Exercícios de Polarização do FET

1) Encontre o valor da tensão no dreno e na fonte do transistor do circuito abaixo:

a) Vcc=10V, IDss = 10mA, Vp=-5V, RD=2K, RS=680Ω.

b) Vcc=25V, IDss = 8mA, Vp=-3V, RD=3,3K, RS=1KΩ.

c) Vcc=15V, IDss = 9mA, Vp=-3V, RD=2,2K, RS=1,2KΩ.

d) Vcc=9V, IDss = 12mA, Vp=-6V, RD=2K, RS=1KΩ.

e) Vcc=12V, IDss = 10mA, Vp=-4V, RD=3,3K, RS=820Ω.

f) Vcc=13,8V, IDss = 16mA, Vp=-8V, RD=1,5K, RS=1KΩ.

g) Vcc=8V, IDss = 10mA, Vp=-5V, RD=2,2K, RS=1,2KΩ.

h) Vcc=6V, IDss = 8mA, Vp=-3,5V, RD=2,7K, RS=1KΩ.

2) Desafio: Conferir o resultado aplicando bhaskara.

Respostas:

1.a)

VD = 10 – 3,2m.2K VD = 3,6V

VS = 680.3,2m VS = 2,17V

1.b)

VD = 25 – 1,64m.3,3K VD = 19,6V

VS = 1K.1,64m VS = 1,64V

1.c)

VD = 15 – 1,48m.2,2K VD = 11,74V

VS = 1,2K.1,48m VS = 1,78V

1.d)

VD = 9 – 3m.2K VD = 3V

VS = 1K.3m VS = 3V

1.e)

VD = 12 – 2,46m.3,3K VD = 3,88V

VS = 820.2,46m VS = 2,02V

1.f)

VD = 13,8 – 4m.1,5K VD = 7,8V

VS = 1.4m VS = 4V

1.g)

VD = 8 – 2,21m.2,2K VD = 3,14V

VS = 2.21m.1,2K VS = 2,65V

1.h)

VD = 6 – 1,83m.2,7K VD = 1,06V

VS = 1.83m.1K VS = 1,83V