Exercise4 - t Umathstat.sci.tu.ac.th/~archara/MA111/MA111-116/exercise...MA111:...
Transcript of Exercise4 - t Umathstat.sci.tu.ac.th/~archara/MA111/MA111-116/exercise...MA111:...
MA111: Prepared by Asst.Prof.Dr.Archara Pacheenburawana 1
Exercise 4.1
1. Find the most general antiderivative of the function.
(a) f(x) = 5 (b) f(x) = x2 + π
(c) f(x) = x5/4 (d) f(x) = 1/3√x2
(e) f(x) = x2 − x (f) f(x) = 4x5 − x3
(g) f(x) = 27x7 + 3x5 − 45x3 +√2x
(h) f(x) =3
x2− 2
x3(i) f(x) =
4x6 + 3x4
x3
2. Evaluate the integral and check your answer by differentiating.
(a)
∫
3x4 dx (b)
∫
(x2 + x) dx
(c)
∫
(3x4 − 3x) dx (d)
∫
(x+ 1)2 dx
(e)
∫
3√x dx (f)
∫(
3− 1
x4
)
dx
(g)
∫
x1/3 − 3
x2/3dx (h)
∫
(x2 + 1)2√x
dx
(i)
∫
(sin x− cosx) dx (j)
∫
2 sec x tan x dx
(k)
∫
5 sec2 x dx (l)
∫
(3ex − 2) dx
(m)
∫
(3 cosx− 1/x) dx (n)
∫(
5x− 3
ex
)
dx
(o)
∫
ex + 3
exdx (p)
∫
x1/4(x5/4 − 4) dx
Answer to Exercise 4.1
1. (a) 5x+ C (b) 1
3x3 + πx+ C (c) 4
9x9/4 + C (d) 3 3
√x+ C (e) 1
3x3 − 1
2x2 + C
(f) 2
3x6 − 1
4x4 + C (g) 27
8x8 + 1
2x6 − 45
4x4 +
√2
2x2 + C (h) − 3
x+ 1
x2 + C
(i) x4 + 3
2x2 + C
2. (a) 3
5x5 + C (b) 1
3x3 + x2
2+ C (c) 3
5x5 − 3
2x2 + C (d) 1
3(x+ 1)3 + C
(e) 2x3/2+C (f) 3x+ 1
3x−3+C (g) 3
2x2/3−9x1/3+C (h) 2
9x9/2+ 4
5x5/2+2x1/2+C
(i) − cos x− sin x+ C (j) 2 sec x+ C (k) 5 tanx+ C (l) 3ex − 2x+ C
(m) 3 sinx− ln |x|+C (n) 5
2x2 + 3e−x +C (o) x− 3e−x +C (p) 2
5x5/2 − 16
5x5/4
MA111: Prepared by Asst.Prof.Dr.Archara Pacheenburawana 2
Exercise 4.2
1. Evaluate the integral by making the given substitution.
(a)
∫
cos 3x dx, u = 3x
(b)
∫
x2(x3 + 2) dx, u = x3 + 2
(c)
∫
4
(1 + 2x)3dx, u = 1 + 2x
(d)
∫
(√x+ 2)3√
xdx, u =
√x+ 2
2. Evaluate the indefinite integral
(a)
∫
2x(x2 + 3)4 dx (b)
∫
(2x+ 1)(x2 + x)3 dx
(c)
∫ √x− 1 dx (d)
∫
x2
√x3 − 2
dx
(e)
∫
dx
5− 3x(f)
∫
2x+ 1
x2 + x− 1dx
(g)
∫
1 + 4x√1 + x+ 2x2
dx (h)
∫
1√x(√x+ 1)2
dx
(i)
∫
cos 2x dx (j)
∫
cosx√sin x+ 1 dx
(k)
∫
x sin(x2) dx (l)
∫
sin x√cosx
dx
(m)
∫
cos4 x sin x dx (n)
∫
sin x(cos x+ 3)3/4 dx
(o)
∫
sec x tanx√1 + sec x dx (p)
∫
cosxesinx dx
(q)
∫
ex√1 + ex dx (r)
∫
xex2+1 dx
(s)
∫
dx
x ln x(t)
∫
4
x(ln x+ 1)2dx
(u)
∫ √cot x csc2 x dx (v)
∫
sin x(cosx− 1)3 dx
(w)
∫
sec3 x tanx dx (x)
∫
ex − e−x
ex + e−xdx
(y)
∫
1 + x
1 + x2dx (z)
∫
2x+ 3
x+ 7dx
MA111: Prepared by Asst.Prof.Dr.Archara Pacheenburawana 3
Answer to Exercise 4.2
1. (a) 1
3sin 3x+C (b) 2
3(x3 + 2)3/2 +C (c) −1/(1 + 2x)2 +C (d) 1
2(√x+ 2)4 +C
2. (a) 1
5(x2 + 3)5 + C (b) 1
4(x2 + x)4 + C (c) 2
3(x− 1)3/2 + C (d) 2
3
√x3 − 2 + C
(e) −1
3ln |5− 3x|+ C (f) ln |x2 + x− 1|+ C (g) 2
√1 + x+ 2x2 + C
(h) −2(√x+1)−1+C (i) 1
2sin 2x+C (j) 2
3(sin x+1)3/2+C (k) −1
2cos(x2)+C
(l) −2√cosx+ C (m) −1
5cos5 x+ C (n) −4
7(cosx+ 3)7/4 + C
(o) 2
3(1 + sec x)3/2 + C (p) esinx + C (q) 2
3(1 + ex)3/2 + C (r) 1
2ex
2+1 + C
(s) ln | lnx|+C (t) −4(ln x+1)−1+C (u) −2
3(cotx)3/2+C (v) −1
4(cosx−1)4+C
(w) 1
3sec3 x+ C (x) ln(ex + e−x) + C (y) tan−1 x+ 1
2ln(1 + x2) + C
(z) 2(x+ 7)− 11 ln |x+ 7|+ C
Exercise 4.3
1. Express the limit as a definite integral on the given interval.
(a) limn→∞
n∑
i=1
xi sin xi4x, [0, π]
(b) limn→∞
n∑
i=1
exi
1 + xi4x, [1, 5]
(c) limn→∞
n∑
i=1
[2(x∗i )
2 − 5x∗i ]4x, [0, 1]
(d) limn→∞
n∑
i=1
√
x∗i 4x, [1, 4]
2. Use the form of the definition of the integral given in (4.7) to evaluate the integral.
(a)
∫
1
0
2x dx (b)
∫
5
−1
(1 + 3x) dx
(c)
∫ 5
1
(2 + 3x− x2) dx (d)
∫ 2
0
(2− x2) dx
(e)
∫ 5
0
(1 + 2x3) dx (f)
∫ 2
1
x3 dx
3. Prove that
∫ b
a
x dx =b2 − a2
2.
4. Prove that
∫ b
a
x2 dx =b3 − a3
3.
MA111: Prepared by Asst.Prof.Dr.Archara Pacheenburawana 4
5. Write the given sum or difference as a single integral in the form∫ b
af(x) dx.
(a)
∫ 2
0
f(x) dx+
∫ 3
2
f(x) dx (b)
∫ 3
0
f(x) dx−∫ 3
2
f(x) dx
(c)
∫
2
0
f(x) dx+
∫
1
2
f(x) dx (d)
∫
2
−1
f(x) dx+
∫
3
2
f(x) dx
(e)
∫
3
1
f(x) dx+
∫
6
3
f(x) dx+
∫
12
6
f(x) dx
6. If
∫ 8
2
f(x) dx = 1.8 and
∫ 8
5
f(x) dx = 3.2, find
∫ 5
2
f(x) dx.
7. If
∫ 1
0
f(x) dx = 3,,
∫ 4
0
f(x) dx = −7, and
∫ 4
3
f(x) dx = 2, find
∫ 3
1
f(x) dx.
Answer to Exercise 4.3
1. (a)
∫ π
0
x sin xdx (b)
∫
5
1
ex
1 + xdx (c)
∫
1
0
(2x2 − 5x)dx (d)
∫
4
1
√x dx
2. (a) 1 (b) 42 (c) 2 (d) 4
3(e) 317.5 (f) 3.75
5. (a)
∫
3
0
f(x) dx (b)
∫
2
0
f(x) dx (c)
∫
1
0
f(x) dx (d)
∫
3
−1
f(x) dx (e)
∫
12
1
f(x) dx
6. −1.4 7. −12
Exercise 4.4
1. Use the First Fundamental Theorem of Calculus to find the derivative.
(a) f(x) =
∫ x
0
(t2 − 3t+ 2) dt (b) g(x) =
∫ x
0
√1− 2t dt
(c) g(y) =
∫ y
2
t2 sin t dt (d) F (x) =
∫ 2
x
cos(t2) dt
(e) f(x) =
∫ x2
0
(e−t2 + 1) dt (f) f(x) =
∫ −1
x
ln(t2 + 1) dt
(g) h(x) =
∫ 1/x
2
arctan t dt (h) y =
∫
√x
3
cos t
tdt
(i) y =
∫ 1
1−3x
u3
1 + u2du (j) y =
∫ x3
√x
√t sin t dt
MA111: Prepared by Asst.Prof.Dr.Archara Pacheenburawana 5
2. Evaluate the definite integrals using the Second Fundamental Theorem of Calculus.
(a)
∫
3
−1
x5 dx (b)
∫
2
0
(2x− 3) dx
(c)
∫ 4
0
√x dx (d)
∫ 4
0
(√x+ 3x) dx
(e)
∫ 2
1
3
x4dx (f)
∫ 1
0
(x√x+ x−1/2) dx
(g)
∫ 3
3
√x5 + 2 dx (h)
∫ π/2
0
2 sin x dx
(i)
∫ π
π/2
sec x tan x dx (j)
∫ π
π/2
(2 sin x− cosx) dx
(k)
∫
9
1
1
2xdx (l)
∫
1
0
(ex − e−x) dx
(m)
∫ 9
8
2x dx (n)
∫ 3
0
(3ex − x2) dx
(o)
∫ π/2
π/6
(
x+2
sin2 x
)
dx (p)
∫
√3
1
6
1 + x2dx
(q)
∫ 2
0
|2x− 3| dx (r)
∫ 3π/4
0
| cosx| dx
(s)
∫
3
−2
f(x) dx, where f(x) =
{
−x, x ≥ 0x2, x < 0
(t)
∫
2
0
f(x) dx, where f(x) =
{
x4, 0 ≤ x < 1x5, 1 ≤ x ≤ 2
Answer to Exercise 4.4
1. (a) f ′(x) = x2 − 3x+ 2 (b) g′(x) =√1 + 2x (c) g′(y) = y2 sin y
(d) F ′(x) = − cos(x2) (e) f ′(x) = (e−x4
+ 1)2x (f) f ′(x) = − ln(x2 + 1)
(g) h′(x) = − arctan(1/x)/x2 (h) y′ =cos
√x
2x(i) y′ =
3(1− 3x)3
1 + (1− 3x)2
(j) y′ = 3x7/2 sin(x3)− (sin√x)/(2 4
√x)
2. (a) 364
3(b) −2 (c) 16
3(d) 88
3(e) 7
8(f) 12
5(g) 0 (h) 2 (i) Does not exist
(j) 3 (k) ln 3 (l) e+ e−1 − 2 (m) 28
ln 2(n) 3e3 − 12 (o) π2
9+ 2
√3 (p) π
2
(q) 5
2(r) 2−
√2
2(s) −11
6(t) 10.7
MA111: Prepared by Asst.Prof.Dr.Archara Pacheenburawana 6
Exercise 4.5
Evaluate the definite integral, if it exists.
1.
∫ 2
0
(x− 1)25 dx 2.
∫ 2
0
x√x2 + 1 dx
3.
∫ 1
0
x2(1 + 2x3)5 dx 4.
∫ 1
−1
x
(x2 + 1)2dx
5.
∫
1
0
cosπx dx 6.
∫ π
π/2
4 cosx
(sin x+ 1)2dx
7.
∫ 4
1
1
x2
√
1 +1
xdx 8.
∫ π/2
π/4
cotx dx
9.
∫
3
0
dx
2x+ 310.
∫
4
1
x− 1√x
dx
11.
∫ π/3
0
sin x
cos2 xdx 12.
∫ 13
0
dx3
√
(1 + 2x)2
13.
∫ 2
1
x√x− 1 dx 14.
∫ e4
e
dx
x√lnx
15.
∫ a
0
x√x2 + a2 dx (a > 0)
Answer to Exercise 4.5
1. 0 2. 5
3
√5− 1
33. 81
44. 0 5. 0 6. −2 7. 4
√2
3− 5
√5
128. 1
2ln 2 9. 1
2ln 3
10. 8
311. 1 12. 3 13. 16
1514. 2 15. 1
3(2√2− 1)a3
Extra Problems
1. Use Part I of the Fundamental Theorem of Calculus to find the derivative of the
function y =
∫ 0
√x
(
1 + sin3 t)
dt.
2. Evaluate the following integrals. Explain your answer.
(a)
∫ π/2
0
d
dx
(
sinx
2cos
x
3
)
dx
(b)d
dx
∫ π/2
0
(
sinx
2cos
x
3
)
dx
(c)d
dx
∫ π/2
x
(
sint
2cos
t
3
)
dt
3. Let F (t) =
∫ t2
1
√1 + u4
udu, find F ′′(1).
MA111: Prepared by Asst.Prof.Dr.Archara Pacheenburawana 7
4. Use the Fundamental Theorem of Calculus to find the derivative of the function
F (x) =
∫ 3
tan x
√
t+√t dt.
Answer F ′(x) = −√
tan x+√tan x · sec2 x
5. Find the derivative of the function g(x) =
∫ x3
x2
t2√1 + t dt.
Answer g′(x) = −2x5√1 + x2 + 3x8
√1 + x3
6. Use the Fundamental Theorem of Calculus to find the derivative of the function
F (x) =
∫ x3
√x
ln(t+ 1)
tdt.
Answer F ′(x) = − ln (√x+ 1)
2x+
3 ln (x3 + 1)
x
7. Use the Fundamental Theorem of Calculus to find the derivative of the functionF (x) when
F (x) =
∫ x2
√x
cos t
t2 + 3t+ 5dt.
Answer F ′(x) = − cos√x
2√x(x+ 3
√x+ 5)
+2x cosx2
x4 + 3x2 + 5
8. Use the Fundamental Theorem of Calculus to find the derivative of the functionF (x) when
F (x) =
∫ 0
3+tan x
sin(t2) dt.
Answer F ′(x) = − sin(3 + tanx)2 sec2 x
9. Given f(x) =
∫ x
0
1
1 + t + t2dt. Find f ′′(0).
10. (a) Evaluate
∫[
2−1/x
x2+ x sin(x2) cos(x2)
]
dx.
(b) Find the derivative of the function g(x) =
∫
4
lnx
tanh t dt.
Answer (a)2−1/x
ln 2+
sin2(x2)
4+ C (b) −tanh(ln x)
x