EP IKASGELAKO PRAKTIKA 2009/02/24 (ebazpena)

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λ λ λ λ Δ λ (J 1 ) 1 (J 1 ) 2 (J 1 ) 3 (I C ) 1 = 30A n 1 n 2 1 = 15 n 1 n 2 2 = 15 n 1 n 2 3 = 30 I SARE (I C ) 2 = 90A (I C ) 3 = 60A
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    21-Jun-2015
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Transcript of EP IKASGELAKO PRAKTIKA 2009/02/24 (ebazpena)

  • 1. ISARE (J1)2(J1)3(J1)1 n1 n1 n1 = 15 = 15 = 30 n 2 1 n2 2 n2 3 (IC)1=30A(IC)2=90A(IC)3=60A

2. n1 = 15 n 2 1 n1 n1 n1 = 15 = n2 2 n 2 2 n 2 1 n1 n1 n1 (V1)2=(V13)3 = 30 = 2 n2 3 n2 3 n 2 1 30o (V13)(IC)1=30A 1(IC)2=90A(IC)2=3(IC)1 (IC)3=60A(IC)3=2(IC)1 3. (J1)1=(Ip1)1 n2 (J1)1 ( IC )1 = x n1 1 n 2 ( IC )1 = x n1 1 n1 = 15 (Is1)1 n 2 1 (IC)1(IC)1 (VL)1 (V32)1 (V12)1 (V13)1 (V23)1 (V21)1 (V31)1 (V32)1 (IC)1=30A60 90 120 150 180 210240 270 300 330 360 30 4. (J1)2=(Ip1)2 2 n n 2 n2 ( IC ) 2 = 2 [ 3 ( IC )1 ] = 2 2 ( IC )1 = 2x(J1)2 3 n1 2 3 n1 1 n1 1 1 n 1 n n 2 ( IC ) 2 = 2 [ 3 ( IC )1 ] = 2 ( IC )1 = x 3 n1 2 3 n1 1 n1 1 n1 = 15(Is1)2 n2 2 (IC)2 (VL)2(V1)2 (V2)2 (V3)2 (IC)2=90A 30 60 90120 150180210240 270300330360 5. (Ip1)3 1 n n2 n2 ( IC ) 3 = [2 ( IC )1 ] = ( IC )1 = x 2 (J1)3 n1 3 2 n1 1 n1 1 n 2 ( IC ) 3 = x n1 3 n1 (Is1)3 = 30 (IC)3 n2 3 (IC)3 (VL)3 (V12)3 (V13)3 (V23)3 (V21)3 (V31)3 (V32)3(IC)3=60A30 60 90 120 150 180 210 240 270 300 330 360 6. (Ip3)3 n2 ( IC ) 3 = x (J1)3 n1 3 n 2 ( IC ) 3 = x n1 3 n1 (Is3)3 = 30 (IC)3 n2 3 (IC)3 (VL)3 (V12)3 (V13)3 (V23)3 (V21)3 (V31)3 (V32)3(IC)3=60A 30 60 90 120 150 180 210 240 270 300 330 360 7. (J1)3=(Ip1)3(Ip3)3 2x(J1)3x x n1 2x = 30 n2 3(Ip1)3 x x (Ip3)3x (IC)3=60A x 30 60 90 120150 180210 240 270 300330 360 8. (J1)1 x 2 2 1 2 (J1 )1 = 2 x = x2 33 2 n 2 2 12 (J1 )1 = x = ( IC )1 = 30 = 1.63A 3 n1 1 3 15 3x (J1)2 2x 2 2 1 2 4 1 12 1 4 2 (J1 ) 2 = (2x ) + 1 ( x) = x 1 4 + = x 2 32 3 32 3 3 n 1 x( J1) 2 = x 2 = 2 ( IC )1 2 = 30 2 = 2.83A n1 115 (J1)3 2xx12 1 1 1 1 12 2 (J1 ) 3 = 2 (2x ) + 4 ( x ) = x 2 4 + 4 = x 2 3 2 332 3 3 n 1 (J1 ) 3 = x 2 = 2 ( IC )1 2 = 30 2 = 2.83An1 115 x2x 30 60 90 120 150 180 210240 270 300 330 360 9. 5x (J1)1 x 4x ISARE x (J1)2 2x 2x3x 4 x x 30 60 90 120 150 180 210 240270 300 330 360 (J1)3 21 2 2 2 4 ( 4 x ) + 2 (5x ) + 2 (2x ) + 2 ( 3x ) ISARE = 2x266 6 6 x 1 = x 4 16 + 2 25 + 2 4 + 2 9 2 666 6 1 64 50 8 18 1 140 70= x+ + = x = x +2 6 6 6 6266 x35 n 2 35 1 352x = ( IC )1 ISARE = x = 30 = 6.83A 3 n1 1 3 153 30 60 90 120 150 180 210240 270 300 330 360