[Cm(P3 +Q)+0.64Pr + · din 4114 (for st52.0 ... − elastic limit according to din 267 par. 3 r =...

DWG N

UT

05/02DATE

9019/1

1) METHOD OF EULERO CASE 2 (COEFF. OF SAFETY 2)

-GRAPHICS DWG 9020/1 – 9030/1-1 – 9030/1-2 IT’S THE SYSTEM OF CALCULATION REQUIRED BY UNI-EN 81.2:99 FOR λ ≥ 100

1.1 2

2

l 2J E π

<=Fs

FOR λ < 100

1.2 ( ) ( )[ ]2λ/100×210-Rm - Rm2A

<=Fs

1.3 ( )[ ]mr3mnS P+0.64P+Q+PC1.4g=F

IN MARKED GRAPHICS IS SHOWED THE TOTAL FORCE APPLIED TO RAM W, THEREFORE:

1.4 P)QP(CW rh3m ++=

2) IMPORTANT FORMULAS

( )[ ]44 2e-d-d64π

=J ]mm[ 4 il

=λ

( )[ ]22 2e-d-d64π

=J ]mm[ 2 I γ=Pr

AJi [mm] ]mm[

4d

A 2p

π=

3) Qfs VALUE TO CALCULATE THE LENGTH OF THE STEM’S FREE FLEXURE (REGISTERED IN DIAGRAMS: 9020/1 - 9030/1-1 – 9030/1-2) WITH THE HIGHEST VALUE “ DL – DC “

9019/1-IN

CALCULATION METHODS FOR BUCKLING FORCE

APPLIED TO RODS (UNI-EN 81.2:99)

F d Qfs Qfs ROD T DL-DC (mm) (mm) (mm) 50 /100 74.5 84.5 110 / 150 81.5 91.5 160 / 238 90 95

DWG N

UT

05/02DATE

9019/2

MEASUREMENTS SYMBOL UNIT

STRENGHT CROSS-SECTIONAL AREA OF THE RAM ………………………………. A ……… 2mm

OUTSIDE DIAMETER OF THE RAM…………………………………………………… d ……… mm

THICNESS OF THE RAM ……………………………………………………………….. e ……… mm

OUTSIDE DIAMETER OF THE CYLINDER…………………………………………….. D ……… mm

THICKNES OF THE CYLINDER …………………………………………………………. ecyl ……… mm

CROSS-SECTIONAL AREA OF THE RAM……………………………………………… Ap ……… 2mm

RADIUS OF GYRATION OF THE RAM …………………………………………………... i ……… mm

SECOND MOMENT OF THE RAM ……………………………………………………... J ……… 4mm

MASS FOR UNIT OF LENGTH OF THE RAM………………. …………………………. γ ……… Kg/mm

COEFFICIENT OF SLENDERNESS OF THE RAM …………………………………... λ

MODULUS OF ELASTICITY (FOR STEEL, E=2.1 510 ) ……………………………… E ……… N/ 2mm LENGTH OF THE STEM’S FREE FLEXURE (TOTAL STROKE+Qfs+DISTANCE, IF ANY OF THE PULLEY AXIS AT THE TOP OF THE STEM …………………..………… I ……… mm

TENSILE STRENGTH OF MATERIAL ………………………………………………….. Rm ……… N/ 2mm

ACCELERATION OF GRAVITY …………………………………………………………. gn ……… m/ 2s

REEVING RATIO ……………………………………………………………………………. mC SUM OF THE MASS OF THE EMPTY CAR AND THE MASS OF THE PORTION OF THE TRAVELLING CABLES SUSPENDED FROM THE CAR………... 3P ……… Kg

RATED LOAD (MASSE) DISPLAYED IN THE CAR ……………………………………. Q ……… Kg

MASS OF THE RAM ………………………………………………………………………… γ ……… Kg

MASS OF THE RAM-HEAD EQUIPMENT………………………………………………... rhP ……… Kg

ACTUAL BUCKLING FORCE APPLIED…………………………………………………... SF ……… N

ADMISSIBLE VALUE OF STRENGTH ACCORDING TO DIN 4114 (FOR σ0.52St d,am=210) …………………………………………………….. am,dσ ……… N/ 2mm

COEFFICIENT TO BE CALCULATED FROM DIN 4114 IN FUNCTION OF …...……... ω

COEFFICIENT OF OVERPRESSURE …………………………………………………… 1.4

EXPLANATORY NOTES ON GRAPHICS

1- THE UPPER AND LOWER LIMIT OF THE CURVE IS CUT BY MAX. AND MIN. VALUES OF THE ADMISSIBLE PRESSURE (RESPECTIVELY 45 AND 12 BAR).

2- REPRESENTED CURVES WERE EXECUTED ACCORDING TO EULERO’S FORMULAS.

- GRAPHICS EXECUTED ACCORDING TO STANDARD EN 81.2 FOR VALUES λ < 100: IN ORDER TO OBTAIN MORE PRECISE VALUES, MUST BE USED THE FORMULA SHOWED AT POINT 1.2 (SEE NOTES ON GRAPHICS)).

- GRAPHICS EXECUTED ACCORDING TO STANDARD TRA 200 FOR 250≤λ : IN ORDER TO OBTAIN MORE PRECISE VALUES, MUST BE USED

THE FORMULA SHOWED AT POINT 4.1 (SEE NOTES ON GRAPHICS). - CURVES EXECUTED ACCORDING TO EULERO’S FORMULAS ARE

ALWAYS ON THE SIDE OF SAFETY.

SYMBOLS AND NOTES FOR BUCKLING FORCE TO BE CALCULATED

9019/2-IN

4567891011121314

200

400

600

800

1000

1200

1400

1600

1800

2000

2200

2400

2600

2800

3000

3200

3400

3600

LENGTH OF STEM'S FREE FLEXURE = [M]

TOTA

L LO

AD O

N T

HE

RO

D +

USE

FUL

LOAD

+ C

AR W

EIG

HT

+ C

AR F

RAM

E +

ACC

ESSO

IRES

= [d

aN]

DATE

DWG N°05/02

9020/1

TABLE FOR CHECKING THE MAX. LOADSFOR RAMS ø50 A ø100

100 : SEE DWG 9019/1

EU

LER

O'S

MET

HO

D C

ASE

2 ( C

OEF

FIC

IEN

T O

F SA

FETY

2 )

- EUROPEAN STANDARD EN 81.2 : 99 -

UT

9020/1 IN

4540

3530

25

20

15

4540

35

30

25

20

15

ø 50 x 7.5ø 50 x 5

4540

35

30

25

20

15

ø 60 x 5ø 60 x 7.5

4540

35

30

25

20

15

4540

35

30

25

20

15

ø 70 x 5

ø 70 x 7.5

4540

35

30

25

20

15

4540

35

30

25

20

15

ø 80 x 5

4540

35

30

25

20

15

ø 80 x 7.5

45

40

35

30

25

20

15

ø 80 x 12

45

40

35

25

30

20

15

45

40

35

30

25

20

15

ø 90 x 5

45

40

35

30

25

20

15

ø 90 x 7.5ø 90 x 12

45

40

35

30

25

20

15

ø 10

0 x

5

ø 10

0 x

7.5

ø 10

0 x

12 4540

35

30

25

20

15

45

40

35

30

25

20

15

45

40

35

30

25

20

15

ø 85 x 7.5

DATE

DWG N°05/02

9030/1-1

678910111213141516

1000

2000

3000

4000

5000

6000

7000

8000

1000

011

000

UT

9030/1-1 IN

9000

1300

012

000

45

40

35

30

25

20

15

45

40

35

30

25

20

15

45

40

35

30

25

20

15

ø 13

0 x

7.5

4540

35

30

25

20

15

ø 13

0 x

5

45

40

35

30

25

20

15

ø 12

0 x

12

ø 13

0 x

12

45

40

35

30

25

20

15

4540

35

30

25

20

15

45

40

35

30

25

20

15

45

40

35

30

25

20

15

ø 11

0 x

5

ø 12

0 x

5

ø 11

0 x

7.5

ø 12

0 x

7.5

ø 11

0 x

12


TOTA

L LO

AD O

N T

HE

RO

D +

USE

FUL

LOAD

+ C

AR W

EIG

HT

+ C

AR F

RAM

E +

ACC

ESSO

IRES

= [d

aN]

TABLE FOR CHECKING THE MAX. LOADSFOR RAMS ø 110 A ø130

100 : SEE DWG 9019/1

EU

LER

O'S

MET

HO

D C

ASE

2 ( C

OEF

FIC

IEN

T O

F SA

FETY

2 )


DATE

DWG N°05/02

9030/1-2

678910111213141516

1000

2000

3000

4000

5000

6000

7000

8000

9000

1000

011

000

1200

013

000

1400

015

000

1600

017

000

1800

019

000

2000

0

UT

9030/1-2 IN

45

40

35

30

25

20

15

ø 15

0 x

6

45

40

35

30

25

20

ø 15

0 x

10

ø 18

0 x

10

45

40

35

30

25

20

ø 16

0 x

10

45

40

35

30

25

45

40

35

30

25

ø 20

0 x

10

45

40

ø 23

8 x

14


TOTA

L LO

AD O

N T

HE

RO

D +

USE

FUL

LOAD

+ C

AR W

EIG

HT

+ C

AR F

RAM

E +

ACC

ESSO

IRES

= [d

aN]

TABLE FOR CHECKING THE MAX. LOADSFOR RAMS ø 150 A ø238

100 : SEE DWG 9019/1

EU

LER

O'S

MET

HO

D C

ASE

2 ( C

OEF

FIC

IEN

T O

F SA

FETY

2 )


DWG N

UT

05/02DATE

9041/3

CYLINDER CALCULATION PROCEDURE

- THE FOLLOWING TECHNICAL DOCUMENTATION IS ABUOT THE CHECKING OF THE CYLINDERS INVOLVED IN LIFTS WORKING.

- CHECKS ARE CARRIED OUT ACCORDING TO STANDARD TRA 200 (AND RELATING REFERENCE MARKS) AND HARMONISED STANDARD UNI-EN 81.2:99.

- THE MAX ADMISSIBLE STATIC PRESSURE FOR EACH CYLINDER, WHICH COORRESPONDS TO THE MAX. ADMISSIBLE LOAD, IS INDICATED IN THE ENCLOSED TABLE

- FOR EACH PLANT IS INDICATED THE REAL LOAD, WHICH MUST BE ALWAYS SMALLER OR EQUAL TO THE MAX. ADMISSIBLE ONE

- THE CONSIDERED CYLINDER, DEVELOPED BY MORIS FACTORY, CORRESPONDS TO DRAWING 0367/2-P

- MEASUREMENT UNITS GENERALLY USED CORRESPOND TO THE INTERNATIONAL SYSTEM (S.I.)

- THE SYMBOLOGY ADOPTED REFERS TO THAT OF STANDARDS TRA 200 (AND SUBSEQUENT REFERENCES) AND STANDARDS UNI-EN 81.2:99

1) CYLINDER PIPE THICKNESS CALCULATION FOR DETERMINING THE INNER PRESSURE

- CALCULATION IS MADE IN COMPLIANCE WITH ANNEX K OF UNI-EN 81.2:99 STANDARDS AND WITH STANDARD DIN 2413 APPLICATION FIELD 1

- MATERIAL FEATURES ACCORDING TO DIN 1629 WITH TESTING CERTIFICATE IN CONFORMITY WITH DIN 50049-3.1B (MAX. WORKING PRESSURE 160 bar)

- DIMENSIONS ACCORDING TO DIN 2448

- MATERIAL ST. 52,0 DIN 1629 (1.0421)

- YIELD TENSION ……………………………………………….. 2P0.2 N/mm 355=R

- BREAKING PERCENTAGE ELONGATION ………….……… A5 > 21 %

- FROM DIN 2413:

exx20PxD

e onamm

cyl +ησ

= WITH P (bar)

- ACCORDING TO TRA 200/229.11 P = 2,3 x Pmax 1eo =

- FROM DIN 2413 1n =η FOR WELDLESS PIPES 8,0n =η FOR WELDED PIPES

S

R=σ P0.2

amm WITH S = 1,7

- REPLACING THE VALUES AND SOLVING WITH RESPECT TO Pmax : ( )

10 x D x 1.7 x 2.3

1-e x R x 2= cylP0.2

maxP1 WELDLESS PIPES

2) CYLINDER PLANE BASE CALCULATION

- CALCULATION ACCORDING TO TECHNICAL SHEET AD-MERKBLATT B5, 6.1.1 CASE (E)

- MATERIAL DIN 17.100 RST 37-2 (1.0038)

9041/3-IN


DWG N

UT

05/02DATE

9041/4

- YIELD TENSION ………………… 2P0.2 N/mm 235=R

e+Rx10

SxPxDxc= o

P0.2i1e

− ACCORDING TO TRA 200 P = 2,3 x Pmax

1o =e

− ACCORDING TO AD-MERKBLATT B0 TABLE 2 S = 1,5

− ACCORDING TO EN 81.2 S = 1,7

− ACCORDING TO AD-MERKBLATT B5 TABLE 1 C = 0,4

− REPLACING THE VALUES (S = 1,7) E RISOLVENDO PER Pmax :

( )10 x

Di1-e x 2.5

x 1.7 x 2.3

R= 2

21

2P0.2

maxP3

REMANING THICKNESS CALCULATION

− CALCULATION ACCORDING TO AD-MERKBLATT B5, TABLE 1, AND

ANNEX K OF UNI-EN 81.2:99 STANDARDS.

− CALCULATION OF “Umin” THICKNESS, WITH PRESSURE P, IS <= THAN THE

MINIMUM PRESSURE AMONG MAXIMUM ALLOWABLE PRESSURES FOR

ALL THE SYSTEM COMPONENTS.

( ) ( )1 +

R0.1 x P x 1.7 x 2.3 x r-0.5 x Di

x 1.3=P0.2

max1minU

MOREOVER, THE FOLLOWING PROJECT CONDITIONS MUST BE VERIFIED:

mm5>=minU

Sx2,0 11>=r

mm51>=r

Sx1,5<= 1minU

111 r +u=>=h

3) CYLINDER PIPE / CYLINDER HEAD WELDING CALCULATION

− MATERIAL RSt 37-2 DIN 17.100

mmN/ 98= 2P0.2R (DV 952)

− WELDING AREA axDx 2π=A

9041/4-IN


DWG N

UT

05/02DATE

9041/5

− ACTUAL FORCE ON THE WELDING

10Px3,2xDx

4max2π

=F

P0.2R<=AF

=τ

− SOLVING WITH RESPECT TO Pmax SI HA:

D x 2.340 x a x R

= 2P0.2maxP5

4) CALCULATION OF THE CYLINDER HEAD FIXING SCREW

− CALCULATION ACCORDING TO AD-MERKBLATT B7

− SCREWS M…..x …..UNI 5931 – 8.8

− ELASTIC LIMIT ACCORDING TO DIN 267 PAR. 3 2N/mm 640R =P0.2

− ACTUAL FORCE ON THE SCREWS :

40DlxxPx3,2 2

max π=F

− MIN. NEEDE BOLT DIAMETER:

C5+nxR

FxZ=

P0.2dK

Z = 1,51 FROM AD-MERKBLATT B7 TABLE 3

n = SCREWS NUMBER

ASSUMING THAT: Y=nxR

FxZ

P0.2

FOR: Y <= 20 C5 = 3 Y >= 50 C5 = 1

20 < Y < 50 15

-Y)65(=C5

− SOLVING WITH RESPECT TO Pmax :

85,1553xDl

)5Cd(xn2

2K

max−

=P6

PROJECT CONDITIONS

− SCREWS PITCH NOT MORE THAN 5 x dK

− MIN. SCREWS NUMBER 4

− MIN.SCREWS DIAMETER M10

− SCREW SHANK LENGTH AT LEAST 2 x dK

− MIN. ENGAGEMENT DEPTH L (CLASSE 8.8)

d / P < 9 L = 1,0 x dK

d / P > 9 L = 1,25 x dK

P = THREAD PITCH

9041/5-IN


DWG N

UT

05/02DATE

9041/6

5) CALCULATION OF THE LIMIT BEARING PRESSURE BETWEEN RAM BASE AND CYLINDER HEAD

− YELD TENSION RAM BASE:

dx4

xPx3,2 21Amax

π=F

− REACTION SURFACE:

)Dd(x4

2A

21A −

π=A

- SOLVING WITH RESPECT TO Pmax

( )2.3 x d

D-dx R x 10= 2

A1

2A

2A1 P0.2

maxP7

6) CALCULATION OF THE FEED LINE PIPES

− CALCULATION ACCORDING TO DIN 2413, APPLICATION FIELD 1, AND ANNEX K OF UNI-EN 81.2:99 STANDARDS

− AMTERIAL FEATURES ACCORDING TO DIN 1629 WITH TESTING CERTIFICATE IN CONFORMITY WITH DIN 50049-3.1 B (MAX WORKING PRESSURE 160 bar )

− DIMENSIONS ACCORDING TO DIN 2391

− MATERIAL St. 37.0 DIN 1629 ( 1.0254 )

− YIELD TENSION ………………. 2P0.2 N/mm 235=R

− BREAKING PERCENTAGE ELONGATION …. A5 = 25%

− FROM DIN 2413 SI HA:

exx20PxD

onamm

cyl +ησ

=e CON P (bar )

- ACCORDING TO TRA 200/229.11 P = 2,3 x Pmax

eo = 0,5

- FROM DIN 2413 ηn = 1

S

R=σ P0.2

amm CON S = 1,7

- REPLACING THE VALUES AND SOLVING WITH RESPECT TO Pmax

( )10 x

Dt x 1.7 x 2.30.5-e x R x 2

= cylP0.2maxP8

7) CYLINDER CONNECTION CALCULATION

- THREAD CALCULATION ACCORDING TO TECHNICAL SHEET AD-MERKBLATT B8 6.13

- MATERIAL St. 37.0 DIN 1629 (1.0254)

- YIELD TENSION………………………………………. 2P0.2 N/mm 235=R

- BREAKING PERCENTAGE ELONGATION ………. A5 = 25%

- WELDINGS CALCULATION ISNT’T NECESSARY; SEE POINT 3 (DRAWING N. 9041/4)

9041/6-IN


DWG N

UT

05/02DATE

9041/7

THREAD CALCULATION

- FROM TECHNICAL SHEET AD-MERKBLATT B8:

DfxπxLFx2

=P0.2

SR

- WITH:

L = THREAD LENGTH

Df = THREAD DIAMETER

S = SAFETY FACTOR = 1,5

P0.2R = YIELD TENSION MATERIAL

F = TENSILE FORCE

Px3,2xDx40 max

2o

π=F

- REPLACING THE VALUES AND SOLVING WITH RESPECT TO Pmax , SI HA:

10 x D x 1.5 x 2.3

Df x L x R x 2= 2

O

P0.2maxP9

9041/7-IN


-NB.: JOINT "A" DOWN (ON REQUEST)

-FULLY EXTENDED RAM WITH SLOWING

-PLATES "MC" AND "MI" ARE IDENTICAL-ROD UPPER PLATE IS OF OSCILLATING

A

SCR

EW

Q øG øD

235

250

3.6

101.

6

7

133 4

114.

3

9

133 4

114.

3

9

155

4.5

133

12

166

4.5

139.

7

13.5

190 5 159

17.5

190 5 159

22202

5.6

177.

8

26228

6.3

193.

7

F

ecy

l

OIL

l x

m

WEIGHT Kg

1 m

4 m

e

6070

8090

100

110

120

130

150

17.5

70

57

424 10

6

65 1253 7.545 558 1247 7.541504034453630383027

312522

24

20

7.5

5

20

18

7.5

5

5127.55127.55127.55

127.55

DIRECT SIDE ACTING 1 : 1 RAMDATE

DWG. N°05/02

9140

SEE

HYD

RA

ULI

C P

OW

ER U

NIT

235

235

235

235

250

250

250

374

343295265302258230264225202252216192188157145

158132120

154

138

133

123

D

150

ROD ø

50/60

1

70

80/85

90

100

110/120

130

150

S D E 1 E 2 E 3 E 4 S E

200

200

200

25 300 250 80 130 22

25

25

25

25

25

25

25

300

300

300

300

400

400

400

250

250

250

250

350

350

350

90

110

120

120

150

160

200

140

160

170

180

200

220

250

22

22

22

22

22

22

22

RO

Død

OILREGAIN

AIR VENT

SCREW

JOIN

TA

e

e

cyl

SD

TOTA

L LE

NG

HT

= S

TRO

KE

+ O

VE

RS

TRO

KE

+ Q

F

øD

øG

(ON REQUEST)PLATE MC

PLATE MI(ON REQUEST)

X X

SECTIONX-X

7.5

5

50

99

9017

19

7

101.

6

3.6/

/

235

M24

x70

Ch=

36

UT

9140-IN

150

150

150

150

BUFFER 35 mm

9

114.

3

4133

235

85

7.513626

Ch=

46M

30x6

0

D1

D1

E1E2

E3 E4

SE

400

20

ø d

TYPE

A Q H øG øD

235

580

3.6

101.

6

7

133 4

114.

3

9

133 4

114.

3

9

155

4.5

133

12

166

4.5

139.

7

13.5

190 5 159

17.5

190 5 159

22202

5.6

177.

8

26228

6.3

193.

7

32.5

249 8

219.

1

41278 8

244.

5

50304

10 273

F

ecy

l

WEIGHT Kg

1 m

4 m

e

6070

8090

100

110

120

130

150

160

180

200

112 639 10

95 582 10

17.5

80 504 10

70

57

424

374

10

6

65 343 1253 7.545 558 1247 7.541504034453630383027

312522

24

20

154

138

7.5

5

20

18

133

123

7.5

5

5127.55127.55127.55

127.55

DIRECT UNDERGROUND 1 : 1 RAM 05/02

9150

69368

12.5

323.

9

238

211 1045 14

235

580

235

580

235

580

235

580

250

600

250

600

250

600

250

600

295

660

295

660

295

660

295

660

295265302258230264225202252216192188157145

158132120

C

350

ø STELO

60 / 1001

110 / 150160 / 238

C 2 C 3 S C D 1 D 2 D 3 S D

400

560

280 20 25 270 210 16 25

330

460

28

30

30

35

350

350

290

290

20

20

25

30

ød

SCR

EW

OIL

l x

m

RO

D

SEE

HYD

RA

ULI

C P

OW

ER U

NIT

DATE

DWG. N°

-FULLY EXTENDED RAM WITH TOP SLOWING BUFFER 35 mm-ROD UPPER PLATE IS OF OSCILLATING TYPE

SECTIONX

OILREGAIN

AIR VENT

SCREW

JOIN

TA

e

e

cyl

SD

TOTA

L LE

NG

HT

= S

TRO

KE

+ O

VE

RS

TRO

KE

+ Q

F

øG

X

SC

UT

7.513626

9

114.

3

4133

580

235

85

9150-IN

M60

x p

. 3.5

L=1

20C

h=80

M30

x60

Ch=

46

238FOR DIMENSIONINGPLEASE CONTACT OURTRADE OFFICE

D1D2

D1

D2

D3

C1C2

C2

C1

C3

øD

H

200

ø d

N.DIS

UTT04/90

DATA

9316

1) PLACE THE LOWER FIXING PLATE ON THE CONCRETE OR WELDEDMETALMADE CAISSON PREVIOUSLY ON LEVELED.

2) PUT THE CYLINDER HEAD SO THAT THE AXIS OF THE RAM IS IN THEPOSITION PREVIEWED IN RELATION TO THE GUIDES.

3) SHIFT THE FFOT OF THE RAM IN A WAY THAT THE GENERATING LINE OFTHE RAM BODY IS // TO THE GUIDES (THE RETRACTED ROD IS ALWAIS // TOTHE BDY OF THE RAM).

4) SCREW THE UPPER FIXING PLATE BY COMPENSATING THE SIDE AND LEVELVARIATIONS BY WEDGES.

5) SCREW THE UPPER FIXING PLATE FOLLOWING THE SAME PROCEDURE ANDCONTROL // WITH A LEVEL.

6) PLACE THE CAR ON THE RAM HEAD.

7) MARK ON THE BRACKET THE FIXATION HOLES OF THE RAM HEAD.

8) DRILL THE BRACKET AND FIX IT ON THE RAM.

9) DEMOUNT THE SLIDING GUIDES AND CHECK THE POSITIONING OF THEBRACKET IN RELATION TO THE GUIDES.

10) REASSEMBLE THE SLIDING GUIDES AND PROCEED, WITH THE HELP OF AHOIST, IN A COMPLETE MANOUVRE ON THE TOTAL RUN OF THE RAM.

9316-IT

ASSEMBLY OF A LATERAL RAM

N.DIS

UTT04/90

DATA

9320/2

ASSEMBLY INSTRUCTIONS

1) CHECK WHETHER THE INTERRED PIPE IS PLUMB DOWN AND WELL DIMENSIONEDTO HOLD THE CYLINDER.

2) INSERT THE CYLINDER IN THE HOLE, WITH RESPECT TO THE WISHED “B”DIMENSION, HOLDING IT PROPERLY.

3) CHECK, USING A SPRIT LEVEL, THE RIGHT CENTERING OF THE CYLINDER AXLEWITH RESPECT TO THE GUIDES.

4) CATCH FROM ROD HEAD THE PROJECTING NYLON WIRE AND FIX IT TO THEUPPER-STROKE SIDE OF THE EQUIPMENT, SO THAT IT RESULTS EQUIDISTANTFROM THE GUIDES AND ON THE RAM AXLE.

5) CHECK WHETHER THE NYLON WIRE IS RIGHT CENTRED WITH RESPECT TO THEHOLE IT’S COMING FROM, SHOULD THAT NOT BE THE CASE, WORK ON THECYLINDER TO ADJUST ITS PERPENDICULARITY (SEE DRAWING ON SHEET N.9320/1)

NOTE:DUE TO PARTICULAR REASONS, THE CYLINDER CAN BE MOVED FROM THE IDEALCENTRE OF 10 cm. IN BOTH DIRECTIONS.

6) AFTER CYLINDER LEVELING, THE BOTTOM OF THE HOLDER MUST BE FIXED WITHCEMENT OR WITH ADDITIONAL PLATES, SO THAT THE ADJUSTMENT SCREWSWON’T BEAR THE LOAD, THEN NUT AND COUNTER-NUT MUST BE BLOCKED(WHEN USING CEMENT WORK ONLY WHEN IT’S SOLIDIFICATED.

WHEN ASSEMBLY’S COMPLETED, CHECK:

- WHETHER THE RAM SURFACE IS CLEAN, RULINGLESS, RUSTLESS,SCRATCHLESS ETC.

- WHETHER THE SEALS HAVE NO OIL LEAKAGES (SEE FOR EVENTUAL CHANGE).

- WHETHER THE OIL RECUPERATOR IS FUNCTIONAL.

- WHETHER THE PLATE FIXING SCREWS ARE RIGHT BLOCKED.

9320-2-ING

DIRECT UNDERGROUND 1:1 RAM

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[Cm(P3 +Q)+0.64Pr + · din 4114 (for st52.0 ... − elastic limit according to din 267 par. 3 r =...

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