Example 12.1

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Transcript of Example 12.1

  1. 1. Heat balance: n-Propanol, Q = 60,000 X 285 = 17,100,000 Btu/hr Water, Q = 488,000 X l(120 - 85) = 17,100,000 Btu/h In Figure (2-60) : (tc-t) = 507-244= 263 = 285 Btu/Ib Assumed t2= 120 f t2= (120 : 150) Maxi. w=488 M Ib/hr So, ta = (85+120)/2= 102.5 F
  2. 2. t=LMTD= 1+2 ( 1 2 ) = 141
  3. 3. No. of Tubes = = 1213 8 0.1963 = 773