[EP] MINTEGIA (2010/03/11) Azterketa: 2008ko Iraila, A atala (ebazpena)

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λ (J 1 ) 1 (J 1 ) 2 (I C ) 1 U 1 U 2 1 = 12000 400 U 1 U 2 2 = 12000 400 I SARE Δ λ Δ (I C ) 2 = (I C ) 1 =I C

Transcript of [EP] MINTEGIA (2010/03/11) Azterketa: 2008ko Iraila, A atala (ebazpena)

Page 1: [EP] MINTEGIA (2010/03/11) Azterketa: 2008ko Iraila, A atala (ebazpena)

λ

(J1)1 (J1)2

(IC)1

U1

U2

1

=12000400

U1

U2

2

=12000400

ISARE

Δ λ

Δ

(IC)2=(IC)1=IC

Page 2: [EP] MINTEGIA (2010/03/11) Azterketa: 2008ko Iraila, A atala (ebazpena)

U1

U2

1

=12000400

⇒n1n2

1

=U1

U2

=12000400

= 30

U1

U2

2

=12000400

⇒n1n2

2

=

U13

U23

=12000

3400

3= 30

λ

Δ

λ

Δ

Page 3: [EP] MINTEGIA (2010/03/11) Azterketa: 2008ko Iraila, A atala (ebazpena)

(V13)1

(V13)2

60o

Page 4: [EP] MINTEGIA (2010/03/11) Azterketa: 2008ko Iraila, A atala (ebazpena)

(VL)1

IS1

IC

D1

D3

RL

IS2

IS3 €

23IC

13IC

IS1 =23IC

IS2 = −13IC

IS3 = −13IC

(V13)1

23IC

(Is1)1

(Is3)1

−23IC

−13IC €

13IC

30 60 90 120 150 180 210 240 270 300 330 360

(V13)1 (V23)1 (V21)1 (V31)1 (V32)1 (V12)1

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(Is1)1

(Is3)1

IS1

IC

D1

D3

RL

IS2

IS3

23IC

13IC

IS1 =13IC

IS2 =13IC

IS3 = −23IC

(V23)1

23IC

23IC

13IC

13IC

−13IC

−13IC

−23IC

−23IC

(VL)1

30 60 90 120 150 180 210 240 270 300 330 360

(V13)1 (V23)1 (V21)1 (V31)1 (V32)1 (V12)1

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(Is1)2

(Is3)2

IS1

IC

D1

D2

RL IS2

IS3 €

23IC

13IC

(V12)1

IS1 =13IC

IS2 = −23IC

IS3 =13IC

23IC

23IC

13IC

13IC

−13IC

−13IC

−23IC

−23IC

(VL)1

30 60 90 120 150 180 210 240 270 300 330 360

(V13)1 (V23)1 (V21)1 (V31)1 (V32)1 (V12)1

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(Ip3)1

(Ip1)1

(J1)1 = (Ip1)1 - (Ip3)1

30 60 90 120 150 180 210 240 270 300 330 360

Δ

(J1)1

n1n2

1

IC

Δ

23x

23x

13x

13x

−13x

−13x

−23x

−23x

−x

x

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30 60 90 120 150 180 210 240 270 300 330 360

(VL)2

(Is1)2

(V13)2 (V23)2 (V21)2 (V31)2 (V12)2

(J1)2 = (Ip1)2

IC

-IC

n2n1

1

⋅ IC( )1 = x

−n2n1

1

⋅ IC( )1 = −x

(V32)2

λ

(J1)2

IC

λ

n1n2

2

=n1n2

1

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ISARE

2x

−2x

30 60 90 120 150 180 210 240 270 300 330 360

(J1)2

(J1)1

x

−x

ISARE =12π

⋅ 2 ⋅ 2π3⋅ 2x( )2

ISARE = 2 ⋅ 23⋅n2n1

1

⋅ IC

ISARE = 2 ⋅ 23⋅130

⋅ 600 = 32.66A

x

−x

(J1)1 = (J1)2 =12π

⋅ 2 ⋅ 2π3⋅ x( )2

(J1)1 = (J1)2 =23⋅n2n1

1

⋅ IC

(J1)1 = (J1)2 =23⋅130

⋅ 600 =16.33A

Page 10: [EP] MINTEGIA (2010/03/11) Azterketa: 2008ko Iraila, A atala (ebazpena)

VLC( )1 = VLC 0( )1 − ΔVX( )1 = VLC 0( )1 − 0.12 VLC 0( )1= (1− 0.12) ⋅ VLC 0( )1 = 0.88 ⋅ 540 = 475v

VLC 0( )1 =VLC 0 S3 =3VO S3

π=3 ⋅ 400 2( )

π= 540v

VO S3 = 2 ⋅U2 = 400 2

λ

Δ

λ

Δ

VLC( )2 = VLC 0( )2 − ΔVX( )2 = VLC 0( )2 − 0.12 VLC 0( )2= (1− 0.12) ⋅ VLC 0( )2 = 0.88 ⋅ 540 = 475v

VLC 0( )2 =VLC 0 PD3=3 3 ⋅VO PD3

π=

3 ⋅ 3 ⋅ 400 23

π= 540v

VO PD3 = 2 ⋅ U23

= 400 2

3

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FSARE =PLC( )1 + PLC( )23 ⋅U1 ⋅ ISARE

=VLC( )1 ⋅ (IC )1[ ] + VLC( )2 ⋅ (IC )2[ ]

3 ⋅U1 ⋅ ISARE=475 ⋅ 600[ ] + 475 ⋅ 600[ ]

3 ⋅12000 ⋅ 32.66= 0.84

cos ϕ1( )1 =1− ΔVX

VLC 0

1

cos ϕ1( )1 =1− 0.12 = 0.88

ϕ1( )1 = arccos 0.88( ) = 28.35º

cos ϕ1( )2 =1− ΔVX

VLC 0

2

cos ϕ1( )2 =1− 0.12 = 0.88

ϕ1( )2 = arccos 0.88( ) = 28.35º

VR

(I1)1

ϕ1( )1 = ϕ1( )2

(I1)2 (I1)SARE = (I1)1 + (I1)2

I1( )SARE = I1( )1 + I1( )2 =VLC 0( )1 ⋅ (IC )1

3 ⋅U1

+VLC 0( )2 ⋅ (IC )2

3 ⋅U1

=540 ⋅ 600 + 540 ⋅ 600

3 ⋅12000= 31.17A

τ SARE =I≈( )SAREI1( )SARE

=ISARE2 − I1( )SARE

2

I1( )SARE=

ISAREI1( )SARE

2

−1 =32.6632.17

2

−1 = 0.31