise specified, the phase angles are neglected in thesequel.
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Phase angles of transformer ratios neglected
150 kV
380 kVpuissances ractives (Mvar)
puissances actives (MW)
D E
A
B
C
modules tensions (pu)15 kV phases tensions (deg)
F
12.4
0.9912
1.0000
106
14
53
14
54
352
163
348
128347
137
154
56
1.0363
1.0134
1.0194
347
5.9 7.8
9.8
0.0
100
30
1.0000
150
79
0.9
400
120
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I Assuming that transformer D-B is equipped with a phase shiftingdevice allowing to vary progressively the phase angle of itstransformer ratio, study the impact of this phase angle on branchpower flows and bus voltage magnitudes.
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Varying the phase angle of the ratio of transformer D-B
10 for E-C and 1 for D-B. Example for = 10.
150 kV
380 kVpuissances ractives (Mvar)
puissances actives (MW)
D E
A
B
C
modules tensions (pu)15 kV phases tensions (deg)
F
10.6
0.9815
1.0000
132
12
153
7
157
355
179
248
136247
151
257
68
1.0315
1.0073
1.0145
247
6.0 7.3
2.6
0.0
100
30
1.0000
150
87
0.9
400
120
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Variation of
-100
0
100
200
300
400
500
600
-15 -10 -5 0 5 10 15
phi (deg)
P B-C (MW)P D-E (MW)P B-D (MW)
0
20
40
60
80
100
120
140
160
-15 -10 -5 0 5 10 15
phi (deg)
Q B-C (MVar)Q D-E (MVar)Q B-D (MVar)
0.97
0.975
0.98
0.985
0.99
0.995
1
1.005
1.01
1.015
1.02
-15 -10 -5 0 5 10 15
phi (deg)
V C (pu)V D (pu)V E (pu)
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I Assuming that transformer D-B is equipped with a tap changerallowing to vary progressively (the magnitude of) its transformerratio, study the impact of this ratio on branch power flows and busvoltage magnitudes.
I Same question for an identical variation of the ratios of bothtransformers D-B an E-C.
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Varying the (magnitude) of the ratio of transformer D-B
10 for E-C and n0 for D-B. Example for n = 0.95.
150 kV
380 kVpuissances ractives (Mvar)
puissances actives (MW)
D E
A
B
C
modules tensions (pu)15 kV phases tensions (deg)
F
12.2
1.0029
1.0000
74
46
61
48
62
352
162
340
91339
102
162
91
1.0364
1.0541
1.0232
339
5.9 7.8
9.7
0.0
100
30
1.0000
150
79
0.9
400
120
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Variation of n
0
50
100
150
200
250
300
350
400
90 95 100 105 110
n (pu)
P B-C (MW)P D-E (MW)P B-D (MW)
-50
0
50
100
150
200
90 95 100 105 110
n (pu)
Q B-C (MVar)Q D-E (MVar)Q B-D (MVar)
0.94
0.96
0.98
1
1.02
1.04
1.06
1.08
1.1
90 95 100 105 110
n (pu)
V C (pu)V D (pu)V E (pu)
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Same variation of the ratios of transformers D-B et E-C
n0 for both transformers. Example for n = 0.95.
150 kV
380 kVpuissances ractives (Mvar)
puissances actives (MW)
D E
A
B
C
modules tensions (pu)15 kV phases tensions (deg)
F
11.8
1.0487
1.0000
105
15
55
15
56
352
159
346
123345
133
156
55
1.0374
1.0705
1.0210
345
5.9 7.8
9.5
0.0
100
30
1.0000
150
77
0.9
400
120
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Same variation of n in both transformers
50
100
150
200
250
300
350
400
90 95 100 105 110
n (pu)
P B-C (MW)P D-E (MW)P B-D (MW)
0
20
40
60
80
100
120
140
90 95 100 105 110
n (pu)
Q B-C (MVar)Q D-E (MVar)Q B-D (MVar)
0.85
0.9
0.95
1
1.05
1.1
1.15
90 95 100 105 110
n (pu)
V C (pu)V D (pu)V E (pu)
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I Let ARTERE (the power flow computation software) adjustautomatically the ratios of both transformers D-B and E-C so as tobring the voltages at buses D and E in the dead-band [1.02 1.04] pu
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Automatic adjustment of the ratios of both transformersto bring the voltages at buses D and E in [1.02 1.04] pu
iter max mismatches : MW Mvar phi(MVA)
1 395.2 407.1 605.1
2 27.4 62.4 78.0
3 1.0 1.2 2.0
4 0.1 0.1 0.1
in-phase trfo taps : 2 down 0 up
4 4.4 58.8 90.6
5 0.2 0.8 1.0
6 0.0 0.1 0.1
in-phase trfo taps : 1 down 0 up
6 4.5 61.1 83.7
7 0.1 0.7 0.7
8 0.0 0.0 0.0
in-phase trfo taps : 1 down 0 up
8 4.5 63.5 86.9
9 0.1 0.7 0.7
10 0.0 0.0 0.0
transfo ctld bus volt set-pt tol ratio tap max
E-C E 1.0275 1.0300 0.0100 0.963 14 25
D-B D 1.0350 1.0300 0.0100 0.988 16 2519 / 27
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Situation after the transformers have been adjusted
150 kV
380 kVpuissances ractives (Mvar)
puissances actives (MW)
D E
A
B
C
modules tensions (pu)15 kV phases tensions (deg)
F
12.1
1.0275
1.0000
121
1
51
2
51
352
161
351
143349
151
151
38
1.0368
1.0350
1.0184
349
5.9 7.8
9.6
0.0
100
30
1.0000
150
78
0.9
400
120
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I Study the effect of varying the voltage of generator F on thereactive power productions of both generators, on the branch powerflows and on the bus voltage magnitudes.
I Same question for an identical variation of the voltages of bothgenerators A and F.
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Varying the voltage of generator F
Example: VF = 0.98 pu
150 kV
380 kVpuissances ractives (Mvar)
puissances actives (MW)
D E
A
B
C
modules tensions (pu)15 kV phases tensions (deg)
F
12.5
0.9828
1.0000
106
14
53
14
54
352
189
348
129347
137
154
56
1.0283
1.0052
1.0112
347
5.9 7.9
9.9
0.0
100
30
0.9800
150
55
0.8
400
120
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Variation of VF
0
50
100
150
200
250
0.96 0.98 1 1.02 1.04
V F (pu)
Q Gen A (MVar)Q Gen F (MVar)
0.97
0.98
0.99
1
1.01
1.02
1.03
1.04
0.96 0.98 1 1.02 1.04
V F (pu)
V C (pu)V D (pu)V E (pu)
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Variation of VF
50
100
150
200
250
300
350
0.96 0.98 1 1.02 1.04
V F (pu)
P B-C (MW)P D-E (MW)P B-D (MW)
0
20
40
60
80
100
120
140
0.96 0.98 1 1.02 1.04
V F (pu)
Q B-C (MVar)Q D-E (MVar)Q B-D (MVar)
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Same variation of voltages of generators A and F
Example: VF = VA = 0.98 pu
150 kV
380 kVpuissances ractives (Mvar)
puissances actives (MW)
D E
A
B
C
modules tensions (pu)15 kV phases tensions (deg)
F
13.0
0.9658
0.9800
106
14
53
15
54
352
168
348
131347
139
154
57
1.0124
0.9888
0.9949
347
6.2 8.1
10.3
0.0
100
30
0.9800
150
81
0.9
400
120
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Variation of VF = VA
60
80
100
120
140
160
180
0.96 0.98 1 1.02 1.04
V Gen (pu)
Q Gen A (MVar)Q Gen F (MVar)
0.92
0.94
0.96
0.98
1
1.02
1.04
1.06
1.08
1.1
0.96 0.98 1 1.02 1.04
V Gen (pu)
V C (pu)V D (pu)V E (pu)V B (pu)
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Variation of VF = VA
50
100
150
200
250
300
350
0.96 0.98 1 1.02 1.04
V Gen (pu)
P B-C (MW)P D-E (MW)P B-D (MW)
0
20
40
60
80
100
120
140
0.96 0.98 1 1.02 1.04
V Gen (pu)
Q B-C (MVar)Q D-E (MVar)Q B-D (MVar)
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